1) I need to search a field value to check for exact 0. If the number is 0, it should throw error.
The line to be searched looks like as below. "Output Rows [1], Affected Rows [1], Applied Rows [1], Rejected Rows [0]"
Here I have to search whether the affected rows is 0. But the code below picks up other values also (lie 10, 20.. etc). How do we write to get an exact match for 0? Code: affected=`echo ${line} | cut -f6 -d" " `
affectedcount='echo ${affected} |grep 0 ` 2) Also, I need to check whether the rejected rows > 0
Code: rejected=`echo ${line} | cut -f12 -d" " `
rejectedcount='echo {rejected} |grep [1-9]`
3)Can we combine these two statements in a better way to get the desired results?
I'm trying to find exact matches of some users in the /etc/passwd file using "grep -w", but it doesn't always work. For example, I have the following users:[URl].. So, let's say, I want to search for the user "stewart" (which doesn't exist)
How do I find a string in files in a directory. And these file names begin with letter a. I also want to get the number of occurrences of this string from the grep I run. I tried this: cat * | grep -c string but it searches all files. I just want to search files that begin with letter a
I just want to grep for a n digit number followed by M alphabet. Generally for a three digit number i can give grep [0-9][0-9][0-9]M , but if the digits are increasing it is tough to represent them.
When I grep kernel.exec-shield I get both line, hence I keep over writing the kernel.exec-shield-randomize in my script because it finds them both for my sed commend.
How can I get an exact match with either sed/awk/grep in shell so I can do a find and replace?
Example: sed 's/^kernel.exec-shield =.*/kernel.exec-shield = 1/g' /etc/sysctl.conf will replace BOTH lines
Example: grep "^kernel.exec-shield" find both line and I want it to find only the exact line.
I am trying to monitor how long an ldap search takes and maybe notify or something that a search takes longer than say 10 seconds.
Code: tail -n 1000 /var/log/ldap.log for SRCH in $( cat monitorldap.log |grep 'SRCH'); do echo search string is echo $SRCH
[Code]....
ok, so to start off with it doesn't appear to get the whole line, just a piece "Aug". How can I get the whole line into a variable so I can then cut it up into the pieces I need?
I'm using Zabbix on which I can use give bash command to the agent.This 1-liner will give me all the interfaces with their IPv4 addresses.I have a 2nd expression which returns a checksum so I can detect a difference whenever someone deletes/adds/changes an ipv4 interface.This is the output on my Ubuntu-server:
in case you have been wondering how some websites hide the exact location of a file on their filesystem, just thought i'd share it with the commnity at large in case someone else is looking for something like this.i take no responsibility for how it is used.
I want to see if all the records in the file are present in the contents of the files of a particular directory.
Basically I want to say if grep doesn't return anything, then report.
For example in /tmp dir I have 4 files and flast 2 values (787862348 and 766428634) are present in the files of /tmp dir, but first one (979798707) is not. I want to echo that in a reporting file.
something like:
while read line do # if ! grep -rl $line /tmp echo $line >> are_not_present done < "myFile"
How do I achieve " if ! grep -rl $line /tmp"? That is, if the line is found by grep, then grep will print the output, but if grep does'nt find it, it will print nothing. How can I check if grep didn't find it (i.e. printed nothing)?
I'm just starting out with bash scripting (yesterday, really). I want to add a file to each user's home directory, pretty simple really, and send it out via our Apple Remote Desktop system to our Macs. Here is my script: Code: #!/bin/bash
for i in $(ls -d /Users/*) doif [ -e $i/.tcshrc ] thenecho "$i/.tcshrc exists!"elseecho "$i/.tcshrc does not exist"
I use grep <pattern> abc.* to read the files. But here grep read files in the order of 1,2,3,4 . I want to to grep the files in reverse order like 1st the abc.4 file will be read and abc.1 file will be last.
I am interested in using the grep method in the shell of my CentOS machine to obtain patterns from a file and use them to search through another file and highlight the patterns found. For example:
I am trying to use a shell script to find a string in a file and do something when found. code...
What should happen is pppd will start in a different process and stream it's output to pppdout. pppdout should be created in the current folder. Then the script should periodically check the pppdout file for the string Script (which eventually will appear, some seconds later) and when found exit the script. Ultimately the script will do something useful when the text is found. However, the output from the program is a repeating: 'scriptname.sh: 12: FOUND: not found'
Where scriptname.sh would be the name of your script and 12 refers to the line with 'done'.
Why does grep not find the text, or at least why deos my script not check the grep output correctly?
But want to gerp / cut it in such a way that it only displays
Code:
Now the thing is that these 3 lines are not static.. there can be N number of lines there.. the only thing is that I want the command / output NOT to display the first line but the rest of the n lines ..
Code: $sql="SELECT table1.datetime, table1.user_id, table2.ip, FROM table1,table2 WHERE id='$id' AND (table1.id = table2.id AND table1.datetime = table2.datetime)";
In table2 the datetime fields are about 1 to 2 seconds off due to the source of the data, which I cannot change.
Is it possible via a query match table1.datetime & table2.datetime by HH:MM (ie. to the minute instead of to the second)?
I want to know that is there any method to grep a particular data from a file without using the "cat --- | grep ' ' " command....I need to use a system call for this functionality.
I'm trying to write a bash script and I'm having trouble with it.I have a list of DNS entires from a file called zoneExport.txt.Than I want to parse a log file to see if that DNS entry has been queried for. So I'm running a grep command and trying to save it into a variable. What I'm looking for is a variable ($varGrepQ) that has the number of matches for the grep query. I will then run this through an if statement and do some things from there..
But my problem right now is with this grep query. It keeps outputting '0' even when I know there are records in that file and when I run the same query on the command line I get the actual count. My thought is that the $record variable is not passing right.
I need to grep a pattern which can be present in one line or could be split in 2 lines.Normal grep wont work in this case. Can anyone please help on this?There are 100's of files in which i need to search for this pattern so time is also a constrain.
I have inherited a wordpress theme with a folder of images that I think are no longer being used. I wanted to find the orphaned images using grep, so I wrote this script:
Code: #!/bin/bash echo $PWD for i in *.*; do cd ..
[Code].....
Its seems like I got some false positives out of it, but it worked pretty ok. I guess. :| Of course, it is not checking for images in the content of the database.
Orphan finding has to be a wheel that is already invented.
