I'm executing the below bash script, but when the m variable doesn't get any value it becomes empty. I don't want that.
Code:
for i in "$@"
do
m=$(grep TOTAL_MAPS $i | awk '{ print $2}');
totalmaps+="<string>"$m"</string>"
[Code]....
I have a text file that needs to be updated to be used by some fortran code later. it looks like that:
1,1 !Ms for y-stations, Ns for x-stations
0,0,0, !xsta, ysta, zsta
I need to replace the "0,0,0" with new values for xsta,ysta and zsta;
how to retrive every portion separately from following file name? DSA4020_frontcover_20346501_2011-05.doc
I want to retrieve informations as below;
name = DSA4020
type = frontcover
id = 20346501
date = 2011-05
is it possible to do with sed??
I have a file in the form below, and wish to replace each start line with an increasing number. So instead of:
Code:
start
content content
start
content content
start
[Code]....
After several searches and a bit of messing around, it's clear I'm missing something, so was wondering if anyone could offer any insight?
I have to read a couple of numbers from a random.txt file. In this .txt file there are random numbers. They are separated by a space. Example if you opened test.txt:
test.txt :1 6 1 3 6 8 10 2 4
I would like to read those numbers using CAT and store them into an array:
numlen=${#num[*]} - (must be like this because it is a part of a larger program)
I am looking for a way to delete the currently entered commandline without wasting seconds on the "Backspace"-key.
For example I scrolled the bash history and have a long commandline that would execute when I pressed ENTER:
~$ aptitude search openssl | grep dev
But now I decide that I do not want to execute this command. Can I get an empty prompt fast without deleting the whole line with Backspace? On the Windows "cmd" you can just press ESCAPE and it is gone. This behavior would be what I want.
The question may seem trivial but this is bothering me for a long time now.
I have an Ubuntu server in which a file is dumped every hour and a new file for the next hour and the process continues. If there is any problem due to which the creation of file stops then empty files are created every minute till the process is killed & started again. I need help to make a shell script to check if the empty files are being created and then kill the process and start it again.It would be a great help if anyone can help me regarding this.
View 9 Replies View RelatedI have lines in some files that look exactly as below, and the line numbers they occur in are always the same. (Lines 136-139)
W 0.00000000 0.00000000 2.00000000
W 0.50000000 0.50000000 2.50000000
W 0.00000000 0.00000000 3.00000000
[code]...
I'm not overly great with bash scripting. I do more batch file stuff for Windows than anything else but I'm trying to branch out a bit. (Frankly, I'd love to do this in Ruby but I'm not there yet...) Maybe I'm not using the correct terminology and that's why my searches are coming up useless...
Anyway, I have a script that does some work with HandBrake. Although it deals with HandBrake, I think the issue is not with HandBrake itself. The issue: I had a simpler script which worked fine but it would give me an MP4 with a file name of: Some Movie Name.iso.mp4 and it would still play but I wanted to get rid of the .iso in the file name. I also wanted to drop it into another directory during the encoding. That's why you see a $source & a $destination variable.
handbrake.sh
Code:
#!/bin/bash
source=/media/data/movies
destination=/media/data/movies/mp4s
[Code]...
Is there an easy way to get a line from a text file into a variable in a bash script?
I have a file called outside_temp that has a single number, say, 63.2
I would like to make a variable in a BASH script have that value.
I know how to use the input redirection and reassignment of stdin using code...
I have a fallowing simple bash script:
Code:
#!/bin/bash
echo -n "Please insert your name: "
read NAME
[Code]....
It works fine, but is it possible to have default values using bash read(1b)? I mean if user is prompter for sex, he just pushes ENTER and by default 'm' is chosen. Or if user is prompted for hometown and he doesn't insert anything, but just pushes ENTER button, 'New-York' sis chosen by default Are such default values possible in bash?
