General :: Insert Tab At Beginning Of Each Line In File?
Aug 5, 2010
I am trying to create a shell script where a user can specify a file with a list of logins and the script will create a batch file with specific information in specific columns.
Example:
loginfile.txt has
User1
User2
User3
I need the output to be as below:
1 User1 Date 12/31/9999
2 User2 Date 12/31/9999
3 User3 Date 12/31/9999
I can use the nl utility to get the numbers easily enough, but I need two tab separations between the number and the user list. Is there a sed command that will insert at the beginning of each line? If so I can just run nl after I get some tabs up in the front.
Was wondering if any perl guru's could help me with a quick log file adjustment. I have a text file that looks like so (tabs and newlines are revealed so you can see what separates the data):
There are maybe 100 lines of text in this file at any given time. I need to delete all duplicate lines only looking at the first bit of text prior to the first tab. It doesn't matter which one gets deleted as long as there are no two lines that begin with that same text at the beginning before the first tab. So in this example, either the fist line "1234" or the last line "1234" would need to be deleted. I already have code in my script that opens the files - I just need the code to read the text into an array and the part that would find matches based on the above criteria, and make the deletions.
If it would be easier, I can even do a system call and use SED (v4.1.5) and/or AWK (3.1.5) instead.
Is there some kind of universally recognized pragma that one can insert at the beginning of a text document to designate it to be UTF-8 encoded (or any other encoding)? I've seen certain editors insert encoding comments, and one or two compilers that have an encoding pragma. But I was wondering if anyone has tried to establish some kind of universal tag format for text documents.
I need to run a command in a shell script to insert a line in a file, after it finds certain line. To add the line 'user = mysql' after the line [mysqld] in file /etc/my.cnf
i have two files with thousands of line, I am trying to combine these two files but i want to insert each line of one file to the another file after certain lines. I am using awk with the following command but it does not work.cat file1 | awk ' { print $0; if (NR%3004==0) {print "file2"}}' > outputfile
I've been reading tutorials of Linux sed command, but haven't got anything yet. the problem is : I want to insert a line into my DNS database file which has a pattern like below:
<Domain name> 3tabs here <IN> <A> <ip address>
the question is : how to add a line into a file like this using linux sed command? I have problem inserting tabs and the spaces!
I have a lot a folders, each named by a number, and in each of these folders I have a specific file (stddev.dat) containing a single line (of numbers) I need to have a single file with each line being one of the stddev.dat (no matter if it is sorted or not), and also I need to add at the begining of each line the number of the folder it comes from.
I 'm no bash expert, and the "add at the begining of the line" is a bit of problem to me". Here is what I've come up with so far, just to put everything in one file, (and also if you know a better/more elegant way to do the same thing I've done, I'm listening)
I need to find each line in a file which does NOT begin with a double quote (") and append that line to the previous line. I have been successful doing this using the following command: cat filname.csv | sed -e :a -e '$!Ns/ [^"]//;ta -e 'P;D' > newfilename.csv
My issue is the substitution. As you would expect after the line is appended to the previous line the first character is removed. I need it to not be removed. I tried: cat filname.csv | sed -e :a -e '$!Ns/ [^"]/&/;ta -e 'P;D' > newfilename.csv but it just hangs.
Goal: Input: "line 1" line 2 Output with existing sed command is: line 1ine2 I need it to be line1line2.
I want to add something at the end of each line, from line 4 to line 8, in vim? How can i do that? I know adding at the beginning is like: 4,8: normal: i# What i want to add contains special characters ( here it is: <br/> ) , in case that matters.
I want to add tabs at the beginning of each line, from line 6 to line 12. How?
I'm trying sed and was able to put a tag on the end of the line
Code:
Output is
Quote:
What I need to have is
Quote:
I'm thinking of I redirect my first sed command to a file and then use sed again to put <group> at the beginning of the line. My problem is how to put <group> to all beginning of the string.
I try to do a function which removes '#' from beginning of line. But if there is not '#' then add it on beginning of line. I try something like this, can you correct me?
