I'm just starting out with bash scripting (yesterday, really). I want to add a file to each user's home directory, pretty simple really, and send it out via our Apple Remote Desktop system to our Macs. Here is my script: Code: #!/bin/bash
for i in $(ls -d /Users/*)
doif [ -e $i/.tcshrc ]
thenecho "$i/.tcshrc exists!"elseecho "$i/.tcshrc does not exist"
[code]....
I'm wondering if it's POSIX + ASCII or something else is mixed in?
View 1 Replies View RelatedAt my work i have a legacy web system that tells the id of documents based on some given variables. this information can be used in another system to retrieve the needed file.
I am trying to automate this, and have managed to feed the variables and download the correct page using wget. The result is a result.php page with a lot of embedded info.
The information i am looking for is enclosed in single quotes on a line like this:
The information i want is the 1234 part.
I thought i could do like this from bash:
But I always get an empty string back... any idea what i am doing wrong?
regex in grep? I need to match ANYTHING in the following with any character combination (something like * in findstr in C): grep "Delivery of nonspam" /var/log/mail.log | grep "to [URL]"
View 1 Replies View RelatedI need to kind of grep within grep. My input file would be something like:
[Code]....
and I need to find the first occurrence of hello before MY PATTERN (hello 9008 in this case), so the output should be:
[Code]....
I need a regex expression to read IP address from lines like these for my perl script:
Code:
2011.05.13-14:54:58, test@xyz.com, 180.211.51.11, pop3
2011.05.13-14:57:26, test@xyz.com, 160.234.47.12, pop3
2011.05.13-14:57:54, www@abcd.com, 166.22.22.224, imap
2011.05.13-14:57:55, www@somedomain.com, 172.58.22.154, imap
2011.05.13-15:03:08, www@example.com, 190.22.120.44, pop3
In a bash-script, only the case if a regular expression does not match is relevant.herefore I used the exclamation mark !. But where to place it?
These two work fine, but are they equivalent?
Code: if ! [[ $abc =~ $pattern ]]; then or
Code: if [[ ! $abc =~ $pattern ]]; then Where is the ! placed more correct?
I'm using bash scripting to find any file that matches a path governed by the following regular expression:
"(monthly|nightly).[0-9]+/home/(user1|user2)/.mailbox/"
to match files like:
monthly.9/home/user1/.mailbox/l23131564
nightly.15/home/user2/.mailbox/cur/6546213
I've tried:
Code:
myRegex="(monthly|nightly).[0-9]+/home/(user1|user2)/.mailbox/"
find ./ -regextype posix-egrep -regex $myRegex
and it just spins and never gives me an answer, even though the file structure isn't that big.
So those of you that know me will agree that when it comes to awk I don't usually ask a lot of questions ... however this one has me stumped. I am guessing I have missed something obvious but for the life of me (and I have tested at great length) I cannot find it So the scenario is this: The following awk code should identify all versions of libgpg-error within the attached file (see below) and only show one for each version:
[Code]...
I'm writing a script to read user input for a computername.I need a check that a given userinput is valid.Right now I use grep like this (for sure not optimal):Quote:
if echo "$name" | grep -q '[^a-z][^A-Z][^0-9]'; then
echo error
else
[code]....
the following works and BASH doesn't complain, but VIM highlights the closing square bracket is if it sees a syntax error. Is there a better way to express regex in a case statement or is this an issue with VIM?
Code:
#!/bin/bash
case $1 in
[code]...
Code:
g echo ${mm[$j]}
4 BashNotes
[code]...
I'm fairly new to Perl and regular expressions. I have a large collection of files with their file names in the following general format: string - another string with spaces (2004) [year].ext I would like to know how I could create a regex to separate out:
the first string
another string with spaces
year
extension
If you know of a better way of doing it without regular expressions, I would be happy to hear that way too.
I'm trying to find out how to extract the string between the 2 <title> tags: <title>this is what i want</title>.I found lots of results but nothing I've tried works.. EG:$page =~ m/<title>($.)</title>/gism;
View 2 Replies View RelatedI was wondering if you insert a variable into a regex in Perl, will the contents of the variable be expanded by the regex engine?
View 14 Replies View RelatedI have .txt.gz files that store queries made on a browser, d my job is to analyze them.The information is stored in a xml-like style.Quote:
<browser>lwp-trivial/1.41</browser>
<http_code>200</http_code>
<keywords />
[code]...
how do you include a string variable as part of a regex in Perl?