I'm trying to get multiple numeric valued version information into a variable, all on the same line. I want for example $VERSION=3.1.0.01.002. I'm trying to pull seperate values from the file named version.properties, wherein the file contains;
patch.rel.num=0
sqa.num=01
major.rel.num=3
build.num=002
minor.rel.num=1
So I have the following script:
#!/bin/bash
BUILDVERFILE="version.properties"
PATCH=`grep "patch.rel.num" ${BUILDVERFILE} | awk {'print $1'}`
SQA=`grep "sqa.num" ${BUILDVERFILE} | awk {'print $1'}`
MAJOR=`grep "major.rel.num" ${BUILDVERFILE} | awk {'print $1'}`
BUILD=`grep "build.num" ${BUILDVERFILE} | awk {'print $1'}`
MINOR=`grep "minor.rel.num" ${BUILDVERFILE} | awk {'print $1'}`
P=`echo $PATCH | tr -d .=[:alpha:]`
S=`echo $SQA | tr -d .=[:alpha:]`
MA=`echo $MAJOR | tr -d .=[:alpha:]`
B=`echo $BUILD | tr -d .=[:alpha:]`
MI=`echo $MINOR | tr -d .=[:alpha:]`
VERSION=$MA.$MI.$P.$S.$B
echo $VERSION #
I end up with the value of .002 ?? Seems like it's only getting the last portion because if I run the script thru "bash -x" I get:
...
+ VERSION=$'3
.1
.0
.01
.002
'
+ echo $'3
.1
.0
.01
.002
'
.002
Using awk I pull the first field of a random line from my datafile.myvar1=`awk -F" " 'NR=='$randline' {printf "%s", $1}' myfileThis works fine. The problem is there will be empty lines at the end of the file. Rather than using awkto filter out blank lines I would like to figure this out first.So I test $myvar1 for a blank string after setting $randline to one that I know is blank:test -z "$myvar1" && echo "true" || echo "false"But, this returns "false"? So the string is not zero length. Why? It's a tab-separated file. Is awk storing the tab with the $1 field or something.This is where I get headache. I try to echo my variable to see what it looks like.
echo "$myvar1"
outputs: nothing
echo "My variable is [$myvar1]"
outputs: [y variable is [
Why is the closing bracket at the beginning? What character could be stored in $myvar1 that would do such a thing and how did it get there?
This _almost_ works. I just can't quite get it to honor the spaces.
Code:
#!/bin/bash
profiles=(
PROFILE_ONE
)
PROFILE_ONE=(setting1 "setting number 2")
[code].....
I've been searching the forums and google in an attempt to find an answer. I'm completely new to scripting and just want to get one or two up and running but I'm having problems with my current script. I want the script to:read my inputs run a loop in certain steps
within the loop execute a program with output to another file enter the values into the program (Problem area)
Quote:
#!/bin/bash
echo "Enter the Lower value, followed by [ENTER]"
read L
echo "Enter the number of steps you want to take, followed by [ENTER]:"
read s
[code]....
Running the program from the shell asks for 3 variables, which in my script are i, tt and adstep. I understand conceptually why it won't work. It won't move onto the next line in the loop until the previous task is completed (which doesn't even start without the 3 inputs!)
Bash acts weird in 10.04 server. Whenever I try to run .sh scripts, every empty line in the script results in "command not found". Then on even simple scripts I get syntax errors, but the same exact scripts work on my 9.10 desktop installation. There's also another problem, I'm not really sure if it's bash-related. After setting the proxy using
[Code]...
I am trying to understand the join command. I wish to join two files:
Code:
$ cat test1
a 0
b 2.51
c 19.85
$ cat test2
a 0
b 2.51
[Code]...
this is great but I do not understand why join ignores the -e flag and fails to insert FOO in the empty field.
I am a final year student doign Computer systems engineering and just been introduced to linux. While still strugling to catch up with the commands, I am now given an assignment under shell scripting.I seriously am strugling to understand this question, can you please assist me.Here follows the assignment:
Operating Systems III
Some tips
e.g. (test if a file is empty, if it is then display "file is empty" otherwise display
[code]....
I want the output of this file to be in a column, not next to each ohter. I tired putting a a newline escape character in a few places, but it breaks the script. It is easy in awk, just ls -ltr | awk '{print $8 }'
casper@casper-laptop:~$ pwd
/home/casper
casper@casper-laptop:~$ ls -ltr > /tmp/outfile
casper@casper-laptop:~$ cat -n /tmp/moreawkreplace
1#!/usr/bin/perl
[Code].....
