I am trying to edit a print file.
For every occurence of the ^L form feed character I need to remove 5 blank lines after it but still keep the ^L.
I am a rare user of sed and am ok with the basics but am struggling with this.
I have such a file(test.txt):
abc 123 456
abc 256 145
axd 125 225
[code]...
Is there a convenient method to find a text pattern that extends over several lines? In this case:
Empty line
LineConsistingOfSingleWord
Preferably to return the line number where the pattern occurs to determine the first such after a known line number. In other words, in order to extract a block of text from within a file.
I have a file with a number of strings like the ones below
string1#m1asdfe23easdf23wefas
string2#mfaaeb2vr1rhserh
anotherstring#ji89ensrsegr
anotherone#m1ynmdt324nsdt
I'm trying to delete everything after #** so that
string1#maasdfeaveasdfawefas
string2#mfaaebvrserhserh
becomes
string1#ma
string2#mf
tried sed 's/#..*//g' but as you all will know it returns string1, string2 etc.
I have to use sed with this problem, and sed is extremely complicated, they could probably teach a whole class on this entire function.
Here's an example to show what I need to do:
Code...
how would I say that every line before I reach the first match of "sweet" should be deleted so that the output will look like: Code...
How do yo find a pattern with sed or awk and then:
- add a # at the beginning of the line containing it
- and add a # at the beginning of the following 2 lines, too?
Say, I want to comment out the line containing "which 0launch" and the two lines following it:
if [ -x "`which 0launch`" ]; then
exec 0launch http://rox.sourceforge.net/2005/interfaces/ROX-Filer -S
fi
Expected result:
#if [ -x "`which 0launch`" ]; then
# exec 0launch http://rox.sourceforge.net/2005/interfaces/ROX-Filer -S
#fi
I need this because I do not want to comment out every line containing "fi", just the "fi" of this specific if statement.
I need to grep a pattern which can be present in one line or could be split in 2 lines.Normal grep wont work in this case. Can anyone please help on this?There are 100's of files in which i need to search for this pattern so time is also a constrain.
View 5 Replies View RelatedI have two files, where the 1. file has special lines that need to be updated by lines from a 2. file:file1:
foo
foo
foo 0.00 0.00 0.00 pattern
[code]....
I have a file which contains milion of records. It contains 12 columns seperated by "||" (delimeter).
First two fields contain first name and last name of a person. Now my requirement is to delete all those records from this file for which:
First two fields does not contain any alphabet.
For e.g i have below mentioned records in file:
gaurav||gandhi||123||456||789
#a%bcd||123abc||89|90||91
12345||@@@||89||123||234
***||!!!!||98||76||90
Now, last two lines should be removed from this file since first two fields does not contain any alphabet for these two records.
Im tryng to replace in specific column and line number within a file where its 3erd column contain the same string in all lines.
[code]....
My goal is to replace only first and last ocurrences of "Normal player", with the following desired output:
[code]....
Im not sure how to use the "IF" and "AND" conditions together. I�ve tryed with the code below, but the script replaces the string for every line.
[code]....
how to replace values for specific column in first and last lines within same AWK script, without taking reference data in other columns?
if the given pattern exists in the file with the very next line starting and endingwith the same pattern , delete the line that starts and ends with the given pattern.So upon running on this file
hai people<PATTERN> we had
<PATTERN>a lot of fun<PATTERN>
writing scripts
[code]....
I have a question about sed programming, actually a one-liner for which I cannot find a solution, right now. I need to delete a line matching a specific pattern only if it is the last line. In practice, I would put together the following:
Code:
#
# This deletes the last line of a file
[code]...
I have a bunch of text files, all of them have a .txt extension. They are all located in subfolders of the /MyTextFiles folder (but could be anywhere, no idea what depth). If any line in any of the text files has the word "hello" I want to delete that entire line. I know sed and awk are made for this problem but I can't seem to get the syntax correct.
View 1 Replies View RelatedI am trying to create a shell script, on taking a input file as parameter, which need to do 3 things
1) create a copy of existing file.
2) add a new line to the copied file.
3) strip off all the absolute paths inside the copied file
The first 2 points are straight forward. but i am finding it difficult to acheive the 3rd point. myself not very good with awk and sed. but gave it a shot in vain. For example, the input script consists of below,
PROGRAM=`/usr/bin/basename $0`
HOST=`/usr/bin/uname -n`
echo Start $PROGRAM `/usr/bin/date` |
/usr/bin/tee -a $LOG
The output of the script should look like,
PROGRAM=`basename $0`
HOST=`uname -n`
echo Start $PROGRAM `date` |
tee -a $LOG
I need to find a string in a file ... then delete the line it is on, as well as the next 6 lines. Or, delete the line the string is on and all subsequent lines until the search finds the character "["
example:
filename = test.txt
contents:
[foo]
test>test
test>test
test>test
[Code]....
so, in this example. I'd like to search the file for string 'foo' and delete all lines from that line until [bar] (not deleting the line with [bar])
My problem is like this I have to delete all lines between two pattern match example- suppose below is the content of the file then i have to delete all lines between text1 and text2
...
text1
abc
def
ghi
[Code]....
I am trying to delete any blank lines within two patterns e.g.
