how to retrive every portion separately from following file name? DSA4020_frontcover_20346501_2011-05.doc
I want to retrieve informations as below;
name = DSA4020
type = frontcover
id = 20346501
date = 2011-05
is it possible to do with sed??
I have to read a couple of numbers from a random.txt file. In this .txt file there are random numbers. They are separated by a space. Example if you opened test.txt:
test.txt :1 6 1 3 6 8 10 2 4
I would like to read those numbers using CAT and store them into an array:
numlen=${#num[*]} - (must be like this because it is a part of a larger program)
Is there an easy way to get a line from a text file into a variable in a bash script?
I have a file called outside_temp that has a single number, say, 63.2
I would like to make a variable in a BASH script have that value.
I know how to use the input redirection and reassignment of stdin using code...
I'm executing the below bash script, but when the m variable doesn't get any value it becomes empty. I don't want that.
Code:
for i in "$@"
do
m=$(grep TOTAL_MAPS $i | awk '{ print $2}');
totalmaps+="<string>"$m"</string>"
[Code]....
I have the following values in my log file:
...
2010-05-13 11:00:00 k_TRANSFER OK (11)
2010-05-13 11:30:01 m_TRANSFER OK (21)
2010-05-13 12:00:00 k_TRANSFER OK (12)
2010-05-13 12:30:00 m_TRANSFER OK (32)
2010-05-13 13:00:00 m_TRANSFER OK (13)
...
I want to replace every number with it's decrement. For example, the above values should be:
...
2010-05-13 11:00:00 k_TRANSFER OK (10)
2010-05-13 11:30:01 m_TRANSFER OK (20)
2010-05-13 12:00:00 k_TRANSFER OK (11)
2010-05-13 12:30:00 m_TRANSFER OK (31)
2010-05-13 13:00:00 m_TRANSFER OK (12)
I want to read values from a file...these are basically one word values, that is to say that the text file I want to read from contains lines of word length 1, as in:
word1
word2
word3
[code]...
I'm doing some bash-scripting and want to be able to print some text (just plain text) files into the new bash-scripts, created within a loop. Here's a short example of what I do:
Code:
# main bash script #
#!/bin/bash
##Filename
variable1=10
for ((j=0;j<=40;j+=1))
do
## Create another bash-script
echo "#!/bin/bash" >> bash_script_$j
... some stuff...
cat file1.txt >> bash_script_$j
... some more stuff...
done
where the text file (file1.txt) I want to print in the the new bash script looks something like:
Code:
# file1.txt #
...some stuff...
logsave log some_program($variable1)
mv output_$j folder_$j/
... some more stuff...
I.e, the text file contains variables such as "$j", "$variable1" etc that are undefined. Doing the above works for creating new bash scripts (bash_script_1 - bash_script_40) but the variables are not determined. I would like, if possible, to somehow print the text in file1.txt into the new bash-scripts with the variables determined, i.e:
Code:
# bash_script_1 #
...some stuff...
logsave log some_program(10)
mv output_1 folder_1/
... some more stuff...
The text files I read are quite extensive so I would really prefer not having to paste them into the FOR-loop directly.
I would like to grep all values other than encrypted password from /etc/shadow fileFor example,each line consists of 8 fields separated with :/The only thing that I want not to print out is the contents between first : and second : (encrypted password)
View 7 Replies View RelatedI have a fallowing simple bash script:
Code:
#!/bin/bash
echo -n "Please insert your name: "
read NAME
[Code]....
It works fine, but is it possible to have default values using bash read(1b)? I mean if user is prompter for sex, he just pushes ENTER and by default 'm' is chosen. Or if user is prompted for hometown and he doesn't insert anything, but just pushes ENTER button, 'New-York' sis chosen by default Are such default values possible in bash?
I am trying to parse a line from a file and place the values into separate variables:
input.txt:
Code:
CreateVegaFeed-20110928-before-skip-start
this is the code i have done so far:
Code:
$input_file="input.txt"
INPUT_FILE=`cat $input_file`
for i in $INPUT_FILE
[Code].....
I'm trying to get multiple numeric valued version information into a variable, all on the same line. I want for example $VERSION=3.1.0.01.002. I'm trying to pull seperate values from the file named version.properties, wherein the file contains;
patch.rel.num=0
sqa.num=01
major.rel.num=3
build.num=002
minor.rel.num=1
So I have the following script:
#!/bin/bash
BUILDVERFILE="version.properties"
PATCH=`grep "patch.rel.num" ${BUILDVERFILE} | awk {'print $1'}`
SQA=`grep "sqa.num" ${BUILDVERFILE} | awk {'print $1'}`
MAJOR=`grep "major.rel.num" ${BUILDVERFILE} | awk {'print $1'}`
BUILD=`grep "build.num" ${BUILDVERFILE} | awk {'print $1'}`
MINOR=`grep "minor.rel.num" ${BUILDVERFILE} | awk {'print $1'}`
P=`echo $PATCH | tr -d .=[:alpha:]`
S=`echo $SQA | tr -d .=[:alpha:]`
MA=`echo $MAJOR | tr -d .=[:alpha:]`
B=`echo $BUILD | tr -d .=[:alpha:]`
MI=`echo $MINOR | tr -d .=[:alpha:]`
VERSION=$MA.$MI.$P.$S.$B
echo $VERSION #
I end up with the value of .002 ?? Seems like it's only getting the last portion because if I run the script thru "bash -x" I get:
...
+ VERSION=$'3
.1
.0
.01
.002
'
+ echo $'3
.1
.0
.01
.002
'
.002
I create a bash script that writes another bash file. But in the generated bash file I want to write a bash command in the file and not executing it.Here's my bash file:
Code:
#!/bin/bash
cat > ~/generateGridmix2data.sh << END
[code]...
