I have the large file (textfile) there are word:
code-007100
...
code-007199
How to substitute those all words, so it will change all instances to:
code-007200
...
code-007299
I'm writing a bash script to search html files, and when I find any occurrence of an img src tag like this:
<img src="123-picture-normal.jpg" alt="some random user entered text" border="0">
I want to add a second line below it that looks like:
<img src="123-picture-thumbnail.jpg" alt="some random user entered text" border="0">
All I need to do is duplicate the line but replace "normal" with "thumbnail"
Each file can have multiple img src tags with different numbered jpgs.
I have a feeling this is a job for sed, but I'm struggling with it. Any ideas?
I want to go through a log file and find pattern1 and then a pattern2 only after pattern 1.So for example I want to know howManyRecords was in 13:30.I figured I grep for "start time for the job" and then only after that (and before the next occurence of that) grep for "howManyRecords". Is this a sane way?
View 1 Replies View RelatedI want to search a file for a particular pattern and if pattern found replace the line with new text. i am using awk 'match($0,"pattern") != 0 {print $0} ' filename to check if the pattern exists.how do i get the line number of the pattern and delete that line and replace the line with my new text?
View 1 Replies View RelatedI have to enhance the behaviour of a backup script written in perl. I don't need to change it, what I need to do is to create a bash script that does some checks like file name and file size, execute the backup script then check if the backup files match the original files.Here's how I try to do it:
- read the files from the original files folder
- store them in an array
- search in the array the files that have a specific file extension
- store the file names that match the search pattern (I know the backup script skips some files so I can hardcode the search pattern)
- run the backup script
- read the files from the backup folder
- store them in an array
- compare the original files name and size stored in an array with those from the backup folder
- send a report email
I have tried making this substitution using both of
Code:
Sed operates with no comment but does nothing. awk objects to the variables content because they include the occasional non-breaking-space. The presence of these is essential so that bash will properly distribute the content of each line to an array.
The content of "orc" and "orch" is as follows (the non-breaking-spaces show as *).
Code:
I tried to use the command:
sed -i ''$line_number',/port/s/port/portMARKED/' file
to substitute the word "port" by the word "portMARKED" at the specific line that is saved in "line_number". The substitution happens, but it is copying my line twice... and I have no idea why... I need to make a single substitution of one word for another at a certain line in my text file. Would somebody know how I could do that?
Assume that i a having the following three lines in an executable file
#/bin/bash
a=Tue
Tue=1
When i give echo $a the value should be 1, how to do this.
I have several (vhdl) files containing a pattern with newline characters that I need to replace by another pattern that also contains newline characters.
I start with something like:
Code:
I want to replace it by something like:
Code:
(I need to paste some lines)
As I need to do this (very) often I want to use a shell script.
I tried:
1.
Code:
result:
Code:
2.
Code:
result:
File remains unchanged
3.
Code:
result:
Code:
4.
Code:
result:
Displays the unchanged testfile
How I can automate the pattern replacement?
Code:
(variable substitution?)
(parameter expansion?)
Code:
run_repeatedly()
{
NUM=0
while [ <irrelevant stuff here> ]
[Code]....
run_repeatedly "programX -o "./messy/path/output-$NUM.txt"" The echo inside the loop prints "...-$NUM.txt"; obviously I'm aiming to have bash substitute the iteration number so that I end up with many output files not 1.
I want to cut out part of the 'uptime' output so all it displays is the load average. In the end I want to cut out everything before the word 'load'. I am a total sed newbie and could really use some examples or links. I've googled and haven't found anything useful yet.##edit###I used the 'cut' command- The code was Code:uptime |cut -d, -f 2,3,4,5 |cut 13-
View 5 Replies View RelatedI want to replace a pattern in a file.The file format is given below.
111111
path=/home/fun/
222222
path=/home/fun/
[Code]....
I want to replace "path=/home/fun" with another pattern, but only under "111111", all the others should be the same.
I have a requirement to list files using find command My folder contains below list of files with out extention.I have a requirement to exclude only ABC.123.* type files and list others. Even though files having MNO contains this pattern i should not exclude. Even if file ends with .txt or .doc it should not be excluded. That is ABC.123.1234.txt should not be excluded.But I am not getting what is required. Can any one please let me know if I am doing wrong any where. As per my requirement I cannot use grep, -regex, or -regex attributes to find command.
