I want to insert a line at a particular line number using sed or awk. where line number is not fixed and is in form of variable.
I want to use variable in sed or awk command.I tried something like below, but no luck.
I have a project due for my Intro to C++ class and we are suppose to generate a file listing that will take an input of a C++ source code with .cpp extension and make a copy of it with a .lst extention that will have a line number preceding each and every line.
View 12 Replies View RelatedI need to run a command in a shell script to insert a line in a file, after it finds certain line. To add the line 'user = mysql' after the line [mysqld] in file /etc/my.cnf
View 3 Replies View RelatedI have two files, file1.traj and file2.traj. Both these files contain identical data and the data are arranged in same format in them. The first line of both files is a comment.
At line 7843 of both files there is a cartesian coordinate X, Y and Z ( three digits ). And at line 15685 there is another three digits. The number of lines in between two cartesian coordinates are 7841. And there are few hundreds of thousands of lines in a file.
What I need to do is copy the X Y Z coordinate (three digits) from file1.traj at line 7843 and paste into file2.traj at the same line number as in file1.traj. The next line will be 15685 from file1.traj and replace at line 15685 at file2.traj. And I dont want other lines (data) in file2.traj get altered. This sequence shall be going on until the end of the file. Means copy and substitude the selected lines from file1.traj into file2.traj.
I tried to use paste command but I cant do for specified line alone.
Here i showed the data format in the file. I used the line number for clarity purpose.
Code:
I want to access a file, and check the length of every line.After, i want to check and replace all lines with length over 10 characters, with a message.Does anyone have a clue on that?
View 1 Replies View RelatedI am trying to write a program in C which compares two files and prints the line that is equal.
Here file1.txt has
and file2.txt has
Note: file2.txt consist of only a single string where as file2.txt has multiple lines. Actually im comparing two files with md5sum values.
Here is the code but it compares only first line of files..but it should compare the whole file1..and sorry iam a beginner in C can any1 sujest some modification to this code so that..it can compare file2 with entire file1
Quote:
How can I list the following with grep. I want to extract 2 lines fron a text file The fixed known part if it exists will static text and the text line after it will change.
A sample file
.
.
textline1
[code]....
If the fixed part does Not exist how can I return error code 1
After running the following command, I get:
[root@yukiko /]# find / -iname .bashrc
/home/clamav/.bashrc
/home/vpopmail/.bashrc
/etc/skel/.bashrc
/root/.bashrc
But I would like to have a command that prints a specific line by supplying the command with the line number, for example:
[root@yukiko /]# find / -iname .bashrc | getline(2)
/home/vpopmail/.bashrc
Is there such a command on CentOS?
I want to sort a number of lines based on their size:
data:
-------
12345678
87654321
1234
[code]....
Should output as:
-----------------
1
2
12
21
[code]....
But i'm gettings this with sort
----------------
1
12
123
1234
[code]....
Can we sort the above "data" text, based on "number of characters" instead of "character order"?
I m writing a script to delete a line at particular location.
But i m unable to use variable for specifying line number.
For example.
Code:
works fine and deletes 7th line from my file
But
Code:
gives following error.
Code:
Did anyone heard about or can suggest mabe a postfix serverside solution in order to insert a counter number into the subject line before the message is sent?
I mean something similar with helpdesk tickets, because I would like to create the possibility for the senders, to make further refference about a speciffic message using it's counter number provided by postfix server.
I want to print the line number with the pattern of the line on a same line using multi-patterns in sed. But i don't know how to do it. For example, I have a file
abc
def
ghi
I want to print
1 abc
2 def
3 ghi
I've never programed shell scripting.
Code goes like so:
I simply want to read a file "data.txt" line by line Then char by char and add them into a result var. The file is supossed to always contain numeric values
I have a string as below
LogFormat "%h %l %u %t "%r" %>s %b "%{Referer}i" "%{User-Agent}i"" combined
Want the above string to be modified as
LogFormat "%h %l %u %D %t "%r" %>s %b "%{Referer}i" "%{User-Agent}i"" combined
inserting %D after %u in the string
I want to copy below content to a file after line 200.
Alias /A/ "/A/B/C/D/"
<Directory "/E/F/G/H/">
Options Indexes MultiViews
AllowOverride None
[Code]....
Or is it possible if I can copy this content in some other file and insert to the main file.
I have following file workers file: There are 800 entries like this.
# consensus/uat
worker.consensus-uat1.host=lonlx10409
worker.consensus-uat1.port=13702
worker.consensus-uat1.type=ajp13
[code]....
I want to insert one line just below the line starting with "woker.list". I think sed can do it but I am not aware.
I'm trying to insert a line using sed that has leading spaces before the text. Sed seems to be just dropping the spaces and only inserting the text. Any ideas what I'm missing?
Code:
NAM=rb134
sed -i.bak -e "$i
host ${NAM} {" /etc/crap
Instead of inserting a line with 8 leading spaces inserts it with "host" at the beginning of the line. I tried
Code:
NAM=rb134
sed -i.bak -e "$i
^ host ${NAM} {" /etc/crap
but it put the "^" at the begging of the line.
How can I set indent in .emacs to enable my new line starts from the same position of previous line?
like this;
Hello world <enter>
Second Hello world // "S" starts right under first line's "H"
I wish to add information to one of my files based on matching IDs,
Here is an example
(the id is the 3 colunm)
(the ID is the 2 colunm)
And the output i wish to be
OUTPUT:
So as you can see the ones that do not match are still present, and the ones that do match just have the extra information from file2.txt added to them.