I am splitting a file based on the values read from an input file. The below one is the script.
1)How do I add the header which is present in the original file to the new split files created?(For eg. pharmacyf conatins header as table column names. The new files created (ODS.POS.$pharmacyid.$tablename.$CURRENT_DATE.dat) are without the header).
2) Also the script is creating 0 byte files for the pharmacyids which are not available in the intial file? Can this be avoided?
for pharmacyf in *
do
tablename=`echo $pharmacyf |cut -f4 -d'.' `
while read pharmacyid
do
grep -w $pharmacyid $pharmacyf >> $OUT/ODS.POS.$pharmacyid.$tablename.$CURRENT_DATE.dat
done< inputfile
done
My script.
This is may script:
Code:
Problem: Output file doest not exclude the values in grep -av
This _almost_ works. I just can't quite get it to honor the spaces.
Code:
#!/bin/bash
profiles=(
PROFILE_ONE
)
PROFILE_ONE=(setting1 "setting number 2")
[code].....
I've been searching the forums and google in an attempt to find an answer. I'm completely new to scripting and just want to get one or two up and running but I'm having problems with my current script. I want the script to:read my inputs run a loop in certain steps
within the loop execute a program with output to another file enter the values into the program (Problem area)
Quote:
#!/bin/bash
echo "Enter the Lower value, followed by [ENTER]"
read L
echo "Enter the number of steps you want to take, followed by [ENTER]:"
read s
[code]....
Running the program from the shell asks for 3 variables, which in my script are i, tt and adstep. I understand conceptually why it won't work. It won't move onto the next line in the loop until the previous task is completed (which doesn't even start without the 3 inputs!)
I am supposed to take some small files, and print them to a specific printer, such that the small files are concatenated into one file. The file name has to be included in the file that gets printed.
Should I be looking to concatenate the files into one file with the file names included, and then print them?
something like: -printfunction -printername < file*
I need a shell script which gathers the data from a remote XML file and then displays it according to my needs.. I need this for my job due to the fact that I need to keep track price changes of euro, usd, gold, etc. The XML file I am talking about is located at this page: here. The reason I am posting the URL is that I need to use curl to get this file and it does NOT have newlines after each tag. I thought that that would be a problem. Here is what I need from the script: 1) curl to get the page 2) make use of sed, awk, etc. to display its contents in a more structured and readable manner as shown below:
A: 64.125 (% -0.26)
B: 81.130 (% -0.32)
C: 1.4930 (% 0.00)
D: 1.9590 (% 0.36)
My swap file is 5.8 gb and I have a swappiness of 60. Is there any reason to increase any of these values?
View 9 Replies View RelatedI have a huge binary log file. There are lets say 4 id's that I want to find in a log file. I know that those 4 id's will be present in the log file and I also know in what order they will be present. I want to find 1st id from the log then 2nd id and then third id and so on..
Simple/inefficient solution is: Loop through the id's and then grep in the log file. Problem with this solution is for each id grep will search from the beginning of the file.
Better/efficient solution would be: Sine I know the order in which id's will be present in the log file. Loop through id's, grep 1st id and then move on to grep 2nd id and so on...this way I can grep all id's in one pass. Is this solution possible ?
I have 500000 + values to find in log files and I have to find efficient solution for it.
I have a text file that needs to be updated to be used by some fortran code later. it looks like that:
1,1 !Ms for y-stations, Ns for x-stations
0,0,0, !xsta, ysta, zsta
I need to replace the "0,0,0" with new values for xsta,ysta and zsta;
I have been trying to import e-mails saved in a file with tab spaced values from outlook. When I import the files into evolution it puts them in my address book. I have tried several times and haven't seen any options to change. in the "wizard" it asks me where i want to put the files, but there is only one option.
View 1 Replies View RelatedI have a .txt file with the format
0.01
0.04
0.07
...
0.83
I am wanting to load this into octave and perform operations on the data.
[Code]...
I've created a bash file that calls another bash. And I would like to get the pid from the second file launched, to wait for the file to ends. The second bash file launches processes in background. How can I get the PID from the second bash file?
Here's my code:
Code:
#!/bin/bash
echo "FIRST"
./second.sh
PID=$(echo $!)
wait $PID
echo "CONTINUUING FIRST"
how to update a file that is already exist in bash. so far i haven found any. I'm using parameter as my first start for the existent, copy file to a different directory.
View 5 Replies View RelatedHow do I compare the timestamp of two files? I tried this but it doesn't work:
file1time=`stat -c %Y fil1.txt`
file2time=`stat -c %Y file2.txt`
[code]....
I printed both the time stamps, in order and it gives me
1273143480
1254144394
./script.sh: line 13: [1273143480: command not found
So basically if comparision is not working, I guess. Or if there is any other nice way than what I am doing, please let me know.
Edit: There was no space in between if, so changing it to this works:
if [ $file1time -gt $file2time ]
What's the difference between using > and >>? How can I use both < and > (redirection operators) in a single command?
View 2 Replies View RelatedI frequently use wget to download tarballs and zip files from the web, then either untar then or gunzip them. I do:
Is there a way for me to automatically pass the zip file to tar or unzip WHILE wget-ting?
In pseudocode: wget google.com/somfile.zip && unzip
I have a file named file.txt with the following contents
Code:
19 man
24 house
44 dyam
90 random
I want to read the file into array and store each line in each index. I've tried using the following code.
Code:
dataarray=($( < file.txt ))
It stores each word in each index rather than each line in each index.
total newb here. call me a script kiddie if you want but here is what i need to do and what i have.
need to:search a hidden log file for a specific string, find what comes after that part, and then output the result to a variable or something that can be used by an application or other script to carry out further actions.