I'm using Zabbix on which I can use give bash command to the agent.This 1-liner will give me all the interfaces with their IPv4 addresses.I have a 2nd expression which returns a checksum so I can detect a difference whenever someone deletes/adds/changes an ipv4 interface.This is the output on my Ubuntu-server:
Code:
~# ifconfig | grep -B1 ' inet ' | grep -oE '(^[a-z0-9:]*|addr:[0-9]+.[0-9]+.[0-9]+.[0-9]+)'
eth0
[code]....
I need to kind of grep within grep. My input file would be something like:
[Code]....
and I need to find the first occurrence of hello before MY PATTERN (hello 9008 in this case), so the output should be:
[Code]....
im writing a cross-platform software (linux/solaris/mac/bsd) so i was wondering, how portable is pthread library? out of 10 linux distros, how many will have it by default? and does it exists on mac/solaris/bsd by default? or user will have to install it?
View 6 Replies View RelatedI have an odd issue that I am running into. My objective is to insert the following lines at the end of /etc/inputrc on an RHES box:
Code:
# alternate mappings for "page up" and "page down" to search the history
"e[5~": history-search-backward
"e[6~": history-search-forward
I would like this sed snippet to be portable and thus far it's worked. However, I ran into one box where after I ran the snippet, Subsequent sessions lost the ability to use the letter "e". The original version I was using looked like this:
Code:
mv /etc/inputrc /tmp/inputrc.orig
sed 's/'$endif'/
# alternate mappings for "page up" and "page down" to search the history
"e[5~": history-search-backward
"e[6~": history-search-forward
&/' /tmp/inputrc.orig > /etc/inputrc
Then instead of using s/ I thought perhaps i/ would be better so I re-did it as:
Code:
mv /etc/inputrc /tmp/inputrc.orig
sed '/'$endif'/ {
i
i
# alternate mappings for "page up" and "page down" to search the history
i
"e[5~": history-search-backward
i
"e[6~": history-search-forward
}' /tmp/inputrc.orig > /etc/inputrc
Both of these produce the expected result BUT they both resulted in the loss of the letter "e". As I mentioned earlier in the post, this was working on 'newer' RHES 5 and up but I have the misfortune of having to support some older RHES 4 boxes in a closed lab. This particular box is an RHES 4u6.
I am trying to monitor how long an ldap search takes and maybe notify or something that a search takes longer than say 10 seconds.
Code:
tail -n 1000 /var/log/ldap.log
for SRCH in $( cat monitorldap.log |grep 'SRCH'); do
echo search string is
echo $SRCH
[Code]....
ok, so to start off with it doesn't appear to get the whole line, just a piece "Aug". How can I get the whole line into a variable so I can then cut it up into the pieces I need?
How can i use grep (or any other command) to check for lines that begin with N number.
E.g. I want to print out commands (from history), but only from the command number 50 until #200.
This one doesn't work:
Code:
history | grep "^[50-200]"
Should print out something like:
Code:
50 cd ~/Desktop
[Code].....
1) I need to search a field value to check for exact 0. If the number is 0, it should throw error.
The line to be searched looks like as below. "Output Rows [1], Affected Rows [1], Applied Rows [1], Rejected Rows [0]"
Here I have to search whether the affected rows is 0. But the code below picks up other values also (lie 10, 20.. etc). How do we write to get an exact match for 0? Code: affected=`echo ${line} | cut -f6 -d" " `
affectedcount='echo ${affected} |grep 0 ` 2) Also, I need to check whether the rejected rows > 0
Code: rejected=`echo ${line} | cut -f12 -d" " `
rejectedcount='echo {rejected} |grep [1-9]`
3)Can we combine these two statements in a better way to get the desired results?
I have a file:
979798707
787862348
766428634
I want to see if all the records in the file are present in the contents of the files of a particular directory.
Basically I want to say if grep doesn't return anything, then report.
For example in /tmp dir I have 4 files and flast 2 values (787862348 and 766428634) are present in the files of /tmp dir, but first one (979798707) is not. I want to echo that in a reporting file.
something like:
while read line
do
# if ! grep -rl $line /tmp
echo $line >> are_not_present
done < "myFile"
How do I achieve " if ! grep -rl $line /tmp"? That is, if the line is found by grep, then grep will print the output, but if grep does'nt find it, it will print nothing. How can I check if grep didn't find it (i.e. printed nothing)?
Can you find an alternative for Code: wc -l using grep?
View 1 Replies View RelatedI'm just starting out with bash scripting (yesterday, really). I want to add a file to each user's home directory, pretty simple really, and send it out via our Apple Remote Desktop system to our Macs. Here is my script: Code: #!/bin/bash
for i in $(ls -d /Users/*)
doif [ -e $i/.tcshrc ]
thenecho "$i/.tcshrc exists!"elseecho "$i/.tcshrc does not exist"
[code]....
i have a sample that looks like this:
Code:
[schneidz@hyper temp]$ wget -q --output-document=- http://world.needforspeed.com/SpeedAPI/ws/game/nfs-w/leaderboards/events
[code]....
I am using Sun 5.9.
I am putting the value "Feb 10" in variable 'c' here.
Code:
-bash-3.00$ c=`date | awk '{print $2 " " $3}'`
-bash-3.00$ echo $c
Feb 10
But when I am grep-ing value of 'c', I am getting this error.
Code:
-bash-3.00$ ls -lrth | grep $c
grep: can't open 10
This is because there is a space between "Feb" and "10".
