I'm having a problem with Vuze locking up when I use the speed scheduler plugin. I never had this issue when I was using them in windows.
Here is whats happening. I have speed scheduler set to pause my seeds during the day. sometimes when it pauses a finished torrent the status of the torrent will be stuck on "stopping". When it does this my bandwidth up and down drop to 0 and I cannot download new torrents. I cannot removed the "stopping" torrent or even restart it. Vuze just kind of locks up. I have to kill the java process and restart Vuse before I can get it working again.
I'm running the latest version of Vuze and the speed scheduler plugin on Ubuntu 10.04.
I am testing version 11.2 (Released version) and have this problem (part of dmesg):
[Code]...
So Opensuse cannot lower the speed of the CPU-cores. I tried updating the BIOS without luck. powernow-K8 under Opensuse version 11.1 (dual-boot) works perfect.
When using make menuconfig - under Device Drivers --> Character Devices --> there should be an option with the label "Enhanced Real Time Clock Support" (CONFIG_JS_RTC).
The problem is that this option seems to only show up while using the menu method when other options are either enabled or disabled and I've entirely forgotten what should be what. I swear fingered it out once.
This is on an older computer (P4) so HPET is no good.
You would think that disabling the HPET option would enable the RTC option but that does not appear to be the case.
I understand I can just add the option to the .config file and avoid this hassle but I'm very interested to know how to make this work.
To show my appreciation I will do something nice for you such as call you a nice name or tell you that you are pretty (or ugly if that's what you prefer).
I'm a very new Fedora user, and I've stumbled upon an issue which I can't seem to resolve. Having had a good look through similar issues, I'm still stuck.I have a Fujitsu Siemens Amilo M3438G laptop, upon which I've recently installed Fedora 14. It seems to work great apart from one thing; CPU speed. The processor in the laptop should run at 2GHz. At the moment, it's running at 600MHz, and I simply can't get it any higher.
I've played around with power profiles a bit, not really knowing what I'm doing, but the issue seems to be that the CPU is somehow reporting to the Operating System that it's top speed is 600MHz.The BIOS on this laptop is very limited, and doesn't give me any clocking options whatsoever, so I can't manually set things like multipliers, etc.So, I guess my first question would be - how does the OS find out what the processor speed is, and is there any way of manipulating the top speed? Surely there must be a way for Speedstep compatible processors to exceed their initial clocks?
I am using FC 2.6.31 kernel and am tying to bring up a SDIO network card. I am not able to change the SDIO clock speed which is by default 50MHz.I have to bring it down to somewhere around 25Mhz to make the card working smooth.How can we set the host clock speed from our driver in this kernel.
I just installed oS11.3 on a new Aspire Revo R3610 which has the Intel Atom 330 chip and Nvidia ION graphics.
I noticed that the CPU is always running at 1600Mhz and doesn't throttle down when there is no load. Do the Atom cpus not throttle down or is there a setting in 11.3 that I can change?
I just wanted to know if having my laptop set to ondemand, will this affect performance in any way? I realize it increases the clock speed to performance when the CPU is under load, but does the time it take to go from ondemand to performance affect speed? Will there be any noticeable difference between the two setups? I have a dual core intel at 2.2GHz when in performance. When ondemand is set with no load it downclocks to 800Mhz.
I'm trying to run a command with the 'at' scheduler in Linux Mint 9. It's basically a ssh connection to my Smoothwall firewall to tell it to shut down, but that part isn't really important. The problem I have is that I can't get the 'at' schedule command to do much. I can type commands into the terminal and they work perfectly. If I enter exactly the same command into 'at' nothing happens.
For example, I can type 'plink -load smoothwall' into a terminal and a new ssh terminal comes up asking for my password to make an ssh connection. If I create an 'at' job with the same command, ie:
Code: $ at now + 5 minutes at> plink -load smoothwall at> <Ctrl-d> $
then nothing at all happens when the 5 minutes are up. I've checked that the job exists by doing an 'atq' command. Obviously there's something about 'at' that I don't understand. I've googled, I've looked in this forum and I've looked in a copy of 'The Linux Bible 2010' all without success. I've tried various alternative ways of entering the command for a couple of hours and I'm still stuck.
I recently loaded ubuntu 10.04 on an older laptop to get a feel for using a GUI version. I would like to setup a recurring job schedule to start sound recorder or Audacity. I would prefer it was from a graphical user interface but would do it with a cron if I could get started.
When I was using Virtual Box in Windows 7, I could choose how many CPU cores to assign to the guest OS. Now I'm using Linux, and when I installed Virtual Box, I couldn't find that option. System Monitor shows that when the VM is busy only one CPU core goes to 100% while the rest are near 0%. How can I make Virtual Box in Linux use multiple CPU cores?
I am using the standalone k10temp temperature sensor but it doesn't give the actual temperature of the cpu, just some "bogus" temp value that isn't very useful.Does anyone know how you can calculate the real temperature from this reading?
Many commands in Mathematica 8 (Integrate, Simplify, etc.) seem to only be using a single core on my system. Is there any way I can change the affinity so that it utilizes all cores for computations?
I have a four-cores machine (core1,core2, core3, core4 ). I want to test the communication or latency between two cores (for example, core1 and core2; core3 and core4). Does anyone know how to write a code to test it under linux operating system?
I have a 8 core computer, which has 8 logical processor in total. I want to create 8 process(nodes). Each node is mapped to each logical processor. The order is code...
I wrote the code as below, could you please see whether it is correct? code...
I am trying to do a comparison of two folders, let's call them dir1 and dir2 and remove any items that have the same file name in both folders from dir2.
i have a problem in finding block of identical strings...i solved the problem in finding consecutive identical words and now i want to expand the code in order to find and remove consecutive identical block of strings... for example the awk code removing consecutive identical word is:
There is a computer with two "Xeon(R) CPU X5550 @ 2.67GHz" CPU. The Hyper-threading is enabled, so it looks like 16-core system, but really there is only 8 physical cores.
I know that when hyperthreading is enabled, each physical core is splitted into two virtual cores. I want to know, which pair of virtual cores shares a physical core and which are not. Or, how (in what order) will Linux enumerate HT-cores comparing to real cores. (enumerating is done for sched_setaffinity and taskset masks).
I have a dump of /proc/cpuinfo file from the system.
I think there are possible:
CPU0-CPU7 are not sharing phys. core. CPU8-CPU15 too. But sharing is in pairs CPU0+CPU8, CPU(i)+CPU(i+8) and so on. or CPU0+CPU1 are from single physical, CPU2+CPU3, CPU(2*i)+CPU(2*i+1). or exotic CPU0+CPU15 sharing, CPU1+CPU14 ... or random?
The hard moment in this case is that there are 2 physical dies of CPU (two sockets), and usual recommendation of using "physical id:" field can't help
The cpuinfo:
processor : 0 vendor_id : GenuineIntel cpu family : 6 model : 26 model name : Intel(R) Xeon(R) CPU X5550 @ 2.67GHz
/media/A and /media/B should be identical, but I want to confirm before deleting one.
Duplicate file finders don't work, because they'll find two copies of the same file within B, for instance. I only want to confirm that every file in one is identical to the other.
diff -qr /media/A/ /media/B/ seems to work, but the output is cluttered with garbage like
diff: /media/A//etc/alternatives/ControlPanel: No such file or directory
and
File /media/A//dev/tty8 is a character special file while file /media/B//dev/tty8 is a character special file
I can suppress the former with 2> /dev/null, but I don't know about the latter.
rsync -avn /media/A/ /media/B/ also produces a bunch of clutter, like "skipping non-regular file".
How can I compare the two trees and just make sure that all the real files exist in both and are identical?
Need confirmation if the following scenario works for making my client and server as identical?
My local(source) Linux server @192.168.0.2 My remote Linux client @192.168.0.70 On the local system : #df -m Filesystem Mounted on /dev/hda3 / /dev/hda1 /boot tmpfs /dev/shm
On the local system , issue the followings to make client and server as identical : #dump -0uvf - /dev/hda3 | ssh root@192.168.0.70 -c "restore -rf - /" #dump -0uvf - /dev/hda1 | ssh root@192.168.0.70 -c "restore -rf - /boot" #dump -0uvf - /dev/shm | ssh root@192.168.0.70 -c "restore -rf - /tmpfs"
I'm using a very simple conky script to diplay the date and time on my desktop. I've noticed that he conky clock is a few seconds early compared to the time displayed in the right hand side of the top panel (Natty). I guess both displays are based on the same "internal" time, so I'm left wondering how this could happen, and how to sync back the clocks.
It seems that Conky is in sync with the system date, while the panel clock is 2 seconds late (on my system). Checked with while true; do date; sleep 0.1; done
I had cloned a centos 5.6 installation from virtualbox virtual machine to physical box. Everything work fine. However, the time showing in os using date command differs from bios time by roughly 4 hours. I am running ntp services which sync the time with another centos server on the network. It appears that some services are using virtual clock and some use physical clock. How do I get rid of virtual clock and only use physical clock?
I have a HP laptop which can support 1600x900. But after I install ubuntu 9.10 on it, it can only support up to 1280x700. My laptop has a Nvidia graphics card. And i am using GNOME as my desktop environment.
I've just installed Slackware 13.1 in two different laptops for first time. I have some strange internet browsing behaviour in one of the laptops. I've installed 2 internet browsers(firefox,opera) using the directions from Slackbuilds.org and there is also konqueror pre-installed. Moreover I installed Wicd network manager.
I can browse some pages e.g. ..... with firefox very slowly but NEVER facebook. I can browse almost any page, even facebook, with OPERA but very very slowly. The same goes with konqueror... Wicd shows that i am always connected with my WPA wireless network
as we all know Process Scheduler does Process scheduling and its a process as well. I was just wondering that if this happens then the Process "Process Scheduler" should be a part of Process queue as well.
So if there are 5 process are there in Process queue & process scheduler is administrating them then since its also a process, once it puts a process under RUN state it should itself go inside queue because at one instant only one process can get executed on a processor. This is quite confusing for me. Please help me out. I tried to search on this but could not find any relevant topics.