Programming :: Copy Files To Dynamic Directories?

Feb 14, 2011

I have been searching for a solution to the following problem:

When my distro of choice updates Firefox web browser, the directory name is '/usr/lib/firefox-<version>'.
The problem here is that the directory name is dynamic by nature and doesn't allow a simple static solution, e.g.
'cp -rf /usr/local/files/bookmarks.html /usr/lib/firefox/defaults/profile'.

The same quandary applies when adding extensions, changing prefs etc.
I have looked at the following commands:-
find, sed, xargs, grep, awk, fprint.
Unfortunately my grasp of syntax and programming is very simple at best.

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I've got a simple command that does almost what I want.

The following will locate all files with a suffix of '_compressed.swf' and copy each into its same directory with a '.bak2' appended:

However, I need to replace '_compressed.swf' with '_content.swf' I'd like to use find, rather than recursive flag on cp for consistency.

Objective
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Out: /content/somefile_content.swf

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Feb 11, 2011

I have 2 massive duplicate dirs of the same format as below:
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subdir1
file1
subdir2
file1
subdir3
file1
...

Dir2 is the same, but it has some newer files of the same name. I want to copy all file1's from Dir2 to the same name and folders in dir1. So basically something like:
cp -pr bkpDir1/*/*-big.gif Dir2/*/*-big.gif

This works for singular cases:
cp -pr bkpDir1/uniquesubdir/*-big.gif Dir2/uniquesubdir/*-big.gif

But not for wildcards:
cp -pr bkpDir1/subdir*/*-big.gif Dir2/subdir*/*-big.gif

Anyway the aim is to do the first cp above, I have tried a few options using find. In trying to show an example stumbled upon a way that worked, while in dir2:
find */*-big.gif | xargs -i cp -rp {} ../dir1/{}
Sure there are better ways also...

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I have a question which has been in part answered many times but nothing I found relateds completely to my situation. I am sure there will be people who will say RTFM but believe me I did, and searched as well but to no avail. I have a situation where I want to copy files created withing last hour in one directory into another one. The problem is that that the directories are on different levels in the dir tree so the absolute path is different. But I want to keep the relative path the same.

I want to copy new files from /mnt/path_to_webdav/user to /home/user. so if there is new file /mnt/path_to_webdav/user/doc/xy.txt I want it to be copied to /home/user/doc/xy.txt. Also if there is a new dir, say /mnt/path_to_webdav/user/newdir I want a new dir to be created in /home/user/newdir with all the files in it, should there be any. I can do find with exec and copy all the files into one directory.This is not what I want though. How do I preserve the relative path and get the files copied into their corresponding directories?

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Currently I get the error:

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Oct 17, 2009

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I have been using the tree command for now, but I have not found a way to ignore paths to directories which only contains other subdirs or nothing at all in any easy way. I may offcourse test each directory after they are listed but this gives an extra loop to go through and I beleive it should be possible to do it directly when creatring the list. I guess by using find or ls in conjuntion with the tree command or by itself it should be possible but I am not to conversant of nested script commands.

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I have a single directory of pairs of files, with the pairs sharing a string as the beginning of the filename:

SF1-27F1492R-clone01_T3_A18_001.ab1
SF1-27F1492R-clone01_T7_A20_002.ab1
SF1-27F1492R-clone02_T3_A19_003.ab1
SF1-27F1492R-clone02_T7_A21_004.ab1
...etc

I need to create a subdirectory for each pair then move the pair into the subdirectory.

I accomplished the first step using:

$find /foo -name '*T3*' -exec mkdir '{}.wrk' ;

I can use a regex to designate the pair and associate the directory, but how do I use regex in a path as the output of a move command?

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Aug 26, 2010

I am new to perl scripting and wrote a perl script to read the directories and files and count the no of files in each directory and generate a log file. The problem is it is not printing anything to the log file. I am copying the script below.

!/usr/local/bin/perl
$dir= 'c:My ProjectsPerl ScriptsNew Folder' ;
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[code].....

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[code]....

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m02_+1+8_London_0000$01.cfg

[code].....

What I want to do is to create a script that will interpret the following string and save into variables part of its name

m02_+1+7_London_0000$01.cfg as
------X-Y--City---------
X=1
Y=7
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[code]....

then I want to copy the files that go all the files with the same City and X and Y to the same subfolder City/MX.Y I will need some help start doing that. And I think the first would be to get part of the filenames strings into variables.

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Here is what I currently do and want to automate:

1) I manually enter a particular web site address in the browser.

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3) Each of these links display another page (file) from which I "cut and paste" information. I do this by highlighting manually the wanted info, click "copy" then select an open file on my computer, select "undo" if necessary to remove any previous content, click "paste" and then "save".

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6) visit the next known web site and repeat 1 to 5

In an automated program, what I need to do is:

1) Visit the known page of the web site showing the links
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###############################3
#/usr/bin/sh
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Originally Posted by Kenny_StrawnPlease wrap [CODE] tags aroung any code posted here. The full source that way could still be posted.I am trying to copy all the files in the directory based on the modification date (i.e created on Dec 29). Not able to find the proper command for this. This is what I have tried.

(none) login: root
#
# cd /mnt/hd/

[code]...

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ftp ()
{

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