Programming :: Grep, Cut, Cat In A Single Command?
Apr 26, 2010Would like to know how to cat the below output.
Code:
grep userlist_file /etc/vsftpd/vsftpd.conf | cut -c15-
Below which is the output for above command.
[code]...
Would like to know how to cat the below output.
Code:
grep userlist_file /etc/vsftpd/vsftpd.conf | cut -c15-
Below which is the output for above command.
[code]...
I have a huge binary log file. There are lets say 4 id's that I want to find in a log file. I know that those 4 id's will be present in the log file and I also know in what order they will be present. I want to find 1st id from the log then 2nd id and then third id and so on..
Simple/inefficient solution is: Loop through the id's and then grep in the log file. Problem with this solution is for each id grep will search from the beginning of the file.
Better/efficient solution would be: Sine I know the order in which id's will be present in the log file. Loop through id's, grep 1st id and then move on to grep 2nd id and so on...this way I can grep all id's in one pass. Is this solution possible ?
I have 500000 + values to find in log files and I have to find efficient solution for it.
I want to know that is there any method to grep a particular data from a file without using the "cat --- | grep ' ' " command....I need to use a system call for this functionality.
View 1 Replies View RelatedThe thing is that the command for sed resembles the following
[code]...
Now if I want to place another command like grep or cut in the address field how do I do it. Actually I don't know the line number. The user has to give it as an input. How shall I do that?
Getting the list of files in the root directory that have changed less than 10 hours earlier, using grep, but without the directories.
View 1 Replies View RelatedI need to kind of grep within grep. My input file would be something like:
[Code]....
and I need to find the first occurrence of hello before MY PATTERN (hello 9008 in this case), so the output should be:
[Code]....
Have this script which is reading in a series of files, one at a time with while-do-done loop, each file goes through various greps/awk's where this info is then saved to various files for later use. i.e....
Script is being run on Linux Red Hat,
In one of the grep/awk's the output (currently) are 2 columns (min max), i.e....| awk '{print $1, $2}' | sort -u which outputs (e.g.)
The number of "min max" pairs varies from file to file. Want to output a single column of unique numbers from the min max pairs & get the number of them for input to a file...i.e...
Where <PROCESS> is some process/technique that will generate a single column of integers (increment of 1) to pipe into the next one (sort -u)
i.e. (example from above)
Have tried command seq - only works for single pair input i.e.
Is there any command like seq etc which will output a single column based on a input of min max numbers (increment 1) to pipe onwards to next command?
I want to find out into some directory, all the files which names are composed of : A specific word README, a litteral "." and any string
file name sample like: "README.string"
how to update a series of values from multiple grep commands outputs to be appended to a single row of a csv file? Work on a linux envir. The values from grep output will be numeric values.
Output sold look like:
1,3,4,5,7,0,5
Each of these values will be odtained from multiple grep commands piped with wc -l Is it possible to update a single row of a csv file if so pleas ehelp me with the command to be used to redirect the output into the csv file
I have question about the UNIX sockets. my goal is to connect multiple sockets from a single client to a single server and keep them open...I'm not sure if that is possible to create or not. Do you have any suggestion or an example of code?
View 1 Replies View RelatedI am intended to simply make printf give "001 002 003 004 006.... 150" but with the single command line of SH (dash) ... not easy ...
Code:
tucholsky:~$ seq 1 1 150 | sed 's/([0-9]+).*/1/g' | tr '
' ' '
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48
[code]...
For the geeks, which distro/version is it, based on the code above
What does this command mean? grep 'GET / HTTP.*Mozilla/5.0 (Windows; U; Windows NT 5.1; ru; rv:1.8.1.1) Gecko/20061204 Firefox/2.0.0.1' last10m |cut -d ' ' -f1 |sort -n |uniq -c|sort -n|tail
Whats the best way to figure out these commands in general? I have a lot of learning to do!
I have a requirement to find the files having its name as ack_reply. However, there are many other files in the same directory as these resides. Now I have to remove these files from the folder and retain others after 7 days. So I tried to write the below script with grep command.
find $directory -type f -mtime +7 | grep ack_reply
how can I pass this output to -exec command.
If I am not using grep command my script would be as
find $directory -type f -mtime +7 -exec remove.sh {}\;;
How can I use -exec with grep and find.
