Almost by mistake, I figured out you could do something like:
$ cp foo.data bar1.data
$ ^bar1^bar2
And that runs the same command with bar2.data instead of bar1.data. Now, how about if I have multiple occurrences of the target word? For example:
$ cp foo.data bar.data
$ ^data^index
It only replaces the first data extension. How do I get it to replace both?
Here's the actual line of code, which exists in a bash script:
Code:
I want to replace instances like this:
Code:
with this:
Code:
Using this:
Code:
Which works great when there's only ONE of the pattern on the line. But in a case like the "actual line" I posted first, where there are two patterns, separated by a slash, only ONE gets replaced
Watch:
Code:
Why? There must be (among many other things) something I'm not knowing about sed, that's causing this.
-- I'm currently using the ~ (tilde) as the separator in the sed command. It doesn't matter, I've used / ~ and % with no difference.
-- As a test, I tried putting a different character(s) in the middle of the original pattern instead of the / but that made no difference.
-- I've come up with various similar but slightly different regexs that will do this replacement, but they all have had this same result.
-- I tried the sed single-quoted, double-quoted, and unquoted; the latter fails to execute, and the formers both work as described here: wrong.
Can the Replace function replace more than one word with the same character(s)?
Also, do you know how to access the plugins provided by the gedit-plugins package?
I'm trying to process a postscript file and I want to change alternate pages by finding the string '%%EndPageSetup' (and then adding a line after it).
I've tried using sed with labels and a branching program to ignore the odd occurrences and process the even ones. In the code below I tried searching for the first and ignoring it by jumping to next and processing it and then to the next odd page and so on.
My logic is obviously flawed here as it doesn't work but I've tried the following:
Code:
#!/bin/bash
sed -e '/%%EndPageSetup/{
b even
:odd
/%%EndPageSetup/ b even
:even
s/%%EndPageSetup/%%EndPageSetup++/ b odd}' filename.ps > newfile.ps
Want to search for ~ and delete it as well as to append the entire line to the above line. For Ex:
1111xxxx date Sandy area is ~around this area.3222xxx date There seems to ~left side of map, the colours are accurate (showing green areas)Even if I ~zoom in, the green parks, xxx3258 date The dammed up
~away, the "other" body of water varies ~blackNatural gas leaching.
IT MUST LOOK LIKE:
1111xxxx date Sandy area is around this area. 3222xxx date There seems to left side of map, the colours are accurate (showing green areas)Even if I zoom in, the green parks, xxx3258 date The dammed up away, the "other" body of water varies blackNatural gas leaching.
I want to use SED to do the following: In a text file replace any occurrences of the three character string ZZZ with a quotation mark "and. replace all occurrences of a comma with a semi-colon. It is the S/ / / command which is stumping me on the first issue...inparticular how to get the replace string to be quote.
View 9 Replies View RelatedI am trying to replace the first number in a string at the end of the line with the word that matches that number. for example i want to replace 546215 to be five-46215. The command that I have tried is
sed -r 's/5[0-9]{5}$/five-[0-9]{5}/'
I have a output file look like this:
{"test1" : "test2", "test3" : "test4"},
How can I read word by word in each line?This is not working code:
a=0
while read word
do a=$(($a+1));
[code]...
In linux, what's a good way to find all occurrences of "string1" in files under a directory and replace them with "string2"?
View 1 Replies View RelatedI am pretty new to bash scripting...I am trying to write a script that will take an input and read it word for word and then DO something with it like echo. I have been able to find how to read word for word from a file but I don't know how to do it with input.
I was looking for something like
Code:
exit 0 The input would be A-Z a-z 0-9 and have a single space between each word.
I'm having problems with Tomboy. I have a few hundred note files and I need to go through all of them and replace all instances of "<link:broken>a</link:broken>" with "a". Is there a bash command I can use to do this?
View 2 Replies View RelatedI wanted to find and replace a string from a perl file. I have written a script in bash which runs the following command.
perl -pi -e "s/$findstring/$replacestring/" testfile
where as $findstring = print F_WC_TMP"$line
";
and $replaceString = $line = join ' ', split ' ', $line; print F_WC_TMP"$line
";
But when I am running the above command, i think it is replacing the $findstring with the above mentioned string and hence it contains a $line, it is looking for the variable $line and not finding the exact string. I am confused about how to search for a string that contains $ in it and replace it with another $string.
I'm trying to use Bash to search some directories for a word in one of documents. I've tried:
Code:
$ grep -R Brzeninski /media/disk-1/Dual_Data/
but It never returned a prompt, and i'm not sure what grep means or does.
