I want to search a file for a particular pattern and if pattern found replace the line with new text. i am using awk 'match($0,"pattern") != 0 {print $0} ' filename to check if the pattern exists.how do i get the line number of the pattern and delete that line and replace the line with my new text?
View 1 RepliesI have to enhance the behaviour of a backup script written in perl. I don't need to change it, what I need to do is to create a bash script that does some checks like file name and file size, execute the backup script then check if the backup files match the original files.Here's how I try to do it:
- read the files from the original files folder
- store them in an array
- search in the array the files that have a specific file extension
- store the file names that match the search pattern (I know the backup script skips some files so I can hardcode the search pattern)
- run the backup script
- read the files from the backup folder
- store them in an array
- compare the original files name and size stored in an array with those from the backup folder
- send a report email
Here's the actual line of code, which exists in a bash script:
Code:
I want to replace instances like this:
Code:
with this:
Code:
Using this:
Code:
Which works great when there's only ONE of the pattern on the line. But in a case like the "actual line" I posted first, where there are two patterns, separated by a slash, only ONE gets replaced
Watch:
Code:
Why? There must be (among many other things) something I'm not knowing about sed, that's causing this.
-- I'm currently using the ~ (tilde) as the separator in the sed command. It doesn't matter, I've used / ~ and % with no difference.
-- As a test, I tried putting a different character(s) in the middle of the original pattern instead of the / but that made no difference.
-- I've come up with various similar but slightly different regexs that will do this replacement, but they all have had this same result.
-- I tried the sed single-quoted, double-quoted, and unquoted; the latter fails to execute, and the formers both work as described here: wrong.
I have several (vhdl) files containing a pattern with newline characters that I need to replace by another pattern that also contains newline characters.
I start with something like:
Code:
I want to replace it by something like:
Code:
(I need to paste some lines)
As I need to do this (very) often I want to use a shell script.
I tried:
1.
Code:
result:
Code:
2.
Code:
result:
File remains unchanged
3.
Code:
result:
Code:
4.
Code:
result:
Displays the unchanged testfile
How I can automate the pattern replacement?
Code:
i need to add this line nameserver 208.67.122.221 from ISP before the first nameserver already exists in resolv.conf in all workstations i know
Code:
sed '/nameserver/ i
ameserver 208.67.122.221'
but that insert it on every line after nameserver not only before the first one
Code:
# blah blah
# blah blah
domain mydom.com
[code]....
I have a file like so:
Code:
one
two
three
four
I would like to insert prior to the word "three" all items from this second file with the following contents:
Code:
four
three
two
one
Now my issue is, and I have been using both sed and awk currently, that after the second line of the new file is read there will of course now be 2 copies of the word "three" but I would like to only insert the final 2 words, ie "two" and "one" prior to only the first occurrence of the word "three" so final file will look like:
Code:
one
two
four
[code]....
So here there is now only one of each word from the second file joined to make the new file. For simple code I have tried something like the following:
Code:
while read line
do
awk -v n=$line '!f && /three/{print n;f++}1' file1 > tmp_file
mv tmp_file file1
done < file2
Now this works but seems very clumsy to me. There is obviously a better sed and / or awk out there.
I want to read from the file and check for the pattern, if the line has some word like <string>: then string should be copied into buffer. Afterwards, I want to insert the same <string> with some word in the next line of the file. use sed command to perform the above mentioned operations?
View 2 Replies View RelatedI have such a file(test.txt):
abc 123 456
abc 256 145
axd 125 225
[code]...
I am trying to create a shell script, on taking a input file as parameter, which need to do 3 things
1) create a copy of existing file.
2) add a new line to the copied file.
