yes, this is a homework question, but no - I'm not trying to get anyone to do it for me. I think that I am really close, but can't quite get one small aspect to work. in gawk, I want to include a variable name in the search string, but the below code doesn't work.
read -p 'Login name please? ' uLogName
userID=$(gawk -F: '/"$uLogName"/{print $3}' /etc/passwd)
echo $userID
[code]...
I want to search a file for a particular pattern and if pattern found replace the line with new text. i am using awk 'match($0,"pattern") != 0 {print $0} ' filename to check if the pattern exists.how do i get the line number of the pattern and delete that line and replace the line with my new text?
View 1 Replies View RelatedI have to enhance the behaviour of a backup script written in perl. I don't need to change it, what I need to do is to create a bash script that does some checks like file name and file size, execute the backup script then check if the backup files match the original files.Here's how I try to do it:
- read the files from the original files folder
- store them in an array
- search in the array the files that have a specific file extension
- store the file names that match the search pattern (I know the backup script skips some files so I can hardcode the search pattern)
- run the backup script
- read the files from the backup folder
- store them in an array
- compare the original files name and size stored in an array with those from the backup folder
- send a report email
how I can search within a variable and assign the results to a new variable. I'll use the following as an example -
cars="Audi BMW Cadillac Chevy Dodge Ferrari Ford Mercedes"
list=`echo ${cars} | egrep -o '<A?+|<C+'`
with the echo command I get the following output assigned to list -
A
C
C
What I'd like to get for output is -
Audi
Cadillac
Chevy
how I could do this regardless of upper/lower case letters?
Any solution using awk/sed/regexp or other standard linux utility (this is for a mix of RH versions)? I am dealing with some very large application log files. I want to see everything that has been written to the log since the last application restart.
For an example take a log file like this:
Code:
# cat test.log
1 msg
2 msg
3 restart 1
4 msg
5 restart 2
6 msg
The following command is close to what I want:
Code:
# awk '/restart/,G' test.log
3 restart 1
4 msg
5 restart 2
6 msg
But the awk command grabs the first restart not the last. If it was working the way I wanted I would see something like this:
Code:
# awk '/restart/,G' test.log
5 restart 2
6 msg
So, I need something in that search pattern that says look for the last occurrence. I know how to do this with a pipe line - I could reverse the file and then do a similar awk and reverse back, or I could find the number associated with the last restart and then use that in the awk search. But these just take too long because the file is too big.
I'm writing a script that edits a Maya ascii file. Inside the .MA(maya ascii file) there is a line defaultRenderGlobals. My script is supposed to find this line and according to what options they manipulate will update the lines below defaultRenderGlobals. I've got that working... but... the issue i'm having is that defaultRenderGlobals is only made when a the maya scene is made into a batch render. I want my script to manually addefaultRenderGlobals line into the .ma file if its not there and add the certain lines below it.RenderGlobals is already there I want to just manipulate whats below it. Hope this makes sense
View 2 Replies View RelatedI have such a file(test.txt):
abc 123 456
abc 256 145
axd 125 225
[code]...
I have this complex log file filled with entries like
test1-G1/0/0-100-QOS-7001923-ROUTING (ClassMap)
Action: Resolved New
sysName: test1.local
[code]...
I need to search for a string "teststring" in all *.java files coming under /home/user1/ (including subfolders). How can I do it in linux via shell command.
View 5 Replies View Relatedi have the follwing code
touch umer.txt
fdisk -l | grep 'Disk /' umer.txt
read file
[code]...
I have 8 files, and each contains around 2000 lines. I want to search the particular word in these files between line number 1500 to 2500.
The output should look like:
sample_1.txt :
1510:declare var testing
sample_2.txt :
1610:declare var testing
sample_7.txt :
1610:declare var testing
sample_10.txt :
1710:declare var testing
Is it possible to use grep for this task?
So unbeknownst to me until today, but apparently all configure scripts rely on some version of awk to create the Makefile when config.status is run.how to get gawk reinstalled?I have compiled one on Ubuntu and copied it to my other machine but when run it throws the error:Code:./gawk: no such file or directorySo I am guessing I either need to create a static copy or maybe also copy the libs created from compile with it.
View 7 Replies View RelatedI write a little script by bash.
#!/bin/bash
a=`gawk '/Iterations /{print $0}' hoge.log | gawk 'BEGIN{FS=" "}{print ($4)}'`
a=`expr 3 '*' $a`
[code]...
I want to delete lines which contain the word "Fehler" but for some reason my programm isn't working:
Code: BEGIN { FS="|"
OFS="|"
SUBSEP="|"
[code]...
