I've a script that it's invoked with n-variable parameters. Here's an examples:
Code:
./myprogram.sh inputdir FIELD1 FIELD2 ... FIELDN outputfile In the script I would like to get the FIELD names that were passed.
On one of my servers I see this when I log in. What does this mean and how can I get it to go away? Everything seems to work fine, but none of my other machines give this error.
View 5 Replies View RelatedI'm trying to write a script where I want to check if any of the parameters passed to a bash script match a string. The way I have it setup right now is if [ "$3" != "-disCopperBld" -a "$4" != "-disCopperBld" -a "$5" != "-disCopperBld" -a "$6" != "-disCopperBld"]but there might be a large number of parameters, so I was wondering if there is a better way to do this?EDIT:I tried this chunk of code out, and called the script with the option, -disableVenusBld, but it still prints out "Starting build". Am I doing something wrong?
while [ $# -ne 0 ]
do
arg="$1"
[code]....
I'm trying to read content of file to variable and use this variable in for loop. The problem is, when I have c++ comment style in file - /*. Spaces in line are also interpreted as separated lines.
For example:
Code:
Changing $files to "$files" eliminate these problems but causes that whole content of variable is treated as one string (one execution of loop).
I have a text file i that has a mailTo: NAME in it. In a bash script i need to extract NAME and put it in a $variable to use. How do i do this?
View 2 Replies View RelatedI have added an application launcher to my desktop and it works fine. However, I want to be able to feed parameters to the launcher before I launch the application. So, for instance, if the command is normally "/usr/bin/foo something" I want to be able to add the "something" parameter dynamically after clicking the launcher but before the application launches. Is this possible in Fedora?
View 2 Replies View Related Assume that i a having the following three lines in an executable file
#/bin/bash
a=Tue
Tue=1
When i give echo $a the value should be 1, how to do this.
I'm basically setting up two sshfs mounts and I have it set up so I run one command but type my password twice.Is there an easy to way to input a password using bash and pass that variable to another process asking for a password?
View 5 Replies View RelatedI want to create a variable that when passed as a parameter to another bash script will keep its string quotes (so it stays as one parameter). What ways can I achieve this cleanly?
Code:
john@ubuntu:/usr/local/src$ cat foo.sh
#!/bin/bash
echo $0
[code]....
In my script, and I would like to concatenate 2 variables names, to give me the true variable.I've 3 variables X1, X2 and X3, and I invoked them inside a for loop.
Code:
#!/bin/bash
X1=HELLO
[code]....
I know that cat can output the file, but how do you store that output in a variable to process:
Code:
CONTENT=cat file.txt
This doesn't seem to work?
i am dealing with this problemI have a function
function Une {
...
return $some_variable
[code]...
I have a hard time with my bash script.
It forget global variable's value.
First look at my script.
Code:
Echo "PKGS is [$PKGS] in after loop"
And data file for it is below. Let's name as list.txt
Code:
As you see, PKGS variable in loop has correct value.
However, after loop I can not get proper value for it.
When I run this command from shell, it runs ok
export REVS=`svn info svn+ssh://svn.myone.ca/var/svn/story/trunk/lib |grep 'Last Changed Rev:'| awk -F: '{print $2}'`
However when I save it into a file called test.sh (of course, I chmod it with +x), I got error "export: 2: bad variable name"
Here is the file:
#!/bin/bash
export REVS=`svn info svn+ssh://svn.myone.ca/var/svn/story/trunk/lib |grep 'Last Changed Rev:'| awk -F: '{print $2}'`
I am using ubuntu.
Quote:
#!/bin/sh
for i in {1..10}
do
for j in {1..50}
[code]....
The first echo generates something like: abc.de.fgh The second echo generates:
I do this:
Code:
a@b:~$ export A=hi
a@b:~$ echo $A
hi
a@b:~$ bash -c "export A=blah; echo $A"
hi
a@b:~$
Why doesn't the bash command print the new value of $A? Is there a way to make it do so?
I have a file (.tmpfile) and inside it is a string which i only know part of, the rest being a random group of characters... I would like to know how to pull the whole string out of the file and into a variable.
View 13 Replies View RelatedFrom the man page for bash...
Quote:
If the -c option is present, then commands are read from string. If there are arguments after the string, they are assigned to the positional parameters, starting with $0.
