I want to search a file for a particular pattern and if pattern found replace the line with new text. i am using awk 'match($0,"pattern") != 0 {print $0} ' filename to check if the pattern exists.how do i get the line number of the pattern and delete that line and replace the line with my new text?
I have to enhance the behaviour of a backup script written in perl. I don't need to change it, what I need to do is to create a bash script that does some checks like file name and file size, execute the backup script then check if the backup files match the original files.Here's how I try to do it:
- read the files from the original files folder - store them in an array - search in the array the files that have a specific file extension - store the file names that match the search pattern (I know the backup script skips some files so I can hardcode the search pattern) - run the backup script - read the files from the backup folder - store them in an array - compare the original files name and size stored in an array with those from the backup folder - send a report email
I'm trying to setup my test nagios to check the disk space of another linux box. I've got it setup and checking. But to my surprise, it was checking the nagios server's local disk space instead of the remote linux.
Here is my services.cfg.
define service{ use basic-service name disk-space check_command check_local_disk!20%!10%! /
I'm trying to write a bash script that has to extract values from a csv file. Problem is there are lines like this:a,b,c,"dd,dd,dd",e,f,gI'm using awk to extract the values but when I try it extract value 4 with awk I get:"ddinstead of:"dd,dd,dd"Does anyone know how to get awk to ignore commas within double quotes?
I writing a script to go through multiple reports. I want to grep daemon.debug @10.10.10.10 on all reports to make sure it is pointing to the right IP address. the problems is the space between debug and @10 are different on all the reports, some have one space some have two and some have tabs how do I ignore the tabs or spaces and grep daemon.debug @10.10.10.10
A function by name abc is called in many files. I want to copy all the lines with the function call to an output file.A simple grep on function name doesn't help me as the function call is spanning across multiple lines as follows:
abc(parameter1, parameter2, parameter3);
So I want to copy all the three lines (till semicolon) to the output file.The problem is because there are more than 200 calls for the same function and I cannot do it manually
I have one file called test.sh and in that file I have the below code. All this code is, is paths to three directories (as you can you can clearly see!).
Code: #!/bin/bash BACKUP="Documents /bin /sbin"
Now I have this other file which reads the directories (by using $BACKUP) and creates a tar file of everything in that folder. But what I am unsure of what to is create a bit of code that will simply look in test.sh, read all the directories and print a line saying either they all exist or some are missing. If possible it would be good to know which directories are missing too!
I have fiddled around with using -d but I can only get it to work for one directory or manually having to write out each directory.
I've just moved onfrom developing some code on Debian (gcc 4.1) to Ubuntu (gcc4.4) and a warning in my g++ code has appeared. Basically in some serial prot code I get this errorwarning: ignoring return value of 'ssize_t write(int, const void*, size_t)', declared with attribute warn_unused_resultfrom function
I need to read a binary file using my C++ application. That binary file may contain arbitary characters and it also contains 0 at some places. I need to read the file without considering null terminating character. (i.e. considering 0 as a normal byte and not as the end of the string)Can some one suggest me a method to read the buffer while ignoring the null terminated character.
I need to add some text using sed before and after the matching pattern. Does any one have any clue?e.g.cat /my/file | sed -e "s/first pattern/New Pattern/g" . /my/file.bakNow I need a result like New Pattern
if the given pattern exists in the file with the very next line starting and endingwith the same pattern , delete the line that starts and ends with the given pattern.So upon running on this file
hai people<PATTERN> we had <PATTERN>a lot of fun<PATTERN> writing scripts
I'm working on a backup script which takes the following input:
Code: RevBackup.sh <options> <source> <target>
The problem I'm having is that the source and target might contain spaces in the path. ie. /home/eRJe/My Documents
I would like the script to ignore " " (backslash-space) as being a delimiter. how could I do this without stopping a normal space from being a delimiter?
I could do this with IFS. But so far I have only found info about setting a delimiter and not to "ignore" one
I want to go through a log file and find pattern1 and then a pattern2 only after pattern 1.So for example I want to know howManyRecords was in 13:30.I figured I grep for "start time for the job" and then only after that (and before the next occurence of that) grep for "howManyRecords". Is this a sane way?
yes, this is a homework question, but no - I'm not trying to get anyone to do it for me. I think that I am really close, but can't quite get one small aspect to work. in gawk, I want to include a variable name in the search string, but the below code doesn't work.
I'm looking for a solution of pattern detection in the logs and then allows to send me an email notification if it detects the previously specified term.I use already Logwatch, but I do not know if it is possible to configure it for that use.
I need to grep a pattern which can be present in one line or could be split in 2 lines.Normal grep wont work in this case. Can anyone please help on this?There are 100's of files in which i need to search for this pattern so time is also a constrain.
Any solution using awk/sed/regexp or other standard linux utility (this is for a mix of RH versions)? I am dealing with some very large application log files. I want to see everything that has been written to the log since the last application restart.
For an example take a log file like this: Code: # cat test.log 1 msg 2 msg 3 restart 1 4 msg 5 restart 2 6 msg
The following command is close to what I want: Code: # awk '/restart/,G' test.log 3 restart 1 4 msg 5 restart 2 6 msg
But the awk command grabs the first restart not the last. If it was working the way I wanted I would see something like this: Code: # awk '/restart/,G' test.log 5 restart 2 6 msg
So, I need something in that search pattern that says look for the last occurrence. I know how to do this with a pipe line - I could reverse the file and then do a similar awk and reverse back, or I could find the number associated with the last restart and then use that in the awk search. But these just take too long because the file is too big.
Is there a convenient method to find a text pattern that extends over several lines? In this case:
Empty line LineConsistingOfSingleWord
Preferably to return the line number where the pattern occurs to determine the first such after a known line number. In other words, in order to extract a block of text from within a file.
I have the following command that greps "/etc/cron.allow" and displays the following 9 lines of $file grep -A 9 "/etc/cron.allow" $file On the other hand I would like to grep a file for a certain text display the next couple of lines and stop when i hit a specified word or blank or pattern.Basically I would like my grep to end when the shell hits a blank, certain key word or pattern specified in command.
I'm fairly new to Perl and regular expressions. I have a large collection of files with their file names in the following general format: string - another string with spaces (2004) [year].ext I would like to know how I could create a regex to separate out:
the first string another string with spaces year extension
If you know of a better way of doing it without regular expressions, I would be happy to hear that way too.
i tried searching on google but found it difficult to say exactly what I was looking for.Task - Capitalise x number of letters at the start of words.eg. Original line - one.two.three.fourRevised line - One.Two.three.four (here only requiring 2 changes)Test data:
I'm writing a script that edits a Maya ascii file. Inside the .MA(maya ascii file) there is a line defaultRenderGlobals. My script is supposed to find this line and according to what options they manipulate will update the lines below defaultRenderGlobals. I've got that working... but... the issue i'm having is that defaultRenderGlobals is only made when a the maya scene is made into a batch render. I want my script to manually addefaultRenderGlobals line into the .ma file if its not there and add the certain lines below it.RenderGlobals is already there I want to just manipulate whats below it. Hope this makes sense
I have a question about sed programming, actually a one-liner for which I cannot find a solution, right now. I need to delete a line matching a specific pattern only if it is the last line. In practice, I would put together the following:
