I do this:
Code:
a@b:~$ export A=hi
a@b:~$ echo $A
hi
a@b:~$ bash -c "export A=blah; echo $A"
hi
a@b:~$
Why doesn't the bash command print the new value of $A? Is there a way to make it do so?
I have a file (.tmpfile) and inside it is a string which i only know part of, the rest being a random group of characters... I would like to know how to pull the whole string out of the file and into a variable.
View 13 Replies View Related(variable substitution?)
(parameter expansion?)
Code:
run_repeatedly()
{
NUM=0
while [ <irrelevant stuff here> ]
[Code]....
run_repeatedly "programX -o "./messy/path/output-$NUM.txt"" The echo inside the loop prints "...-$NUM.txt"; obviously I'm aiming to have bash substitute the iteration number so that I end up with many output files not 1.
I'm trying to make an environmental variable RPMS that will resolve to a website. I know I have to make the changes in .bash_profile, but all the things I try don't seem to want to work.
I've tried:
PATH=$RPMS:ftp://rha-server/pub/os/rhel5/Server/
or simply just making the variable itself
$RPMS=ftp://rha-server/pub/os/rhel5/Server/
The second one made a variable just fine, but when I attempted to run this command:
rpm -ihv $RPMS/caching-nameserver*
I have bash. I installed Qt libs and want to set environmental variable PATH, I tried some stuff from qt tutorials..
Here is what i tried:
Code:
and it does nothing so i tried
Code:
then checked path
Code:
Now there are two issues
1) the make gives error that header not found( probably make don't have the path)
2) when i closed the terminal and opened it again the PATH I newly entered was not there !
I have a program that loops over each word in a sentence. I need to append a constant to the beginning and end of each word. It works up until the last word on the line.
Code:
Output:
Here is the code:
Code:
How ever when I run this script I get the following error
Quote:
I just don't get it, I have racked my brain trying to figure out every combination of how I should write this if statement and I can't get it to work.
i am trying to declare an environmental variable in the /etc/profile' (as per the tutorial i'm following) but when i declare it and do an echo i get nothing.Here's what i've done so far..nside /etc/profile:
# /etc/profile: system-wide .profile file for the Bourne shell (sh(1))
# and Bourne compatible shells (bash(1), ksh(1), ash(1), ...).
if [ -d /etc/profile.d ]; then
[code]...
Bash 3.1.7
Code:
Code:
Code:
I think read A1 A2 makes A1, A2 string variables. Then, when A2 gets the value 01, '01' should be a string. But for some reason bash takes it as numeric. I know there are no types in bash.
When I run this command from shell, it runs ok
export REVS=`svn info svn+ssh://svn.myone.ca/var/svn/story/trunk/lib |grep 'Last Changed Rev:'| awk -F: '{print $2}'`
However when I save it into a file called test.sh (of course, I chmod it with +x), I got error "export: 2: bad variable name"
Here is the file:
#!/bin/bash
export REVS=`svn info svn+ssh://svn.myone.ca/var/svn/story/trunk/lib |grep 'Last Changed Rev:'| awk -F: '{print $2}'`
I am using ubuntu.
For example, if I'm in csh, I can use `setenv VARNAME varVALUE` while I can use export in Bash. Given that the environmental variables are created, can BASH read env vars from csh and vice versa?
View 2 Replies View RelatedIve been using linux for a while but I am just getting into shell scripting, im currently trying to get a simple script for finding and copying files powered by the command:
Code:
This works fine from the command line but when put in a script such as:
Code:
Code:
with the keyboard inputs for $fc1 and $fc2 being *.doc and ~/test respectivly. The only problem i can see is the xargs -ivar "var" part possibly needing $var to be defined?
I created some new accounts on a dev seat: Code: useradd -m newUser1.Users get created fine and can log in but are missing all the bash files (.bashrc, .bash_history, etc). When these users try to use the up and down arrows to view shell history they get junk characters. I checked and there is no history file in their homes. Where is the environmental variable set and how can I get this working?
View 1 Replies View RelatedCode:
/*[workhard@localhost BeginningLinuxProgrammingC3]$ echo new_value 1122
new_value 1122
It's ok when I add value"1122" to a new value. But how can I add value "11 22" to a new value.
#include <stdio.h>
#include<string.h>
#include <stdlib.h>
int main (int argc, char **argv)
[Code]....
I am Just trying to set the Environmental variable using a script file and my code is as follows:
#!/bin/bash
echo $PATH
PATH=${PATH}:/opt/bin
export PATH
echo Environmental Variable path is Set
echo $PATH
When I am running the above script, from the last line "echo $PATH" I am getting that /opt/bin has been appended to the PATH but again when I am typing echo $PATH in the terminal I am not getting the newly appended path.
On one of my servers I see this when I log in. What does this mean and how can I get it to go away? Everything seems to work fine, but none of my other machines give this error.
