I'm building my first BASH programs and I have a hard time. I can't do a search in a folder and filter only script files without extension, the problem is to differentiate the script files from the others. I tried with ls I tried with find and i don't find a way to make it work.
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i have a sample that looks like this:
Code:
[schneidz@hyper temp]$ wget -q --output-document=- http://world.needforspeed.com/SpeedAPI/ws/game/nfs-w/leaderboards/events
[code]....
I would like to know how to use grep command to filter the log files created between 3:00 PM to 4:30 PM in buch of log for whole day in different headings. This files resembles like sar file in linux.
View 5 Replies View RelatedI need to rename the resulted searched files from a loopI have the following code:
find . -name DOC* | while read i
do
find $i -type f -name '*.txt'
done
basically, I am searching for all txt files inside any folder starting with DOC name.this code is working fine with me.I need to rename those .txt files to .txtOLDOS: Ubuntu 10.4Bash shell
I am an uploader to a various hosts, so this tiny script me a lot. I make a rar archive and split files with 100mb. I could get 3-4 or even 76 parts of rar files and it would take me some time to paste all these urls to remote upload function of filehosting sites. For example:
Code:
server:/home/cober/downloads/teevee# ls -al
total 358784
drwxrwxrwx 2 root root 4096 Dec 8 19:38 .
[code]....
I have a lot of filenames (strings) following the same convention
m02_+1+7_London_0000$01.cfg
m02_+1+8_London_0000$01.cfg
m02_+1+8_London_0000$01.cfg
[code].....
What I want to do is to create a script that will interpret the following string and save into variables part of its name
m02_+1+7_London_0000$01.cfg as
------X-Y--City---------
X=1
Y=7
City=London
[code]....
then I want to copy the files that go all the files with the same City and X and Y to the same subfolder City/MX.Y I will need some help start doing that. And I think the first would be to get part of the filenames strings into variables.
I am trying to find a nightly backup if it was successfully copied over, rename it and curl, but it's always passing the check even if the file is older than specified. From the command line it does as it should. Example is here;
Code:
find /backup -type f -mmin +4440 -exec echo "found" {} ;
- nothing returned (good). Then I change the time
[code].....
I'm making a small script for searching and doing some operations with photos, but I'm kinda stuck on this little function:
Code:
function findallformat {
prefix=""
if [ $1 = -pre ] then
[code]....
That function should find for every file with a certain type; and you can specify a prefix using a "-pre" followed by the prefix that you want to search. The format should be "stackable", so you can use as many types that you want, without repeating the same function on the code.
Example: findallformat -pre IMG_ .JPG .CR2 #That should search files that start with "IMG_" and finishes with .JPG and .CR2. My problem it's that, when I try to use it on the script, it says "bash: syntax error near `token' unexpected `}'"
I want to catch some outputs in two different log files in bash, file simple.log and all.log So far, the script is started like this:
Code:
xterm -e "(./myscript.sh | tee -a simple.log) >& all.log"
What I want is:
- In simple.log, I want all the stdout but WITHOUT errors.
- In all.log I want BOTH stdout and stderr.
So all is ok, and the output becomes:
all.log
Code:
starting copying files
mv: cannot move ... : permission denied
copying completed
simple log
Code:
starting copying files
copying completed
But, in the new xterm, I'm loosing stdout. There is no output.How can I have the files logged as they are but also have the stdout in the xterm.
I'm trying to rename a lot of files getting rid of the space on the names. For that purpose I wrote this very simple bash script, but for some reason is not working.
Code:
for i in "$(ls)"
do
j=$(echo "$i" | sed 's/ /_/g')
mv "$i" "$j"
done But what I get in return for each line is just one long file name with all the file names concatenated. I've tried with echo -e "$i" as well with no results. This has to be something really simple that I'm missing but I just can't see it.
I am trying to write a simple script to list all the files in a directory. The script I wrote was as below where the pdb_files is a directory and all the files which I want to list are in that folder.
Code:
files=`ls -F pdb_files/*THERMO*`
for inFiles in $files
do
echo $inFiles
[Code]....
