I want to list all the files that don't have a copy with the same filename with -1 somewhere in it. So, in the example above, the results would be 3.png.
NB: the file and its copy with "-1" in it will be the same filesize, if that helps.
I've written a script to parse a file and print each line that ends with matching pattern, if the next line is blank. The pattern lines are the result of md5sum $i|sed 's/path///g' so that only md5 and filename appear. Here's what I'm using.
Quote: for fline in `sed -n '/.*.ext$/p' file1` do if [ "`sed -n -e '/'"$fline"'/ {n; p;}' file1`" == "" ] then echo ""$fline" has no info" >>file2 fi done [Code]....
I have a question about sed programming, actually a one-liner for which I cannot find a solution, right now. I need to delete a line matching a specific pattern only if it is the last line. In practice, I would put together the following:
I want to search a file for a particular pattern and if pattern found replace the line with new text. i am using awk 'match($0,"pattern") != 0 {print $0} ' filename to check if the pattern exists.how do i get the line number of the pattern and delete that line and replace the line with my new text?
I have a requirement to list files using find command My folder contains below list of files with out extention.I have a requirement to exclude only ABC.123.* type files and list others. Even though files having MNO contains this pattern i should not exclude. Even if file ends with .txt or .doc it should not be excluded. That is ABC.123.1234.txt should not be excluded.But I am not getting what is required. Can any one please let me know if I am doing wrong any where. As per my requirement I cannot use grep, -regex, or -regex attributes to find command.
I'm new to the shell scripting. can any one help in creating shell script for matching the content of the specific variable with file. it should remove that line from the file if line is containing same value as variable and keep the other content as it is.i used grep -v for accomplishing the same. But grep will remove the pattern which is similar.For eg. Assume file "test" contain datas :aaffif i used grep -v command for the pattern "a" to this file this will remove content "aa" from the file. I want the pattern only "a" should remove from the file, if it is existing. otherwise it should throw alert content not exists.
Here's the actual line of code, which exists in a bash script:
Code:
I want to replace instances like this:
Code:
with this:
Code:
Using this:
Code:
Which works great when there's only ONE of the pattern on the line. But in a case like the "actual line" I posted first, where there are two patterns, separated by a slash, only ONE gets replaced
Watch:
Code:
Why? There must be (among many other things) something I'm not knowing about sed, that's causing this.
-- I'm currently using the ~ (tilde) as the separator in the sed command. It doesn't matter, I've used / ~ and % with no difference.
-- As a test, I tried putting a different character(s) in the middle of the original pattern instead of the / but that made no difference.
-- I've come up with various similar but slightly different regexs that will do this replacement, but they all have had this same result.
-- I tried the sed single-quoted, double-quoted, and unquoted; the latter fails to execute, and the formers both work as described here: wrong.
I need to add some text using sed before and after the matching pattern. Does any one have any clue?e.g.cat /my/file | sed -e "s/first pattern/New Pattern/g" . /my/file.bakNow I need a result like New Pattern
Quote:Originally Posted by topcatI would like to know how i can write a shell script to delete a line if a particular pattern exists?E.g. I have a text file with multiple lines. Say 1000s. in the following pattern.
If the patternusername@email.com exists then the line "username@email.com:149.0.3.4:1 should be deleted from the file.I have a very similar question but I need to delete one line in a file which matches one very precise instance of a string only. Let's assume I have a file composed of thousands of lines and let's call the file chap-secrets. Let's take the following sample entries:
Code: #USERNAME SERVER PASSWORD IP pp pptpd blahblah *
I need to grep for a particular string and if found need to display the line containing that string, the line above that and also the first line of that paragraph.
Can this be done via sed.
Eg, My Paragraphs
OA connectA
Enclosure:
Interconnect Module #6 Status:
Here, if I grep for Critical, it should display the following
Similarly if I grep for Degraded, it should display
i tried searching on google but found it difficult to say exactly what I was looking for.Task - Capitalise x number of letters at the start of words.eg. Original line - one.two.three.fourRevised line - One.Two.three.four (here only requiring 2 changes)Test data:
Are there some good tutorials or reference materials on how do pattern matching and text manipulation in Linux?I have a few simple tasks I'd like taken care of...like formatting numbers in file names, stripping some text from directory names, etc
I am interested in the following problem: given a string (pattern) find a regexp which match this pattern. I will need this for a developing of an idea 'pattern based filtration'.
I need to be able to convert HTML email messages saved as text files (.eml or .msg) to PDF documents, one PDF per email, retaining formatting and images.
Are there any Linux tools that will allow me to do this from the command line (so it can be scripted)?
I have found many information about how to delete/grab a line in a text file including delete line with match a pattern but I did not find info about how to delete a line which match a pattern of a particular column only.
for example mydata.txt: id type x y z 1 6 0.474611 0.227223 0.583947
Let's say i have a link to a file http://www.domain.com/dir/myfile.ext
Is there a command line tool that will allow me to download this file. I'm looking for something like: download <http address> ... is there anything that simple?
I want to download a file from the Linux command line. Basically I'm using ssh and I'm trying to download a file to my file system on my laptop. How can I do that from the command line?
How can I create multipart rar file in Linux using the official console rar client?RAR 3.90 Copyright (c) 1993-2009 Alexander Roshal 16 Aug 2009Shareware version Type RAR -? for helpI want a multipart rar with each part size being 150 MB.
I have a jar, and I need to replace a class in it, at this moment, I can only open it with "archive manager" and then drag and drop the new compiled class into the jar, but I think this is really boring, if I can do with with just a command ?
I've got a Debian Squeeze computer on which the graphics have packed up, but the terminal in single user mode work perfectly fine.
There are a few files on this Debian computer that I want to transfer off, to a networked computer, but I have no idea how to do this.
The destination computer is a freshly re-setup Mandriva install, without (as yet) samba. I don't think it's necessary though. The Mandriva install works fine, has graphics, etc, but can't see the Debian Squeeze computer on the network, possibly because it's in single user mode, thus prompting the problem of how to transfer the files, using only a command line.