I want grep multiple files:
let abc.1.abc.2,abc.3,abc.4
I use grep <pattern> abc.* to read the files. But here grep read files in the order of 1,2,3,4 . I want to to grep the files in reverse order like 1st the abc.4 file will be read and abc.1 file will be last.
Is this possible ?
I am interested in using the grep method in the shell of my CentOS machine to obtain patterns from a file and use them to search through another file and highlight the patterns found. For example:
pattern file:
one
two
three
test file:
AAAAAAAAAAAAAAAAAAAAAoneAAAAAAAAAAAAAAAAthreeAAAAAAAAAAAA
I am trying to use a shell script to find a string in a file and do something when found. code...
What should happen is pppd will start in a different process and stream it's output to pppdout. pppdout should be created in the current folder. Then the script should periodically check the pppdout file for the string Script (which eventually will appear, some seconds later) and when found exit the script. Ultimately the script will do something useful when the text is found. However, the output from the program is a repeating: 'scriptname.sh: 12: FOUND: not found'
Where scriptname.sh would be the name of your script and 12 refers to the line with 'done'.
Why does grep not find the text, or at least why deos my script not check the grep output correctly?
Would like to know how to cat the below output.
Code:
grep userlist_file /etc/vsftpd/vsftpd.conf | cut -c15-
Below which is the output for above command.
[code]...
So For example I run this command:
Code:
But want to gerp / cut it in such a way that it only displays
Code:
Now the thing is that these 3 lines are not static.. there can be N number of lines there.. the only thing is that I want the command / output NOT to display the first line but the rest of the n lines ..
I want to know that is there any method to grep a particular data from a file without using the "cat --- | grep ' ' " command....I need to use a system call for this functionality.
View 1 Replies View RelatedI'm trying to write a bash script and I'm having trouble with it.I have a list of DNS entires from a file called zoneExport.txt.Than I want to parse a log file to see if that DNS entry has been queried for. So I'm running a grep command and trying to save it into a variable. What I'm looking for is a variable ($varGrepQ) that has the number of matches for the grep query. I will then run this through an if statement and do some things from there..
But my problem right now is with this grep query. It keeps outputting '0' even when I know there are records in that file and when I run the same query on the command line I get the actual count. My thought is that the $record variable is not passing right.
I want to write some code to search for a specific string in a text file, but without using grep command.
View 5 Replies View RelatedI need to grep a pattern which can be present in one line or could be split in 2 lines.Normal grep wont work in this case. Can anyone please help on this?There are 100's of files in which i need to search for this pattern so time is also a constrain.
View 5 Replies View Relatedif I'd a file like this
something
somethine123
begin something end
begin xyz end
somethingelse
and I want to find the strings only between begin and end, exluding begin and end; How can I grep that?
I have inherited a wordpress theme with a folder of images that I think are no longer being used. I wanted to find the orphaned images using grep, so I wrote this script:
Code:
#!/bin/bash
echo $PWD
for i in *.*; do
cd ..
[Code].....
Its seems like I got some false positives out of it, but it worked pretty ok. I guess. :| Of course, it is not checking for images in the content of the database.
Orphan finding has to be a wheel that is already invented.
I've tried every combination of ' " that I have come across in similar threads on the forum but no luck.. I have 2 files
strings.txt: contains a list of numbers, 4 digits per line file.
txt: contains a lines that I want to grep for the strings.
for example:
>cat strings.txt
3214
8746
2411
[code]....
if I echo $i in the loop, I print out the contents of strings.txt If I put 3214 in place of grep "<$i>" file.txt I get "carls phone number is 3214"
I writing a script to go through multiple reports. I want to grep daemon.debug @10.10.10.10 on all reports to make sure it is pointing to the right IP address. the problems is the space between debug and @10 are different on all the reports, some have one space some have two and some have tabs how do I ignore the tabs or spaces and grep daemon.debug @10.10.10.10
daemon.debug /var/log/ftp rotate size 20m files 4 compress
daemon.debug @10.10.10.10
authpriv.* /var/log/secure rotate size 20m files 4 compress
authpriv.* @10.10.10.10
I am trying a search for a pattern in the file. I can have any character in the pattern. I am pretty sure I will have $, ", ', ^, ` etc., The Problem I am facing is if I use "" (double quotes) to enclose the pattern, it gives special meaning to $, ^ and " within the string. I have no control over the pattern input. I am getting it from some other file. On the other hand, If I use '' (single quotes) to enclose the pattern, it gives special meaning to the ' (apostrophe) within the string and terminates the pattern prematurely. How do I disable the special meaning these characters have? For example, in perl, I could enclose the pattern within Q and E. Is there an equivalent in grep pattern expression? I could find one in the man page of grep. Is there a solution to this problem?
View 5 Replies View RelatedI have the following command that greps "/etc/cron.allow" and displays the following 9 lines of $file grep -A 9 "/etc/cron.allow" $file On the other hand I would like to grep a file for a certain text display the next couple of lines and stop when i hit a specified word or blank or pattern.Basically I would like my grep to end when the shell hits a blank, certain key word or pattern specified in command.
View 7 Replies View RelatedI would like to know how I can get the ouput from the following dmidecode command in example 1 to look like example 2 without having to grep -v all the unwanted lines.Is there a way in awk or sed?Example 1
Code:
Processor Information
Socket Designation: Socket 1 CPU 1
[code]...
I have such a file(test.txt) as below:
[code]...
I want to use grep to fetch the lines contain 'AB_001'.
[code]...
get the first 2 lines, not the 'AB_0011/10/105'.
is there a way for me to grep the process that running more than 30 days only using linux command or script?
example:i do ps -ef to list out the process, then i want to filter only the process that always running more than 30 days..