I've written a simple perl code to learn switches in perl.My code is pasted below,
#!/usr/bin/perl
$opt = 1;
switch($opt) {
[code]...
the following works and BASH doesn't complain, but VIM highlights the closing square bracket is if it sees a syntax error. Is there a better way to express regex in a case statement or is this an issue with VIM?
Code:
#!/bin/bash
case $1 in
[code]...
Does it possible to escape * in the case statement
Code:
I've started dabbling with the case statement in order to pass some option's arguments into variables. I do not think I am doing this right.
Code:
usage() {
echo "Usage: $0 [-z|--snooze] [-c|--channel] [-p|--playlist]
[-m|--message] [-v|--mpcvolume]"
[code]....
As you can see, I want to pass arguments depending on the option(s) chosen by the user; ie. --snooze, or --channel. By default, if no options are chosen, I'll display a usage message; though in the future I'll provide some sane defaults. I'd like to create a case statement to handle passing arguments to any number of options; something like:
Code:
wakethehellup.sh --snooze 20 --message 'wake up!'
and for the other arguments, it would have a default set. The case statement I provided fails with a syntax error "syntax error near unexpected token `$2'" near the '--snooze' in the statement, so I take it you can't pass a parameter in this way; but I'm confused as to how I'm supposed to pass different parameters to different options without the options being confused as parameters.
How do i make my strings case-insensitive while comparing them with an if statement?
View 2 Replies View RelatedI am facing problem with the following script. Could you please look into this.echo 'Enter Staging number' case $STGNUM in
1)
for i in {'stg1-greg','stg1-marsha','stg1-peter','stg1-jan','stg2-greg','stg2-marsha','stg2-peter','stg2-jan'};do echo $i; ssh $i sudo -u dev /opt/usr/apps/workflow/stopwf.sh;done;
[code]....
Here's my need:
If Calendar Day= Then FCPeriod= And FCYear=
Jan 11 to Feb 1002Current Year of Feb 10
Feb 11 to Mar 1003Current Year of Mar 10
Mar 11 to Apr 1004Current Year of Apr 10
Apr 11 to May 1005Current Year of May 10
May 11 to June 1006Current Year of June 10
June 11 to July 1007Current Year of July 10
July 11 to Aug 1008Current Year of Aug 10
Aug 11 to Sept 1009Current Year of Sept 10
Sept 11 to Oct 1010Current Year of Oct 10
Oct 11 to Nov 1011Current Year of Nov 10
Nov 11 to Dec 1012Current Year of Dec 10
Dec 11 to Jan 1001* Current Year of Jan 10
* Note for Dec 11 - Dec 31,
The Next Year to be used
IE: Current date is Dec 28th, 2010. Year = 2011
IE: Current date is Jan 8th, 2011, Year = 2011.
Looks like I'll need a case statement with some regular expressions...
Im a bit stuck with a simple script that im practicing with... im trying to get my head around some simple scripting. Basically i want to write a script that will work as below: It will ask the user to enter their userid. If its correct it will say 'Correct' If its the wrong id (But the ID exists in /etc/passwd) then it will say 'incorrect' If its not a valid userid it will say 'doesnt exist'. What i have so far is:
[Code]...
# If the user enters their own userid they will get a comment saying 'correct' $LOGNAME) echo "Correct";;
# If they enter another users ID (That exists in the /etc/passwd), then they get a message to say 'incorrect userid used'. Im not sure what i need to do here to get it to check the /etc/passwd to see if the input exists in there.... im guessing some kind of simple 'if' statement to say ---- "if 'input' exists in /etc/passwd then echo "incorrect userid used"
# If its entered incorrectly and not a valid ID then they will get this comment. Again, im guessing this part would be similar to te above option..... *) echo "not a valid ID";;
Ive managed to work out how the basic Case staements work, but to add a conditional statement based on the input, i just cant figure out. I have tried looking on google, and found some help but it doesnt really explain how i check the input against the /etc/passwd.
