I would like to remove a string pattern which like this.You should not remove this /*This is the part should remove*/ You should not remove this.I would like to remove all the text inside the /* and */.
I need to grep for a particular string and if found need to display the line containing that string, the line above that and also the first line of that paragraph.
Can this be done via sed.
Eg, My Paragraphs
OA connectA
Enclosure:
Interconnect Module #6 Status:
Here, if I grep for Critical, it should display the following
Similarly if I grep for Degraded, it should display
How can you remove files containing a specific string?I have...Code:find |grep 'string'This may return several results and I wanted to rm the results.I also have...Code:ls -l |grep 'string'|awk '{print $9}'which also may return results.But point is, I can't supply the results as a parameter to rmI was thinking of looping but I don't know how to access the results as if they were an array or something.
I have been fighting with a sed statement trying to get it to remove everything in a string until the last match and have been failing badly. how to get this to work..
sed --> enterprises.9.9.171.1.5.2.1.1.5 returns 5
I want sed to strip everything out until the last period. The final digit can and will change. Some parts before the final period can change as well, since enterprises will sometimes also be represented as more numbers and periods.
I want to go through a log file and find pattern1 and then a pattern2 only after pattern 1.So for example I want to know howManyRecords was in 13:30.I figured I grep for "start time for the job" and then only after that (and before the next occurence of that) grep for "howManyRecords". Is this a sane way?
need all spaces between two letters or a letter and a number exchanged for an underscore, but all spaces between a letter and other characters need to remain. One example for clarity:
Input:
force -- lamin 90 [label] active A -- generation [label]
needed Output:
force -- lamin_90 [label] active_A -- generation [label]
I tried solving this with sed but obviously s/ /_/g does not work, nor does any s/[a-zA-z0-9] [a-zA-z0-9]/[a-zA-z0-9]_[a-zA-z0-9]/g , because you just can't do this...
I want to search a file for a particular pattern and if pattern found replace the line with new text. i am using awk 'match($0,"pattern") != 0 {print $0} ' filename to check if the pattern exists.how do i get the line number of the pattern and delete that line and replace the line with my new text?
I have to enhance the behaviour of a backup script written in perl. I don't need to change it, what I need to do is to create a bash script that does some checks like file name and file size, execute the backup script then check if the backup files match the original files.Here's how I try to do it:
- read the files from the original files folder - store them in an array - search in the array the files that have a specific file extension - store the file names that match the search pattern (I know the backup script skips some files so I can hardcode the search pattern) - run the backup script - read the files from the backup folder - store them in an array - compare the original files name and size stored in an array with those from the backup folder - send a report email
I have a string of files named recup_dir.1 thru .66. I have the command sudo rm -r /home/"name"/Pictures/recup_dir.1 to remove them one at a time, how do I remove 20 or thirty at one command?
I am reading strings from a file using readline() function,the file contains some strings which has only special characters, I need to avoid the strings which has only special characters, the special characters are not similar. How to do it in python.??
I want to replace a string of directory path in a string to empty:
Code:
But this doesnt seem to give me the desired thing:
Code:
This gives the desired outcome, but its specific, i need a variable in the sed not a string. And if I replace STRING="/mnt/sda1/record/$dd/" then I cant use it for something else, cause its has all the weird backslashes now.
I am working with a Tcl script and have some strings in the following format (RE): [a-zA-Z]+[0-9]{6}-[0-9]
There are some leading letters, combinations of capital and lowercase. Then six digits, followed by a hyphen, then one more digit. I would like to remove all of the leading alphabetic characters from the string. The resulting string would then be in this format: [0-9]{6}-[0-9]. In other words, six numeric digits, a hyphen, then one more digit.
I have tried: Code: set newstr [string trimleft $origstr alpha] But that only removes the first alphabetic character, not all of them.
I couldn't get anything with regsub to work correctly, but I am somewhat of a noob with RE's in general and regsub in particular. There are usually 5 leading letters at the beginning of these strings, and I could in most cases get away with using string replace and constant indices to extract the substring. However, my preference is for this to be robust enough to handle all cases with 1 through n leading alphabetic characters.
My server was hit with an injection script which has placed code across many of my clients files. I need a script that can remove a block of php code that spans multiple lines, multiple directories/files and is dynamic, meaning that part of the code changes. I think using find/sed is what I need but cannot seem to figure out how to get it to work.The following is the script that is being injected everywhere. The catch is that they have generated dynamic code at the start/end of the script. (I have commented the parts that are dynamically changing on EVERY instance).PLEASE NOTE: Directly following this script is the start of a valid php script that I do not want to delete.
<?php //{{65281980 - DYNAMIC!! GLOBAL $alreadyxxx;
I need a hand with a line of terminal commands. I need to be able to search a given .sh file in a given location for a string, and when found, add a "#" to the start of that string and save the file back to it's original location.