I have a directory where there are folders and in them some .txt data files. I am trying to output a .txt file with the folder name and the number of .txt files in it using gawk. However, when I run my shell program, because print is nested in a "while" loop, gawk overwrites what's already saved in the output file. I want gawk to print "new" output in a new line without overwriting the already existing text in the output fil
#! /bin/sh
# getting the folder list and the number of folders
ls | gawk '{print}' > ../folder_list.txt
[code]...
To search a string pattern in all files in a directory and subdirectories, I am using;
Code:
grep -R "myclass::my-func(" mydirectory/
Now I want grep, to search in only specific file types say *.cc. Please help me. I have read manual of grep, but could not deduce any hint.
Best Regards.
I'm working on a simple data processing script.My script uses a loop with getline to check for the value on the next line to decide if it's time to terminate the loop.This works dandy, but the problem is that getline eats that line, which then isn't processed by the rules in the remainder of the script (even though I want it to be). To illustrate what I mean, consider this simple gawk script:
Code:
{
print $0
[code]...
adf 32 324 100 100 24 234I want a gawk statement to match the above line if lets sayand field between 4 and 6 == 100.
View 2 Replies View RelatedI'm trying to read content of file to variable and use this variable in for loop. The problem is, when I have c++ comment style in file - /*. Spaces in line are also interpreted as separated lines.
For example:
Code:
Changing $files to "$files" eliminate these problems but causes that whole content of variable is treated as one string (one execution of loop).
my script has a variable which comes in the form +00.00 +0.00 -00.00 or -0.00 (the numbers can be any in that form) for any that have a + symbol I need to remove the +, but if it has a - symbol it needs to stay.
i need to make a new variable with the string from the old variable btut without any plus sign. I have tried a lot of different ways with no success, each thing I tried either left the + or removed the entire string. I think this should work but doesn't
foo=+12.40
bar=${foo#+}
I have a file that contains 5 fields and anothen one with two I want to take the value from user and search file1 and if the value exists then write in file2 to the $2 to the line that $1=value
file 1
1:fsdfsd:g:33:fsdf
2:yytgdcf:a:3:sgd
3:tttt:g:67:yujhggfg
[code].....
included shell script inside c program, and i wanted to assign the value of c variable to shell variable..Can any one please suggest me how to do it?
View 8 Replies View RelatedI need to search a text file for a string of numbers which are different lengths, and always are between number=" and " like:
number="1234567890"
number="22390"
I need to grab those numbers and pipe each one to a line in a file. I've already tried something with awk and that didn't seem to work.
This loop is part of a bash script which takes multiple arguments.
Code:
for ((i=1;i<=$number;++i)) ; do
offset=$(($i+5))
[code]...
I'm writing a bash script to search html files, and when I find any occurrence of an img src tag like this:
<img src="123-picture-normal.jpg" alt="some random user entered text" border="0">
I want to add a second line below it that looks like:
<img src="123-picture-thumbnail.jpg" alt="some random user entered text" border="0">
All I need to do is duplicate the line but replace "normal" with "thumbnail"
Each file can have multiple img src tags with different numbered jpgs.
I have a feeling this is a job for sed, but I'm struggling with it. Any ideas?
I need to add some text using sed before and after the matching pattern. Does any one have any clue?e.g.cat /my/file | sed -e "s/first pattern/New Pattern/g" . /my/file.bakNow I need a result like New Pattern
View 7 Replies View Relatedif the given pattern exists in the file with the very next line starting and endingwith the same pattern , delete the line that starts and ends with the given pattern.So upon running on this file
hai people<PATTERN> we had
<PATTERN>a lot of fun<PATTERN>
writing scripts
[code]....
I am trying to split a pattern in perl and so far I cannot get it to work. I have a pattern that looks like this:
76|2455311|2455312|00:00:00|00:00:00|Once|0|Donkey | |
I always need to print out the 8th field. So in this case donkey. Here is what I have so far:
Code:
#!/usr/bin/perl
use strict;
use warnings;
[Code].....
I'm working on a backup script which takes the following input:
Code:
RevBackup.sh <options> <source> <target>
The problem I'm having is that the source and target might contain spaces in the path. ie. /home/eRJe/My Documents
I would like the script to ignore " " (backslash-space) as being a delimiter. how could I do this without stopping a normal space from being a delimiter?
I could do this with IFS. But so far I have only found info about setting a delimiter and not to "ignore" one
I want to go through a log file and find pattern1 and then a pattern2 only after pattern 1.So for example I want to know howManyRecords was in 13:30.I figured I grep for "start time for the job" and then only after that (and before the next occurence of that) grep for "howManyRecords". Is this a sane way?
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