We are building our C++ project in Kdevelop IDE. Every time we run "Run Configure" from the "Build" menu, a file named "libtool" gets automatically generated. This file contains a statement as "ECHO="echo"".f we run "Automake", without modifying the "libtool" the system hangs and theputer needs to be restarted.Therefore every time we run "Run Configure" we need to include the line "echo="echo"" below the statement "ECHO="echo"" manually.I think a script can be written which does the above on its own.I am not a shell script programmer, I know the good tutorials for shell scripts are available on the net, but learning scripting only for this task would be time-consuming and painful.
View 4 Replies View RelatedI tried to add my wife , and when I put in a password for her, this error comes up."Please set a valid user name consisting of a lower case letter followed by lower case letters and numbers." I did all that and I still can't set a password for her.
View 3 Replies View RelatedKernel 2.6, Slackware 12.0
mkisofs 2.01
I do 'mkisofs -iso-level 1 -o image John Smith.txt'. Only an example. When I mount image, ls outputs john_smi.txt. So it has shorten to 8.3 and translated ' ' into '_'. This is in accordance with the manual, although it doesn't say the conversion will be done.
Quote:
-iso-level level
.........................
With all iso9660 levels from 1..3, all filenames are restricted to upper case letters, numbers and the underscore (_).
...........................
However, as it did not reject the file name, it should have converted it to all upper case, it seems to me. And -iso-level 2|3 does the same thing.
Code:
root@darkstar:~# mkisofs -iso-level 1 -o image John Smith.txt
Total translation table size: 0
Total rockridge attributes bytes: 0
Total directory bytes: 0
[code]....
I am trying to create a script to be used on RHEL server. If I replace the $t with a number, the script works. If I try add a variable or the $1, the script doesn?t work (returns all processes even if less than the $t value). I thought that it may be treating it as a literal, but I wasn?t sure of the conversion.
t=$1
echo $t
lcnt=`ps -eo pid,ppid,rss,vsize,pcpu,pmem,cmd -ww --sort=pid | awk '{if ($6 > $t) print
[code]...
When you use an if statement directly in bash you have to put the ";" at the end or not? or am I mixing it with the for loop? I am reading advance bash scripting and it shows the if - then statements without ";" so I need a little clarification here.
View 2 Replies View RelatedI have a site which will have, for example, a login system where people have to enter their usernames and passwords, depending on which they'll be let in to the site. So, in code, I've got a line like:
if ($_POST['password'] == $password) {
then do whatever
}
else { print "Wrong password" ; )
My problem is, this "Wrong password" printing is just a solitary line, not keeping with the colours and style of the site, and it looks very bad. I want to ideally, output some HTML, which will have a picture, and print the "Wrong password" in the font and colours I desire. Do I have to put all the HTML in a print statement, and then deal with the nightmare of escaping all the quote marks in it with a ""? Or is there a cleaner method to the whole thing? Maybe something like this -
if ($_POST['password'] == $password) {
then do whatever
}
[code]....
I'm trying to code a sql statement for use in a PHP script.I'm looking to find the number of matching records in two tables and display them.How would you write that statement.I've tried using count a few ways, but no cigar.
View 2 Replies View RelatedI have returned the below mentioned lines of code however I am receiving error "Syntax Error On Done Statement".
while:
do
clear
echo "-------------------------------------------------------------------"
echo "Main Menu"
echo "-------------------------------------------------------------------"
echo "[1] Today's Date"
echo "[2] Show files in the current Directory"
read yourch
case $yourch in
1) echo "Today is `date`,press a key ........";read;;
2) echo ls -l;read;;
*) echo "Select the yourch as 1 or 2";
The script that Iam trying to write is running a for loop and reading line by line from a text file. inside this for loop i would like to execute update SQL statement .
a pesudo code is
Quote:
`$ISQL -U $username -P $Password -D $Dbname -I $INTERFACE <<QRY
for id in $idlist #idlist iam reading from a file
[code]...
It is under PHP/MySQL
$queryresult = $conn->query("INSERT INTO normalrequests VALUES($finalkey, 1234, 5678, FALSE)");
It is connected to the database successfully but I feel there is something wrong with the statement up there.
