General :: Script (Case & IF Statement Syntax) - Easy To Answer If Know Shell Scripting

May 6, 2011

Im a bit stuck with a simple script that im practicing with... im trying to get my head around some simple scripting. Basically i want to write a script that will work as below: It will ask the user to enter their userid. If its correct it will say 'Correct' If its the wrong id (But the ID exists in /etc/passwd) then it will say 'incorrect' If its not a valid userid it will say 'doesnt exist'. What i have so far is:

[Code]...

# If the user enters their own userid they will get a comment saying 'correct' $LOGNAME) echo "Correct";;

# If they enter another users ID (That exists in the /etc/passwd), then they get a message to say 'incorrect userid used'. Im not sure what i need to do here to get it to check the /etc/passwd to see if the input exists in there.... im guessing some kind of simple 'if' statement to say ---- "if 'input' exists in /etc/passwd then echo "incorrect userid used"

# If its entered incorrectly and not a valid ID then they will get this comment. Again, im guessing this part would be similar to te above option..... *) echo "not a valid ID";;

Ive managed to work out how the basic Case staements work, but to add a conditional statement based on the input, i just cant figure out. I have tried looking on google, and found some help but it doesnt really explain how i check the input against the /etc/passwd.

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1)
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[code]....

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Code:

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Code:

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if [[ $status = 0 ]];
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