if the given pattern exists in the file with the very next line starting and endingwith the same pattern , delete the line that starts and ends with the given pattern.So upon running on this file
hai people<PATTERN> we had
<PATTERN>a lot of fun<PATTERN>
writing scripts
[code]....
I have a question about sed programming, actually a one-liner for which I cannot find a solution, right now. I need to delete a line matching a specific pattern only if it is the last line. In practice, I would put together the following:
Code:
#
# This deletes the last line of a file
[code]...
I am trying to create a shell script, on taking a input file as parameter, which need to do 3 things
1) create a copy of existing file.
2) add a new line to the copied file.
3) strip off all the absolute paths inside the copied file
The first 2 points are straight forward. but i am finding it difficult to acheive the 3rd point. myself not very good with awk and sed. but gave it a shot in vain. For example, the input script consists of below,
PROGRAM=`/usr/bin/basename $0`
HOST=`/usr/bin/uname -n`
echo Start $PROGRAM `/usr/bin/date` |
/usr/bin/tee -a $LOG
The output of the script should look like,
PROGRAM=`basename $0`
HOST=`uname -n`
echo Start $PROGRAM `date` |
tee -a $LOG
I want to search a file for a particular pattern and if pattern found replace the line with new text. i am using awk 'match($0,"pattern") != 0 {print $0} ' filename to check if the pattern exists.how do i get the line number of the pattern and delete that line and replace the line with my new text?
View 1 Replies View RelatedI have found many information about how to delete/grab a line in a text file including delete line with match a pattern but I did not find info about how to delete a line which match a pattern of a particular column only.
for example mydata.txt:
id type x y z
1 6 0.474611 0.227223 0.583947
[code]....
I am trying to edit a print file.
For every occurence of the ^L form feed character I need to remove 5 blank lines after it but still keep the ^L.
I am a rare user of sed and am ok with the basics but am struggling with this.
I have such a file(test.txt):
abc 123 456
abc 256 145
axd 125 225
[code]...
I have a file with a number of strings like the ones below
string1#m1asdfe23easdf23wefas
string2#mfaaeb2vr1rhserh
anotherstring#ji89ensrsegr
anotherone#m1ynmdt324nsdt
I'm trying to delete everything after #** so that
string1#maasdfeaveasdfawefas
string2#mfaaebvrserhserh
becomes
string1#ma
string2#mf
tried sed 's/#..*//g' but as you all will know it returns string1, string2 etc.
I have a file like so:
Code:
one
two
three
four
I would like to insert prior to the word "three" all items from this second file with the following contents:
Code:
four
three
two
one
Now my issue is, and I have been using both sed and awk currently, that after the second line of the new file is read there will of course now be 2 copies of the word "three" but I would like to only insert the final 2 words, ie "two" and "one" prior to only the first occurrence of the word "three" so final file will look like:
Code:
one
two
four
[code]....
So here there is now only one of each word from the second file joined to make the new file. For simple code I have tried something like the following:
Code:
while read line
do
awk -v n=$line '!f && /three/{print n;f++}1' file1 > tmp_file
mv tmp_file file1
done < file2
Now this works but seems very clumsy to me. There is obviously a better sed and / or awk out there.
Here's the actual line of code, which exists in a bash script:
Code:
I want to replace instances like this:
Code:
with this:
Code:
Using this:
Code:
Which works great when there's only ONE of the pattern on the line. But in a case like the "actual line" I posted first, where there are two patterns, separated by a slash, only ONE gets replaced
Watch:
Code:
Why? There must be (among many other things) something I'm not knowing about sed, that's causing this.
-- I'm currently using the ~ (tilde) as the separator in the sed command. It doesn't matter, I've used / ~ and % with no difference.
-- As a test, I tried putting a different character(s) in the middle of the original pattern instead of the / but that made no difference.
-- I've come up with various similar but slightly different regexs that will do this replacement, but they all have had this same result.
-- I tried the sed single-quoted, double-quoted, and unquoted; the latter fails to execute, and the formers both work as described here: wrong.
I have this complex log file filled with entries like
test1-G1/0/0-100-QOS-7001923-ROUTING (ClassMap)
Action: Resolved New
sysName: test1.local
[code]...
Was wondering if any perl guru's could help me with a quick log file adjustment. I have a text file that looks like so (tabs and newlines are revealed so you can see what separates the data):
There are maybe 100 lines of text in this file at any given time. I need to delete all duplicate lines only looking at the first bit of text prior to the first tab. It doesn't matter which one gets deleted as long as there are no two lines that begin with that same text at the beginning before the first tab. So in this example, either the fist line "1234" or the last line "1234" would need to be deleted. I already have code in my script that opens the files - I just need the code to read the text into an array and the part that would find matches based on the above criteria, and make the deletions.
If it would be easier, I can even do a system call and use SED (v4.1.5) and/or AWK (3.1.5) instead.
I have to enhance the behaviour of a backup script written in perl. I don't need to change it, what I need to do is to create a bash script that does some checks like file name and file size, execute the backup script then check if the backup files match the original files.Here's how I try to do it:
- read the files from the original files folder
- store them in an array
- search in the array the files that have a specific file extension
- store the file names that match the search pattern (I know the backup script skips some files so I can hardcode the search pattern)
- run the backup script
- read the files from the backup folder
- store them in an array
- compare the original files name and size stored in an array with those from the backup folder
- send a report email
I've written a script to parse a file and print each line that ends with matching pattern, if the next line is blank. The pattern lines are the result of md5sum $i|sed 's/path///g' so that only md5 and filename appear. Here's what I'm using.
