Programming :: KSh Script - Assigning A File Path ?
Jul 25, 2011I am assigning a file path to a variable like
$1 means it should accept some file name from cmd prompt but in my case its not working.
I am assigning a file path to a variable like
$1 means it should accept some file name from cmd prompt but in my case its not working.
I've been dabbling in IDL lately, and it seems useful enough, but occasionally I come across a problem like this: I'm trying to call an IDL procedure from within an IDL script which is called from a .csh script. (Don't ask, trust me, you don't want to know.) The IDL procedure may or may not be in the same directory as the .csh, so I'm calling it by it's full path: /home/ic/rad_sim However, all IDL will do is give me a syntax error and tell me ic is an undefined variable. Putting ic in double quotes makes the undefined variable error go away, but it still reports a syntax error.
View 13 Replies View RelatedIs there a way to get the full path of a file in C? I have a method that accepts a file name as an argument and is supposed to read the content of the file. The file name might include "../" so this might lead to accessing files outside of the current directory. I tried to use fstat but I could not figure out how to get the full path.
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I'm fighting my way through JAVA. But have hit another wall. Basically I need to to set paths in java so it can set/read files/director for Linux,Mac and windows.
The tutorials I'm using says to do this through the FileSystems class eg
Code:
However this reports it is missing, so a look on line says I need the headers so I set them with
Code:
This gives the following error
This has me totally confused as the tutorial shows this and checking online shows this, do I need to link in libraries or something like that?
I'm using the latest Ubuntu 11.04 and netbeans.
Is there any API to get partition name based on file path in C on Linux OS?
View 1 Replies View RelatedI wanted to read out the absolute file-path (filename) as sorted in a folder (on Linux). The reading the file-paths is ok but I have problems in sorting.
Code:
selectedDirectory = fl_dir_chooser ("Select Imagedirectory:",NULL,0); //This is just a widget to show the folder.
DIR *d;
dirent *de;
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The files -105.dcm, -106.dcm, -107.dcm lie in the folder at the bottom and -36.dcm, -37.dcm- at the top. The program compares 1 and 3 of 105 and 37, 1 is lesser than 3, then prints out first, but does not know that 105 is three digits and 37 is two digits.
I am trying to replace the default path in a file(which is a script)with the new path which I have get when the bash script runsThe code is
SCRIPT=$(readlink -f $0)
SCRIPTPATH=`dirname $SCRIPT`
sed -i "s/$HomeDir/$SCRIPTPATH/g" <filename>
[code]....
How do you set up a command just to copy a file's full path name (%F) onto the clipboard?(I can't seem to get this without copying the contents of the file.)
View 2 Replies View RelatedJava applet not loading image with relative path(e.g. images/1.jpg) but loads image with absolute path(i.e. from /root/user/images/1.jpg) . This is a problem when i want to host the applet on web server
View 2 Replies View RelatedI am trying to run this and was into issues
function() {
node=echo "10.11.12.13" | awk '{split ($0, a, "."); print a[1]}'
}
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I'm new to UNIX scripting; I�m stuck with the following I have an Oracle SQL script that takes three parameters
1- File Name
2- File Path
3- File creation date
Under UNIX I have a folder where files will be placed frequently and I need to upload those files to Oracle, what I need is a UNIX script that can do the following
Loop through Directory "/home/applmgr/snktmp"
Picks only files
Pass the file name to parameter &1
[code]....
Is the above possible? I already knows how to call the Oracle Script from UNIX Im only stuck on writing the UNIX part where it List the files attribute(name,path,date) and store them to parameters ,Looping until the last file in the directory If the above is not possible,then how can I create the below from the command line
Filename{concatenation Mark}filePath{concatenation Mark}creationdate
Filename{concatenation Mark}filePath{concatenation Mark}creationdate
Filename{concatenation Mark}filePath{concatenation Mark}creationdate
Filename{concatenation Mark}filePath{concatenation Mark}creationdate
I use this command:
Code:
find ./ -atime +360
to figure out the files that haven't been accessed since 360 days. The command above will return results like this:
Code:
/uploads/2010/02/some-file-name.ext
/uploads/2009/08/another-file-name.ext
... etc
I'm taking here about tins of directories, thousands of files. I'm looking to find a command that makes me able to move the results above to another path, and to create that path once it doesn't exist like below:
Code:
mv /uploads/2010/02/some-file-name.ext /old-files/uploads/2010/02/some-file-name.ext
But I want the executed command to create this path
Code:
/old-files/uploads/2010/02/
If it doesn't exist.
Using things like awk/sed, but have managed to cobble together what I needed so far without a problem. The only thing I'm struggling with is to assign the content of a particular line as a variable, and then to use it again throughout the file.
For example, if what I want is the first line of the file to become the variable "from1", and then to replace the word "Subject" in the file with the string "Message from [from1]". What I thought would work
I tried a few diff combinations but nothing seems to work. All I get is the terminal hanging indefinitely.
I am having all sorts of trouble trying to assign a variable within an awk script with the system command. I know there is a lot of ways around this problem, but for efficiency reasons, I would like to, within my awk script, do something like
system(x=3)
or
system(x=NR)
and, latter on the shell script which calls the awk script, use the variable $x. But nothing is passed to x. I have already tried things like
command = "x=3"
system(command)
and also used a pipeline within the system to pipe it to /bin/sh In fact tried a lot of stuff like that, using $(( )) etc etc etc I can create directories e write to files (yes, i could write to a file and read from there, but I dont think it is efficient, plus I am puzzled).