3) strip off all the absolute paths inside the copied file
The first 2 points are straight forward. but i am finding it difficult to acheive the 3rd point. myself not very good with awk and sed. but gave it a shot in vain. For example, the input script consists of below,
PROGRAM=`/usr/bin/basename $0`
HOST=`/usr/bin/uname -n`
echo Start $PROGRAM `/usr/bin/date` |
/usr/bin/tee -a $LOG
The output of the script should look like,
PROGRAM=`basename $0`
HOST=`uname -n`
echo Start $PROGRAM `date` |
tee -a $LOG
I need to search for a string "teststring" in all *.java files coming under /home/user1/ (including subfolders). How can I do it in linux via shell command.
View 5 Replies View RelatedI want to replace a pattern in a file.The file format is given below.
111111
path=/home/fun/
222222
path=/home/fun/
[Code]....
I want to replace "path=/home/fun" with another pattern, but only under "111111", all the others should be the same.
yes, this is a homework question, but no - I'm not trying to get anyone to do it for me. I think that I am really close, but can't quite get one small aspect to work. in gawk, I want to include a variable name in the search string, but the below code doesn't work.
read -p 'Login name please? ' uLogName
userID=$(gawk -F: '/"$uLogName"/{print $3}' /etc/passwd)
echo $userID
[code]...
Any solution using awk/sed/regexp or other standard linux utility (this is for a mix of RH versions)? I am dealing with some very large application log files. I want to see everything that has been written to the log since the last application restart.
For an example take a log file like this:
Code:
# cat test.log
1 msg
2 msg
3 restart 1
4 msg
5 restart 2
6 msg
The following command is close to what I want:
Code:
# awk '/restart/,G' test.log
3 restart 1
4 msg
5 restart 2
6 msg
But the awk command grabs the first restart not the last. If it was working the way I wanted I would see something like this:
Code:
# awk '/restart/,G' test.log
5 restart 2
6 msg
So, I need something in that search pattern that says look for the last occurrence. I know how to do this with a pipe line - I could reverse the file and then do a similar awk and reverse back, or I could find the number associated with the last restart and then use that in the awk search. But these just take too long because the file is too big.
I'm writing a script that edits a Maya ascii file. Inside the .MA(maya ascii file) there is a line defaultRenderGlobals. My script is supposed to find this line and according to what options they manipulate will update the lines below defaultRenderGlobals. I've got that working... but... the issue i'm having is that defaultRenderGlobals is only made when a the maya scene is made into a batch render. I want my script to manually addefaultRenderGlobals line into the .ma file if its not there and add the certain lines below it.RenderGlobals is already there I want to just manipulate whats below it. Hope this makes sense
View 2 Replies View RelatedIm tryng to replace in specific column and line number within a file where its 3erd column contain the same string in all lines.
[code]....
My goal is to replace only first and last ocurrences of "Normal player", with the following desired output:
[code]....
Im not sure how to use the "IF" and "AND" conditions together. I�ve tryed with the code below, but the script replaces the string for every line.
[code]....
how to replace values for specific column in first and last lines within same AWK script, without taking reference data in other columns?
To search a string pattern in all files in a directory and subdirectories, I am using;
Code:
grep -R "myclass::my-func(" mydirectory/
Now I want grep, to search in only specific file types say *.cc. Please help me. I have read manual of grep, but could not deduce any hint.
Best Regards.
if the given pattern exists in the file with the very next line starting and endingwith the same pattern , delete the line that starts and ends with the given pattern.So upon running on this file
hai people<PATTERN> we had
<PATTERN>a lot of fun<PATTERN>
writing scripts
[code]....
I've written a script to parse a file and print each line that ends with matching pattern, if the next line is blank. The pattern lines are the result of md5sum $i|sed 's/path///g' so that only md5 and filename appear. Here's what I'm using.
Quote:
for fline in `sed -n '/.*.ext$/p' file1`
do
if [ "`sed -n -e '/'"$fline"'/ {n; p;}' file1`" == "" ]
then
echo ""$fline" has no info" >>file2
fi
done
[Code]....
