I want to match for this string:
Code:
Content-Transfer-Encoding:[:space:]base64
Content-Disposition:[:space:]attachment;[:space:]filename="%variable%"
Both lines are new lines, so they won't be inline. Other than that, they are all constants, I want this regex match to be an if statement rather than returning match string. so if the $content variable contains some string that matches:
Code:
if `sed "//p"` ;
the following works and BASH doesn't complain, but VIM highlights the closing square bracket is if it sees a syntax error. Is there a better way to express regex in a case statement or is this an issue with VIM?
Code:
#!/bin/bash
case $1 in
[code]...
am trying to find a proper regex to match the two numbers in the following log entry.
Code:
15:08:16.142 INF Found 64468
15:08:16.142 ERR [Uniform test code=64469]
Basically the pattern I'm looking for will match the two different numbers spanned across two lines.Thought I need to use multi-line mode as follow but this doesn't match on [URL]...
Code:
/^($[0-9]{5}
[0-9]{5})$/m;
I have a sed match that matches for certain string of a regex expression:
Code:
tname=$(echo "$contents" | sed -n 'some pattern')
How do I match for multiple strings in the $contents and return them as an array? for example
Code:
contents="this is a text, just to match patterns, here is another text to be matched"
the sed func would be able to recognize both "text"s, but only one is outputted?
Possible to put it in an array? so ${bar[0]} gives one and ${bar[1]} gives another
adf 32 324 100 100 24 234I want a gawk statement to match the above line if lets sayand field between 4 and 6 == 100.
View 2 Replies View RelatedI am trying to read a file character wise and trying to write the same character to another file. In this process, I unable to read and write white spaces successfully to the new file. The script reads the white spaces but while writing the white space is lost. The section of the code, is given below. Please advice how can i read and retain the white space while writing to a new file.
Code:
if [ -s f_test.txt ] && [ -f f_test.txt ]; then
echo "File Exists !!"
while read -n1 char; do
[code]....
Im using this unix command(in a php file) to remove a certain string and then remove the whitespace left by that string. Unofrtunately in many cases, the files get completely erased. Is there a workaround?
Code
<?php
$dir = "./";
$rmcode = `find $dir -name "*.php"
[cod3e]....
here is what is in my file:
[code]...
i have xterminus installed. i also have a white block over the first letter in my username and when i begin typing, the 'block-type cursor' just leaves full white spaces behind and i cannot read my text at all. even when i delete back over the white spaces, they stay whited out.
I'm looking at a way to match the "euro" signe in my php code
below is my code which doesn't work:
Code...
so in clear word I would like to change the "�" above with the hexadecimal or unicode value.
1. How can I use hexa or unicode in regex to match special characters?
2. Does anyone have a link where I can find these tables?
I have some lines of text and I want to detect words that meet some criteria with sed.
E.g. The line "tetris cat dog test cactus stereotype"
I want to detect the word that contains two (2) ore more t letters. That mean the words tetris, test and stereotype.
The following regex doesn't do the job because it can;t distinguish words very well.
I thinks I have ti incorporate something like [^ ] in the regex but I wasn't successful...
We are building our C++ project in Kdevelop IDE. Every time we run "Run Configure" from the "Build" menu, a file named "libtool" gets automatically generated. This file contains a statement as "ECHO="echo"".f we run "Automake", without modifying the "libtool" the system hangs and theputer needs to be restarted.Therefore every time we run "Run Configure" we need to include the line "echo="echo"" below the statement "ECHO="echo"" manually.I think a script can be written which does the above on its own.I am not a shell script programmer, I know the good tutorials for shell scripts are available on the net, but learning scripting only for this task would be time-consuming and painful.
View 4 Replies View Relatedregex in grep? I need to match ANYTHING in the following with any character combination (something like * in findstr in C): grep "Delivery of nonspam" /var/log/mail.log | grep "to [URL]"
View 1 Replies View RelatedI use the Actions feature of KDE's Klipper utility to run certain commands when I copy something into the clipboard that matches a particular regular expression. Unfortunately, I have to turn on Enable Clipboard Actions and select the command from a menu every time I copy something that I want to run the command on. I'd like to have that command run automatically instead.
You'd think this was possible, as there is an automatic checkbox in the action settings dialog box:
Unfortunately, that appears to do nothing. The documentation included with Klipper does not indicate what that checkbox is supposed to do.
Is it possible to configure Klipper to run a command automatically if the contents of the clipboard matches a regular expression? If not, is there another way to accomplish this?
I've written a simple perl code to learn switches in perl.My code is pasted below,
#!/usr/bin/perl
$opt = 1;
switch($opt) {
[code]...
I have the following query:
Code:
$sql="SELECT table1.datetime, table1.user_id, table2.ip, FROM table1,table2 WHERE id='$id' AND (table1.id = table2.id AND table1.datetime = table2.datetime)";
In table2 the datetime fields are about 1 to 2 seconds off due to the source of the data, which I cannot change.
