How to get the week number in linux using gawk with different first day of the week? the date command can give me the week number with +%V but it is based on Monday (1-53) or +%U (based on Sunday, 0-53).
I tried to to do this: date -d "ddmmyy+2days" +%V, but the result is not correct. I want the first day of the week is based on Saturday.
Sequentially number files based on date modified (rename cli)
I'm almost done a larger script which takes all the pictures in a folder, converts it to video, and emails it to me. Everything worked fine until I realized the picture filenames weren't always starting at 1, then ffmpeg chokes.
I have a bunch of files in a folder which I need to rename to:
I don't want to install any additional packages and I'd like this to run in a single command if possible.
If not possible, then a bash script would work too.
I am using CRON to create a new, blank file, every minute, in a specific location on my web server. After web searching, and reading man pages, I get the impression that the following command is supposed to work:touch /home/mydomain/var/folder/attachments/`date +%H%M`.txtThis should give me a new file with a file name that is the current hour and minute.However, when executed, the CRON mailer reports:touch /home/mydomain/var/folder/attachments/`date +/bin/sh: -c: line 0: unexpected EOF while looking for matching /bin/sh: -c: line 1: syntax error: unexpected end of fileSo, it looks like shell is seeing the plus (+) sign as an EOFObviously, nothing get created.What would be the easiest, single line command to create an empty file, at a given location, with a time based file name
View 5 Replies View RelatedI'd like to tweak my Conky so it automatically displays the days of the week correctly. So for example, if TODAY were Tuesday, it would look like this:
Tuesday
Wednesday
Thursday
Friday
[etc.]
And then tomorrow, *automatically*, it would look like this:
Wednesday
Thursday
Friday
[etc.]
I know I can get it to display *today's* date like this:
${time %A}
But how do I get it to display tomorrow's date?
I know find can do what I am looking for, but I am wondering if there is an alternative way to find files on the filesystem either created before/after a certain point, or at a certain time.
Typically I rely on updatedb & locate for most of my file searching needs. Issues with those tools, though, are that it only has directory and file names, and it only creates a database of local directories, not anything mounted via CIFS|NFS or via -o loop (eg, .iso images).
So if I need to find files created after yesterday across the entire system (local and remote filesystems), I am currently needing to use find.
What other tools, if any, would accomplish this in a similar fashion?
I have tried ls and grep, but that requires (in my attempts so far) multiple searches:
ls -lR | grep Aug | grep 10
ls -lR | grep Aug | grep 11
What offline method is there of finding out days since a certain date. Example: How would someone find the number of days from 1-Jan-2003 to 7-Dec-2010? Could someone write a script that takes in the 2 dates and output the number of days?
View 5 Replies View Relatedselectively archive the subdirectories of a single parent directory in which said subdirectories have creation year-date 2008 and older.
View 5 Replies View RelatedHow to get output of text file containing account number, debit amount, credit amount,date using shell script?
View 1 Replies View RelatedI'm looking for some help for renaming files that contain a sequential number. The files are spoken word radio programs that have a sequential program number. I want to have a date in the file name ie. Pgm 3028 Abcxyz 2010-01-18.mp3. Here's a catch, the program only air Mon-Fri, yet I want all the programs to play in sequenceDoes anyone know of a script out there that can do this? I don't have programming knowledge to do myself.
View 2 Replies View RelatedI have hundreds of MTS and AVI files since 2000 and would like to rename them in the following manner based on the date created: DD-MMM-YYYY HH.MM.SS_X; where X begins at 1 and increments by 1 if there are dublicate date/time stamped videos.
Ex: 19-Nov-2002 08.12.30.avi, 19-Nov-2002 08:13:30_1 and 19-Nov-2002 08:13:30_2
Someone previously wrote the following script for me, and it works great for photos. It uses EXIV2 to get the image date created info. I have tried to understand the script, but am struggling. The video files I have can use the date modified since I have not modified them since I filmed them.
#!/usr/bin/env python
import os
import stat
import pyexiv2
import time
directory = '/home/david/Desktop/test'
[Code].....
Originally Posted by Kenny_StrawnPlease wrap [CODE] tags aroung any code posted here. The full source that way could still be posted.I am trying to copy all the files in the directory based on the modification date (i.e created on Dec 29). Not able to find the proper command for this. This is what I have tried.
(none) login: root
#
# cd /mnt/hd/
[code]...
I have 3 gateways in my office. I want to redirect all web traffic (port 80 and 443) through one gateway and ssh connections through other one. All machines have single network interface. For this what I did is created an ip alias et0:1 and assigned ip to it. Then wrote an ip route rule to route packets from eth0:1's ip to other gateway. All other traffic will go through default gateway. But here I am not sure how I can make web browser to use eth0:1's ip. It's using eth0 's ip. I wrote a ip table rule to change source ip of http packets to et0:1's ip. But rule is on POSTROUTING chain. So I think it's happening after routing.
