I have a jar, and I need to replace a class in it, at this moment, I can only open it with "archive manager" and then drag and drop the new compiled class into the jar, but I think this is really boring, if I can do with with just a command ?
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For example, I always go to this path:
/user/something/somefolders/somewhere
but I don't want to type
cd
/user/something/somefolders/somewhere
in the terminal all the time, can I have some short hand to do so? for example, can I do something like
cd commandPlace
to replace the path?
I want to know the Perl command to replace a string by pointing the line number. I know how to replace a string without pointing a line number but I am in need to replace only the two matching string in a file
View 6 Replies View RelatedI trying to change a file with hundreds of entries, replacing line with "IP Address Number" for "Host Name", one for another.
this is the original: [IP Address Configuration : "172_17_27_161.SUBNET_U"] IP Address Number = 172.17.27.161Assignment Type = 8Host Name = CAST124Last Used = 1290499294000MAC Address = 1 00 16 35 74 4C 59Client Identifier = 01 00 16 35 74 4C 59and the result desired is: [IP Address Configuration : "172_17_27_161.SUBNET_U"]Host Name = CAST124Assignment Type = 8IP Address Number = 172.17.27.161Last Used = 1290499294000MAC Address = 1 00 16 35 74 4C 59Client Identifier = 01 00 16 35 74 4C 59I know how to change one character by another with sed, but not to change a line for another, because I don't know in which line number it is.
I have large text files with space delimited strings (2-5). The strings can contain "'" or "-". I'd like to replace say the second space with a pipe. What's the best way to go?
Using sed I was thinking of this:
sed -r 's/(^[a-z'-]+ [a-z'-]+) /1|/' filename.txt
I can't get sed to actually change the file, clearly there's something basic not working, can anyone point me in the right direction? I know nothing about scripting. Oh yeah, all the directories have spaces which was why so elaborated.
find . -name "*epub" | while read file; do unzip -o "$file" content.opf && mv content.opf content.opf.bak && sed 's/<dc:language>UND</dc:language>/<dc:language xsi:type="dcterms:RFC4646">EN</dc:language>/' < content.opf.bak > content.opf && zip "$file" content.opf && rm -f content.* ; done
how to use a variable in a sed command, but I can't get the output into a variable.
FILE=readme.txt
now i want to remove the extension of filename
so file woud be:
FILE=readme
my script:
NFILE=`echo $FILE | sed 's/.txt//'`
mv ../out/$FILE ../out/$NFILE
FILE=$NFILE
now when i run my script. i get this unknown character extensions in my new file(NFILE).
I'd like show a certain line or lines of a file with context, kind of like a unified diff, on the command line in Linux:
$ (something) -l 154 stuff.py
150: def foo(bar):
151: """
[code]....
I have an SQL dump, file.sql that has many references to a particular domain, d1.com. I would like to run a command that can replace every occurrence of d1.com with d2.com. I've tried looking into sed before but the man pages are quite daunting.
View 14 Replies View RelatedHere's the actual line of code, which exists in a bash script:
Code:
I want to replace instances like this:
Code:
with this:
Code:
Using this:
Code:
Which works great when there's only ONE of the pattern on the line. But in a case like the "actual line" I posted first, where there are two patterns, separated by a slash, only ONE gets replaced
Watch:
Code:
Why? There must be (among many other things) something I'm not knowing about sed, that's causing this.
-- I'm currently using the ~ (tilde) as the separator in the sed command. It doesn't matter, I've used / ~ and % with no difference.
-- As a test, I tried putting a different character(s) in the middle of the original pattern instead of the / but that made no difference.
-- I've come up with various similar but slightly different regexs that will do this replacement, but they all have had this same result.
-- I tried the sed single-quoted, double-quoted, and unquoted; the latter fails to execute, and the formers both work as described here: wrong.
I'm pretty sure this is doable from the command line, but my CLI skills have degraded a lot since my pre-Y2K admin days. The goal is to search all the files in the directory for a very long string of text and replace it with another string of text. The text being searched for is my Google Adsense code (which will be stripped from my website) and it will be replaced with a placeholder so I can easily tack something else in there in the future.
Seeing how I have that long snip of code on about 100 pages, automating the process would make life easier.
If I was searching for a single word, I can see ways to do this.
If I paste the code I'm searching for into a text file, is there a way to:
find (contents of oldstring.txt) and replace with (contents of newstring.txt)?
