Programming :: Case Statement Passing Multiple Arguments?

I've started dabbling with the case statement in order to pass some option's arguments into variables. I do not think I am doing this right.

Code:

usage() {
echo "Usage: $0 [-z|--snooze] [-c|--channel] [-p|--playlist]
[-m|--message] [-v|--mpcvolume]"

[code]....

As you can see, I want to pass arguments depending on the option(s) chosen by the user; ie. --snooze, or --channel. By default, if no options are chosen, I'll display a usage message; though in the future I'll provide some sane defaults. I'd like to create a case statement to handle passing arguments to any number of options; something like:

Code:

wakethehellup.sh --snooze 20 --message 'wake up!'

and for the other arguments, it would have a default set. The case statement I provided fails with a syntax error "syntax error near unexpected token `$2'" near the '--snooze' in the statement, so I take it you can't pass a parameter in this way; but I'm confused as to how I'm supposed to pass different parameters to different options without the options being confused as parameters.