i'm not actually using Linux but i figured this might be the right place nonetheless..o i've got this little script file to compile and run some Java code:
Code:
#!/bin/bash
cd /Users/acid/Desktop/javaTest
[code]...
I'm trying to read content of file to variable and use this variable in for loop. The problem is, when I have c++ comment style in file - /*. Spaces in line are also interpreted as separated lines.
For example:
Code:
Changing $files to "$files" eliminate these problems but causes that whole content of variable is treated as one string (one execution of loop).
I have a text file i that has a mailTo: NAME in it. In a bash script i need to extract NAME and put it in a $variable to use. How do i do this?
View 2 Replies View RelatedI know that cat can output the file, but how do you store that output in a variable to process:
Code:
CONTENT=cat file.txt
This doesn't seem to work?
I have a file (.tmpfile) and inside it is a string which i only know part of, the rest being a random group of characters... I would like to know how to pull the whole string out of the file and into a variable.
View 13 Replies View RelatedOn one of my servers I see this when I log in. What does this mean and how can I get it to go away? Everything seems to work fine, but none of my other machines give this error.
View 5 Replies View RelatedBasically, I am trying to locate and copy the newest .json bookmark backup in my .mozilla/firefox/w987sdg9.default/bookmarkbackups directory.
I tried this
Code:
ls -t ~/.mozilla/firefox/b1ahb1ah.default/bookmarkbackups/ | head -1
which does return the newest file, but only the filename itself. I found readlink, but I haven't gotten that to output a full path which I can then feed to copy. So, it seems to me that find might work well here, and I know how to find based on absolute dates, but not relative.
How can we do a file replacing string on debian/rules file using sed and bash variable ? I don't seem to be able to do so. I have tried below under the install section with arch dependent amd64, as far as I know all the bash commands are allowed to be executed in debian/rules file.
I have tried this :
Code: Select all
debian/rules file
ipaddr=`<long command to find ipaddr>`
myVar=`hostname`
sed -i -e 's/somestring/'$myVar'/g' $(configs)*
sed -i -e "s/somestring/$myVar/g" $(configs)*
[Code]...
Nothing works. Sed works but the hostname replacement doesn't work.
I understand the tilde (~) at the end of a file displayed in bash is a backup file in the Linux file system. Is there a way to keep these hidden when listing the contents of a directory?
View 2 Replies View RelatedI cannot move a my file into my archives directory in my bash scrip.
View 7 Replies View RelatedI googled and tried to find an easy step by step-by-step guide on how to use a bash script read a variable from a file. This is the way I did it (but it does not really work so something is wrong, but what?) (testfil2 contains one line that readsidnumber=1578
#!/bin/bash
value="/home/user1/Desktop/testfil2"
echo $value
kill $pidnumber
I want to remove the index.html file alone in the every directory via bash script, for example i have 5 directories in the path /var/www/vhost
anish
kumar
linux
question
friend
each directories have index.html file now i want to replace the index.html file alone from the other directory /var/tmp/vhosbak
anish
kumar
linux
question
friend
How we can do this using script?
# /etc/init.d/dhcpd.conf -bash: /etc/init.d/dhcpd.conf: No such file or directory what is the problem? and how to configure out "joe"
View 5 Replies View RelatedI've run into a problem with my bash program.
Code:a mkdir -p /home/chris/Downloads/ARCHIVE/`date -I` find /home/chris/Downloads* -mtime +14 -exec "cp {} /home/chris/Downloads/ARCHIVE/`date -I` ;
It's meant to move old files from my Downloads folder into an archive file (later tar them). The directory exists, I've used $PWD and nautilus and ls to make sure it's there, yet for every file it gives
Code: find: `cp /home/chris/Download/foo.bar /home/chris/Downloads/ARCHIVE/2011-08-19': No such file or directory I tried to test it on a different destination, specifically my home folder. IT still gave me the error.IS it a bad syntax within find or something else? I'm running a 32-bit system with 11.04
At my wit's end I can't find anything that I understand well enough to use. This is for a Unix class, we are working with shell scripting. File1 has 5 in it and File2 has 100 in it.The teacher wants us to read the values then do the math. This is what I have so far:#!/bin/bashvar1='cat File1'var2='cat File2'var3=`echo "scale=4; $var1 / $var2" | bc`echo The final result is: $var3
View 9 Replies View RelatedI am trying to think of a logic where my file contains some data I had to read and do some processing. Issue is that file contains data multiple times. For example:
:::::::::::
var1=value1
var2=value2
[code].....