I am trying to execute a Unix Command in perl and assigning its output to an array:
Code:
@File_List=exec("ls -1 /tmp");
but it is not working. I have tried the perl function system() also but its return code is
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How can I pass by reference, a parameter, without assigning a new object? In my first example, var = "changed" creates a new local object. In the second, mylist.append will affect the reference target. How to i achieve the same effect with example 1?
Code:
#!/bin/python
var = "unchanged"
def print_string( var ):
[Code].....
I am working on some minor programming projects. and wouldt like to keep track of them by version numbers. E.g. 1.0.0
Is there a tool or other method for automatically assigning version numbers to software ?
I am currently using Mercurial. as far as i can see it only assigns revision numbers. E.g. 5
Kindly take a look at the code below :
Code:
#include <stdio.h>
struct test
{
int i;
int j;
[Code]....
why i am getting this error. I know the error is occuring because i have assigned values to obj.i and obj.j outside main(). But i want to know why do that result in an error. From my part i have created an object 'obj' of stucture 'test' and assigned values to its variables.
How I can tell tar to assign a new creation date to extracted files? Let's say I have an archive filled with old files of varying ages. Upon extraction I want all files to have the same time stamp (that of the time of the extraction).
View 1 Replies View RelatedI am connecting to MySQL DataBase using shellscript and writing a select statement like select attachmentid from attachments where pageid=10175 I want to store the output of the select statement into a shellvariable or a file. How can i do it using shellscript.
View 4 Replies View RelatedI am pondering a reinstall of a freshly installed Ubuntu; I may or may not take that drastic step.However, I have partitioned my drive to include a 16-GB partition labelled "Ubuntu-tmp", in my case /dev/sda7, with the intent of mounting that file system as /tmp. Depending on how I decide to go about the reinstall I need an answer to these questions:If I reinstall: Is it possible to designate /dev/sda7 to mount as /tmp during the installation process?If I cannot designate the mounts at install time, or if I opt not to reinstall: I can't really empty the /tmp directory in the root in order to properly use it as a mount point for [the file system on] /dev/sda7; many files in there are still in use by running processes. So how can I clear the /-mounted /tmp directory and assign it to /dev/sda7?
I have attached a screen shot of gparted to illustrate my layout scheme.The gparted manual suggests I select the partition, click [Partition]->[Mount]. Of course, my gparted drops a menu with [Mount] is absent and an [Unmount] option is greyed out.This raises a question of how I am going to mount /users and /var in their intended file systems (/dev/sda8 and /dev/sda9, respectively), because the [partition] menu looks the same for these partitions as well.
How do I decide what IP address to enter in my config file when assigning a static IP. All of the instructions I can find say something like "of course you should modify the file according to your own settings." Should I just use the gateway and IP that returns from "iwconfig" and "route -nee"?
View 5 Replies View RelatedDoes anyone know how to get the path with a inode number by C programming?
Or can I get the absolute path without giving a "path" but a inode number by C?
like this: get_path(unsigned inode);
not such this function: getcwd(".", xxx);
taowuwen@gmail.com
I've been given a custom-made string class which handles string, wstring and bstr. It has a number of methods and assignment operators to convert to and from different types. The app I work on compiles happily in VS6 and VS2008, but when trying to compile in Redhat (version 4.1.1 in Redhat 5.0)
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I have asked this over on Launchpad and have found bugs filed on the eclipse bug tracker but it seems to be going nowhere so I guess ill ask here.
I am using Eclipse for some development work and having saved a file, defocus the eclipse window (to test changes in a browser) when I refocus the eclipse window I get the following error...
The file 'path omyfile' has been changed on the file system.Do you want to replace the editor contents with these changes?
I have searched and searched and this seems to be a CIFS/SAMBA problem. I even found one solution suggesting that changing his mounts from cifs to smbfs fixed his problem however that would appear not to be an option for me since using smbfs in the fstab causes cifs mounts. This problem would seem to occur in Bluefish as well as some other IDE's so it is not an Eclipse issue.
---------- LINKS TO RELATED ----------
Launchpad Question
Eclipse Bug
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I had a situation in which the the path of the file to be copied is written in other file and I had to copy it using shell script..I can use cp $(cat /home/robert/location.txt) /media/sda1 on normal linux shell...But I am using buildroot script where $(cat /home/robert/location.txt) evaluate to nothing..is just blank..
View 1 Replies View RelatedI have just installed SABnzb application in my home folder. The executable file is SABnzb.py When I run the command in the Konsole # python SABnzb.py I have this Quote: python: can't open file 'SABnzbd.py': [Errno 2] No such file or directory
View 5 Replies View RelatedI found the following function in /etc/profile file.
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1. I dont undestand what "if ! echo $PATH | /bin/grep -qE "(^|:)$1($|:)"" this if statement actually comapres??
2. Also what is the difference between PATH=$PATH:$1 & PATH=$1:$PATH
How to find filename and file path from a string
View 7 Replies View RelatedI have file which consists of many files with their path,i need to check for the file exists in the given path,how to check?
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