Quote:
for fline in `sed -n '/.*.ext$/p' file1`
do
if [ "`sed -n -e '/'"$fline"'/ {n; p;}' file1`" == "" ]
then
echo ""$fline" has no info" >>file2
fi
done
[Code]....
I need to grep for a particular string and if found need to display the line containing that string, the line above that and also the first line of that paragraph.
Can this be done via sed.
Eg, My Paragraphs
OA connectA
Enclosure:
Interconnect Module #6 Status:
Here, if I grep for Critical, it should display the following
Similarly if I grep for Degraded, it should display
I want to delete lines which contain the word "Fehler" but for some reason my programm isn't working:
Code: BEGIN { FS="|"
OFS="|"
SUBSEP="|"
[code]...
I would like to delete a single line from a file that contains many lines passing through the same values as the two parameters. Again, I would like to delete a single line and not all those that contain parameters. How can I make bash?
View 14 Replies View RelatedDelete this with maximum prejudice, mods.
View 1 Replies View Relatedi have a file containing contents as
1 2 3
2 2 3
11 2 3
now i want to delete the line which first column content is 1. so, if i pass the parametere 1 to function delete_row. is should remove the first row as
2 2 3
11 2 3
and then write the contents in file.
Quote:Originally Posted by topcatI would like to know how i can write a shell script to delete a line if a particular pattern exists?E.g. I have a text file with multiple lines. Say 1000s. in the following pattern.
username@email.com:149.0.3.4:1
username1@email.com:149.0.3.4:1
username1@email.net:149.0.3.4:1
username1@email.edu:149.0.3.4:1
If the patternusername@email.com exists then the line "username@email.com:149.0.3.4:1 should be deleted from the file.I have a very similar question but I need to delete one line in a file which matches one very precise instance of a string only. Let's assume I have a file composed of thousands of lines and let's call the file chap-secrets. Let's take the following sample entries:
Code:
#USERNAME SERVER PASSWORD IP
pp pptpd blahblah *
[code]....
How can I use grep -Ev "pattern" not only to delete the matching "pattern" but to edit and save the file permanently as well
View 2 Replies View RelatedI have to use sed with this problem, and sed is extremely complicated, they could probably teach a whole class on this entire function.
Here's an example to show what I need to do:
Code...
how would I say that every line before I reach the first match of "sweet" should be deleted so that the output will look like: Code...
I have requirement to delete some log files from a directory if a string"deletethisfile" is found.Then restart the application servers.1. Search for the string ?deletethisfile? in server.log file under a directory, If found 2. Stop that particular server.3. Delete the log file 4. Restart the server.
View 2 Replies View RelatedI've got files in a directory as follows:
1.png
1_thumb.png
1-1.png
1-1_thumb.png
[code]....
I want to list all the files that don't have a copy with the same filename with -1 somewhere in it. So, in the example above, the results would be 3.png.
NB: the file and its copy with "-1" in it will be the same filesize, if that helps.
I have to delete a certain line of text from the a textfile via ubuntu's shell scripting.I have done research, and it seems that most people advocate the usage of sed /d option. sed makes does not edit the text file. Hence, most options I discovered involved the use of a temporary variable/textfile and then overwriting the old file with the temporary new file. Is there anyway whereby I can bypass the use of temporary storage containers? I hope there is any magical combination of commands to edit the file directly.
View 3 Replies View RelatedI have some code written in VHDL that looks as follows:
Code:
foo = "bar";
foo <= 'bar',
[code]...
I have installed Ubuntu 10.04 on a Dell Dimension 2350/ 2Ghz P4/ 1.5GB memory.After running for up to 10mins the system dies and the monitor alternates between black & a half-screen display of vertical black & white bars every second or so (first the top half then the bottom half of the screen). The unit has the standard Intel onboard graphics chip.The same happens with Ubuntu Studio & Xubuntu yet Mepis 8.5 & Fedora 13 run without problem.It's a standard installation of Ubuntu & all updates have been applied.
View 4 Replies View RelatedI'm new to the shell scripting. can any one help in creating shell script for matching the content of the specific variable with file. it should remove that line from the file if line is containing same value as variable and keep the other content as it is.i used grep -v for accomplishing the same. But grep will remove the pattern which is similar.For eg. Assume file "test" contain datas :aaffif i used grep -v command for the pattern "a" to this file this will remove content "aa" from the file. I want the pattern only "a" should remove from the file, if it is existing. otherwise it should throw alert content not exists.
View 5 Replies View RelatedI m writing a script to delete a line at particular location.
But i m unable to use variable for specifying line number.
For example.
Code:
works fine and deletes 7th line from my file
But
Code:
gives following error.
Code:
I have two files, file1.traj and file2.traj. Both these files contain identical data and the data are arranged in same format in them. The first line of both files is a comment.
At line 7843 of both files there is a cartesian coordinate X, Y and Z ( three digits ). And at line 15685 there is another three digits. The number of lines in between two cartesian coordinates are 7841. And there are few hundreds of thousands of lines in a file.
What I need to do is copy the X Y Z coordinate (three digits) from file1.traj at line 7843 and paste into file2.traj at the same line number as in file1.traj. The next line will be 15685 from file1.traj and replace at line 15685 at file2.traj. And I dont want other lines (data) in file2.traj get altered. This sequence shall be going on until the end of the file. Means copy and substitude the selected lines from file1.traj into file2.traj.
I tried to use paste command but I cant do for specified line alone.
Here i showed the data format in the file. I used the line number for clarity purpose.
Code: