This is what I have right now. Well, I thought I knew sed, and apparently I don't... I tried writing this for someone else, and this has given me trouble, so since the user pretty much figured it out on his own, here it goes.
Say VARR=1, so VARX and VARY contain the above text, appended by 1.
What I am trying to do is replace the text "defaults.ctl.card 0" by VARX and "defaults.pcm.card 0" by VARY. The contents of FILE1 is the file being used to search for both text fields, and FILE2 is the output file. I tried using single quotes, double quotes, and a mixture of both, and no go whatsoever. So my question... What is the proper way of searching for text within a file and replacing with a variable?
I am trying to write a Perl script that can open a file, find text that appears between two identifying strings (for now, "start" and "end"), then modify that text by enclosing it between "term_" and "_term" . Since the identified strings vary, the replacement string becomes "term_$1_term". From looking at other threads in this forum I've been able to get as far as spitting out the modified terms using the following code:
open FILE, "start2.txt" || die ("Could not open file <br> $!"); $text = <FILE>; while ($text=~ s/start (.*?) end//) {
[code]....
The problem is how to get "term_$1_term" into the file in the same while loop, which I'm guessing would be some of variant of "$text=~ s/$1/$term/;" (which doesn't work as it stands).
I am trying to think of a logic where my file contains some data I had to read and do some processing. Issue is that file contains data multiple times. For example:
::::::::::: var1=value1 var2=value2
[code].....
I have to read first paragraph of variables and do some processing and then move on until the end of file. Variable names are same in whole file but for each paragraph the value is different. I can't think of a logic to attain this task. How can I do it? It should be a simple bash script, but I am not able to work out.
Is there any way to use sed to replace certain text in a file with the persons username automatically? Right now i'm using Code: Select allsed -i.bak s/STRING_TO_REPLACE/STRING_TO_REPLACE_IT/g file.foo
I would like it to automatically inject the persons usrname in the replacement string. Is this possible? I've been looking on line at various sed tutorials and I cant quite find what i'm looking for. I also didn't really see anything in the forums search function.Essentially i'm trying to take this file URL...Android.rules and replace all instances of username with the persons actual username automatically.
As indicated in the subject, I want to search a text. If the text is present I want to replace it. But if the text is not present, I want to insert it after first line and before last line.
I want to use SED to do the following: In a text file replace any occurrences of the three character string ZZZ with a quotation mark "and. replace all occurrences of a comma with a semi-colon. It is the S/ / / command which is stumping me on the first issue...inparticular how to get the replace string to be quote.
Something very handy to do in a Linux shell, is manipulating files and strings - essentially parsing data. Write a utility which will scan in a text file and search and replace strings. We also want to keep track of how many strings we've replaced.
I know that my command would look like this: <utility name> <filename> <stringToSearchFor> <stringToReplaceWith> Code: #!/bin/bash
What I have works, but wondering what is the 'right' way to replace the digits with the letters given in this loop? somehow use a case or multiple sed? i thought of a multiple sed or a case but couldn't get it to work
Code:
# ... bcv=$(echo $line | awk -F" " '{ print $1 }' | sed 's/1/q/g;s/2/w/g;s/3/e/g') # and so on
Code:
while read line do bcv=$(echo $line | awk -F" " '{ print $1 }') if [ $bcv == "" ]
i am on processing text tasks And i found that if you assign a text to a variable is chomp'ed automatically the newline
Code:
variable=$(cat file.txt)
The problem is i can only access the items/lines using:
Code:
for line in $variable do echo $line # Other commands done
how do i convert this to an indexed array. More importantly, how do i get access to individual $line[0], ..., $line[n] Another thing, if the file.txt, has lines with spaces it is a mess using the for...in..., but echoing prints line by line...o_0
I want to search a file for a particular pattern and if pattern found replace the line with new text. i am using awk 'match($0,"pattern") != 0 {print $0} ' filename to check if the pattern exists.how do i get the line number of the pattern and delete that line and replace the line with my new text?
But the variable $sentence can not be identified in ' ' . And also you can see I just want to update the old file. But the sed command can not save the file for me ,so I need to write them to a new file and over write the new file .
I'm trying to read content of file to variable and use this variable in for loop. The problem is, when I have c++ comment style in file - /*. Spaces in line are also interpreted as separated lines.
For example:
Code:
Changing $files to "$files" eliminate these problems but causes that whole content of variable is treated as one string (one execution of loop).
(if need be, i think i can just add another line of "-e /s/char/newchar/" if i need to target more charecters or words as needed.) the issue with the above code. . . how do i get it to target whatever text file follows the command? without having to manually designate sed to it each time? e.g. in commanding:
I am on Ubuntu 11.04 and using Libre Office 3.3.2 to compose new documents and am saving them using .doc, .ppt and .xls files. (due to having to share them with others who are on Windows systems)
I have a lot of doc files and I need to search for text INSIDE these files. I am perplexed with the fact that no search tool is able to search for text INSIDE these file types. "cat" can display them of course, but grep is not able to locate text INSIDE these file types. I even tried to save a .doc file as an .odt file, but no luck. The Applications>Accessories>Search for Files does not search INSIDE doc, xls or ppt with the option "Contains the text".
When I grep kernel.exec-shield I get both line, hence I keep over writing the kernel.exec-shield-randomize in my script because it finds them both for my sed commend.
How can I get an exact match with either sed/awk/grep in shell so I can do a find and replace?
Example: sed 's/^kernel.exec-shield =.*/kernel.exec-shield = 1/g' /etc/sysctl.conf will replace BOTH lines
Example: grep "^kernel.exec-shield" find both line and I want it to find only the exact line.
The output of following code is not like it's intended ...
Code:
This is the output:
Code:
Test prepending ...apple is a nice word, hour is a nice word, But of course what I want to do in the first set of commands is to prepend the word "an" to the words "apple" and "hour" in the for-loop.
I want to get the last term of an unknown-sized text line, by usig the awk command. Is there any variable which points to the last term of a text line ? (obviously, y can obtain that term if i knew how many terms does the line have... i.e. awk '{print $12}' ; if we are talking about a 12-terms text line) I wonder if there is an option like $?, to get the last term.
I have an SQL dump, file.sql that has many references to a particular domain, d1.com. I would like to run a command that can replace every occurrence of d1.com with d2.com. I've tried looking into sed before but the man pages are quite daunting.
I have large text files with space delimited strings (2-5). The strings can contain "'" or "-". I'd like to replace say the second space with a pipe. What's the best way to go? Using sed I was thinking of this:
I'm having problems with Tomboy. I have a few hundred note files and I need to go through all of them and replace all instances of "<link:broken>a</link:broken>" with "a". Is there a bash command I can use to do this?
on creating a new perl script which replace IP address from the text file. eg. If in a file, we found any word like 11.222.333.44 then it has to be replaced to XX.XXX.333.44