I am using grep to filter out directories I am not interested in like this:svn stat | grep -v data/charts | grep -v lib/model | grep -v web/picsIt seems a bit "hacky". Is there a better way to specify more than one string to ignore, so that I dont have to chain multiple grep commands?
View 3 Replies View RelatedIs there a way to use the grep command in conjunction with an editor such as nano or vi so that I can remove the commented out lines from a conf file and then proceed to edit it ? I can use grep -v "^#^" squid.conf (example ) which gives me a nicely tidy conf file but I can't edit it.Can this command be used with nano or ?
View 6 Replies View Relatedcat filename| awk '{print $3}' | cut -c -3 | cut -c 2- | grep 66
this returns the lines containing "66" at 2nd 2 characters of 3rd column of a line, now i need complete lines for this, how can i do it?
For searching a file or directory i normally use grep command. kindly can you guide me the difference between grep and find command. I have used both but that are the difference between them ? are the same or grep is new as comapird to find command.
View 2 Replies View RelatedSo theres this command
Code:
man -k mail
Which lists commands that contain the keyword "mail" in their description.I want the output of this command in less and the words highlighted by grep. Something like
Code:
man -k mail | grep mail | less
The command doesn't work, how do I fix it?
how to search for those files which contain word "AM_COLLECTION=22". I need to know all the files with this string. ( I know the grep command can do it but either
View 4 Replies View RelatedAfter typing "grep some_word" on terminal 6, the system doesn't do a thing, just lets me type endlessly. I've tried "Esc", "q" , [CTRL] + x, "exit" and no luck. I bet I'll kick my ass when you tell me but at the moment I can't figure it out. Rebooting would probably solve the problem but there must be a better way.
View 5 Replies View RelatedCan someone please tell me how I can use grep to display all users running a particular command.
View 3 Replies View RelatedA simple TCP based chat server could allow users to use any TCP client (telnet, for example) to communicate with each other. For this question you should consider a single process, single thread server that can support exactly 2 clients at once, the server simply forwards whatever is sent from one client to the other (in both directions). Your server must not insist on any specific ordering of messages as soon as something is sent from one client it is immediately forwarded to the other client. As soon as either client terminates the connection the server can exit
View 4 Replies View RelatedThis has to also show the line count. I can get it to show the files but not the line count. What is the single command used to identify only the matching count of all lines within files under the /etc directory that contain the word „HOST? List only the files with matches and suppress any error messages.
View 4 Replies View RelatedWhen I used the find command, I almost always need to search the local drives. But, I almost always have super large network shares mounted and these are included in the search. Is there an easy way to exclude those in the find command, grep and other similar commands? Example:
find / -name .vimrc
I want to pipe the output of a command into grep as the search TERM, rather than the text to be searched, like this for example
Code:
cat /var/log/auth.log | grep date "&b &d"
so that I only see the lines in auth.log for the current day...but obviously that line doesn't work.... is there a way to do this with grep, or even another command?
I would like to know how to use grep command to filter the log files created between 3:00 PM to 4:30 PM in buch of log for whole day in different headings. This files resembles like sar file in linux.
View 5 Replies View Relatedi want a process that can operate as both a TCP echo server and a UDP echo server. The process can provide service to many clients at the same time, but involves a single process that does not start up any other threads.
View 3 Replies View RelatedI am trying to monitor how long an ldap search takes and maybe notify or something that a search takes longer than say 10 seconds.
Code:
tail -n 1000 /var/log/ldap.log
for SRCH in $( cat monitorldap.log |grep 'SRCH'); do
echo search string is
echo $SRCH
[Code]....
ok, so to start off with it doesn't appear to get the whole line, just a piece "Aug". How can I get the whole line into a variable so I can then cut it up into the pieces I need?
I'm using Zabbix on which I can use give bash command to the agent.This 1-liner will give me all the interfaces with their IPv4 addresses.I have a 2nd expression which returns a checksum so I can detect a difference whenever someone deletes/adds/changes an ipv4 interface.This is the output on my Ubuntu-server:
Code:
~# ifconfig | grep -B1 ' inet ' | grep -oE '(^[a-z0-9:]*|addr:[0-9]+.[0-9]+.[0-9]+.[0-9]+)'
eth0
[code]....
How can i use grep (or any other command) to check for lines that begin with N number.
E.g. I want to print out commands (from history), but only from the command number 50 until #200.
This one doesn't work:
Code:
history | grep "^[50-200]"
Should print out something like:
Code:
50 cd ~/Desktop
[Code].....