Code:
I have a bash script where I am replacing a date with a variable
Code:
variable="date"
sed -r "s/([0-9][0-9])/([0-9][0-9])/([0-9][0-9][0-9][0-9])/$variable/g" /path/to/file.txt
I have googled but cant find any info on what the -r, or sometimes I have seen -i and -e, after the "sed" I googled "sed parameters"
r appears to output the replaced date, but not change the original file. Usually using -i will change an original file for me. Does anyone know what the -i, -e, -r are about? A link to an explanation would be good, as I have been unable to find one in my searches.
I have a config file that contains:
my.config:
Code:
Now in my bash script, I want to get the output /home/user instead of $HOME once read. So far, I have managed to get the $HOME variable but I can't get it to echo the variable. All I get is the output $HOME.
Here is my parse_cmd script:
Code:
How do I pass file names as parameters to the shell through a script? I have installed 'wipe' from the repos and it is a shell based app. so I made a shellscript and put it in my script folder.
the normal usage of wipe is 'wipe -q /path/to/file' so if I were to make a shell script, right click on the file in question, and run the script on it, how to I permit the shell to wipe that file only, in other words pass it as a parameter. I think on windows it was the use of %1, such as. 'wipe -q %1' for example, which was simple enough. how to I achieve this with bash?
(variable substitution?)
(parameter expansion?)
Code:
run_repeatedly()
{
NUM=0
while [ <irrelevant stuff here> ]
[Code]....
run_repeatedly "programX -o "./messy/path/output-$NUM.txt"" The echo inside the loop prints "...-$NUM.txt"; obviously I'm aiming to have bash substitute the iteration number so that I end up with many output files not 1.
I'm writing a script for asterisk to monitor trunk failure, i do a loop for every trunk it got nad would like to name variable like server1=, server2= naming the server upgoing as the trunk is. here is the scripts:
[Code]....
what i would like to do is name the variable server, username and status with the count variable, like this server$COUNT to have server1 when on trunk one, bu as soon as i add the $COUNT after the server, it seems to try to make it a command, it says that:
Code:
./test.sh: line 45: server1=74.63.41.218: command not found
I get no print to stdout on screen from the C code.Does bash somehow block or mask it?I get print from bash. I get this error in the non-test bash script like: let "rdval = $rdstr"syntax error: operand expected (error token is " ")The let command prints rdval= but I presume this is due to the printf test statements getting in the way.I am getting no compile errors. Why does the C code not print the values specified?
View 2 Replies View RelatedI've searched online and found many examples using getopts, but nothing that clearly explains it use, nor any examples of what I'm trying to do. I have a script named "process". It can take from 0 to 3 different options. I'd like to be able to handle these options regardless of the order that they are entered.
Syntax:
process [-v] [-d #] [-h|-?] [string]
-v = verbose mode on
-d # = how deep to do the process, expecting a number parameter
-h or -? = show command usage
string = only process lines containing the specified string
[Code]..
Ive been using linux for a while but I am just getting into shell scripting, im currently trying to get a simple script for finding and copying files powered by the command:
Code:
This works fine from the command line but when put in a script such as:
Code:
Code:
with the keyboard inputs for $fc1 and $fc2 being *.doc and ~/test respectivly. The only problem i can see is the xargs -ivar "var" part possibly needing $var to be defined?
Is it possible to assign an "here documents" section to a variable in bash?I would like to assign the following to a variable:
Code:
<html>
<body>
<p>THis is a test</p>
</body>
</html>
i'm not actually using Linux but i figured this might be the right place nonetheless..o i've got this little script file to compile and run some Java code:
Code:
#!/bin/bash
cd /Users/acid/Desktop/javaTest
[code]...
I'm making a script I want to be able to just call (ie, rclick instead of ./rclick) where do I put it?
~/bin?
/bin?
/usr/bin?
Also, how do I pass a variable to the script (rclick 10 will rightclick 10 times) (Found, so simple... $1)Lastly, can I force it to run on CPU2? CPU1 is completley locked up if I run this on it... Or can I make it use less cpu cycles?
I have beat this enough and don't get what should have been a very simple thing to do. I build a variable;
Code:
CLIST=java,lua,python,php,perl,ruby,tcl
CLIST will be used by another bash script but I need to replace the commas with a space. I
[code]...