I have around 600 empty text files that I need to add the name of this file as part of the data, I meanfiles from "file1.txt to "file599.txt, all of them empty, and I need to get the name inside the file, so, when I open the file show the name as part the data "file1".these files were created on my web site, I am thinking in a small script in bash
View 5 Replies View RelatedHow can I iterate over all the files in the current directory to check for certain permissions? This is what I have:
Code: #!/bin/bash
for file in *.tar.gz
do if [ -r "$file" ]
then echo "$file is readable"
else echo "$file is NOT readable"
fi done
But this only checks that the current user has read permissions for each file. I want to check that the group "others" has read permissions for each file. How can I do this? Is there a built in function to check if a file has read permissions for the "others" group? Otherwise, I thought I might be able to use this:
Code: $ stat --format=%a file
744 And parse the output "744" and make sure the 3rd number is between 4 and 7 (since the octals 4-7 have read permissions for others).
Never mind, I figured it out myself. Firstly, the old version of BASH I'm using doesn't support
Code:
for i in {1..27}
So I had to use
Code:
for i in 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27
Secondly, it was simply
Code:
#!/bin/bash
for i in 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27
do
[code]....
I have about 50 files that the script will operate on, they are all located in the same directory.I need a bash script that will operate on all files in a directory. The script needs to add two lines to the beginning of each file based on the file name, and one line to the end of the file.A file named myfile.h should add these two lines to beginning of the file:
Code:
#ifndef MYFILE_H
#define MYFILE_H
[code]....
i was wondering if there's a bash script to check the amount of files in a directory with an IF statement..
View 8 Replies View RelatedI have wrote a 1 line command that parses a file, locates the IP Address in the file and then trims the output the way I want it, and then sorts numerically and by uniqueness and then >> appends to output.txt
I can get all the IP's into 1 file "output.txt", but what I am really looking for is some type of way to create a text file, for each IP it finds labeled xxx.xxx.xxx.xxx.txt and also put that ip address into that file..
xxx.xxx.xxx.xxx = the ip address it finds
However, the ffmpeg command generates a temporary file blahblah.mpg.tmp of about 1GB per hour of transcoded video.My issue is that I can't seem to delete these files automatically from any bash script.Now from the command line, I can cd to the directory and just rm -f *.tmp and they get deleted. However, from my script, that same command doesn't remove those files. I thought maybe the file was in use, so I put a sleep command in for like an hour before the delete happens, but it still fails. I also put rm -f /mnt/mythtv/*.tmp in a root cronjob and it still doesn't delete the files.
If I just rm *.tmp I do get a prompt about "Are you sure you want to delete this write protected file?". But the -f switch seems to work fine as a normal user from the command line and just delete them.Does anyone have an idea how to troubleshoot this problem? The particular filesystem that the tmp files get generated on is on it's own xfs partition mounted as /mnt/mythtv.
I have to copy some log files with a cron job; I'd like to copy only the newer files added because I run the script with a weekly cron. all the log files are named like "10-03-29.CVS" and reside in a dir. When I copy I'd like to copy only the files not already copied with the last cron job.
View 8 Replies View Relatedbash script to give sensible names to a large number of photos. I hope to be able to run a script with an argument which will become the filename followed by a number beginning at 1.
Code:
./file_rename.sh Summer2009_
Summer2009_0001
Summer2009_0002
Summer2009_0003
[Code]....
i want to find all files with .h or .c extension and print them on the screen. How can i do it with bash script programming?
View 5 Replies View Related*I'm using Ubuntu 10.10
My issue is I can't handle the files with spaces in their name, I've donde the below script to print each file found inside folder and subbfolders with "find".
I would like to "ls" to each file found with its complete path and with its basename too.
Code:
files=$(find . -type f)
for each in "$files"
do
ls -l "$each" # 1rst option I've tried to list with full path
ls -l "$(/bin/echo "$each")" # 2nd option I've tried to list with full path
ls -l "$(/bin/echo $(basename "$each"))" # 1nd option I've tried to list with it basename
[Code].....
How can I list "ls -l" in both cases (with full path and with basename) when there are files with spaces in their name?
I want to delete all files within a specific folder without actually deleting the folder, what is a good bash command for this?. I found this one but encountered some errors even though I am executing it within the specific folder:
useratdebian:/home/user/folder# find . -type f -exec rm -rf {} ;
[1] 5052
useratdebian:/home/user/folder# find: missing argument to `-exec'
[1]+ Exit 1 find . -type f -exec rm -rf
The command as it appears is:
find . -type f -exec rm -rf {} ;
how to delete only the files contained within the folder called "folder" for example?
