I need to output of a script to a file with tags.
I'm trying sed and was able to put a tag on the end of the line
Code:
Output is
Quote:
What I need to have is
Quote:
I'm thinking of I redirect my first sed command to a file and then use sed again to put <group> at the beginning of the line. My problem is how to put <group> to all beginning of the string.
I am working with a Tcl script and have some strings in the following format (RE):
[a-zA-Z]+[0-9]{6}-[0-9]
There are some leading letters, combinations of capital and lowercase. Then six digits, followed by a hyphen, then one more digit. I would like to remove all of the leading alphabetic characters from the string. The resulting string would then be in this format: [0-9]{6}-[0-9]. In other words, six numeric digits, a hyphen, then one more digit.
I have tried:
Code:
set newstr [string trimleft $origstr alpha]
But that only removes the first alphabetic character, not all of them.
I couldn't get anything with regsub to work correctly, but I am somewhat of a noob with RE's in general and regsub in particular. There are usually 5 leading letters at the beginning of these strings, and I could in most cases get away with using string replace and constant indices to extract the substring. However, my preference is for this to be robust enough to handle all cases with 1 through n leading alphabetic characters.
Was wondering if any perl guru's could help me with a quick log file adjustment. I have a text file that looks like so (tabs and newlines are revealed so you can see what separates the data):
There are maybe 100 lines of text in this file at any given time. I need to delete all duplicate lines only looking at the first bit of text prior to the first tab. It doesn't matter which one gets deleted as long as there are no two lines that begin with that same text at the beginning before the first tab. So in this example, either the fist line "1234" or the last line "1234" would need to be deleted. I already have code in my script that opens the files - I just need the code to read the text into an array and the part that would find matches based on the above criteria, and make the deletions.
If it would be easier, I can even do a system call and use SED (v4.1.5) and/or AWK (3.1.5) instead.
I've been trying to understand pthread in C a little better. So I made a simple program that takes in a string from the command line and creates a thread to print the string. I've looked online and copied the basic concepts but there are something things I'm confused about. The programs works just fine, but I have questions. Here's what I have so far.
[Code]....
One thing I'd like to know is why the 3rd argument in the pthread_create function which is my SendMessage function needs to be typecasted to a void pointer and then send the address of the function. Also as for the 4th argument, I would see typecasting to void pointer in some of the pthread examples I saw online, but in my case I'm passing a char pointer, would this be correct? In which case would I ever want to pass a void pointer?
Do I need a pthread_exit(NULL) in my main and in the SendMessage function? If so, why? I added the sleep() function so that I could let the pthread_exit function in my SendMessage function execute first. I simply saw that the online examples on pthread had pthread_exit() in both locations.
I try to do a function which removes '#' from beginning of line. But if there is not '#' then add it on beginning of line. I try something like this, can you correct me?
Code:
awk '
!/^#/{ sub(/^[^#]*/,"#$0","'$line'")
}
/^#/{ sub(/#/,"","'$line'")
}'
I am having some difficulties with an expect script. What I want is that as soon as expect sees a newline followed by a dollarsign ($), that interact is done. So I would expect something like this to work:
Code:
"
$" { interact }
However it doesn't.
This is debugging output:
Code:
expect: continuing expect
expect: does " " (spawn_id exp6) match glob pattern "#"? no
[Code]...
I have a set of lines as ahown below:
Leon went to school
Leon came back from school..
Leon had dinner...
I have to replace the line containing "dinner" by a single string LUNCH...
Does any one know what syntax i could use to allow me to replace all instances at the beginning of a line with ones.
Before :
Code:
----------------------------------------------------------------------
Logical device information
----------------------------------------------------------------------
Logical device number 0
Logical device name : RAID1Mirror
RAID level : 1
Status of logical device : Optimal
After
Code:
----------------------------------------------------------------------
Logical device information
----------------------------------------------------------------------
Logical device number 0
111Logical device name : RAID1Mirror
1111RAID level : 1
11111Status of logical device : Optimal
I want to convert strings like 002, 049, 050, 100 to numbers: 2, 49, 50, 100.
I tried to use:
Code:
`printf "%5d" $i`
, but it doesnt work , it convert:
002=>2
014=>12
049=>0
I have a requirement like this..this just a sample script...
Code:
when i run this scipt...
Code:
Code:
It is appended in the same line...
I want it to be added to the next line.....
I want to do this by explitly using the filehandles in perl....and not with redirection operators in shell.
I want to append a variable string to the end of a specific line. not like append the same string to each line. like in my file i have 4 columns, i want to add a string in 5th column in some fixed row.
View 4 Replies View RelatedQuote:Originally Posted by topcatI would like to know how i can write a shell script to delete a line if a particular pattern exists?E.g. I have a text file with multiple lines. Say 1000s. in the following pattern.
username@email.com:149.0.3.4:1
username1@email.com:149.0.3.4:1
username1@email.net:149.0.3.4:1
username1@email.edu:149.0.3.4:1
If the patternusername@email.com exists then the line "username@email.com:149.0.3.4:1 should be deleted from the file.I have a very similar question but I need to delete one line in a file which matches one very precise instance of a string only. Let's assume I have a file composed of thousands of lines and let's call the file chap-secrets. Let's take the following sample entries:
Code:
#USERNAME SERVER PASSWORD IP
pp pptpd blahblah *
[code]....
in gcc how to read a blank line ie a string of length 0.my code:
Code:
#include<stdio.h>
#include<string.h>
[code]...