View 5 Replies View RelatedI am having all sorts of trouble trying to assign a variable within an awk script with the system command. I know there is a lot of ways around this problem, but for efficiency reasons, I would like to, within my awk script, do something like
system(x=3)
or
system(x=NR)
and, latter on the shell script which calls the awk script, use the variable $x. But nothing is passed to x. I have already tried things like
command = "x=3"
system(command)
and also used a pipeline within the system to pipe it to /bin/sh In fact tried a lot of stuff like that, using $(( )) etc etc etc I can create directories e write to files (yes, i could write to a file and read from there, but I dont think it is efficient, plus I am puzzled).
my script has a variable which comes in the form +00.00 +0.00 -00.00 or -0.00 (the numbers can be any in that form) for any that have a + symbol I need to remove the +, but if it has a - symbol it needs to stay.
i need to make a new variable with the string from the old variable btut without any plus sign. I have tried a lot of different ways with no success, each thing I tried either left the + or removed the entire string. I think this should work but doesn't
foo=+12.40
bar=${foo#+}
I'm facing problems in developing the script as there are errors that sometimes i dun have any idea on how to solve it.What i'm doing now is not homework, but i had been assigned to develop some system in linux.
My problem currently is on sub-string matter, where i need to read the line from file/directory and based on the line retrieved,i need to seperate the information in the line and assign as variable..
Below are my script:
Thus, the output something like this: file_name successfully ran on Mon Jul 12 23:15:00 SST 2009.
Now, what i need to do is to extract certain information from that line which is the name, date, time and the status
The desired output is:
So,my next step is to identify the sub-string and assigned as variable first in order to parse the info and output it.
Thus,my script is:
But i received error message which is:
I'm trying to execute the following command within a bash script:
Code:
tac /var/log/system.log | head -1
The script I wrote is:
[code]...
I wanted to find and replace a string from a perl file. I have written a script in bash which runs the following command.
perl -pi -e "s/$findstring/$replacestring/" testfile
where as $findstring = print F_WC_TMP"$line
";
and $replaceString = $line = join ' ', split ' ', $line; print F_WC_TMP"$line
";
But when I am running the above command, i think it is replacing the $findstring with the above mentioned string and hence it contains a $line, it is looking for the variable $line and not finding the exact string. I am confused about how to search for a string that contains $ in it and replace it with another $string.
How do i convert variable to string?
For example:
So how do i make the code with variable work?
My question has to do with how environmental variables are passed from parent to child processes at the BASH SOURCE CODE level. I have a need to add an environmental variable that has the complete invocation line so that the child process can see it via ENVP.I have been studying the source for a quite a while and can't seem to find how to make the variable pass to the child. In EXECUTE_CMD.c I found a good place to set the variable: I made a routine similar to PUT_COMMAND_NAME_INTO_ENV called PUT_COMMAND_LINE_INTO_ENV which would add "?=THE FULL INVOCATION LINE" as an environmental variable but it doesn't make it to the child. (I've tried names other than '?' but they don't work either.
I'm thinking that there is either a LIST or a attribute associated with those environmental variables that should be passed to the child but I can't find it.
I want to match some filename in some text, but the filenames I have no control of, so "[" can "]" can appear in the filenames.so do I always have to use sed to addslashes to these variables before I have to grep them? and what other characters have I missed other than "[", "]", "."?
View 4 Replies View RelatedI need to search a text file for a string of numbers which are different lengths, and always are between number=" and " like:
number="1234567890"
number="22390"
I need to grab those numbers and pipe each one to a line in a file. I've already tried something with awk and that didn't seem to work.
i use this script to get the time and date of back and fourth transactions for a particular execution id. I use a substr command on the 5th column to to cut the milli seconds off the time value. - otherwise the times would look like 08:30:04.235
grep <executionID> <auditfile> | awk '{ print $1, $2, $3, $4, substr($5,1,8}
FIX -> Mon 3/1/2010 08:30:04
FIX <- Mon 3/1/2010 08:32:36
FIX <- Mon 3/1/2010 08:35:08
[code].....
anyhow - i append two sed commands to further clarify the direction of the message.
awk '{ print $1, $2, $3, $4, substr($5,1,8} | sed -e 's/->/ ->IN/g' | sed -e 's/<-/<-OUT/g'
FIX -> IN Mon 3/1/2010 08:30:04
FIX <- OUT Mon 3/1/2010 08:32:36
[code]....
I tried using an awk gsub () command within the string instead of the two seds, but it did not work:
awk '{ print gsub(/<regex>/, <replace with>,$1), $2, $3, $4, substr($5,1,8}
the sed works ok, but it would be cooler to make the replacement within the awk command:
gsub(/->/,-> IN, $1)
Is there a way where i could replace the value of the $1 column in the awk print string?
I'm trying to read content of file to variable and use this variable in for loop. The problem is, when I have c++ comment style in file - /*. Spaces in line are also interpreted as separated lines.
For example:
Code:
Changing $files to "$files" eliminate these problems but causes that whole content of variable is treated as one string (one execution of loop).
I have a text file i that has a mailTo: NAME in it. In a bash script i need to extract NAME and put it in a $variable to use. How do i do this?
View 2 Replies View RelatedI've a string "this.is.a.name", and I would like to return "is.a.name". How can I do that in bash?
View 3 Replies View RelatedI've a script that it's invoked with n-variable parameters. Here's an examples:
Code:
./myprogram.sh inputdir FIELD1 FIELD2 ... FIELDN outputfile In the script I would like to get the FIELD names that were passed.