This script that I found online does the job it promises. it does convert the files to mp3 without an issue. What I need to include now is an if statement that says If $file.mp3 exists then delete $file.wav
Code:
#!/bin/sh
# name of this script: wav2mp3.sh
# wav to mp3
# Credit to the script creator (Nikesh Jauhari):
[Code]...
After that I'm stumped as to how to do the if statement
I want to match for this string:
Code:
Content-Transfer-Encoding:[:space:]base64
Content-Disposition:[:space:]attachment;[:space:]filename="%variable%"
Both lines are new lines, so they won't be inline. Other than that, they are all constants, I want this regex match to be an if statement rather than returning match string. so if the $content variable contains some string that matches:
Code:
if `sed "//p"` ;
This is what I have
Code:
When I run the program it will print
Quote:
rather than
Quote:
And completely ignore the kbd.nextLine statement.
However, when I write next instead of nextLine, it works.
A question of ODBC correctness - maybe someone knows.
Code:
// statement handle is sth, connection handle is dbch
SQLExecDirect(sth, ...);
// ... bind var, fetch results ...
SQLFreeHandle(SQL_HANDLE_STMT, sth); // free statement handle
SQLEndTran(SQLHANDLE_DBC, dbch, SQL_COMMIT);
(error checking removed for clarity).
To my mind this seems wrong - surely the statement handle should be free'd only after the commit is done? Or maybe not. I theorize about the ODBC library like this: a whole set of statements can be created, run, executed in one transaction (which is held at the connection level), and only after all that is a commit/rollback done. So maybe it's OK. Even so it still feels weird. What is written above works, but there are rare and very difficult to replicate problems with this code, and I wonder if a premature free might be the cause...?
how do I get this regular expression to work in an if/else statement? This is just a little script for learning BASH. don't be too harsh.
This script will test if a certain number of files with 1-4 in their filename exist and print their filename. An error message will be printed if not.
#
for i in `ls file[1-9]`
do
if [[ "$i" == *1-4 ]] ; then
echo "This file, $i, ends in a number between 1-4"
else
echo "Error, this file, $i, does not end with a number between 1-4"
fi
done
I get this error. ./file_test.sh: 13: [[: not found
At the moment I got my md5sum checking working which I write to a text file and see below.
If the md5sum works it will write the output to check2.md5 test.txt: OK
If the md5sum fails it will write test.txt: FAILED
How do I write if statement to check the output whether or not the md5sum failed or not ?
check1="/home/ops/Desktop/test1/check1.md5"
check2="/home/ops/Desktop/test1/check2.md5"
cd /home/ops/Desktop/test1
md5sum test.txt > $check1
[Code]....
adf 32 324 100 100 24 234I want a gawk statement to match the above line if lets sayand field between 4 and 6 == 100.
View 2 Replies View RelatedI was doing an exercise on Learning Perl, 3rd edition. (exercise chapter 10 btw) The problem asks to create a program that generates a random number and asks the user to guess. It should tell the user if the guess is lower or higher and exit if the user types either exit or quit. My code is the following:
Code:
#! /usr/bin/perl
$correct = int(1+rand 100);
[code]....
As you know that GNU-C provides qsort() function in <cstdlib> in this prototype
Code:
You may know about Selection Sort Algorithm already, I want to write a function to perform Selection Sort but it can apply generally for many type: int, long, float, double... like qsort() above.
GNU assembler 2.17 (invoked as 'as').
Is there a way of setting no case sensitivity in as?
I'm having this problem with this piece of code, and i don't really get what the problem is, maybe is because i am already too sleepy to concentrate enough but maybe
switch(plazo){
case 1:
plazo = 12;
[code]....
I want to display 4 options using the case command and refresh the screen when options 1 and 2 are chosen (no changes to the options and you get asked again to chose option), but give a message for option 3 and exit on option 4. I set this up with the script below, but choosing option 1 works and choosing option 2 exits the script.
Code:
#!/bin/bash
#testing options
Option="0"
[code]....