I'm making a script I want to be able to just call (ie, rclick instead of ./rclick) where do I put it?
~/bin?
/bin?
/usr/bin?
Also, how do I pass a variable to the script (rclick 10 will rightclick 10 times) (Found, so simple... $1)Lastly, can I force it to run on CPU2? CPU1 is completley locked up if I run this on it... Or can I make it use less cpu cycles?
On one of my servers I see this when I log in. What does this mean and how can I get it to go away? Everything seems to work fine, but none of my other machines give this error.
View 5 Replies View RelatedI'm trying to read content of file to variable and use this variable in for loop. The problem is, when I have c++ comment style in file - /*. Spaces in line are also interpreted as separated lines.
For example:
Code:
Changing $files to "$files" eliminate these problems but causes that whole content of variable is treated as one string (one execution of loop).
I have a text file i that has a mailTo: NAME in it. In a bash script i need to extract NAME and put it in a $variable to use. How do i do this?
View 2 Replies View RelatedI have a config file that contains:
my.config:
Code:
Now in my bash script, I want to get the output /home/user instead of $HOME once read. So far, I have managed to get the $HOME variable but I can't get it to echo the variable. All I get is the output $HOME.
Here is my parse_cmd script:
Code:
Code:
#!/bin/bash
f1=apple
f2=banana
f3=grape
echo "Enter number 1,2 or 3:" # 3 is entered
read x
choice=${f+$x} # yielding choice=$f3
echo "$choice" # so $choice is, essentially, read as f3, which = grape
grape I am, essentially, trying to combine "f" and the number entered (3, for example) to create "f3", which when echoed as "$choice" will lead to grape!
I have beat this enough and don't get what should have been a very simple thing to do. I build a variable;
Code:
CLIST=java,lua,python,php,perl,ruby,tcl
CLIST will be used by another bash script but I need to replace the commas with a space. I
[code]...
I googled and tried to find an easy step by step-by-step guide on how to use a bash script read a variable from a file. This is the way I did it (but it does not really work so something is wrong, but what?) (testfil2 contains one line that readsidnumber=1578
#!/bin/bash
value="/home/user1/Desktop/testfil2"
echo $value
kill $pidnumber
Just a simple BASH for loop to read the file path from a text file (clean.txt) echo the variable for debug purposes, and scp it to a server I have using port 50 for SSH.
I've already formatted the entries in clean.txt to handle spaces correctly, using sed replacement.
Example from the clean.txt file:
Code:
/MP3/NAS000000001/Barenaked Ladies/Barenaked Ladies - Barenaked For The Holidays/20 Auld Lang Syne.mp3
/MP3/NAS000000001/Barenaked Ladies/Barenaked Ladies - Barenaked For The Holidays/14 Deck the Stills.mp3
[Code]....
I want to write a c program with some shell scripts.Now For a simple C program. I am Setting a variable called val2 in bash, now I want to use bash variable val2 in C code. How do I do that?The above doesn't work (coz its spawning a different memory space and when shell script ends the variable dies with it as per my research but how do I keep them in same memory space)Also Is there any Good reference where they teach how to integrate C and Bash Together?
View 5 Replies View RelatedI've a script that it's invoked with n-variable parameters. Here's an examples:
Code:
./myprogram.sh inputdir FIELD1 FIELD2 ... FIELDN outputfile In the script I would like to get the FIELD names that were passed.
Assume that i a having the following three lines in an executable file
#/bin/bash
a=Tue
Tue=1
When i give echo $a the value should be 1, how to do this.
i've just started to learn about functions in Bash scripting. I'm able to set the functions and execute the commands correctly. However, if my_var is set in the first function and then later in the script in the script the 2nd function is called, it doesn't seem to remember my_var and quits (at least i suspect this is the problem).
Here's my code (it requires yad available via webupd8. org). My specific problem seems to lay in line #27 where if we view the changelog and then exit that window, it returns to the "main" function but any subsequent commands cause a crash. Is this because of the get command on line #29? It's presumably now out of scope after calling menu on line #25?
I have a file with around 1000 IP addresses in it and I need to be able to ssh into each one of them, run a single command, and then exit. I already know the ssh command I want to run and it looks like this:
Code:
shpass -p [password] ssh -p 10022 -o StrictHostKeyChecking=no root@[ip variable] 'reboot'
(I know shpass is not good to use and keys are the correct way but I don't have any other options in this scenario.) if these ip addresses were in a .csv file, by themselves with no other information, how would I create a script to do the above command to each ip until the end of the file?
I cannot for the life of me get this little (simple) script I wrote to work. Here is the entire script:
Code:
#!/bin/bash
ASPECT=`mediainfo $1 |grep "Display aspect ratio" |cut -d : -f 2`
HEIGHT=`echo "320 / $ASPECT" |bc`
SIZE=`echo 320x$HEIGHT`
[code]......
