Programming :: Bash - To Prepend Text To Variable

Feb 13, 2010

The output of following code is not like it's intended ...

Code:

This is the output:

Code:

Test prepending ...apple is a nice word, hour is a nice word, But of course what I want to do in the first set of commands is to prepend the word "an" to the words "apple" and "hour" in the for-loop.

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Programming :: Bash Text To Variable Accessing Individual Text Lines?

May 2, 2010

i am on processing text tasks And i found that if you assign a text to a variable is chomp'ed automatically the newline

Code:

variable=$(cat file.txt)

The problem is i can only access the items/lines using:

Code:

for line in $variable
do
echo $line
# Other commands
done

how do i convert this to an indexed array. More importantly, how do i get access to individual $line[0], ..., $line[n] Another thing, if the file.txt, has lines with spaces it is a mess using the for...in..., but echoing prints line by line...o_0

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Programming :: Prepend To ASCII Text File In C?

Jun 15, 2010

To start off I would like to acknowledge that I am not a very good C programmer and pretty much everything I know has been self taught through mostly trial and error. So forgive me if there is an obvious answer to my question, or if I don't immediately grasp the concepts involved in the possible solution.

Basically, I'm writing an application which will be creating log file entries rather rapidly (potentially hundreds per minute), and I would like each new line to appear at the top of the log file, rather than the end. Opening a text file in append mode is easy enough, but I can't seem to find any obvious way to do the opposite.

I have been looking online and it seems that there exists no standard way to do this, and I have only been able to find a few mentions of how somebody might achieve it. The most common method seems to be using two files and copying the data back and forth between them. This seems like it would be insanely I/O intensive with the number of lines I'm likely to be generating. If this is the best method to use, I will give it a shot; though I am not 100% clear on how to implement it, I am also open to any other ideas as to how to accomplish this, and I don't have to worry about portability since the program already uses Linux-only libraries. So calling out to sed or something is not necessarily out of the question (though I imagine performance would also be an issue there).

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Programming :: Parse Multiple Variable From Text File With Bash?

Jul 13, 2010

I am trying to think of a logic where my file contains some data I had to read and do some processing. Issue is that file contains data multiple times. For example:

:::::::::::
var1=value1
var2=value2

[code].....

I have to read first paragraph of variables and do some processing and then move on until the end of file. Variable names are same in whole file but for each paragraph the value is different. I can't think of a logic to attain this task. How can I do it? It should be a simple bash script, but I am not able to work out.

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Software :: Get Variable From Text File Into Bash Variable?

Jun 10, 2009

I have a text file i that has a mailTo: NAME in it. In a bash script i need to extract NAME and put it in a $variable to use. How do i do this?

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Programming :: Bash - Read Content Of File To Variable And Use This Variable In For Loop ?

Aug 21, 2009

I'm trying to read content of file to variable and use this variable in for loop. The problem is, when I have c++ comment style in file - /*. Spaces in line are also interpreted as separated lines.

For example:

Code:

Changing $files to "$files" eliminate these problems but causes that whole content of variable is treated as one string (one execution of loop).

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Programming :: Reading A Bash Variable In Bash Scripting ?

Nov 26, 2008

I have a config file that contains:

my.config:

Code:

Now in my bash script, I want to get the output /home/user instead of $HOME once read. So far, I have managed to get the $HOME variable but I can't get it to echo the variable. All I get is the output $HOME.

Here is my parse_cmd script:

Code:

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Programming :: Sed A Variable In Bash?

Mar 25, 2011

I have beat this enough and don't get what should have been a very simple thing to do. I build a variable;

Code:
CLIST=java,lua,python,php,perl,ruby,tcl
CLIST will be used by another bash script but I need to replace the commas with a space. I

[code]...

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Programming :: Variable Substitution In BASH?

Feb 17, 2011

Just a simple BASH for loop to read the file path from a text file (clean.txt) echo the variable for debug purposes, and scp it to a server I have using port 50 for SSH.

