In my script, and I would like to concatenate 2 variables names, to give me the true variable.I've 3 variables X1, X2 and X3, and I invoked them inside a for loop.
Code:
#!/bin/bash
X1=HELLO
[code]....
I am supposed to take some small files, and print them to a specific printer, such that the small files are concatenated into one file. The file name has to be included in the file that gets printed.
Should I be looking to concatenate the files into one file with the file names included, and then print them?
something like: -printfunction -printername < file*
I'll try to be clear but I think I'm in a mess with my code right now, so it may appear here too
Here is a function. The part I want you to see is the 'eval' sentence.
This works.
It evaluates ${SourceTxt} (which is $1), takes away a part of it and uses it as an array to put data in.
That's alright.
Code:
Now, later, I NEED to count the number of elements in the array(s).
So, I try to do something like....
Which gives me the evaluated name ('#txtFields_email_customers[@]' e.g)
Or
Which gives me nothing....
I was wondering if I was reaching the limits of bash in this kind of capabilities, or if there is a.... bash-like solution. I.e. a good solution
How do I concatenate two environment variables in bash?
View 3 Replies View RelatedI have a file like below. For all the lines (except for the ones listed as 'Unknown Owner' and N/A') I would like to change to lower case and concatenate the first and last names.Before:
Code:
aaa.bbb.ccc.ddd,Unknown Owner
ddd.eee.fff.ggg,N/A
hhh.iii.jjj.kkk,John Doe
aaa.bbb.ccc.ddd,Mary Jane
[Code]...
On one of my servers I see this when I log in. What does this mean and how can I get it to go away? Everything seems to work fine, but none of my other machines give this error.
View 5 Replies View RelatedI'm trying to read content of file to variable and use this variable in for loop. The problem is, when I have c++ comment style in file - /*. Spaces in line are also interpreted as separated lines.
For example:
Code:
Changing $files to "$files" eliminate these problems but causes that whole content of variable is treated as one string (one execution of loop).
I have a text file i that has a mailTo: NAME in it. In a bash script i need to extract NAME and put it in a $variable to use. How do i do this?
View 2 Replies View RelatedI'd like to instruct bash to use a special method to perform completion on certain directory names. For example, bash would call a program of mine to perform completion if a path starts with "$$", and perform completion normally otherwise. Is this at all possible? How would you implement it? The goal is to allow autojump to complete paths for all commands when the user starts them with a certain prefix. So for example when copying a file from a far directory, you could type: cp $$patern + <Tab>
and autojump would complete cp /home/user/CompliCatedDireCTOry/long/path/bla/bla and you would just have to add where you want to put the file. Of course I can use ott's comment to add it to a few specific commands
I understand the tilde (~) at the end of a file displayed in bash is a backup file in the Linux file system. Is there a way to keep these hidden when listing the contents of a directory?
View 2 Replies View RelatedAny script to categorize folders with similar name into one directory. For example: There are 4 directories named LinuxFedora, LinuxUbuntu, WindowsXP and Windows7. The script should be able to create two folder named Linux and Windows wheree respective directories are moved.
Next example: If there are many folder as below:
DevLys 010
DevLys 010
[code]...
I've a script that it's invoked with n-variable parameters. Here's an examples:
Code:
./myprogram.sh inputdir FIELD1 FIELD2 ... FIELDN outputfile In the script I would like to get the FIELD names that were passed.
Assume that i a having the following three lines in an executable file
#/bin/bash
a=Tue
Tue=1
When i give echo $a the value should be 1, how to do this.
How can I handle the situation below so that the "Fatal Error" message is not shown. It would be ideal if I could supply a default class to be used. I'd prefer to not use: ini_set() to supress the errors but actually be able to "handle" the error.
Code:
<?php
class MyClass
[code]....
I'm basically setting up two sshfs mounts and I have it set up so I run one command but type my password twice.Is there an easy to way to input a password using bash and pass that variable to another process asking for a password?
View 5 Replies View RelatedI want to create a variable that when passed as a parameter to another bash script will keep its string quotes (so it stays as one parameter). What ways can I achieve this cleanly?