View 5 Replies View RelatedI want to match for this string:
Code:
Content-Transfer-Encoding:[:space:]base64
Content-Disposition:[:space:]attachment;[:space:]filename="%variable%"
Both lines are new lines, so they won't be inline. Other than that, they are all constants, I want this regex match to be an if statement rather than returning match string. so if the $content variable contains some string that matches:
Code:
if `sed "//p"` ;
Im trying to extract the href of a <link> tag from a html page however as some links contain further preferences I seem to be unable to extract them, do you have any idea how I can write this: Link:
[Code]...
am trying to find a proper regex to match the two numbers in the following log entry.
Code:
15:08:16.142 INF Found 64468
15:08:16.142 ERR [Uniform test code=64469]
Basically the pattern I'm looking for will match the two different numbers spanned across two lines.Thought I need to use multi-line mode as follow but this doesn't match on [URL]...
Code:
/^($[0-9]{5}
[0-9]{5})$/m;
How do i use perl regex to extract the hostname from a FQDN?
I have
Quote:
$host=ganymede.a.linux.com
$host=io.a.linux.com
$host=europa.a.linux.com
i just want the characters which are to the left of the first .(dot) in FQDN name. I could get it using substr and split function,but how do i get it through regex.
I have a sed match that matches for certain string of a regex expression:
Code:
tname=$(echo "$contents" | sed -n 'some pattern')
How do I match for multiple strings in the $contents and return them as an array? for example
Code:
contents="this is a text, just to match patterns, here is another text to be matched"
the sed func would be able to recognize both "text"s, but only one is outputted?
Possible to put it in an array? so ${bar[0]} gives one and ${bar[1]} gives another
I'm having a small issue with regex matching in Perl. I'm pretty certain it's a simple fix, but it all looks correct to me...
If I run the following:
Code:
It prints out all the lines containing a 'P', as one would expect. But when the regex is
Code:
I get zero lines printed. It seems to match only single-character patterns.
The file I'm reading is: (It has the same effect whether I leave it with Windows linebreaks or convert them to unix).
Code:
I have written a regular expression (tested in regexpal and regextester alpha something) with which I want to replace something like code...
but it only matches functions which occupy one line only, despite my tests showing multiple line matching in javascript testers online and using the m and s flags (which should make it multi line no?)
I am trying to construct a quick regex that will search for six lines of text without a clear line break between them. It only needs to search, not replace, as I will be using in gEdit (with regex plugin) anyway.
It's for editing subtitle files. The video player I will be using them on can only cope with 3-line subtitles, so I just need to edit any in the srt file that contain four or more. There won't be many so I can do it manually. For example:
26
00:01:47,357 --> 00:01:49,359
a motivated business
professional with
clearly defined goals.
[Code].....
but .* seems to mean "any character, or none", so that doesn't work. My experience of regular expressions is limited, but I do know they are very powerful when used correctly!
What I am doing is reading the text from a text document and storing all of the text inside of a ArrayList. I then set one of the values of the Arraylist as a string. I want to use regular expressions find out what the first two characters of the String are. if first two characters = "//" then function(); I only care about the first two characters though. If you need any more information, just ask.
View 4 Replies View RelatedIts my first post in here so please be patient I am trying to use regex in perl script to detect allowed words from the file and then print output to the screen.
As an example : I have text file with orders and returns :
Item2-SKU-2-11.08.2010-online
Item3-SKU-3-11.09.2010-return
Item4-SKU-4-11.09.2010-store
My question: is it possible to make sure that i am ony outputing to the screen orders based on few conditions like Item,order form e.g. online.And is it possible to have multiple matches (Item2 only diplay if ordered online etc)
I am trying to monitor how long an ldap search takes and maybe notify or something that a search takes longer than say 10 seconds.
Code:
tail -n 1000 /var/log/ldap.log
for SRCH in $( cat monitorldap.log |grep 'SRCH'); do
echo search string is
echo $SRCH
[Code]....
ok, so to start off with it doesn't appear to get the whole line, just a piece "Aug". How can I get the whole line into a variable so I can then cut it up into the pieces I need?
I'm using Zabbix on which I can use give bash command to the agent.This 1-liner will give me all the interfaces with their IPv4 addresses.I have a 2nd expression which returns a checksum so I can detect a difference whenever someone deletes/adds/changes an ipv4 interface.This is the output on my Ubuntu-server:
Code:
~# ifconfig | grep -B1 ' inet ' | grep -oE '(^[a-z0-9:]*|addr:[0-9]+.[0-9]+.[0-9]+.[0-9]+)'
eth0
[code]....
How can i use grep (or any other command) to check for lines that begin with N number.
E.g. I want to print out commands (from history), but only from the command number 50 until #200.
This one doesn't work:
Code:
history | grep "^[50-200]"
Should print out something like:
Code:
50 cd ~/Desktop
[Code].....