I am having some difficulties with an expect script. What I want is that as soon as expect sees a newline followed by a dollarsign ($), that interact is done. So I would expect something like this to work:
Code: " $" { interact } However it doesn't. This is debugging output: Code: expect: continuing expect expect: does " " (spawn_id exp6) match glob pattern "#"? no
I saved a page from Linuxquestions. It was saved under a filename beginning with '[' (left square bracket). And I now can't delete the file. Unfortunately I cannot send you a screenshot because opening a terminal in the GUI makes ls behave differently. I shall try to describe, assuming the file is in dir '.'. Also let '[SOLVED]foo.html' be the file in question:
Code: $ ls <the file is listed> $ ls [* /bin/ls: cannot access [*: No such file or directory $
If I want the hdd to get rid of this file, what should I do? Any hint will be welcome.
Does any one know what syntax i could use to allow me to replace all instances at the beginning of a line with ones.
Before :
Code: ---------------------------------------------------------------------- Logical device information ---------------------------------------------------------------------- Logical device number 0 Logical device name : RAID1Mirror RAID level : 1 Status of logical device : Optimal
After
Code: ---------------------------------------------------------------------- Logical device information ---------------------------------------------------------------------- Logical device number 0 111Logical device name : RAID1Mirror 1111RAID level : 1 11111Status of logical device : Optimal
I'm looking for a way to insert the number of lines in a file to the start of the aformentioned file. This should be simple but as I am not used to scripts in Linux, I am finding it tough going. I can find the number of lines in a file easily enough via
filesize=$(awk 'END {print NR}' $1)
but as for inserting this into the first line, i'm failing to do so. I've tried some of the other approaches on these forums but none so far have been able to do so.
I've tried:
sed '1i$filesize' $1
but sed i requires a string, not a variable so no go I've also tried:
but again with no luck as cat seems to need an input stream Just to recap, i want to insert a line at the start of a given file that holds the number of lines the original file has.
I'm a newbie on Linux and had to do something like this with the zip command:
My folder structure inside a zip file abc.zip is code...
It would move into abc.zip as folder3/textfile.txt (the hierarchy preserved) Also used a -j switch (help said it junked the path info and it did but) - it would move only into abc.zip and sit at the same level as folder1 and folder2 instead of replacing the textfile.txt within abc.zip/folder1
My question is - I want to replace the abc.zip/folder1/textfile.txt with the one inside seconddir/folder3/textfile.txt.
How do I achieve this via the command line interface?
I'm trying to insert a line using sed that has leading spaces before the text. Sed seems to be just dropping the spaces and only inserting the text. Any ideas what I'm missing?
Code:
NAM=rb134 sed -i.bak -e "$i host ${NAM} {" /etc/crap
Instead of inserting a line with 8 leading spaces inserts it with "host" at the beginning of the line. I tried
Code:
NAM=rb134 sed -i.bak -e "$i ^ host ${NAM} {" /etc/crap
I would like to insert prior to the word "three" all items from this second file with the following contents:
Code:
four three two one
Now my issue is, and I have been using both sed and awk currently, that after the second line of the new file is read there will of course now be 2 copies of the word "three" but I would like to only insert the final 2 words, ie "two" and "one" prior to only the first occurrence of the word "three" so final file will look like:
Code:
one two four
[code]....
So here there is now only one of each word from the second file joined to make the new file. For simple code I have tried something like the following:
Code:
while read line do awk -v n=$line '!f && /three/{print n;f++}1' file1 > tmp_file mv tmp_file file1 done < file2
Now this works but seems very clumsy to me. There is obviously a better sed and / or awk out there.
I am trying to write a script that takes an input file ($FileName) and an intermediate file ($FileName.info) and removes lines from $FileName if the value in $2 of $FileName.info is <75.
I can't figure out how to feed only one line of the .info file to the if statement at a time so that it will perceive it as an integer instead of a list.
The error I am getting now is ./script.sh: line 6: [: : integer expression expected
I've written a script to parse a file and print each line that ends with matching pattern, if the next line is blank. The pattern lines are the result of md5sum $i|sed 's/path///g' so that only md5 and filename appear. Here's what I'm using.
Quote: for fline in `sed -n '/.*.ext$/p' file1` do if [ "`sed -n -e '/'"$fline"'/ {n; p;}' file1`" == "" ] then echo ""$fline" has no info" >>file2 fi done [Code]....
