General :: Script To Insert Number Of Lines In A File To The Start Of The File?
Sep 17, 2009
I'm looking for a way to insert the number of lines in a file to the start of the aformentioned file. This should be simple but as I am not used to scripts in Linux, I am finding it tough going. I can find the number of lines in a file easily enough via
filesize=$(awk 'END {print NR}' $1)
but as for inserting this into the first line, i'm failing to do so. I've tried some of the other approaches on these forums but none so far have been able to do so.
I've tried:
sed '1i$filesize' $1
but sed i requires a string, not a variable so no go I've also tried:
but again with no luck as cat seems to need an input stream Just to recap, i want to insert a line at the start of a given file that holds the number of lines the original file has.
i have two files with thousands of line, I am trying to combine these two files but i want to insert each line of one file to the another file after certain lines. I am using awk with the following command but it does not work.cat file1 | awk ' { print $0; if (NR%3004==0) {print "file2"}}' > outputfile
i need to count the number of files and put the output into a variable. i used wc -l filename but i couldnt find an option to put the output to variable. example if the number o line is 5, i need the output of echo $x is 5.
I recently found myself in possession of a large file (a few million lines in length) of short strings and would like to count the number of lines that are unique to the file. I thought this would be an easy process, but while working on the problem, I encountered the following. Can anyone explain this weird result to me?
I need to create a script to count the number of lines from a text file . The output must be put on another text file (no_lines.txt) and in this file i need to generate from the script this output :"File $FILE has $NO_LINES lines ".
I have this massive table file with some data in it and I want to replace some lines that are wrong with the correct ones that are in another table file of the same format. The wrong lines are not all together in a block but randomly distributed so I need to make a loop checking if the line is in the other file and if it is, replace it. I want to try and do it with sed or awk but I don't really know how to....
I am using RHEL 5.I have a very large test file which cannot be opened in vi.The content of the file has some 8000 lines.I need to view ten lines between 5680 to 5690.How can i view these particular lines in a large file.what is command and option i need to use.
I have a large text file containing over 180k lines and another text file containing about 1k. I would like to remove lines in the 180k-line file that exist in the 1k-line file.
i want to grep lines which do not start with # or a blank space. like
bla bla bla bla
how do i do this? i tried grep --invert-match '^#' which gives lines not starting with # but gives me blank lines too i tried grep --invert-match '^#|^ ' which will give lines not starting with # OR not starting with blank ( which means any line including ones starting with #
I'm a newbie on Linux and had to do something like this with the zip command:
My folder structure inside a zip file abc.zip is code...
It would move into abc.zip as folder3/textfile.txt (the hierarchy preserved) Also used a -j switch (help said it junked the path info and it did but) - it would move only into abc.zip and sit at the same level as folder1 and folder2 instead of replacing the textfile.txt within abc.zip/folder1
My question is - I want to replace the abc.zip/folder1/textfile.txt with the one inside seconddir/folder3/textfile.txt.
How do I achieve this via the command line interface?
I am trying to create a shell script where a user can specify a file with a list of logins and the script will create a batch file with specific information in specific columns.
Example:
loginfile.txt has
User1 User2 User3
I need the output to be as below:
1 User1 Date 12/31/9999 2 User2 Date 12/31/9999 3 User3 Date 12/31/9999
I can use the nl utility to get the numbers easily enough, but I need two tab separations between the number and the user list. Is there a sed command that will insert at the beginning of each line? If so I can just run nl after I get some tabs up in the front.
Is installing "php5-suhosin" from yast and restarting apache enough to make suhosin work out of the box? Or do I need to add few lines to php.ini file and modify suhosin file?
HI am facing the strange issue in netbeans on ubuntu 9.04. whenever the file contains more than 3000 lines the characters overlap on each other and the file is not readable, where as if the file is less than 3000 lines it works fine. what may be the reason ?
I would like to modify the content of a text file in Linux, in the following way:=> the file has several of these lines:./run_pest3 ./g134366.04080_0.062 x 2_d043 1 0.43 results_EC=> I want to modify all lines to be:./run_pest3 ./g134366.04080_0.062 x 2_d043 1 0.43 results_EC0.062i.e., the last number of $2 should be "attached" to the end of $7, for each line.
I'm trying to output two certain fields of a very large text file to 2 very small text files. Then take those files and add all the lines together to come up with a total from each file (two totals).
Breakdown: Put 0 in a text file to be drawn by respective while loops for math later
Output last 60 integers to a file for total A (new integer every minute) Output last 60 integers to a file for total B (new integer every minute)
The two while loops are supposed to be adding the lines together. The echo commands at the end are for testing purposes, just to see the output. However, when I run this, I get the output of
Code:
0 0
Which is obviously not what it's supposed to be. Is there a more efficient way to do this or am I missing something in the script that would reset the values to "0"?
I need to get the max number from the name of a file
Formant of the file name: [a-zA-Z]*_[0-9][0-9]_[A-Z][A-Z].log Delimiter as underscore '_'
[code]....
known part in the above file name will be GA.log A give directory may or may not contain files in the above format or may contain file other then the above format if so then ignore it.
cmd=> ls *[0-9][0-9]_GA.log 2> /dev/null | awk -F_ '{ print $2}' | sort -nr | head -n1 | awk 'BEGIN { if ($1 >0 ) x=0; else x=1 } END {printf "%02.0f ", $1+1}'
output=> 01
if there are no files the output should be 01 and if file(s) found the output should be next highest number+1, In the above example it is 06 My cmd is bit lenghty. reduce my cmd and it should be in one line.
I'm having a file with repeated particular text lines. So I need to view the file content ignoring these lines. Is there anyway I can achieve this using VI
I am facing some problem regarding deletion of a line from a text file. The file consists of the lines of type which consists of more than 6 occurrences of : character in it. The line should be deleted completely and the line next to it must be shifted up.
I have a file that contains 100 ligns, i need to write a script that read 70 lignes and redirect those 70 ligns to another files and these 70ligns have to be erased in the first file
when i write this command head -70 somefile.txt>test.txt or
sed -n 70p somefile.txt>test.txt
i have these 70 lines in the text.txt files but these 70 lines have to be deleted inthe first file somefile.txt