Is it possible via a query match table1.datetime & table2.datetime by HH:MM (ie. to the minute instead of to the second)?
I need a regex expression to read IP address from lines like these for my perl script:
Code:
2011.05.13-14:54:58, test@xyz.com, 180.211.51.11, pop3
2011.05.13-14:57:26, test@xyz.com, 160.234.47.12, pop3
2011.05.13-14:57:54, www@abcd.com, 166.22.22.224, imap
2011.05.13-14:57:55, www@somedomain.com, 172.58.22.154, imap
2011.05.13-15:03:08, www@example.com, 190.22.120.44, pop3
I am trying to create a script to be used on RHEL server. If I replace the $t with a number, the script works. If I try add a variable or the $1, the script doesn?t work (returns all processes even if less than the $t value). I thought that it may be treating it as a literal, but I wasn?t sure of the conversion.
t=$1
echo $t
lcnt=`ps -eo pid,ppid,rss,vsize,pcpu,pmem,cmd -ww --sort=pid | awk '{if ($6 > $t) print
[code]...
When you use an if statement directly in bash you have to put the ";" at the end or not? or am I mixing it with the for loop? I am reading advance bash scripting and it shows the if - then statements without ";" so I need a little clarification here.
View 2 Replies View RelatedI have a site which will have, for example, a login system where people have to enter their usernames and passwords, depending on which they'll be let in to the site. So, in code, I've got a line like:
if ($_POST['password'] == $password) {
then do whatever
}
else { print "Wrong password" ; )
My problem is, this "Wrong password" printing is just a solitary line, not keeping with the colours and style of the site, and it looks very bad. I want to ideally, output some HTML, which will have a picture, and print the "Wrong password" in the font and colours I desire. Do I have to put all the HTML in a print statement, and then deal with the nightmare of escaping all the quote marks in it with a ""? Or is there a cleaner method to the whole thing? Maybe something like this -
if ($_POST['password'] == $password) {
then do whatever
}
[code]....
I'm trying to code a sql statement for use in a PHP script.I'm looking to find the number of matching records in two tables and display them.How would you write that statement.I've tried using count a few ways, but no cigar.
View 2 Replies View RelatedIn a bash-script, only the case if a regular expression does not match is relevant.herefore I used the exclamation mark !. But where to place it?
These two work fine, but are they equivalent?
Code: if ! [[ $abc =~ $pattern ]]; then or
Code: if [[ ! $abc =~ $pattern ]]; then Where is the ! placed more correct?
I'm just starting out with bash scripting (yesterday, really). I want to add a file to each user's home directory, pretty simple really, and send it out via our Apple Remote Desktop system to our Macs. Here is my script: Code: #!/bin/bash
for i in $(ls -d /Users/*)
doif [ -e $i/.tcshrc ]
thenecho "$i/.tcshrc exists!"elseecho "$i/.tcshrc does not exist"
[code]....
I'm using bash scripting to find any file that matches a path governed by the following regular expression:
"(monthly|nightly).[0-9]+/home/(user1|user2)/.mailbox/"
to match files like:
monthly.9/home/user1/.mailbox/l23131564
nightly.15/home/user2/.mailbox/cur/6546213
I've tried:
Code:
myRegex="(monthly|nightly).[0-9]+/home/(user1|user2)/.mailbox/"
find ./ -regextype posix-egrep -regex $myRegex
and it just spins and never gives me an answer, even though the file structure isn't that big.
Does it possible to escape * in the case statement
Code:
The script that Iam trying to write is running a for loop and reading line by line from a text file. inside this for loop i would like to execute update SQL statement .
a pesudo code is
Quote:
`$ISQL -U $username -P $Password -D $Dbname -I $INTERFACE <<QRY
for id in $idlist #idlist iam reading from a file
[code]...
It is under PHP/MySQL
$queryresult = $conn->query("INSERT INTO normalrequests VALUES($finalkey, 1234, 5678, FALSE)");
It is connected to the database successfully but I feel there is something wrong with the statement up there.
So those of you that know me will agree that when it comes to awk I don't usually ask a lot of questions ... however this one has me stumped. I am guessing I have missed something obvious but for the life of me (and I have tested at great length) I cannot find it So the scenario is this: The following awk code should identify all versions of libgpg-error within the attached file (see below) and only show one for each version:
[Code]...
I'm writing a script to read user input for a computername.I need a check that a given userinput is valid.Right now I use grep like this (for sure not optimal):Quote:
if echo "$name" | grep -q '[^a-z][^A-Z][^0-9]'; then
echo error
else
[code]....
Code:
g echo ${mm[$j]}
4 BashNotes
[code]...
I'm fairly new to Perl and regular expressions. I have a large collection of files with their file names in the following general format: string - another string with spaces (2004) [year].ext I would like to know how I could create a regex to separate out:
the first string
another string with spaces
year
extension
If you know of a better way of doing it without regular expressions, I would be happy to hear that way too.
