I m writing a script to delete a line at particular location.
But i m unable to use variable for specifying line number.
For example.
Code:
works fine and deletes 7th line from my file
But
Code:
gives following error.
Code:
I have two files, file1.traj and file2.traj. Both these files contain identical data and the data are arranged in same format in them. The first line of both files is a comment.
At line 7843 of both files there is a cartesian coordinate X, Y and Z ( three digits ). And at line 15685 there is another three digits. The number of lines in between two cartesian coordinates are 7841. And there are few hundreds of thousands of lines in a file.
What I need to do is copy the X Y Z coordinate (three digits) from file1.traj at line 7843 and paste into file2.traj at the same line number as in file1.traj. The next line will be 15685 from file1.traj and replace at line 15685 at file2.traj. And I dont want other lines (data) in file2.traj get altered. This sequence shall be going on until the end of the file. Means copy and substitude the selected lines from file1.traj into file2.traj.
I tried to use paste command but I cant do for specified line alone.
Here i showed the data format in the file. I used the line number for clarity purpose.
Code:
After running the following command, I get:
[root@yukiko /]# find / -iname .bashrc
/home/clamav/.bashrc
/home/vpopmail/.bashrc
/etc/skel/.bashrc
/root/.bashrc
But I would like to have a command that prints a specific line by supplying the command with the line number, for example:
[root@yukiko /]# find / -iname .bashrc | getline(2)
/home/vpopmail/.bashrc
Is there such a command on CentOS?
I want to insert a line at a particular line number using sed or awk. where line number is not fixed and is in form of variable.
I want to use variable in sed or awk command.I tried something like below, but no luck.
I want to sort a number of lines based on their size:
data:
-------
12345678
87654321
1234
[code]....
Should output as:
-----------------
1
2
12
21
[code]....
But i'm gettings this with sort
----------------
1
12
123
1234
[code]....
Can we sort the above "data" text, based on "number of characters" instead of "character order"?
I want to print the line number with the pattern of the line on a same line using multi-patterns in sed. But i don't know how to do it. For example, I have a file
abc
def
ghi
I want to print
1 abc
2 def
3 ghi
I have a project due for my Intro to C++ class and we are suppose to generate a file listing that will take an input of a C++ source code with .cpp extension and make a copy of it with a .lst extention that will have a line number preceding each and every line.
View 12 Replies View RelatedWas wondering if any perl guru's could help me with a quick log file adjustment. I have a text file that looks like so (tabs and newlines are revealed so you can see what separates the data):
There are maybe 100 lines of text in this file at any given time. I need to delete all duplicate lines only looking at the first bit of text prior to the first tab. It doesn't matter which one gets deleted as long as there are no two lines that begin with that same text at the beginning before the first tab. So in this example, either the fist line "1234" or the last line "1234" would need to be deleted. I already have code in my script that opens the files - I just need the code to read the text into an array and the part that would find matches based on the above criteria, and make the deletions.
If it would be easier, I can even do a system call and use SED (v4.1.5) and/or AWK (3.1.5) instead.
I'm trying to add text to a file for a specific group of users, I'll need to do examples as I can't think of an easy way of explaining, my file is like this:
Code:
users{
user1
user2
[code]....
At the present my code lists all the available groups, how would I add a user to a specified group? (e.g add "members user3") to the end of group 1 for example. So the code ends up like this
Code:
members user2,user3
I am starting to learn shell programming, but I couldn't accomplish a simple thing that can be done with sed, awk.Its simple, I am dynamically getting an IP number, and a rule name, that I need to save them on a single file on a specific line number.I found how to enter a value on a specific line, but couldn't understand how to enter the second value.
View 3 Replies View RelatedI'm trying to use sed to search for a certain 'primary' pattern that may exist on several lines, with each primary pattern followed by an --unknown-- number of 'secondary' patterns.The lines containing the pattern start with: test(header_name)On that same line is an arbitrary number of strings that come after it.I want to move those strings over to their own lines so that they each are preceded by their own test(header_name).e.g. Original file (mytest.txt):
apples
test("Type1", "hat", "cat", "dog", "house");
bananas
[code]....
I am using Vi editor for editing and configuring my file.I am facing a little problem when there is long file like 3000 lines. Normally i use
Code:
:set number
in vi editor to visible my line number.The problem is when i have to go in the top of the file like say line number one I use k for it and to move down I use j which is too much time consuming. How can i jump directly my cursor to line number 2333 or line number 2600.
i have a problem about deleting a line from a text file which contains two specific patterns. i am using "sed -i "/$name/ d" peop.txt" but i must use one more variable which is surname.
"
burak:ak:3242:2342:dsa@a.com
gokhan:an:432:4234:da@a.com
"
and this is the code of text file. and the second question when i use "/$name/ d" it deletes not only the names which are macthing with $name but also all words that contain $name. so how can i fix these problems_?
I was creating a few scripts, I am trying to create a restore script to restore files that have previously been moved to a folder I selected. When moved I stored the original path for these files all in one text file.
I want to know if anyone can tell me how to delete the line from the file after using it restore the file. I have used the grep command to search through the file "pathName" to find where the file was stored but now want to delete that same line.