I have a question about sed programming, actually a one-liner for which I cannot find a solution, right now. I need to delete a line matching a specific pattern only if it is the last line. In practice, I would put together the following:
Code:
#
# This deletes the last line of a file
[code]...
As indicated in the subject, I want to search a text. If the text is present I want to replace it. But if the text is not present, I want to insert it after first line and before last line.
Searched text is:CleanCache "*";
Where * can be anything.
Example: CleanCache "false"; -> CleanCache "true";
If CleanCache "false"; is not present, only insert CleanCache "true"; after first line and before last line.
I want to replace a pattern with other pattern in a textfile. But there are two same patterns,but I need two change only the second occurence. EG:
Text file is
aaaa=1
bbbb=2
cccc=3
dddd=4
[code]....
Now I want to change aaaa=x into some other entry.
Something very handy to do in a Linux shell, is manipulating files and strings - essentially parsing data. Write a utility which will scan in a text file and search and replace strings. We also want to keep track of how many strings we've replaced.
I know that my command would look like this: <utility name> <filename> <stringToSearchFor> <stringToReplaceWith>
Code: #!/bin/bash
[code]....
I have this complex log file filled with entries like
test1-G1/0/0-100-QOS-7001923-ROUTING (ClassMap)
Action: Resolved New
sysName: test1.local
[code]...
I've got files in a directory as follows:
1.png
1_thumb.png
1-1.png
1-1_thumb.png
[code]....
I want to list all the files that don't have a copy with the same filename with -1 somewhere in it. So, in the example above, the results would be 3.png.
NB: the file and its copy with "-1" in it will be the same filesize, if that helps.
Just using shell scripting, how can I insert text into the middle of a file name. The file has a predictable pattern, let's say 3 letters and 3 numbers and I want to insert text in the middle of those 2 patterns. Say ABC123 is the file name. As a result, the file name should be ABC.blah.123
View 2 Replies View RelatedUsing sed, I am trying to append four commas ',,,,' at the end of lines containing the pattern 'Response' in a text file with lines such as these:
6,Pulse,50,254968,14886,NA,,,,
7,Picture,8,265157,0,1,15045,2,0,15000
7,Response,1,271553,6396,1
7,Pulse,50,274969,9812,NA,,,,
8,Picture,1,290232,0,1,15045,2,0,15000
8,Pulse,50,294969,4737,NA,,,,
[Code].....
I'm writing a bash script to search html files, and when I find any occurrence of an img src tag like this:
<img src="123-picture-normal.jpg" alt="some random user entered text" border="0">
I want to add a second line below it that looks like:
<img src="123-picture-thumbnail.jpg" alt="some random user entered text" border="0">
All I need to do is duplicate the line but replace "normal" with "thumbnail"
Each file can have multiple img src tags with different numbered jpgs.
I have a feeling this is a job for sed, but I'm struggling with it. Any ideas?
I'm new to the shell scripting. can any one help in creating shell script for matching the content of the specific variable with file. it should remove that line from the file if line is containing same value as variable and keep the other content as it is.i used grep -v for accomplishing the same. But grep will remove the pattern which is similar.For eg. Assume file "test" contain datas :aaffif i used grep -v command for the pattern "a" to this file this will remove content "aa" from the file. I want the pattern only "a" should remove from the file, if it is existing. otherwise it should throw alert content not exists.
View 5 Replies View RelatedI have requirement to delete some log files from a directory if a string"deletethisfile" is found.Then restart the application servers.1. Search for the string ?deletethisfile? in server.log file under a directory, If found 2. Stop that particular server.3. Delete the log file 4. Restart the server.
View 2 Replies View RelatedI want to go through a log file and find pattern1 and then a pattern2 only after pattern 1.So for example I want to know howManyRecords was in 13:30.I figured I grep for "start time for the job" and then only after that (and before the next occurence of that) grep for "howManyRecords". Is this a sane way?
View 1 Replies View Related