How can I move around the bash commandline efficiently?In the Windows prompt, one can go back or forward one word by pressing ctrl and <-/->.What's the equivalent in a bash environment?
View 1 Replies View RelatedI have a text file that contains a single word and I want to write a bash script that will read the word from the text file... The following is my incorrect attempt, as it assigns the name of the textfile to the variable as opposed to the word stored within the textfile:(assume I have a text file value.txt that has its contents a single word, say wordone)
Code:
#!/bin/sh
for f in value.txt
do
echo $f
done
so the output of the above script is value.txt, however I want it to be wordone.to summarise: how do I assign the value of the word contained within a textfile to a variable?
I have a file in the form below, and wish to replace each start line with an increasing number. So instead of:
Code:
start
content content
start
content content
start
[Code]....
After several searches and a bit of messing around, it's clear I'm missing something, so was wondering if anyone could offer any insight?
I want to write a small script to rename a bunch of files. Their name is of the form 'long number'|'name'|'extension', for example:
52354Football_part2.flv
2353452Nice_weather_4_ducks.flv
I would like to rename these to:
Football_part2.flv
Nice_weather_4_ducks.flv
If in my script I use something like
Code:
sed s/[0-9]//g
on each file, I will get
Football_part.flv, instead of Football_part2.flv,
and
Nice_weather__ducks.flv, instead of Nice_weather_4_ducks.flv.
how to instruct sed to only remove numbers that are in the beginning of the name in a simple way?
i am using openSUSE 10.3 & like to use power of terminal to do tasks.I want to search all files containing word 'echo' in given folder.What should be command.
View 14 Replies View RelatedWhat is the command to sort a text file by the second word?
View 4 Replies View RelatedWhen looking for a certain word or phrase in the man page of linux command, one can type '/' followed by the word/phrase to search for it. What I'd like to be able to do is to search for the next occurrence of the word/phrase without having to type it out again. Kinda like when you use 'ctrl+f' in a browser to search for a word, and then press 'enter' to find the next occurrence of that word.If this is possible to do, how do I do it?
View 2 Replies View Relatedtell me the command used to find a specific word in directories and sub-directories in linux?
View 4 Replies View RelatedI create a bash script that writes another bash file. But in the generated bash file I want to write a bash command in the file and not executing it.Here's my bash file:
Code:
#!/bin/bash
cat > ~/generateGridmix2data.sh << END
[code]...
I have to modify formsweb.cfg file in Oracle IAS.
Problem description
In formsweb.cfg file are two lines with labels archive_jini= and archive= at the beginning of line. After equal sign (=) is row of filenames of java archives delimited by coma(,). When I insert a new jar file in java directory, I have to append the very same name of jar file to both lines if that name is not yet present.
Example snippet from formsweb.cfg
Is there any command in Linux which will find a particular word in all the files in a given directory and the folders below and replace it with a new word?
View 4 Replies View Relatedhow to use a variable in a sed command, but I can't get the output into a variable.
FILE=readme.txt
now i want to remove the extension of filename
so file woud be:
FILE=readme
my script:
NFILE=`echo $FILE | sed 's/.txt//'`
mv ../out/$FILE ../out/$NFILE
FILE=$NFILE
now when i run my script. i get this unknown character extensions in my new file(NFILE).
For example, I always go to this path:
/user/something/somefolders/somewhere
but I don't want to type
cd
/user/something/somefolders/somewhere
in the terminal all the time, can I have some short hand to do so? for example, can I do something like
cd commandPlace
to replace the path?
I have a jar, and I need to replace a class in it, at this moment, I can only open it with "archive manager" and then drag and drop the new compiled class into the jar, but I think this is really boring, if I can do with with just a command ?
View 1 Replies View RelatedI have an SQL dump, file.sql that has many references to a particular domain, d1.com. I would like to run a command that can replace every occurrence of d1.com with d2.com. I've tried looking into sed before but the man pages are quite daunting.
View 14 Replies View RelatedI have:
Code:
C:u002Cdatau002CDocuments
If I used:
Code:
sed 's/u0052//'
It only removes the first occurrence. How can I remove all occurrence in the line?
Bash's command history is great, especially it is useful when adding the history -a command to the COMMAND_PROMPT.However, I'm wondering if there is a way to log the commands to a file as soon as the Return key is pressed, e.g. before starting the command and not on completion of the command (using the COMMAND_PROMPT option would save the command once the prompt is there again).
I read about auditing programs like snoopy and session recorder like script but I thought they're already too complex for the simple question I have. I guess that deactivating that script logs all the output of the command would lead already in the right direction but isn't there a quicker way to solve that probelm?