I have two files, where the 1. file has special lines that need to be updated by lines from a 2. file:file1:
foo
foo
foo 0.00 0.00 0.00 pattern
[code]....
I have a file which contains milion of records. It contains 12 columns seperated by "||" (delimeter).
First two fields contain first name and last name of a person. Now my requirement is to delete all those records from this file for which:
First two fields does not contain any alphabet.
For e.g i have below mentioned records in file:
gaurav||gandhi||123||456||789
#a%bcd||123abc||89|90||91
12345||@@@||89||123||234
***||!!!!||98||76||90
Now, last two lines should be removed from this file since first two fields does not contain any alphabet for these two records.
I have such a file(test.txt):
abc 123 456
abc 256 145
axd 125 225
[code]...
I'm writing a bash script to search html files, and when I find any occurrence of an img src tag like this:
<img src="123-picture-normal.jpg" alt="some random user entered text" border="0">
I want to add a second line below it that looks like:
<img src="123-picture-thumbnail.jpg" alt="some random user entered text" border="0">
All I need to do is duplicate the line but replace "normal" with "thumbnail"
Each file can have multiple img src tags with different numbered jpgs.
I have a feeling this is a job for sed, but I'm struggling with it. Any ideas?
I want to search a file for a particular pattern and if pattern found replace the line with new text. i am using awk 'match($0,"pattern") != 0 {print $0} ' filename to check if the pattern exists.how do i get the line number of the pattern and delete that line and replace the line with my new text?
View 1 Replies View RelatedI need to grep a pattern which can be present in one line or could be split in 2 lines.Normal grep wont work in this case. Can anyone please help on this?There are 100's of files in which i need to search for this pattern so time is also a constrain.
View 5 Replies View RelatedIs there a convenient method to find a text pattern that extends over several lines? In this case:
Empty line
LineConsistingOfSingleWord
Preferably to return the line number where the pattern occurs to determine the first such after a known line number. In other words, in order to extract a block of text from within a file.
I am trying to edit a print file.
For every occurence of the ^L form feed character I need to remove 5 blank lines after it but still keep the ^L.
I am a rare user of sed and am ok with the basics but am struggling with this.
Im tryng to replace in specific column and line number within a file where its 3erd column contain the same string in all lines.
[code]....
My goal is to replace only first and last ocurrences of "Normal player", with the following desired output:
[code]....
Im not sure how to use the "IF" and "AND" conditions together. I�ve tryed with the code below, but the script replaces the string for every line.
[code]....
how to replace values for specific column in first and last lines within same AWK script, without taking reference data in other columns?
Using sed, I am trying to append four commas ',,,,' at the end of lines containing the pattern 'Response' in a text file with lines such as these:
6,Pulse,50,254968,14886,NA,,,,
7,Picture,8,265157,0,1,15045,2,0,15000
7,Response,1,271553,6396,1
7,Pulse,50,274969,9812,NA,,,,
8,Picture,1,290232,0,1,15045,2,0,15000
8,Pulse,50,294969,4737,NA,,,,
[Code].....
A function by name abc is called in many files. I want to copy all the lines with the function call to an output file.A simple grep on function name doesn't help me as the function call is spanning across multiple lines as follows:
abc(parameter1,
parameter2,
parameter3);
So I want to copy all the three lines (till semicolon) to the output file.The problem is because there are more than 200 calls for the same function and I cannot do it manually
I have to enhance the behaviour of a backup script written in perl. I don't need to change it, what I need to do is to create a bash script that does some checks like file name and file size, execute the backup script then check if the backup files match the original files.Here's how I try to do it:
- read the files from the original files folder
- store them in an array
- search in the array the files that have a specific file extension
- store the file names that match the search pattern (I know the backup script skips some files so I can hardcode the search pattern)
- run the backup script
- read the files from the backup folder
- store them in an array
- compare the original files name and size stored in an array with those from the backup folder
- send a report email
I have an interesting problem, sed '/pattern/{n;p;}' file, doesn't seem to be catching all of the matches in my file. As an example of this see below.test:
Turn
Turn
Turn
[code]....
What I am attempting to do is rename some television shows into the format that my PVR will understand for the naming convention. I have a script that cleans them up about 95%, now I just cant figure out the last little detail..
For example: NCIS_01.mkv
I think it can be done in sed, but I just figure out how. I need it to be renamed to: NCIS_s01e01.mkv
How can I make sed (or something else) match the last "_" and any numbers after it until the period and then insert text between them reliably?
Depending on the show, it can be something like: This_show_name_243.avi so I need it to be more flexible than I can figure out how to do..
Suppose i have a file(1.txt) separated by TAB delimiter in a line
1 B AB 2
2 C AB 2
if I need to search for the records having B?? using grep.If i need to perform multiple search like line having "C and AB" or "B and AB"??
I want to read from the file and check for the pattern, if the line has some word like <string>: then string should be copied into buffer. Afterwards, I want to insert the same <string> with some word in the next line of the file. use sed command to perform the above mentioned operations?
View 2 Replies View RelatedHow do yo find a pattern with sed or awk and then:
- add a # at the beginning of the line containing it
- and add a # at the beginning of the following 2 lines, too?
Say, I want to comment out the line containing "which 0launch" and the two lines following it:
if [ -x "`which 0launch`" ]; then
exec 0launch http://rox.sourceforge.net/2005/interfaces/ROX-Filer -S
fi
Expected result:
#if [ -x "`which 0launch`" ]; then
# exec 0launch http://rox.sourceforge.net/2005/interfaces/ROX-Filer -S
#fi
I need this because I do not want to comment out every line containing "fi", just the "fi" of this specific if statement.
I have to use sed with this problem, and sed is extremely complicated, they could probably teach a whole class on this entire function.
Here's an example to show what I need to do:
Code...
how would I say that every line before I reach the first match of "sweet" should be deleted so that the output will look like: Code...
I have 8 files, and each contains around 2000 lines. I want to search the particular word in these files between line number 1500 to 2500.
The output should look like:
sample_1.txt :
1510:declare var testing
sample_2.txt :
1610:declare var testing
sample_7.txt :
1610:declare var testing
sample_10.txt :
1710:declare var testing
Is it possible to use grep for this task?
I have a file called test. It has the following contents.Code:there youI want the output to be.Code:replaced youI am trying to use the sed command to replace every occurance of "hey newline there" with "replaced". I tried the following naive apporach.Code:sed 's/heythere/replace/' testThis gives a result containing the same data as the test file.
View 3 Replies View RelatedI have a text file that needs to be updated to be used by some fortran code later. it looks like that:
1,1 !Ms for y-stations, Ns for x-stations
0,0,0, !xsta, ysta, zsta
I need to replace the "0,0,0" with new values for xsta,ysta and zsta;
As much as I didn't want to ask a sed question, especially considering there's already one on this page I've looked as best I could and cant find the solution. Id like to use sed to replace occurrences of a pattern but exclude two or 3 specific lines that are not consecutive. For example I know with 1,10 i could exclude the first 10 lines, what is the syntax if I just wanted to exclude line 3 and 7. The sed command I'm working with right now is for rearranging Ethernets.
cat /etc/udev/rules.d/70-persistent-net.rules | sed -e '/'"$found1fullmac"'/!s/eth1/'"found1eth"'/' > /etc/udev/rules.d/70-persistent-net.rules
I would like to replace $found1fullmac with two variables representing line numbers to exclude from the replacement.
working on a script to update .Jar file, I have tried jar xf to unpack and jar cf to repack it is giving me java.lang.NoClassDefFoundError exception at main class. I also tried jar uf, which is also not working for me Basically my jar file requires to update date, which i do from "winrar" Manual it works fine, but now to remove "Donkey work", i want to make an script which does this all automatically, and the last stage is to update jar file which is not happening.
View 1 Replies View RelatedI am trying to delete lines of a file if they contain text that is present on another file. For example
> cat one.txt:
a
b
c
d
[code]....
I get the following output:
> ./test.sh one.txt two.txt
a
b
d
e
[code]....
i have two files with thousands of line, I am trying to combine these two files but i want to insert each line of one file to the another file after certain lines. I am using awk with the following command but it does not work.cat file1 | awk ' { print $0; if (NR%3004==0) {print "file2"}}' > outputfile
View 14 Replies View RelatedI have several (vhdl) files containing a pattern with newline characters that I need to replace by another pattern that also contains newline characters.
I start with something like:
Code:
I want to replace it by something like:
Code:
(I need to paste some lines)
As I need to do this (very) often I want to use a shell script.
I tried:
1.
Code:
result:
Code:
2.
Code:
result:
File remains unchanged
3.
Code:
result:
Code:
4.
Code:
result:
Displays the unchanged testfile
How I can automate the pattern replacement?
Code:
For example, I have a file called "file" like this one:
type=strongsubj len=1 word=absolve pos=verb stemmed=y priorpolarity=positive
type=strongsubj len=1 word=unique pos=adj stemmed=n priorpolarity=neutral
type=strongsubj len=1 word=absolutely pos=adj stemmed=n priorpolarity=neutral
type=weaksubj len=1 word=taking pos=verb stemmed=y priorpolarity=positive
type=weaksubj len=1 word=friend pos=noun stemmed=n priorpolarity=positive
type=weaksubj len=1 word=usually pos=adverb stemmed=n priorpolarity=positive
type=strongsubj len=1 word=purecolor pos=anypos stemmed=n priorpolarity=negative
type=strongsubj len=1 word=accusingly pos=anypos stemmed=n priorpolarity=negative
I want to add the plural for the noun, for example if find this line:
type=weaksubj len=1 word=friend pos=noun stemmed=n priorpolarity=positive
will add one more line :
type=weaksubj len=1 word=friends pos=noun stemmed=n priorpolarity=positive
where we add "s" for the word friend
I did try to do like that:
<code>
cat file | while read LINE ; do
set -- ${line}
if [[ "${4#pos1=}" == "noun" ]];then
#I tried this line but it doesn't work properly:
v3==$(echo $line |sed 's/$3/$s') #I want to find the third word "word=friend" in that line and add "s" after that word
# I don't know what command to add this new line "$v3" to the file ???
done
</code>
Every now and then I have to indent the lines in my script to 4 space characters. I generally do it line by line. Is there an automated command in vi using which I can indent some set of lines to desired number of space characters in one go.
View 5 Replies View RelatedI'm trying to find the correct sed syntax to match from a given pattern to the end of the file and then append that pattern to the end of the file.
I was trying:
But that prints each line right after its original occurrence. I want to match the block and then append it to the end of the file.
I have a plain text file with 360 lines of varying length text. How do I add a comma or other symbol to the end of each line so that I can convert the file to csv format that I can open in a spreadsheet (45 rows, 8 columns). That means each 8 lines of text forms 8 columns, with 45 rows.
View 9 Replies View Related