View 4 Replies View RelatedI can not for the life of me determine how to get the monitor serial number / manufacture date using Extended Display Identification Data (EDID). Does anyone know? None of the following provide this info:
monitor-get-edid
monitor-edid --v
monitor-edid --MonitorsDB
monitor-get-edid | monitor-parse-edid
dmidecode -q
### TO DO: Determine the report file name based on the source directory name and current date### The report name and thumbnail directory must follow this pattern: source-%j-%H### for example, for pictures in /home/you/pictures, the file name will be: pictures-%j-%H### HINT: Use sed to extract the directory name from the path and combine it with date command output
View 1 Replies View RelatedI'm dipping my toes into some bash scripting and was wondering if there was a way to delete a file not based on how old it is, but rather how many other files are currently in the folder... or something to that effect....
What I'm doing is creating a script to back up a folder nightly. I'd like to keep a maximum of 3 backups. However in case the script for some reason fails to run one night (computer turned off possibly) I don't want to set the condition for deletion to be the date.
I know that if I run:
Code:
find /path/to/files* -mtime +3 -exec rm {} ;
that it will delete everything older than three days. -atime and -ctime don't seem to be what I"m looking for... is there another command I can use to achieve what I"m trying to?
Anyone have a ksh solution to convert julian date to gregorian date?
View 6 Replies View RelatedI need a script that will take all the files in a given directory and create new monthly sub-directories and sort all the files based on the creation date into the appropriate directory.For example, all files created between 01/01/09 and 01/31/09 will be placed in 'JAN-2009'
View 5 Replies View RelatedI have been requested to deliver the logs for last friday, but the problem is that I have configured squid logs to be weekly, not daily. How can I extract the logs generated friday from the week file?
View 3 Replies View Relatedi am going to write rhce exam in this month ,i want some tips how to do revision for the same.
View 1 Replies View RelatedWe need to collect data from nagios once a week and have it sent/mailed.What would be a good place to get it? I am thinking starting with nagios/var/nagios.logscan it once a week and get most recent entries from each hosts.
View 3 Replies View RelatedI notice that on DistroWatch, the descriptions include "debian based", "arch based", etc. For the newbie, is there any practical difference between the different bases, or is it a Coke vs Pepsi type question?
Is a distro based on Debian say, easier for a newbie to learn or work with than say one that is FreeBSD based?
When you use an IDE and it asks you if you want frame based or dialog based, what is the difference?
View 1 Replies View Relatedwhat distro should i use, rpm based or debian based?
View 2 Replies View RelatedSo unbeknownst to me until today, but apparently all configure scripts rely on some version of awk to create the Makefile when config.status is run.how to get gawk reinstalled?I have compiled one on Ubuntu and copied it to my other machine but when run it throws the error:Code:./gawk: no such file or directorySo I am guessing I either need to create a static copy or maybe also copy the libs created from compile with it.
View 7 Replies View RelatedI write a little script by bash.
#!/bin/bash
a=`gawk '/Iterations /{print $0}' hoge.log | gawk 'BEGIN{FS=" "}{print ($4)}'`
a=`expr 3 '*' $a`
[code]...
Why does unix ps -l whows one number in column "PRI" but in same time ps -o pri shows another number? cpu and nice are zero for those processes
View 1 Replies View Relatedyes, this is a homework question, but no - I'm not trying to get anyone to do it for me. I think that I am really close, but can't quite get one small aspect to work. in gawk, I want to include a variable name in the search string, but the below code doesn't work.
read -p 'Login name please? ' uLogName
userID=$(gawk -F: '/"$uLogName"/{print $3}' /etc/passwd)
echo $userID
[code]...
I want to delete lines which contain the word "Fehler" but for some reason my programm isn't working:
Code: BEGIN { FS="|"
OFS="|"
SUBSEP="|"
[code]...
I have a directory where there are folders and in them some .txt data files. I am trying to output a .txt file with the folder name and the number of .txt files in it using gawk. However, when I run my shell program, because print is nested in a "while" loop, gawk overwrites what's already saved in the output file. I want gawk to print "new" output in a new line without overwriting the already existing text in the output fil
#! /bin/sh
# getting the folder list and the number of folders
ls | gawk '{print}' > ../folder_list.txt
[code]...
I have 2 text files : file1.txt and file2.txt
cat file1.txt
15 this is a sentence containing various words and spaces
34 this is a another sentence containing various words and spaces
cat file2.txt
2 this is sentence1file2
6 this is sentence2file2
54 this is sentence3file2
I would like to join these 2 files. The result should look as follows :
cat joinedfile.txt
2 this is sentence1file2
6 this is sentence2file2
15 this is a sentence containing various words and spaces
34 this is a another sentence containing various words and spaces
54 this is sentence3file2
==> so the joined file must be sorted on the first number. Any ideas how this can be achieved ?