How to build a list of files under a directory that may have any permissible characters in the name, that is anything except NUL? The only possible (?) bash data structure to contain a list of such names is an array because NUL cannot be used as a list item separator so no X-separated list can safely be used; there is no "X" that might not be part of a file name. OK -- but how to populate such an array? Here's what I've tried.
Code:
#!/bin/bash
# Set up test files
dir=$(mktemp -d "/tmp/${0##*/}.XXXXXX")
touch $dir/foo $dir/bar
[code].....
I have scowered the internet for the answer to this one. I need a script to rename multiple files to the same exact name, run a program on the file then do the same for the next file. We have a unix backend system that is expecting to load the file with the filename of cards.in So I will have files named card.2009xxx, like i said i will have around 4 or five of those. I want the script to rename card.2009xxx to cards.in, run our unix program on cards.in which inturn changes the file name and once complete i want the script to rename the next cards.2009 to "cards.in"Until there are no more left in the directory and the unix program has processed all the files. All of this is occurring in the same directory. I have written some scripts but they fail by moving for example cards.200901 to cards.in then immediately moving cards.200902 to cards.in and that is not good because it is overwriting valuable data
View 10 Replies View Relatedi have lots of files with dots insde file name for example:
document.1.is.bigger.doc
resume.version12.doc
10.photo.www.cnn.com.jpg
i want to rename all files in that directory to be the same (with same extention) but convert dots to underscore "_"
how can i do that on bash script / php.
I have this cool bash script that I worked hard on. But it broke down when it can across files that had non-English characters. Another small problem was getting it to descend into a directory. If it renamed a directory it would not descend into that dir to rename the other files. I would have to run the script twice on the same directory.
Here is the script:
Code:
find -type d -o -regextype egrep -iregex '(.*.ogg|.*.mp3|.*.wav)' | while read s
do
rename -v 'y/A-Z/a-z/' "$s"
done
find -type d -o -regextype egrep -iregex '(.*.ogg|.*.mp3|.*.wav)' | while read n
do
rename -v 's/ /_/g' "$n"
done
A French name like this:
Code:
Chateau De Sable (imagine accents above the letter a)
became this:
Code:
ch303242tea_de_sable
This is not what I wanted.
Why would the script not descend into a directory after it was renamed?
I've tried a number of suggestions found on the internet and none of them work. Here's one:Code:mv "$x" ~/.Trash/...where $x is the pathname of the file passed to the script.I've also tried different paths to Trash - on Desktop, in Home folder, in my user folder, it makes no difference. Either nothing happens, or more often, the file is simply copied to my desktop or userfolder with the name "Trash".What is the actual path to the Trash folder and how can I move files there? I'm using Ubuntu 10.04.
View 1 Replies View RelatedI have 2 very long files which are quite similar:
file1.csv:
Code:
file2.csv:
Code:
I need this output:
Code:
explanation:
If the fields 3 (serie) and 4 (modello) are identical, the lines of the 2 files should be "added":
Code:
If the fields 3 (serie) and 4 (modello) are different, just print the line of both files:
Code:
Is there a way to do this without reading the (huge) files with a "while read line" loop?
I'm working on a bash script that will go through a directory, find the sub-directories that have been created since the last time the script ran, count the results, and output that integer (will most likely be '1' or less per each instance run) to a file. Give the circumstances, my previous (and very limited) experience with bash is not sufficient for me to pull this off. since it probably has bearing, is that my mail server stores files that it flags as viruses in a folder. It creates a sub-directory for each virus that it quarantines .I want to count those subdirectories and graph them with MRTG. Hence the script. I'm going to post what I've got so far and the purpose of it, because I'm told I have a very odd and efficient way of doing scripting.
[Code]...
But then it dawned on me that it wouldn't work because I would have to not count the directories that have already been counted and count the ones that have not been counted. Given that the purpose of this is to generate a graph about every 5 minutes, using find won't work because, to my knowledge, that will only find things based on whole day values, I need it almost down to the minute.
