Programming :: Shell Script For Adding A Statement In A File After A Particular Statement?
Jun 28, 2010
We are building our C++ project in Kdevelop IDE. Every time we run "Run Configure" from the "Build" menu, a file named "libtool" gets automatically generated. This file contains a statement as "ECHO="echo"".f we run "Automake", without modifying the "libtool" the system hangs and theputer needs to be restarted.Therefore every time we run "Run Configure" we need to include the line "echo="echo"" below the statement "ECHO="echo"" manually.I think a script can be written which does the above on its own.I am not a shell script programmer, I know the good tutorials for shell scripts are available on the net, but learning scripting only for this task would be time-consuming and painful.
This script that I found online does the job it promises. it does convert the files to mp3 without an issue. What I need to include now is an if statement that says If $file.mp3 exists then delete $file.wav
Code: #!/bin/sh # name of this script: wav2mp3.sh # wav to mp3 # Credit to the script creator (Nikesh Jauhari):
[Code]...
After that I'm stumped as to how to do the if statement
Im a bit stuck with a simple script that im practicing with... im trying to get my head around some simple scripting. Basically i want to write a script that will work as below: It will ask the user to enter their userid. If its correct it will say 'Correct' If its the wrong id (But the ID exists in /etc/passwd) then it will say 'incorrect' If its not a valid userid it will say 'doesnt exist'. What i have so far is:
[Code]...
# If the user enters their own userid they will get a comment saying 'correct' $LOGNAME) echo "Correct";;
# If they enter another users ID (That exists in the /etc/passwd), then they get a message to say 'incorrect userid used'. Im not sure what i need to do here to get it to check the /etc/passwd to see if the input exists in there.... im guessing some kind of simple 'if' statement to say ---- "if 'input' exists in /etc/passwd then echo "incorrect userid used"
# If its entered incorrectly and not a valid ID then they will get this comment. Again, im guessing this part would be similar to te above option..... *) echo "not a valid ID";;
Ive managed to work out how the basic Case staements work, but to add a conditional statement based on the input, i just cant figure out. I have tried looking on google, and found some help but it doesnt really explain how i check the input against the /etc/passwd.
I am trying to create a script to be used on RHEL server. If I replace the $t with a number, the script works. If I try add a variable or the $1, the script doesn?t work (returns all processes even if less than the $t value). I thought that it may be treating it as a literal, but I wasn?t sure of the conversion.
When you use an if statement directly in bash you have to put the ";" at the end or not? or am I mixing it with the for loop? I am reading advance bash scripting and it shows the if - then statements without ";" so I need a little clarification here.
I have a site which will have, for example, a login system where people have to enter their usernames and passwords, depending on which they'll be let in to the site. So, in code, I've got a line like:
if ($_POST['password'] == $password) { then do whatever } else { print "Wrong password" ; )
My problem is, this "Wrong password" printing is just a solitary line, not keeping with the colours and style of the site, and it looks very bad. I want to ideally, output some HTML, which will have a picture, and print the "Wrong password" in the font and colours I desire. Do I have to put all the HTML in a print statement, and then deal with the nightmare of escaping all the quote marks in it with a ""? Or is there a cleaner method to the whole thing? Maybe something like this -
if ($_POST['password'] == $password) { then do whatever }
I'm trying to code a sql statement for use in a PHP script.I'm looking to find the number of matching records in two tables and display them.How would you write that statement.I've tried using count a few ways, but no cigar.
the following works and BASH doesn't complain, but VIM highlights the closing square bracket is if it sees a syntax error. Is there a better way to express regex in a case statement or is this an issue with VIM?
The script that Iam trying to write is running a for loop and reading line by line from a text file. inside this for loop i would like to execute update SQL statement .
a pesudo code is Quote: `$ISQL -U $username -P $Password -D $Dbname -I $INTERFACE <<QRY for id in $idlist #idlist iam reading from a file
It is under PHP/MySQL $queryresult = $conn->query("INSERT INTO normalrequests VALUES($finalkey, 1234, 5678, FALSE)"); It is connected to the database successfully but I feel there is something wrong with the statement up there.
As you can see, I want to pass arguments depending on the option(s) chosen by the user; ie. --snooze, or --channel. By default, if no options are chosen, I'll display a usage message; though in the future I'll provide some sane defaults. I'd like to create a case statement to handle passing arguments to any number of options; something like:
Code:
wakethehellup.sh --snooze 20 --message 'wake up!'
and for the other arguments, it would have a default set. The case statement I provided fails with a syntax error "syntax error near unexpected token `$2'" near the '--snooze' in the statement, so I take it you can't pass a parameter in this way; but I'm confused as to how I'm supposed to pass different parameters to different options without the options being confused as parameters.
Both lines are new lines, so they won't be inline. Other than that, they are all constants, I want this regex match to be an if statement rather than returning match string. so if the $content variable contains some string that matches:
A question of ODBC correctness - maybe someone knows.
Code: // statement handle is sth, connection handle is dbch SQLExecDirect(sth, ...); // ... bind var, fetch results ... SQLFreeHandle(SQL_HANDLE_STMT, sth); // free statement handle SQLEndTran(SQLHANDLE_DBC, dbch, SQL_COMMIT); (error checking removed for clarity).
To my mind this seems wrong - surely the statement handle should be free'd only after the commit is done? Or maybe not. I theorize about the ODBC library like this: a whole set of statements can be created, run, executed in one transaction (which is held at the connection level), and only after all that is a commit/rollback done. So maybe it's OK. Even so it still feels weird. What is written above works, but there are rare and very difficult to replicate problems with this code, and I wonder if a premature free might be the cause...?
how do I get this regular expression to work in an if/else statement? This is just a little script for learning BASH. don't be too harsh.
This script will test if a certain number of files with 1-4 in their filename exist and print their filename. An error message will be printed if not.
# for i in `ls file[1-9]` do if [[ "$i" == *1-4 ]] ; then echo "This file, $i, ends in a number between 1-4" else echo "Error, this file, $i, does not end with a number between 1-4" fi done
I get this error. ./file_test.sh: 13: [[: not found
I was doing an exercise on Learning Perl, 3rd edition. (exercise chapter 10 btw) The problem asks to create a program that generates a random number and asks the user to guess. It should tell the user if the guess is lower or higher and exit if the user types either exit or quit. My code is the following:
made a simple script called "msg" to make it simpler to use the "wall" command, but it is giving me some issues. The problem is more cosmetic than performance, but it's annoying.OS:Ubuntu 10.10 Text Editor: Nano (Probably not important, but hey...)Here's what I got:
I have to enhance the behaviour of a backup script written in perl. I don't need to change it, what I need to do is to create a bash script that does some checks like file name and file size, execute the backup script then check if the backup files match the original files.Here's how I try to do it:
- read the files from the original files folder - store them in an array - search in the array the files that have a specific file extension - store the file names that match the search pattern (I know the backup script skips some files so I can hardcode the search pattern) - run the backup script - read the files from the backup folder - store them in an array - compare the original files name and size stored in an array with those from the backup folder - send a report email
I am trying to write a script that takes an input file ($FileName) and an intermediate file ($FileName.info) and removes lines from $FileName if the value in $2 of $FileName.info is <75.
I can't figure out how to feed only one line of the .info file to the if statement at a time so that it will perceive it as an integer instead of a list.
The error I am getting now is ./script.sh: line 6: [: : integer expression expected
If I'm in a directory and I want to move into the next directory I just type it in raw without the relative ./ All I use is cd "next directory" enter. So my point is that I can not find a purpose for the "./" statement other than to state it on paper ;or the like as , ./directory/directory (from whatever current directory) I was in. Is the "./" statement for an older version of BASH?
I have multiple drives and software that defaults to my primary drive. I want to change preferences to use my second drive.This is the current path "/home/guy/dvdrip-data" my second drive is named "2Internal".How do I properly format the path statement to use the second drive?
I have returned the below mentioned lines of code however I am receiving error "Syntax Error On Done Statement".
while: do clear echo "-------------------------------------------------------------------" echo "Main Menu" echo "-------------------------------------------------------------------" echo "[1] Today's Date" echo "[2] Show files in the current Directory" read yourch case $yourch in
1) echo "Today is `date`,press a key ........";read;; 2) echo ls -l;read;; *) echo "Select the yourch as 1 or 2";
the script below prints the pwd of where I want to be. after the fi it puts me back at the original dir. just writing these scripts to understand what's going on.
#! /bin/bash if [ -d mydir ] then cd mydir/ && pwd fi
I am running Debian Squeeze, 64-bit.I would like to try my hand at bash scripting. So at the author's suggestion (first chapter of Chris F. A. Johnson, Pro Bash Scripting from apress) I created a /bin directory in my home directory. So now I would like to modify my PATH statement so that when I run a script from my bin directory my shell will find it.I did that. He then says that I should add this to ".bash_profile, .bashrc, or .profile depending on how bash is invoked." The find command is unable to locate any of these files. So I searched the forum, found the link above and tried to follow that. No luck so I assume that how Debian handles PATH statements has changed since that post?
I also have checked the wiki and worked Google as hard as I know how to do.Very simply where the heck is my PATH statement and how do I modify it?