An input filename ($1) is fed into mediainfo, which by the use of grep and cut spits out a single number which is the aspect ratio. This is then divided by bc into 320, which gives the desired height dimension for the file that I want ffmpeg to create for me. Finally, ffmpeg runs using the calculated dimensions... Basically, it's the passing of the $ASPECT variable to bc that seems to fail. It looks like bc won't read the output from the mediainfo line... It always crashes out with:
Code:
(standard_in) 1: illegal character: ^M I've tried doing something even simpler like this to debug by just trying it to display the calculation on the screen:
Code:
#!/bin/bash
ASPECT=`mediainfo $1 |grep "Display aspect ratio" |cut -d : -f 2`
HEIGHT=`echo "320 / $ASPECT" |bc`
echo $HEIGHT
and it does the same, so it's definitely bc that won't accept the output from mediainfo.
I am killing myself with this, please someone come to the rescue...
Code:
#!/bin/sh
IFILE=$@
[code]...
I am having some weird problems with calling commands stored in a variable (I need to do this to assemble a command with a bunch of parameters automatically and then execute it).Example code that will replicate the weirdness:
$ echo "hello world" > "test file.txt"
$ cat "test file.txt"
hello world
[code]....
I would expect the output to be:
hello world
What happens to the quotes? I have tried various combinations of single quotes, escaped quotes, etc, but it seems like quotes in a variable are not evaluated as quotes when that variable is executed.
I have this script:
Code:
a=awk'{print $8}' f1.txt
How can I make it store lines in $a ? In the way above it creates one big line.
How can we do a file replacing string on debian/rules file using sed and bash variable ? I don't seem to be able to do so. I have tried below under the install section with arch dependent amd64, as far as I know all the bash commands are allowed to be executed in debian/rules file.
I have tried this :
Code: Select all
debian/rules file
ipaddr=`<long command to find ipaddr>`
myVar=`hostname`
sed -i -e 's/somestring/'$myVar'/g' $(configs)*
sed -i -e "s/somestring/$myVar/g" $(configs)*
[Code]...
Nothing works. Sed works but the hostname replacement doesn't work.
I'm basically setting up two sshfs mounts and I have it set up so I run one command but type my password twice.Is there an easy to way to input a password using bash and pass that variable to another process asking for a password?
View 5 Replies View RelatedI want to create a variable that when passed as a parameter to another bash script will keep its string quotes (so it stays as one parameter). What ways can I achieve this cleanly?
Code:
john@ubuntu:/usr/local/src$ cat foo.sh
#!/bin/bash
echo $0
[code]....
In my script, and I would like to concatenate 2 variables names, to give me the true variable.I've 3 variables X1, X2 and X3, and I invoked them inside a for loop.
Code:
#!/bin/bash
X1=HELLO
[code]....
I know that cat can output the file, but how do you store that output in a variable to process:
Code:
CONTENT=cat file.txt
This doesn't seem to work?
I am not parsing on a webserver so is it possible to have both
#! /usr/bin/php &
#!/bin/bash
in the same script? Alternatively, I have a current bash script that I need to get some variables from mysql and not sure how to get mysql results in bash:
Quote:
mysql -h server.net -u username1 -paaa -e "USE squid; SELECT email, usern FROM TABLE WHERE blah blah;"
emailadd="resultfrom above"
usern="resultfromabove"
I'm using a simple Bash script to export an environment variable, eg.
Code:
export PATH=/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games:/my/own/dir
[code]....
I'm trying to use brace expansion on a string, but I can't seem to get it working with variable substitution:
Code:
$ cat script.sh
#!/bin/bash
echo {1,2,3} # 1.
VAR=1,2,3
[code]....
I've searched google, tldp.org and these forums and I can't seem to find an example of how this would work. I want #2 to work like #1. Any suggestions?
**Edit: I forgot to add, the values in VAR are not sequential and can have multiple digits. For example, VAR=13,17,10.
**Edit2: [URL] The bottom line of code in the first gray block of code shows that you cannot use variables in such an expansion:
Code:
#!/bin/bash
a=1
b=5
echo {$a..$b}
But I'm looking for pasting the complete contents of a variable into these braces, not some portion of it...
I have a program that loops over each word in a sentence. I need to append a constant to the beginning and end of each word. It works up until the last word on the line.
Code:
Output:
I was wondering if possible in bash for a variable to take the value of a function, I mean the function returns a value and a variable will take it. example:
[Code]....
Here is the code:
Code:
How ever when I run this script I get the following error
Quote:
I just don't get it, I have racked my brain trying to figure out every combination of how I should write this if statement and I can't get it to work.
I need to find the value of:
Code:
$Namenumber
My script asks for the name you want to look up and I want it to return the value of $Namenumber
I was thinking:
Code:
number=$"$name"number
but this returns
Code:
$Namenumber
but does not actually resolve what the variable $Namenumber is equal to.