I've already formatted the entries in clean.txt to handle spaces correctly, using sed replacement.

Example from the clean.txt file:

Code:
/MP3/NAS000000001/Barenaked Ladies/Barenaked Ladies - Barenaked For The Holidays/20 Auld Lang Syne.mp3
/MP3/NAS000000001/Barenaked Ladies/Barenaked Ladies - Barenaked For The Holidays/14 Deck the Stills.mp3

[Code]....

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Programming :: How To Use Bash Variable In C Code?

Feb 16, 2011

I want to write a c program with some shell scripts.Now For a simple C program. I am Setting a variable called val2 in bash, now I want to use bash variable val2 in C code. How do I do that?The above doesn't work (coz its spawning a different memory space and when shell script ends the variable dies with it as per my research but how do I keep them in same memory space)Also Is there any Good reference where they teach how to integrate C and Bash Together?

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Programming :: (BASH) Keep Variable In Scope?

Jul 15, 2011

i've just started to learn about functions in Bash scripting. I'm able to set the functions and execute the commands correctly. However, if my_var is set in the first function and then later in the script in the script the 2nd function is called, it doesn't seem to remember my_var and quits (at least i suspect this is the problem).

Here's my code (it requires yad available via webupd8. org). My specific problem seems to lay in line #27 where if we view the changelog and then exit that window, it returns to the "main" function but any subsequent commands cause a crash. Is this because of the get command on line #29? It's presumably now out of scope after calling menu on line #25?

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Programming :: Bash - Passing Variable To Ssh?

May 8, 2010

I have a file with around 1000 IP addresses in it and I need to be able to ssh into each one of them, run a single command, and then exit. I already know the ssh command I want to run and it looks like this:

Code:

shpass -p [password] ssh -p 10022 -o StrictHostKeyChecking=no root@[ip variable] 'reboot'

(I know shpass is not good to use and keys are the correct way but I don't have any other options in this scenario.) if these ip addresses were in a .csv file, by themselves with no other information, how would I create a script to do the above command to each ip until the end of the file?

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Programming :: Passing A Variable To Bc In Bash ?

Jan 14, 2009

I cannot for the life of me get this little (simple) script I wrote to work. Here is the entire script:

Code:

#!/bin/bash
ASPECT=`mediainfo $1 |grep "Display aspect ratio" |cut -d : -f 2`
HEIGHT=`echo "320 / $ASPECT" |bc`
SIZE=`echo 320x$HEIGHT`

[code]......

An input filename ($1) is fed into mediainfo, which by the use of grep and cut spits out a single number which is the aspect ratio. This is then divided by bc into 320, which gives the desired height dimension for the file that I want ffmpeg to create for me. Finally, ffmpeg runs using the calculated dimensions... Basically, it's the passing of the $ASPECT variable to bc that seems to fail. It looks like bc won't read the output from the mediainfo line... It always crashes out with:

Code:

(standard_in) 1: illegal character: ^M I've tried doing something even simpler like this to debug by just trying it to display the calculation on the screen:

Code:

#!/bin/bash
ASPECT=`mediainfo $1 |grep "Display aspect ratio" |cut -d : -f 2`
HEIGHT=`echo "320 / $ASPECT" |bc`
echo $HEIGHT

and it does the same, so it's definitely bc that won't accept the output from mediainfo.

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Programming :: Setting Variable In Bash With Sed?

Jun 18, 2011

I am killing myself with this, please someone come to the rescue...

Code:
#!/bin/sh
IFILE=$@

[code]...

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Programming :: Variable Which Points To The Last Term Of A Text Line?

Jan 5, 2011

I want to get the last term of an unknown-sized text line, by usig the awk command. Is there any variable which points to the last term of a text line ? (obviously, y can obtain that term if i knew how many terms does the line have... i.e. awk '{print $12}' ; if we are talking about a 12-terms text line) I wonder if there is an option like $?, to get the last term.

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Programming :: Bash Concatenating String To Variable ?

Jan 18, 2011

I have a program that loops over each word in a sentence. I need to append a constant to the beginning and end of each word. It works up until the last word on the line.