I have a big file full of records like this
1, 2, 4, 5, 6
1, 3, 5, 6, 3
1, 4, 5, 6, 6
2, 4, 5, 5, 5
2, 3, 4, 5, 2
anyway i need to take the average of all rows with the same 1st number(key). i.e.
1, 3, 4.66, 5.66, 5
2, 3.5, 4.5, 5, 3.5
I know this is something awk/sed would be great for, i just dont have enough experience with them to accomplish it, Also, what about averaging those columns together? so, after I output this to a file, id like to get another like:
1, 4.58
1, 4.125
The number of colums to add might not always be 4 either. EDIT: this might be easier to do in gnuplot, so I mainly just need an answer to the first part.
I'm not that familiar with sed and awk in order to be able to solve this problem on my own, so I'm calling on you for a bit of assistance. I'm writing a Nagios plugin to check our Oracle tablespaces and the output is given in one line like this: 1.04007771 TEMP 0 UNDOTBS1 .005340579 USERS 0 7 rows selected. I've been playing around with sed like below to delete the obsolete info and change every second space into a newline:
[code]...
how many tablespaces there are so I'd have to check all databases and 'hardcode' the tablespaces in my script. Is there any way to 'automate' this knowing that 'rows selected' preceded by a number is always the last line and using a sort of counter to auto-adjust the number to put in the -e 's/ / /2' part?
Is this the correct way to show the line count of a specific file?
cat file | grep * -c
I want to replace specific character in a file after every specific line. example as follows.
O 000000000000000000
A 111111111111111111
C 222222222222222222
[code]...
I have a log file which is continously being accessed. Now I want to delete the first line without disturbing the file.Is it possible? The Issue is the log file is being provisioned with ^@^@^@ characters in the first line occupying huge space.So I need to get rid of that. I dont have time to work with root cause but just a script to reduce this space.
View 3 Replies View RelatedI need to organise an external HDD such that there is no more than 500 folders on it.
Ubuntu's "Properties" pane shows only the file count, not the folder count.
Is there a simple CLI line that will tell me the number of subdirectories?
I want to access a file, and check the length of every line.After, i want to check and replace all lines with length over 10 characters, with a message.Does anyone have a clue on that?
View 1 Replies View RelatedWhat's a Unix/Linux one-liner that will let me delete all but the most recent N revisions of each file?
I've got a bunch of files with revision numbers as part of a legacy asset-management system:
bar.r7.js
bar.r8.js
bar.r9.js
bar.r10.js
bar.r11.js
[Code]....
I want to keep the last three of each, so in the above list the command would delete bar.r7.js, bar.r8.js and foo.r1.js.
I want to delete all may mail root in command line and i don't find this... the command mail + "d" work fine but i want use it in a .sh
I explain too : I use fetchmail to have mail from a gmail box, and use RIPMIME to save the attachment in a folder... these work fine, but the i want delete these mails.
I need a PHP script to delete a line with certain pattern from all filesin a directory. The Directory contain files with extensions .js,.html and.php. Do any body give a working code snippet to Read all files in a directory with above extension and delete that line from the files.
View 1 Replies View RelatedI read this thread but
Code:
anisha@linux-uitj:~> su
Password:
[code]...
I have a log file that contains information like this:
----------------------------
r11141 | prasath-palani | 2010-12-23 16:21:24 +0530 (Thu, 23 Dec 2010) | 1 line
Changed paths:
M /projects/
M /projects/
[code]....
what i need is, i need to copy the data given between the "---" to seperate files, for, e.g. the first set of data between the "---" should be in one file and another set of data in another file.
I'm new to the shell scripting. can any one help in creating shell script for matching the content of the specific variable with file. it should remove that line from the file if line is containing same value as variable and keep the other content as it is.i used grep -v for accomplishing the same. But grep will remove the pattern which is similar.For eg. Assume file "test" contain datas :aaffif i used grep -v command for the pattern "a" to this file this will remove content "aa" from the file. I want the pattern only "a" should remove from the file, if it is existing. otherwise it should throw alert content not exists.
View 5 Replies View RelatedLets say I have 20 files named FOOXX, where XX is the number of the file, eg 01, 02 etc. At the moment, if I want to delete all files lower than the number 10, this is easy and I just use a wildcard, eg rm FOO0* However, if I want to delete specific files ina range, eg 13-15, this becomes more difficult. rm FPP[13-15] does not work, and asks me if I wish to delete all files. Likewse rm FOO1[3-5] wishes to delete all files that begin with FOO1 So, what is the best way to delete ranges of files like this? I have tried with both bash and zsh, and I don't think they differ so much for such a basic task?
View 2 Replies View RelatedI have a file "test.txt" with following data
#1
aaa
#2
bbb
#3
aaa
#4
ddd
I wanted it to be displayed as
#1
aaa
#2
bbb
#4
ddd
I used awk "'!x[$0]++' test.txt > file.new"
,but it deleted #1 also.I tried using uniq command but i didn't work.
Can anyone Please let me know is there any way to do this using shell script.
I have found many information about how to delete/grab a line in a text file including delete line with match a pattern but I did not find info about how to delete a line which match a pattern of a particular column only.
for example mydata.txt:
id type x y z
1 6 0.474611 0.227223 0.583947
[code]....