Is there a way to get the full path of a file in C? I have a method that accepts a file name as an argument and is supposed to read the content of the file. The file name might include "../" so this might lead to accessing files outside of the current directory. I tried to use fstat but I could not figure out how to get the full path.
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How do you set up a command just to copy a file's full path name (%F) onto the clipboard?(I can't seem to get this without copying the contents of the file.)
View 2 Replies View RelatedI've been dabbling in IDL lately, and it seems useful enough, but occasionally I come across a problem like this: I'm trying to call an IDL procedure from within an IDL script which is called from a .csh script. (Don't ask, trust me, you don't want to know.) The IDL procedure may or may not be in the same directory as the .csh, so I'm calling it by it's full path: /home/ic/rad_sim However, all IDL will do is give me a syntax error and tell me ic is an undefined variable. Putting ic in double quotes makes the undefined variable error go away, but it still reports a syntax error.
View 13 Replies View RelatedI'm fighting my way through JAVA. But have hit another wall. Basically I need to to set paths in java so it can set/read files/director for Linux,Mac and windows.
The tutorials I'm using says to do this through the FileSystems class eg
Code:
However this reports it is missing, so a look on line says I need the headers so I set them with
Code:
This gives the following error
This has me totally confused as the tutorial shows this and checking online shows this, do I need to link in libraries or something like that?
I'm using the latest Ubuntu 11.04 and netbeans.
Is there any API to get partition name based on file path in C on Linux OS?
View 1 Replies View RelatedI am assigning a file path to a variable like
$1 means it should accept some file name from cmd prompt but in my case its not working.
I wanted to read out the absolute file-path (filename) as sorted in a folder (on Linux). The reading the file-paths is ok but I have problems in sorting.
Code:
selectedDirectory = fl_dir_chooser ("Select Imagedirectory:",NULL,0); //This is just a widget to show the folder.
DIR *d;
dirent *de;
[code]....
The files -105.dcm, -106.dcm, -107.dcm lie in the folder at the bottom and -36.dcm, -37.dcm- at the top. The program compares 1 and 3 of 105 and 37, 1 is lesser than 3, then prints out first, but does not know that 105 is three digits and 37 is two digits.
I am trying to replace the default path in a file(which is a script)with the new path which I have get when the bash script runsThe code is
SCRIPT=$(readlink -f $0)
SCRIPTPATH=`dirname $SCRIPT`
sed -i "s/$HomeDir/$SCRIPTPATH/g" <filename>
[code]....
Java applet not loading image with relative path(e.g. images/1.jpg) but loads image with absolute path(i.e. from /root/user/images/1.jpg) . This is a problem when i want to host the applet on web server
View 2 Replies View RelatedI want a simple list of files in a directory that is not my current directory. I run ls /other/directory/*.txt and get:
/other/directory/file1.txt
/other/directory/file2.txt
I want:
file1.txt
file2.txt
How can I get the second list?
What is a full path name?
View 6 Replies View RelatedI'm new to UNIX scripting; I�m stuck with the following I have an Oracle SQL script that takes three parameters
1- File Name
2- File Path
3- File creation date
Under UNIX I have a folder where files will be placed frequently and I need to upload those files to Oracle, what I need is a UNIX script that can do the following
Loop through Directory "/home/applmgr/snktmp"
Picks only files
Pass the file name to parameter &1
[code]....
Is the above possible? I already knows how to call the Oracle Script from UNIX Im only stuck on writing the UNIX part where it List the files attribute(name,path,date) and store them to parameters ,Looping until the last file in the directory If the above is not possible,then how can I create the below from the command line
Filename{concatenation Mark}filePath{concatenation Mark}creationdate
Filename{concatenation Mark}filePath{concatenation Mark}creationdate
Filename{concatenation Mark}filePath{concatenation Mark}creationdate
Filename{concatenation Mark}filePath{concatenation Mark}creationdate
I have the following files:
~/Dir1/file1.txt
~/Dir2/file2.txt
Then I use the following command:
cd ~ zip out.zip /Dir1/file1.txt /Dir2/file2.txt
In the out.zip i can see two directories (dir1 and dir2) but want only these two files (file1.txt and file2.txt) were in the root of out.zip! I thought the "-D" option is what I need, but it doesn't work
I use this command:
Code:
find ./ -atime +360
to figure out the files that haven't been accessed since 360 days. The command above will return results like this:
Code:
/uploads/2010/02/some-file-name.ext
/uploads/2009/08/another-file-name.ext
... etc
I'm taking here about tins of directories, thousands of files. I'm looking to find a command that makes me able to move the results above to another path, and to create that path once it doesn't exist like below:
Code:
mv /uploads/2010/02/some-file-name.ext /old-files/uploads/2010/02/some-file-name.ext
But I want the executed command to create this path
Code:
/old-files/uploads/2010/02/
If it doesn't exist.