Code:

Output:

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Programming :: Bash: Give A Variable The Value Of A Function?

Aug 8, 2010

I was wondering if possible in bash for a variable to take the value of a function, I mean the function returns a value and a variable will take it. example:

[Code]....

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Programming :: BASH - If Variable -eq String Not Working ?

Jan 24, 2010

Here is the code:

Code:

How ever when I run this script I get the following error

Quote:

I just don't get it, I have racked my brain trying to figure out every combination of how I should write this if statement and I can't get it to work.

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Programming :: Bash: Making A Variable Out Of Two Other Variables?

Mar 18, 2010

I need to find the value of:

Code:
$Namenumber
My script asks for the name you want to look up and I want it to return the value of $Namenumber

I was thinking:

Code:
number=$"$name"number
but this returns

Code:
$Namenumber

but does not actually resolve what the variable $Namenumber is equal to.

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Programming :: Bash Redirection With Exec: Specify Fd With Variable?

Feb 21, 2010

Within a bash script, I'm attempting to redirect file descriptors with exec, e.g. exec 3>&1 1>&2; however, I'd like to do something like exec $FD>&1 1>&2, which doesn't work because bash tries to execute the value of $FD. Various placements of eval fail, as well. Is there a way around this, or am I stuck hard-coding the descriptor?

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Programming :: Grep For Variable In A Bash Script?

Aug 19, 2010

I've tried every combination of ' " that I have come across in similar threads on the forum but no luck.. I have 2 files

strings.txt: contains a list of numbers, 4 digits per line file.
txt: contains a lines that I want to grep for the strings.

for example:

>cat strings.txt
3214
8746
2411

[code]....

if I echo $i in the loop, I print out the contents of strings.txt If I put 3214 in place of grep "<$i>" file.txt I get "carls phone number is 3214"

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Programming :: Make Bash Replace The Value Of A Variable?

Apr 18, 2009

I have a program I am writing where I have a for loop and I want to make it substitute the variable twice like:

for ((i=0;i<5;i++)) do
echo $"$i"
done

[code]...

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Programming :: Retain The Eol In Bash Variable Or Ssh Output?

Jan 17, 2011

I have to save the result of ssh/grep into a file to keep the eol ("/n"):

ssh $SSH_OPTIONS $USER@$NODE "cd $LOG_DIR; grep -h '$pattern' log.*" > $file

So that when I grep on the local file again later, it can be printed out with original log lines. Otherwise, the log lines will be dropped and lines becomes concatenated into a single line, e.g., if I rewrite the script in this way, echoing the $result is not a good idea..

result=`ssh $SSH_OPTIONS $USER@$NODES "cd $LOG_DIR; grep -h '$pattern' log.*"`

is there some workaround that I can save it to a variable rather than file but still keep the eol? That will simplify my script and don't need to do all those I/Os!

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Programming :: Java Output Into Bash Variable?

Feb 20, 2011

I have a bash script that calls a java class method. The method returns a string to the linux console when run independently. how can I assign the value from the java method to a variable in a bash script?running the script: java -cp /opt/my_dir/class.method [parameter]

output: my_string if added in a bash script:

read parameter
java -cp /opt/my_dir/class.method [parameter] | read the_output
echo $the_output

the above doesnt work, I also tried unsuccessfully:

the_output=java -cp /opt/my_dir/class.method [parameter]
the_output=`java -cp /opt/my_dir/class.method [parameter]`
java -cp /opt/my_dir/class.method [parameter] 2>&1

How can i get the output stored into the_output variable?

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Programming :: Keymapping Variable For Bash Script?

Jul 5, 2010

Is there a variable which will tell you which keyboard mapping you are using? I want to write a bash script that will change my keymapping from Dvorak keyboard to US keyboard. I cannot seem to find a variable to read from. I was going to use the "if [ ] then; statement".

