General :: Sed Command - Find Line Not Beginning With Double Quote

Mar 15, 2011

I need to find each line in a file which does NOT begin with a double quote (") and append that line to the previous line. I have been successful doing this using the following command:
cat filname.csv | sed -e :a -e '$!Ns/
[^"]//;ta -e 'P;D' > newfilename.csv

My issue is the substitution. As you would expect after the line is appended to the previous line the first character is removed. I need it to not be removed. I tried:
cat filname.csv | sed -e :a -e '$!Ns/
[^"]/&/;ta -e 'P;D' > newfilename.csv
but it just hangs.

Goal:
Input:
"line 1"
line 2
Output with existing sed command is:
line 1ine2
I need it to be line1line2.

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Aug 12, 2010

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I want to convert double quote to single quote in a text file. I tried escape characters however no success. Please find details as follows:

-sh-3.00$ sed 's/"/'/g test.txt
sed: -e expression #1, char 7: unterminated `s' command
-sh-3.00$ cat test.txt
"unix"

I want "unix" to be converted to 'unix'

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So far I have tried:

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Feb 28, 2011

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I 'm no bash expert, and the "add at the begining of the line" is a bit of problem to me". Here is what I've come up with so far, just to put everything in one file, (and also if you know a better/more elegant way to do the same thing I've done, I'm listening)

[Code]...

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Aug 5, 2010

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Example:

loginfile.txt has

User1
User2
User3

I need the output to be as below:

1 User1 Date 12/31/9999
2 User2 Date 12/31/9999
3 User3 Date 12/31/9999

Where the columns are separated as below.

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Code:
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[code]....

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I want to add tabs at the beginning of each line, from line 6 to line 12. How?

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Code:

Output is

Quote:

What I need to have is

Quote:

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Code:
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}
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Code:
"
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However it doesn't.
This is debugging output:
Code:
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[Code]...

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Before :

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----------------------------------------------------------------------
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After

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Code:
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on each file, I will get
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