Is there a way to NOT display the current full directory path in the terminal? I'd like to set the default to be just the current directory instead of everything back to ~.
View 2 Replies View RelatedHow can I get the full path to display in Nautilus so I can copy it to the clipboard and/or type a path manually?
View 7 Replies View RelatedUsually when i did, for example:
:~/> vi documents/<tab><tab>
i would get list of files in 'documents' dir on my konsole.
:~/> vi documents/
doc1 doc2 doc3
Bu now in 11.4 when i do that i get whole path, like this for example:
:~/> vi documents/<tab><tab>
:~/> vi documents/
documents/doc1 documents/doc2 documents/doc3
how to make it look "old" style?
Is there a way to display and edit the full path of the current directory in nautilus? I am using Ubuntu 10.10 and I think it was possible with an older version.
View 3 Replies View Related- When using SU - , I need the option to show the full user path (root user, home dir, etc..), not just root@name. Is there one?
-If not in sudoers file, how can a user get in to edit a file for example. Is that possible?
-Does service ssh restart disconnect users?
Checking the process table for the running sendmail, I would like to know the full path to the sendmail binary a la the ps -ef on a Sun or other servers. How do I get ps to give me the actual path, or should I use a different tool on my Linux servers?
View 2 Replies View RelatedIs there a command to know " From where a specific RPM package was downloaded & installed ( The full HTTP/FTP path ) " ? For example, if I had previously installed Firefox from here [URL] is there a specific rpm query, or any other place, from where I can get the full ftp path back.
View 1 Replies View RelatedDoes anyone know how to get the path with a inode number by C programming?
Or can I get the absolute path without giving a "path" but a inode number by C?
like this: get_path(unsigned inode);
not such this function: getcwd(".", xxx);
taowuwen@gmail.com
I have a tiny shell script to rsync files between two servers and remove the source files.
This script works fine, when it has been initiated manually or even when the rsync command is executed on the command line.
But the same script doesn't work, when I try to automate it through crontab.
I am using 'abc' user to execute this rsync, instead of root, as root login to servers are restricted in all of our servers, by us.
As I mentioned earlier, manual execution works like charm!
When this rsync.sh is initiated through crontab, it runs the first command(chown abc.abc ...) perfectly without any issues. But the second line is not at all executed, and there is no log entry i can find at /mnt/xyz/folder/rsync.log.
I have asked this over on Launchpad and have found bugs filed on the eclipse bug tracker but it seems to be going nowhere so I guess ill ask here.
I am using Eclipse for some development work and having saved a file, defocus the eclipse window (to test changes in a browser) when I refocus the eclipse window I get the following error...
The file 'path omyfile' has been changed on the file system.Do you want to replace the editor contents with these changes?
I have searched and searched and this seems to be a CIFS/SAMBA problem. I even found one solution suggesting that changing his mounts from cifs to smbfs fixed his problem however that would appear not to be an option for me since using smbfs in the fstab causes cifs mounts. This problem would seem to occur in Bluefish as well as some other IDE's so it is not an Eclipse issue.
---------- LINKS TO RELATED ----------
Launchpad Question
Eclipse Bug
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I had a situation in which the the path of the file to be copied is written in other file and I had to copy it using shell script..I can use cp $(cat /home/robert/location.txt) /media/sda1 on normal linux shell...But I am using buildroot script where $(cat /home/robert/location.txt) evaluate to nothing..is just blank..
View 1 Replies View RelatedI have just installed SABnzb application in my home folder. The executable file is SABnzb.py When I run the command in the Konsole # python SABnzb.py I have this Quote: python: can't open file 'SABnzbd.py': [Errno 2] No such file or directory
View 5 Replies View RelatedI found the following function in /etc/profile file.
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1. I dont undestand what "if ! echo $PATH | /bin/grep -qE "(^|:)$1($|:)"" this if statement actually comapres??
2. Also what is the difference between PATH=$PATH:$1 & PATH=$1:$PATH
How to find filename and file path from a string
View 7 Replies View RelatedI have file which consists of many files with their path,i need to check for the file exists in the given path,how to check?
View 12 Replies View RelatedDoes executable file contains the precise path to SO file? Should it be compiled with precise knowing of SO file location?
View 8 Replies View Related