I have to read first paragraph of variables and do some processing and then move on until the end of file. Variable names are same in whole file but for each paragraph the value is different. I can't think of a logic to attain this task. How can I do it? It should be a simple bash script, but I am not able to work out.
I am new to Linux and I wanted to setup a dedicated game server on my notebook.
I've installed Ubuntu 9.04. I than created a directory named /home/phlex/kfserver. I downloaded the application binary from Steam. I changed the file permission with chmod +x hldsupdatetool.bin and now the file attributes are -rwxr-xr-x.
The problem is when I try to run the binary file. If I type ./hldsupdatetool.bin I get an error message "-bash: ./hldsupdatetool.bin: No such file or directory. It seems the OS can't find the file. I've downloaded the file several times thinking it may have been corrupt but it's not. I can delete the file, I can rename it and so the file is there. Sometimes Linux can be aggravating to use.
I've a script that it's invoked with n-variable parameters. Here's an examples:
Code:
./myprogram.sh inputdir FIELD1 FIELD2 ... FIELDN outputfile In the script I would like to get the FIELD names that were passed.
Assume that i a having the following three lines in an executable file
#/bin/bash
a=Tue
Tue=1
When i give echo $a the value should be 1, how to do this.
I'm basically setting up two sshfs mounts and I have it set up so I run one command but type my password twice.Is there an easy to way to input a password using bash and pass that variable to another process asking for a password?
View 5 Replies View RelatedI want to create a variable that when passed as a parameter to another bash script will keep its string quotes (so it stays as one parameter). What ways can I achieve this cleanly?
Code:
john@ubuntu:/usr/local/src$ cat foo.sh
#!/bin/bash
echo $0
[code]....
In my script, and I would like to concatenate 2 variables names, to give me the true variable.I've 3 variables X1, X2 and X3, and I invoked them inside a for loop.
Code:
#!/bin/bash
X1=HELLO
[code]....
i am dealing with this problemI have a function
function Une {
...
return $some_variable
[code]...
I have a hard time with my bash script.
It forget global variable's value.
First look at my script.
Code:
Echo "PKGS is [$PKGS] in after loop"
And data file for it is below. Let's name as list.txt
Code:
As you see, PKGS variable in loop has correct value.
However, after loop I can not get proper value for it.
When I run this command from shell, it runs ok
export REVS=`svn info svn+ssh://svn.myone.ca/var/svn/story/trunk/lib |grep 'Last Changed Rev:'| awk -F: '{print $2}'`
However when I save it into a file called test.sh (of course, I chmod it with +x), I got error "export: 2: bad variable name"
Here is the file:
#!/bin/bash
export REVS=`svn info svn+ssh://svn.myone.ca/var/svn/story/trunk/lib |grep 'Last Changed Rev:'| awk -F: '{print $2}'`
I am using ubuntu.
Quote:
#!/bin/sh
for i in {1..10}
do
for j in {1..50}
[code]....
The first echo generates something like: abc.de.fgh The second echo generates:
I do this:
Code:
a@b:~$ export A=hi
a@b:~$ echo $A
hi
a@b:~$ bash -c "export A=blah; echo $A"
hi
a@b:~$
Why doesn't the bash command print the new value of $A? Is there a way to make it do so?
I had netbeans installed and I removed it using wheris netbeans and then sudo rm whatever files it gave.I also remember doing sudo rm -r /usr/lib/netbeans6.9 I did this because i wanted to install netbeans via the repo. Now I installed netbeans suing
Code:
varun@varun:~$ sudo apt-get install netbeans
and when I try running netbeans i get...
Code:
varun@varun:~$ netbeans
/bin/bash: : No such file or directory
Have i changed permissions or something?
I upgraded my php from 5.1.6 to 5.2.10 but at php -v I got a weird error, so I figured let's reinstall some things. This was the probably very dumb commando I used:
yum remove gcc-c++l zlib zlib-devel php*
Now I think my whole server is fxxxed because I get the following messages:
-bash: /usr/bin/yum: No such file or directory
-bash: rpm: command not found
-bash: ls: command not found
And the only thing I'm glad about is I still have an SSH connection open because creating a new connection isn't possible either. what should I do to repair this all.
I have a config file that contains:
my.config:
Code:
Now in my bash script, I want to get the output /home/user instead of $HOME once read. So far, I have managed to get the $HOME variable but I can't get it to echo the variable. All I get is the output $HOME.
Here is my parse_cmd script:
Code: