Ubuntu :: Comparing Multiple Files In Shell Script?

I've got an interesting challenge for the shell scripting wizards here. I've got a mySQL dump of three files for my amarok database with the intention of copying some files to my media server (cover art) so that I can keep the server the server and not rely on my local machine.

Step 1: Identify any cover art files on my local machine.

I did this with:

Code:
mysql -u amarok -p amarok -e "SELECT * FROM images WHERE path like '%.kde%'" > cover_art.txt
Output looks like this:

[Code]....

What I have here now is the ENTIRE album list in my collection -- and something to compare the IDs in Step 1 against. I'm going to stop here and will update the thread as I get past this stumbling block. "ID" in cover_art.txt = "image" in albums.txt... straightforward enough, right?

So the question is this: how do I create a simple shell script that will loop through the IDs in cover_art.txt (i.e. characters 0 -> 4 -- it will always be a 4 digit ID) and then search for that ID in the Albums.txt file.