Possible Duplicate: replacing dot in string, but leaving last one replace the "." [dots], but leave the last one: e.g.: .txt [there could be random number of dots in the string, even zero, i just need the last one]
$ echo 'someth.ing.something.txt' | SOMEMAGIC
someth-ing-something.txt
$
Is there any working commandline alternative to # find /some/dir -group xxx -user yyy | chown xxxxx:yyyyyThe main purpose is to replace ownership and goup of certain files in subdirectories. Or nevertheless I need to write shell script for that simple operation ?
View 5 Replies View Relatedhow to replace following text in the file name.cfg ?I need to replace
name:=inet.hr=>1|inet.hr=>1
with
name:=none
I am using
sed -i 's/name:=inet.hr=>1|inet.hr=>1/name:=none/g' name.cfg
assume that i am having the following line in a file called file1. triumph and disaster must be treated same. I want to replace this line with. follow excellence success will chase you. is it possible to do this using sed. if possible kindly post me the code.
View 6 Replies View RelatedI have a line like
port = 2566
I want to replace it as
port = 8080
how to do this in shell script. when i tried to do this with sed
sed -i 's/port=.*/port='$3'/' /root/$2
it is not recognizing spaces , it works only if line is port=2566 .
I need to replace a value in a file. For example the content of data.txt file is:
1 1 23
2 1 42
3 2 52
4 2 62
5 1 77
6 1 88
7 2 99
8 1 100
Could I substitute 2 in second column with 3 using awk and or sed or other command so that the data will be change as follow?
1 1 23
2 1 42
3 3 52
4 3 62
5 1 77
6 1 88
7 3 99
8 1 100
I have just re transcoded a bunch of avi's. to tell the new ones from the old ones I put '[xvid]' at the end of all the new avi's. but now I have deleated the old avi's I want to remove the [xvid] part of the file name. This is what I have so far
Code:
#!/bin/bash
for name in *.avi
do
newname=`echo "$name" | tr -d [xvid]`
[Code]...
Code:
# ps
22355 pts/3 00:00:00 bash
#
# ps -l 22355
F S UID PID PPID C PRI NI ADDR SZ WCHAN TTY TIME CMD
0 S 519 22355 22354 0 75 0 - 1338 wait4 pts/3 0:00 -bash
#
# ps -o pid,priority,command 22355
PID PRI COMMAND
22355 15 -bash
#
Why are the priority values of the process different? What is the difference? Is the value 15 the "nice" priority? Then, what is the value 75? Please, explain the difference of each result.
I couldn't really decide where this should be posted, but this is the most general of the forums. Anyway, I've been playing a wargame on intruded.net in which some of the challenges require me to pass hexvalues into the programs as character values. All is well with this, and usually I would use the shell to pass it in, but most of these programs use the gets() method to get my input.
Here comes the problem... The other day I was using my desktop which runs slackware 64 13.1 to do these challenges. My method was to use "echo -e 'xefxbexadxde'" to print them to the shell's standard output and then highlight and copy the resulting values to paste to the program. This works just fine on slackware, but when I repeated the same processes on Ubuntu 64 10.04 (which runs on my laptop) the 'xde' always turns up to be 'x00'. Then I tried some other levels with similar responses, not all the hex values convert to the correct ASCII characters.
Is there any way i can pass two / three values to grep. Basically i want to list the lines in the file with three different values. Currently I'm using three grep to get my work done.
EG: more Filename | grep text1 | grep text2 | grep text3
BRs
I have the following values in my log file:
...
2010-05-13 11:00:00 k_TRANSFER OK (11)
2010-05-13 11:30:01 m_TRANSFER OK (21)
2010-05-13 12:00:00 k_TRANSFER OK (12)
2010-05-13 12:30:00 m_TRANSFER OK (32)
2010-05-13 13:00:00 m_TRANSFER OK (13)
...
I want to replace every number with it's decrement. For example, the above values should be:
...
2010-05-13 11:00:00 k_TRANSFER OK (10)
2010-05-13 11:30:01 m_TRANSFER OK (20)
2010-05-13 12:00:00 k_TRANSFER OK (11)
2010-05-13 12:30:00 m_TRANSFER OK (31)
2010-05-13 13:00:00 m_TRANSFER OK (12)