I want to know how can I add something to a specific line.. the output would be something like:
abc
def 123
ghi
Search for string "def" and add something to that line.
I think this can be done using sed. Let's say I have file called, "orig.txt" with following contents:
Code:
[User Prefs]
Ignore Unrequested Popups=1
DevTools Splitter Position=500
History View Style=0
[Code]....
So basically if a line contains the word "Home URL" then go ahead and replace that *entire* line with the supplied *new* line.
I have a very large data file, with 3 numbers in each line, ex. 3 4 5 ; 6 7 8.I want to add two numbers (0 and 1) at the end of every line, and a string at the beginning of the line. Does anyone know a efficient way to do so?
View 7 Replies View RelatedInside a loop i'm populating a string variable. Because csh doesn't have very good support for arrays I thought of doing this. I want to add a new line character to the end of the concatenation each time the loop iterates. Then at the end print this variable out.
I tried " and some resources said it was just a "". Neither work. What am I doing wrong?
copy string a to string b and change string b with toupper() and count the chars
View 3 Replies View RelatedHere is the issue. I am reading in a outside text file and putting in the string on that line into a char array that is already allocated.
Code:
int main(int argc, char *argv[])
{
[code]....
I want to add something at the end of each line, from line 4 to line 8, in vim? How can i do that? I know adding at the beginning is like: 4,8: normal: i# What i want to add contains special characters ( here it is: <br/> ) , in case that matters.
I want to add tabs at the beginning of each line, from line 6 to line 12. How?
I have a lot a folders, each named by a number, and in each of these folders I have a specific file (stddev.dat) containing a single line (of numbers) I need to have a single file with each line being one of the stddev.dat (no matter if it is sorted or not), and also I need to add at the begining of each line the number of the folder it comes from.
I 'm no bash expert, and the "add at the begining of the line" is a bit of problem to me". Here is what I've come up with so far, just to put everything in one file, (and also if you know a better/more elegant way to do the same thing I've done, I'm listening)
[Code]...
I am trying to create a shell script where a user can specify a file with a list of logins and the script will create a batch file with specific information in specific columns.
Example:
loginfile.txt has
User1
User2
User3
I need the output to be as below:
1 User1 Date 12/31/9999
2 User2 Date 12/31/9999
3 User3 Date 12/31/9999
Where the columns are separated as below.
1[tab][tab]User1[tab]date +%D[tab]12/31/9999
2[tab][tab]User2[tab]date +%D[tab]12/31/9999
3[tab][tab]User3[tab]date +%D[tab]12/31/9999
I can use the nl utility to get the numbers easily enough, but I need two tab separations between the number and the user list. Is there a sed command that will insert at the beginning of each line? If so I can just run nl after I get some tabs up in the front.
I need to find each line in a file which does NOT begin with a double quote (") and append that line to the previous line. I have been successful doing this using the following command:
cat filname.csv | sed -e :a -e '$!Ns/
[^"]//;ta -e 'P;D' > newfilename.csv
My issue is the substitution. As you would expect after the line is appended to the previous line the first character is removed. I need it to not be removed. I tried:
cat filname.csv | sed -e :a -e '$!Ns/
[^"]/&/;ta -e 'P;D' > newfilename.csv
but it just hangs.
Goal:
Input:
"line 1"
line 2
Output with existing sed command is:
line 1ine2
I need it to be line1line2.
After running the following command, I get:
[root@yukiko /]# find / -iname .bashrc
/home/clamav/.bashrc
/home/vpopmail/.bashrc
/etc/skel/.bashrc
/root/.bashrc
But I would like to have a command that prints a specific line by supplying the command with the line number, for example:
[root@yukiko /]# find / -iname .bashrc | getline(2)
/home/vpopmail/.bashrc
Is there such a command on CentOS?
I need to grep for a particular string and if found need to display the line containing that string, the line above that and also the first line of that paragraph.
Can this be done via sed.
Eg, My Paragraphs
OA connectA
Enclosure:
Interconnect Module #6 Status:
Here, if I grep for Critical, it should display the following
Similarly if I grep for Degraded, it should display
I have a dataset (see example below) that I would like to go through and copy all lines containing a certain string ("LGIG") plus the line immediately following that line to a new file. I have no problem grepping lines containing the string LGIG but I'm lost how to translate that to line number and shift up one line number for each instance of that string.
Example input file:
[code].....
I need to creates string suffixes out of a Reference string. for eg. suffixes of abcdefg will be
1)bcdefg
2)cdefg
3)defg
and so on...
create an array of pointers to point to the first few characters and then use that pointer to print the rest of the string.But when i print using the pointer i get GARBAGE values! shudn't std::cout<<ptr[w] print the string following the char it is pointing to? why do i get garbage values?
So if I'm given a location of a file like:
How can I just take the type of the file at the end? I know I can use strrchr() for a period to get the pointer to the period just before file type. Is there a build in string function that will just take the rest of the string from a certain point on forward in the string? I know it wouldn't be much work to make it myself, but I figured I would find out if it already existed before doing it.
Code:
The error is:
Code:
What I want to do is take input of ip4 as a string, convert it to an integer to add 1 to it, then reconvert it back to a string. Its not working.
My full code is:
Code:
I've been given a custom-made string class which handles string, wstring and bstr. It has a number of methods and assignment operators to convert to and from different types. The app I work on compiles happily in VS6 and VS2008, but when trying to compile in Redhat (version 4.1.1 in Redhat 5.0)
[code]....