View 7 Replies View RelatedI need to search for a string "teststring" in all *.java files coming under /home/user1/ (including subfolders). How can I do it in linux via shell command.
View 5 Replies View RelatedIf I wanted to copy all *.so files from src to dst I'd do:
cp src/*.so dst
However, I want to copy all *.so files from src and it's subdirs into dst.
I would like to remove a string pattern which like this.You should not remove this /*This is the part should remove*/ You should not remove this.I would like to remove all the text inside the /* and */.
View 2 Replies View RelatedHow can I use grep -Ev "pattern" not only to delete the matching "pattern" but to edit and save the file permanently as well
View 2 Replies View RelatedHow do yo find a pattern with sed or awk and then:
- add a # at the beginning of the line containing it
- and add a # at the beginning of the following 2 lines, too?
Say, I want to comment out the line containing "which 0launch" and the two lines following it:
if [ -x "`which 0launch`" ]; then
exec 0launch http://rox.sourceforge.net/2005/interfaces/ROX-Filer -S
fi
Expected result:
#if [ -x "`which 0launch`" ]; then
# exec 0launch http://rox.sourceforge.net/2005/interfaces/ROX-Filer -S
#fi
I need this because I do not want to comment out every line containing "fi", just the "fi" of this specific if statement.
Want to grep pattern of root dir. (/). Staying in current directory. But I don't want to use the below code:
cd /
grep m *
I have some lines of text and I want to detect words that meet some criteria with sed.
E.g. The line "tetris cat dog test cactus stereotype"
I want to detect the word that contains two (2) ore more t letters. That mean the words tetris, test and stereotype.
The following regex doesn't do the job because it can;t distinguish words very well.
I thinks I have ti incorporate something like [^ ] in the regex but I wasn't successful...
I have to use sed with this problem, and sed is extremely complicated, they could probably teach a whole class on this entire function.
Here's an example to show what I need to do:
Code...
how would I say that every line before I reach the first match of "sweet" should be deleted so that the output will look like: Code...
wher i wil find rhce dumps of new pattern.
View 3 Replies View RelatedI would like to write a newline delimeted rules file using PCREs for use with the grep command. Grep has the option -f to obtain the search pattern from a file, and option -P to search using PCREs. However, these two options do not work together. The -f option only seems to work with fixed string rules.A friend previously helped me get around this limitation somehow, but I can't remember how he did it. I also would like the ability to add comments at the end of each rule in the file.
View 11 Replies View RelatedI was looking for a way to get the same or similar functionality as the Nokia PC Suite on Ubuntu 10.04. I did find a discussion here [url].
However it is fairly old (2008). I was wondering if it is possible to get more recent information.
In the Ubuntu Software Center I find two applications that seem to fit the bill. I need to know which is better or are the complimentary.
I have 8 files, and each contains around 2000 lines. I want to search the particular word in these files between line number 1500 to 2500.
The output should look like:
sample_1.txt :
1510:declare var testing
sample_2.txt :
1610:declare var testing
sample_7.txt :
1610:declare var testing
sample_10.txt :
1710:declare var testing
Is it possible to use grep for this task?
I've got files in a directory as follows:
1.png
1_thumb.png
1-1.png
1-1_thumb.png
[code]....
I want to list all the files that don't have a copy with the same filename with -1 somewhere in it. So, in the example above, the results would be 3.png.
NB: the file and its copy with "-1" in it will be the same filesize, if that helps.
I want to replace a pattern with other pattern in a textfile. But there are two same patterns,but I need two change only the second occurence. EG:
Text file is
aaaa=1
bbbb=2
cccc=3
dddd=4
[code]....
Now I want to change aaaa=x into some other entry.
I would like to search a specific directory and pull out filenames that have this pattern: "_bsc_" Then I want to do some processing and move the file to another directory
View 5 Replies View RelatedI have a file called test. It has the following contents.Code:there youI want the output to be.Code:replaced youI am trying to use the sed command to replace every occurance of "hey newline there" with "replaced". I tried the following naive apporach.Code:sed 's/heythere/replace/' testThis gives a result containing the same data as the test file.
View 3 Replies View RelatedI have found many information about how to delete/grab a line in a text file including delete line with match a pattern but I did not find info about how to delete a line which match a pattern of a particular column only.
for example mydata.txt:
id type x y z
1 6 0.474611 0.227223 0.583947
[code]....