Code:
john@ubuntu:/usr/local/src$ cat foo.sh
#!/bin/bash
echo $0
[code]....
I know that cat can output the file, but how do you store that output in a variable to process:
Code:
CONTENT=cat file.txt
This doesn't seem to work?
I am bad with bash programming and I need some help how I can make variable names out of a string.I will need some help start doing that. And I think the first would be to get part of the filenames strings into variables.
View 7 Replies View RelatedI want to have an environment variable name (not value) containing ':', such as X:X=PQR. There seems to be no reason in principle why not. According to this:[URL].. the only printable character you can't have is '='. And indeed I can set and get such variables with a C program:
#include <stdio.h>
main()
{
setenv("X:X", "PQR", 1);
printf("%s
", getenv("X:X"));
[Code]..
and I can't find a quoting mechanism to make this work. Is there a unix guru out there who knows how to do this in bash, or any other linux shell?
i am dealing with this problemI have a function
function Une {
...
return $some_variable
[code]...
I have a hard time with my bash script.
It forget global variable's value.
First look at my script.
Code:
Echo "PKGS is [$PKGS] in after loop"
And data file for it is below. Let's name as list.txt
Code:
As you see, PKGS variable in loop has correct value.
However, after loop I can not get proper value for it.
When I run this command from shell, it runs ok
export REVS=`svn info svn+ssh://svn.myone.ca/var/svn/story/trunk/lib |grep 'Last Changed Rev:'| awk -F: '{print $2}'`
However when I save it into a file called test.sh (of course, I chmod it with +x), I got error "export: 2: bad variable name"
Here is the file:
#!/bin/bash
export REVS=`svn info svn+ssh://svn.myone.ca/var/svn/story/trunk/lib |grep 'Last Changed Rev:'| awk -F: '{print $2}'`
I am using ubuntu.
Quote:
#!/bin/sh
for i in {1..10}
do
for j in {1..50}
[code]....
The first echo generates something like: abc.de.fgh The second echo generates:
I do this:
Code:
a@b:~$ export A=hi
a@b:~$ echo $A
hi
a@b:~$ bash -c "export A=blah; echo $A"
hi
a@b:~$
Why doesn't the bash command print the new value of $A? Is there a way to make it do so?
I have a file (.tmpfile) and inside it is a string which i only know part of, the rest being a random group of characters... I would like to know how to pull the whole string out of the file and into a variable.
View 13 Replies View RelatedI have a config file that contains:
my.config:
Code:
Now in my bash script, I want to get the output /home/user instead of $HOME once read. So far, I have managed to get the $HOME variable but I can't get it to echo the variable. All I get is the output $HOME.
Here is my parse_cmd script:
Code:
(variable substitution?)
(parameter expansion?)
Code:
run_repeatedly()
{
NUM=0
while [ <irrelevant stuff here> ]
[Code]....
run_repeatedly "programX -o "./messy/path/output-$NUM.txt"" The echo inside the loop prints "...-$NUM.txt"; obviously I'm aiming to have bash substitute the iteration number so that I end up with many output files not 1.
I'm writing a script for asterisk to monitor trunk failure, i do a loop for every trunk it got nad would like to name variable like server1=, server2= naming the server upgoing as the trunk is. here is the scripts:
[Code]....
what i would like to do is name the variable server, username and status with the count variable, like this server$COUNT to have server1 when on trunk one, bu as soon as i add the $COUNT after the server, it seems to try to make it a command, it says that:
Code:
./test.sh: line 45: server1=74.63.41.218: command not found
Ive been using linux for a while but I am just getting into shell scripting, im currently trying to get a simple script for finding and copying files powered by the command:
Code:
This works fine from the command line but when put in a script such as:
Code:
Code:
with the keyboard inputs for $fc1 and $fc2 being *.doc and ~/test respectivly. The only problem i can see is the xargs -ivar "var" part possibly needing $var to be defined?
Can fedora do bash completion of package names in yum?
View 4 Replies View Related