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Programming :: Using A Variable To Control A BASH For Loop

Jul 3, 2009

I know of 4 different ways to use a for loop:

1. for I in {1..10}; do echo $I; done|

2. for I in 1 2 3 4 5 6 7 8 9 10; do echo $I; done|

3. for I in $(seq 1 10); do echo $I; done|

4. for ((I=1; I <= 10 ; I++)); do echo $I; done

I have a script which uses the 1st form of for loop. I'm trying to modify it to use a variable instead of a static hard-coded value in the section that controls the looping.of the for loop.

I've tried all different ways of quoting and escaping the variable, and the problem is that the quoting chars and escape char are being translated and passed into the loop along with the value stored in the variable.

For example, to change the start value of 1 to whatever value I want passed in through a variable:

Change:

I have tried: {{$a}..10} and {`$a`..10}, to have the variable evaluated first.

I have tried using the eval() function.

I have tried single and double quotes and the backslash escape character.

Nothing I've tried works. It's probably a syntax error.

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Programming :: Sed Script - Searching For Text Within File / Replace With Variable

Feb 25, 2011

Code:
#!/bin/bash
VARR=`cat /proc/asound/cards | grep HDMI | cut -c 1-2`
VARX="defaults.ctl.card $VARR"
VARY="defaults.pcm.card $VARR"
FILE1="alsa"
FILE2="alsa.new"
echo $VARX
echo $VARY
sed "s/defaults.ctl.card*/'$VARX'/g" $FILE1 > $FILE2

This is what I have right now. Well, I thought I knew sed, and apparently I don't... I tried writing this for someone else, and this has given me trouble, so since the user pretty much figured it out on his own, here it goes.
Say VARR=1, so VARX and VARY contain the above text, appended by 1.
What I am trying to do is replace the text "defaults.ctl.card 0" by VARX and "defaults.pcm.card 0" by VARY. The contents of FILE1 is the file being used to search for both text fields, and FILE2 is the output file. I tried using single quotes, double quotes, and a mixture of both, and no go whatsoever. So my question... What is the proper way of searching for text within a file and replacing with a variable?

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Programming :: Send Block Device Name To Bash Variable?

Feb 13, 2009

I'm setting up a machine that's going to be used to test randomly connected tape drives one at a time, and as such, I'm writing the test routine using mt in a bash script, for user-friendliness. The problem is the block device name changes on occasion as tape drives are swapped out and busses are rescanned, so I can't "hard code" a block name into the script.

I know programs like lsscsi and hwinfo will give you block device names as part of their output, but I can't seem to grep anything in such a way as to have the final output be just the block name (ie /dev/st2, or optimally 'st2'), so that I can just have the script read said output, and drop it into the necessary variable.

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Programming :: Assigning Bash Variable With The System Command In Awk?

Mar 1, 2011

I am having all sorts of trouble trying to assign a variable within an awk script with the system command. I know there is a lot of ways around this problem, but for efficiency reasons, I would like to, within my awk script, do something like

system(x=3)

or

system(x=NR)

and, latter on the shell script which calls the awk script, use the variable $x. But nothing is passed to x. I have already tried things like

command = "x=3"
system(command)

and also used a pipeline within the system to pipe it to /bin/sh In fact tried a lot of stuff like that, using $(( )) etc etc etc I can create directories e write to files (yes, i could write to a file and read from there, but I dont think it is efficient, plus I am puzzled).

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Programming :: Bash - Dynamiquely Evaluating Variable Names

May 23, 2011

I'll try to be clear but I think I'm in a mess with my code right now, so it may appear here too

Here is a function. The part I want you to see is the 'eval' sentence.

This works.

It evaluates ${SourceTxt} (which is $1), takes away a part of it and uses it as an array to put data in.

That's alright.

Code:

Now, later, I NEED to count the number of elements in the array(s).

So, I try to do something like....

Which gives me the evaluated name ('#txtFields_email_customers[@]' e.g)

Or

Which gives me nothing....

I was wondering if I was reaching the limits of bash in this kind of capabilities, or if there is a.... bash-like solution. I.e. a good solution

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