I have two text files i want to compare the differances between but i dont wnat all of them, there is only about 30lines of relvent text i want to compare.
I need to count files in a dir which were updated yesterday.
ls -lth | grep -i 'Jul 7' | wc -l
The dir holds files of last 15 days and total count is as 2067476. Is it efficient to count the files using perl? I have developed the following perl script making use of system().
I am looking for some suggestions if possible, regarding processing the files using perl script. Scenario is I have a location where new files will be added always. I need to process these files for some validation. I wrote a perl script to do this and I thought I can rename the files once they are processed in that way I dont process the same files again. But now I can't rename the files due to some restrictions. Second thought, to process them based on date stamp but as my perlscript is being automated and runs every one hour to process the files I can't go by date stamp.
I want to compare the following two tab-delimited .txt files (both were subsets of the original files) by comparing Columns 3 and 4 simultaneously. It is easy to compare C3 because both C3s are just numbers. But how to compare C4s?Basically, in File1, "G,G" = G in File2, "C,C" = C in File2, "A,A" = A in File2, "T,T"= T in File2.In File2, A/T in Column4 just equals "A,T" or "T,A" in Column4 of File1. C/T in Column4 just equals "C,T" or "T,C" in Column4 of File1, and etc.
I am new to perl scripting and wrote a perl script to read the directories and files and count the no of files in each directory and generate a log file. The problem is it is not printing anything to the log file. I am copying the script below.
I need write a script that can compare multiple input files and output a file. The basic idea is:1: All my input files are in the same format2: I want to find in-common lines (in-common 1) from some of my input files (e.g., input1, 2 an 3), and find in-common lines (in-common 2) from the rest of my input files (e.g., input 4,5,6,7). And then, compare in-common1 and in-common2 and remove any overlap from in-common 1.3: Output the remaining in-common 1 file after removing any of its overlap with in-common 2I know how to write this script by putting all the filenames in one script and compare them. But the thing is, if I have more input files, such as 100, it might not be that efficient to write all filenames in one script and compare them.
I am wondering if there is any way to do such as:1: put all input filenames in a text file (file1)2: write a script3: Everytime, when I run this script, it will read in file1 directly no matter how many input files I have, give an output.I want this because I will have more and more input files and I don't wanna add multiple lines in the script just for reading the new inputfiles and compare them with the previous files. So, I guess this is something related to making my script a package or standardize it and make it easy to use in the future no matter how many input files I will have.
I am fairly new to Linux and was needing some help on a comparing more than 2 files. I am try to come up with something that would compare at least 10+ different files to a master file and give me an output of what is missing.
Example would be: a.txt, b.txt, c.txt, d.txt compare each of them to the master.txt file, than output the missing text for each file into new file.
I came across comm and diff commands, am I looking in the right place or is there a much easier way of doing this?
If I have a variable, say xvar, which can take both string and integer value and I want to perform an operation in following 2 conditions:1. Either xvar is null2. xvar equals 2[ -z "$xvar" ] || [ $xvar -eq 2 ] && <some-code>Doesn't seem to work if xvar takes string valuesI know that since I have no restriction on xvar, I can get away with string comparison in second test too, ie[ -z "$xvar" ] || [ "$xvar" = "2" ] && <some-code> But, 'Sams teach yourself shell script in 24 hrs' says that [ expr1 -eq expr2 ], if either is string, it assumes 0 valueIs it true
Is there a way, besides writing a PERL program, to read each line one by one in file A and tell if this line also exists in file B? Can this be done via a shell script?
1. similar nos in both the file 1 and file 2 > output= File 3; 2. In file 1, but not in file 2 > out put= file 4; 3. In file 2, but not in file 1 > output = file 5;
The command sdiff is giving output with symbols > < | etc, and the such output file is not clear and ready to print. I want to print directly the output files. AND ALSO TELL ME WHERE I HAVE TO WRITE AWK PROGRAMS AND HOW TO RUN IT.
I want to compare 2 IP addresses, so that I may compare which is more/less "specific" or "restricted" than the other. So is there any function/library that may help in doing this comparison in C (on Ubuntu 10.10)?
I have two arrays of data, called data1.dat and data2.dat. each contains 60 data. What I want to do is to compare the data in each file and write the counting into bins. It goes like this. First, take the first data in data1.dat file and compare with the 60 data in data2.dat file. If there is any data which is same with the data in data1.dat then it count in bin. The total bins are also 60. Next it goes to the second data in data1.dat and compare with all the 60 data in data2.dat. If there is any data same then it add in second bin. And it repeats to all the data in data1.dat
I've got an interesting challenge for the shell scripting wizards here. I've got a mySQL dump of three files for my amarok database with the intention of copying some files to my media server (cover art) so that I can keep the server the server and not rely on my local machine.
Step 1: Identify any cover art files on my local machine.
I did this with:
Code: mysql -u amarok -p amarok -e "SELECT * FROM images WHERE path like '%.kde%'" > cover_art.txt Output looks like this:
[Code]....
What I have here now is the ENTIRE album list in my collection -- and something to compare the IDs in Step 1 against. I'm going to stop here and will update the thread as I get past this stumbling block. "ID" in cover_art.txt = "image" in albums.txt... straightforward enough, right?
So the question is this: how do I create a simple shell script that will loop through the IDs in cover_art.txt (i.e. characters 0 -> 4 -- it will always be a 4 digit ID) and then search for that ID in the Albums.txt file.
Im trying to compare two files and I only want to display the user names that are in the first file and not the second.
So I have one file named final.txt (which contains every user name and only the user names in a list no other information)
Then I have another file Over1.txt (which only contains certain users that have different permissions This file is also setup differently with the user name and some information about the user after the user name.
I need a way to compare final.txt to over1.txt so that I will only display the names that are in final.txt but not Over1.txt
Ive tried using diff and comm but just cant seem to get it two work correctly. Im not sure if im missing a option or what.
I just downloaded Tk-804.028 and try to install it (according to the README.linux) but I get:
> perl Makefile.PL /opt/ActivePerl-5.10/bin/perl-static is installed in /opt/ActivePerl-5.10/lib okay PPM for perl5.010001 Test Compiling config/perlrx.c Test Compiling config/pmop.c Test Compiling config/pregcomp2.c