Address: 53 HIGH STREET Cred Id :
MYTOWN
MYCOUNTY
MM12 6MM
Pay Method : Crossed Cheque
The start of my pattern is "Cred Id" and the end is "Pay Method" and I want to delete the blank lines between county and post code. I did find the code below but it doesn't seem to change anything:
sed -ne '/Cred Id/,/Pay Method/!bp' -e '/^$/b' -e -e p ll.out
I can get it to print just the range I'm interested in by doing sed -ne '/Cred Id/,/Pay Method/p'.
I have a file looks like the following:
digraph topology
{
"192.168.3.254" -> "10.1.1.11"[label="1.000", style=solid];
"192.168.3.254" -> "10.1.1.12"[label="1.000", style=solid];
[code]...
Order of these lines are random... So I cannot delete line #19, for example... And you can see that top four lines I want to delete are pairs. So there might be some clever way to detect the lines, if a line has both "1.9" and "1.11", then delete the line... I am new to perl language. The following is the code I have now... I think I just need to write some code inside the while loop checking if I want to delete the line $dotline before I write to a NEW file.
Code:
#!/usr/bin/perl -w
$TOPPATH = "/tmp";
$NAME = "topology";
$FILENAME = "$TOPPATH/$NAME.dot";
[code]....
I have a file with three consecutive blank lines. I want to delete two and keep one.Also, if anyone could direct me towards a guide on regular expressions particularly as they apply to sed, I would be grateful. I am having a hell of a time figuring out the syntax.
View 8 Replies View RelatedI want to go through a log file and find pattern1 and then a pattern2 only after pattern 1.So for example I want to know howManyRecords was in 13:30.I figured I grep for "start time for the job" and then only after that (and before the next occurence of that) grep for "howManyRecords". Is this a sane way?
View 1 Replies View RelatedI want to search a file for a particular pattern and if pattern found replace the line with new text. i am using awk 'match($0,"pattern") != 0 {print $0} ' filename to check if the pattern exists.how do i get the line number of the pattern and delete that line and replace the line with my new text?
View 1 Replies View RelatedI have to enhance the behaviour of a backup script written in perl. I don't need to change it, what I need to do is to create a bash script that does some checks like file name and file size, execute the backup script then check if the backup files match the original files.Here's how I try to do it:
- read the files from the original files folder
- store them in an array
- search in the array the files that have a specific file extension
- store the file names that match the search pattern (I know the backup script skips some files so I can hardcode the search pattern)
- run the backup script
- read the files from the backup folder
- store them in an array
- compare the original files name and size stored in an array with those from the backup folder
- send a report email
I've come across an unusual requirement for a service in my Ubuntu system.Simply put, I need to find a way to search for all instances of a term in a file, delete lines containing containing that term, and delete four lines below each instance of that term. ither that, or copy the entirety of a file to a new file and skip over all lines containing the term plus four below it.This sounds kinda weird, I know. Without going too far into detail, I either have to change the logfile format for a server I'm running which is a huge pain in the butt, or I can just run a script to edit an HTML report generated from said logs. (Said report is really just for managers to peruse, and I like my log format, so I'm pursuing option 2.)
View 4 Replies View RelatedI have 8 files, and each contains around 2000 lines. I want to search the particular word in these files between line number 1500 to 2500.
The output should look like:
sample_1.txt :
1510:declare var testing
sample_2.txt :
1610:declare var testing
sample_7.txt :
1610:declare var testing
sample_10.txt :
1710:declare var testing
Is it possible to use grep for this task?
I have a file called test. It has the following contents.Code:there youI want the output to be.Code:replaced youI am trying to use the sed command to replace every occurance of "hey newline there" with "replaced". I tried the following naive apporach.Code:sed 's/heythere/replace/' testThis gives a result containing the same data as the test file.
View 3 Replies View RelatedI am trying to delete lines of a file if they contain text that is present on another file. For example
> cat one.txt:
a
b
c
d
[code]....
I get the following output:
> ./test.sh one.txt two.txt
a
b
d
e
[code]....
Using sed, I am trying to append four commas ',,,,' at the end of lines containing the pattern 'Response' in a text file with lines such as these:
6,Pulse,50,254968,14886,NA,,,,
7,Picture,8,265157,0,1,15045,2,0,15000
7,Response,1,271553,6396,1
7,Pulse,50,274969,9812,NA,,,,
8,Picture,1,290232,0,1,15045,2,0,15000
8,Pulse,50,294969,4737,NA,,,,
[Code].....
I've got this line find . -type d -name 'elements' -exec rm -rf {} ; put together to find and delete all directories named elements and their contents.
It does work but whenever I run it I get the error/warning
Code: find: `./dir3/elements': No such file or directory
find: `./dir6/elements': No such file or directory
[code]....
I want to remove duplicate or multiple similar lines from multiple files. I.e. if I have four files file1.txt file2.txt file3.txt and file4.txt and would like to find and remove similar lines from all these files keeping only one line from these similar lines. I only that uniq can be used to remove similar lines from a sorted file.
View 9 Replies View RelatedA function by name abc is called in many files. I want to copy all the lines with the function call to an output file.A simple grep on function name doesn't help me as the function call is spanning across multiple lines as follows:
abc(parameter1,
parameter2,
parameter3);
So I want to copy all the three lines (till semicolon) to the output file.The problem is because there are more than 200 calls for the same function and I cannot do it manually