I thought about using join but that only seems to join the ones that match displays thoes only. i would like all the information in the output file.
I currently have 3 files with floating point data that I wish to have in a single file with the format:
Code:
F1 F1 F3 Output
a1 b1 c1 a1 b1 c1
a2 b2 c2 a2 b2 c2
a3 b3 c3 a3 b3 c3
a4 b4 c4 a4 b4 c4
At the moment I have a flat file which is being used by a few people. I want a script to remotely change the file, so I can start logging who is doing what.At this point here is one requirement I am trying to develop. We have text blocks who pretty much look like.I hope this is somewhat clear. I try to find $param for the right $workflow and change that. Can you help me to find $$var3 and change that?
View 1 Replies View RelatedI have two txt files containing x and y coordinates: xcoord.txt & ycoord.txt. I need to open them; read them line by line to get each coordinate; then each time I need to update Xs and Ys parameters inside another file called "dc.in" with the grabbed values.
Finally each time I need to run two exe files ( dc_2002 and st_vac) and produce corresponding output for each Xs and Ys ( dc.in is an input file for this exe files)
I have written the following code but it does not work:
Was wondering if any perl guru's could help me with a quick log file adjustment. I have a text file that looks like so (tabs and newlines are revealed so you can see what separates the data):
There are maybe 100 lines of text in this file at any given time. I need to delete all duplicate lines only looking at the first bit of text prior to the first tab. It doesn't matter which one gets deleted as long as there are no two lines that begin with that same text at the beginning before the first tab. So in this example, either the fist line "1234" or the last line "1234" would need to be deleted. I already have code in my script that opens the files - I just need the code to read the text into an array and the part that would find matches based on the above criteria, and make the deletions.
If it would be easier, I can even do a system call and use SED (v4.1.5) and/or AWK (3.1.5) instead.
I have a file like so:
Code:
one
two
three
four
I would like to insert prior to the word "three" all items from this second file with the following contents:
Code:
four
three
two
one
Now my issue is, and I have been using both sed and awk currently, that after the second line of the new file is read there will of course now be 2 copies of the word "three" but I would like to only insert the final 2 words, ie "two" and "one" prior to only the first occurrence of the word "three" so final file will look like:
Code:
one
two
four
[code]....
So here there is now only one of each word from the second file joined to make the new file. For simple code I have tried something like the following:
Code:
while read line
do
awk -v n=$line '!f && /three/{print n;f++}1' file1 > tmp_file
mv tmp_file file1
done < file2
Now this works but seems very clumsy to me. There is obviously a better sed and / or awk out there.
bash 3.1.17(2) I'm trying do write a shell script which must operate on each line of an ASCII text file. So, all the code must be inside a loop, and inside the loop, the first thing should be to read the next line from the file. I have the bash read command. But it reads from stdin. Any way to make read from a file?
View 6 Replies View RelatedI have a set of files containing data that I need to re-arrange into one single property list.
The files that I have look like this:
Code:
# cat uk
<string>10</string>
<string>11</string>
...
<string>29</string>
[Code]....
So the lines in the files match up but I haven't found a way of reading several files line by line.
I'm extracting data from a xml file writing it to separate files then combining the results as a csv file.The problem is keeping the separate files in sync line by line.When a grep does not action I would like to put in a blank line or something to keep the lines in order.When the "<title>" is missing as in as in the first"<programme </programme>" that's where I need somethingto write to the file as dummy data to increment the line
here's the data
Code:
<programme channel="15552.dvb.guide" start="20100504200000" stop="20100504204000">
<category>Show / Game Show</category>
</programme>
<programme channel="14498.dvb.guide" start="20100504200000" stop="20100504203000">
[code]....
I'm trying to make another file annotation script a little speedier than it has been by the up-until-now proven method of checking the last four characters in a filename before the "dot" (eg .jpg, .psd) against a list of known IPTC categories and Exiv2 command files. It occurred to me that if one script generated a list of files in directory foo, and the same or another script sorted that list by that four-letter tag,then that list could be used(instead of a for/do/done loop on the real files in the folder) by the command-file-matching script to "vomit out" which annotator file would go with file nastynewfile.jpg, f'r'instance. The script I had been using for this task looks like this:
Code:
while read 'line';
do
sp=$(echo $line)
vc=$(echo $sp | cut -d"," -f1)
cv=$(echo $sp | cut -d"," -f2)
[code]....
Where I seem to be stuck is with how to sort the lines in templist, which may be any number of different lengths, from back to front. sort -k looked promising, except it seems only to work the other way round. I thought of invoking a
Code:
q=$(expr length $line); echo $q
n=$[q-8]; echo $n
kind of thing, but that presented the problems of how to sort by those, how to tell sort where to find them (grep?) and how to "stitch them back in" to the original list, which is what I want to sort in the first place.
I have a log file with entries such as;
Where result is 0 or more.
I want to get the list of file names where result count is more than 0 (in other words filter out files names with result 0).
File name and result are in two different lines in log file.
How can i filter file name based on result?
I have a perl/python interpreter available on the system so really as long as the script would run on a standard linux build I'll be happy.So I don't know how to program a script that would find the unique key (which if needed, can be easily stripped out and put into a separate file) and then print out the data below it without going into the other lines.
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