I have the file abc.txt
cat abc.txt This is a test file Nothing is new in this world
I want to replace "This is a test file" to "Text is replaced"
Code:
FindString='This is a test file'
ReplaceString='Text is replaced'
Findarray=(`echo $FindString | tr ' ' ' '`)
[Code]....
But this is not effective. how to replace entire line either using sed or awk or any other utility.
I need to be able to convert HTML email messages saved as text files (.eml or .msg) to PDF documents, one PDF per email, retaining formatting and images.
Are there any Linux tools that will allow me to do this from the command line (so it can be scripted)?
I want to replace a certain line of a file, my bash script looks like:
#!/bin/sh
sentence="if [ -e /home/inf/Download/$playlist ]"
sed '4c
$sentence' oldfile > newfile
mv -f newfile oldfile
But the variable $sentence can not be identified in ' ' . And also you can see I just want to update the old file. But the sed command can not save the file for me ,so I need to write them to a new file and over write the new file .
I am beginner in this business of shell script and I have no idea how to do the following: I would like to replace the lines of my file that contains 'CFL=' by 'CFL=0.5'. Note that I want to replace the full line meaning
View 11 Replies View RelatedLet's say i have a link to a file http://www.domain.com/dir/myfile.ext
Is there a command line tool that will allow me to download this file. I'm looking for something like: download <http address> ... is there anything that simple?
I would like to insert a line into the /etc/sysconfig/iptables with a command like sed or with any script. How can I insert this line:
-A INPUT -m state --state NEW -m tcp -p tcp --dport 80 -j ACCEPT
but under the line "-A INPUT -p tcp -m state --state NEW -m tcp --dport 22 -j ACCEPT"
I want to download a file from the Linux command line. Basically I'm using ssh and I'm trying to download a file to my file system on my laptop. How can I do that from the command line?
View 3 Replies View RelatedHow can I create multipart rar file in Linux using the official console rar client?RAR 3.90 Copyright (c) 1993-2009 Alexander Roshal 16 Aug 2009Shareware version Type RAR -? for helpI want a multipart rar with each part size being 150 MB.
View 1 Replies View RelatedHow to split a tar file into smaller parts at file boundaries?
How can I create a multipart tar file in Linux?
What's a Unix/Linux one-liner that will let me delete all but the most recent N revisions of each file?
I've got a bunch of files with revision numbers as part of a legacy asset-management system:
bar.r7.js
bar.r8.js
bar.r9.js
bar.r10.js
bar.r11.js
[Code]....
I want to keep the last three of each, so in the above list the command would delete bar.r7.js, bar.r8.js and foo.r1.js.
I've got files in a directory as follows:
1.png
1_thumb.png
1-1.png
1-1_thumb.png
[code]....
I want to list all the files that don't have a copy with the same filename with -1 somewhere in it. So, in the example above, the results would be 3.png.
NB: the file and its copy with "-1" in it will be the same filesize, if that helps.
find and use the file-manipulation tools for the command line.
View 2 Replies View RelatedWhat is file-manipulation tool used for on the Linux command line?
View 7 Replies View RelatedI've got a Debian Squeeze computer on which the graphics have packed up, but the terminal in single user mode work perfectly fine.
There are a few files on this Debian computer that I want to transfer off, to a networked computer, but I have no idea how to do this.
The destination computer is a freshly re-setup Mandriva install, without (as yet) samba. I don't think it's necessary though. The Mandriva install works fine, has graphics, etc, but can't see the Debian Squeeze computer on the network, possibly because it's in single user mode, thus prompting the problem of how to transfer the files, using only a command line.
I want to insert the text "DB dept" in the last line of passwd file which looks like this right now
Quote:
newuser:x:717:717::/home/sacharje:/bin/bash
And I want it to be like this:
Quote:
newuser:x:717:717: DB dept:/home/sacharje:/bin/bash
I tried to do that with sed but failed, I'd like to know the proper syntex with sed to achieve this.
How do I find the file-manipulation tools on the command line?
View 5 Replies View RelatedI need to be able to edit a file from the commend line as I intend to script this operation, the file is called menu.lst The original is as below
Code:
titleUbuntu 8.04.3 LTS, kernel 2.6.24-24-generic
root(hd0,0)
kernel/boot/vmlinuz-2.6.24-24-generic root=UUID=b09feb23-5524-4ec4-862f-94700b968f64 ro quiet splash
[code]....
I want to tail the latest log file in one command line. I dont know what command/option to use for the same.
View 5 Replies View RelatedIn Linux, I'd like to know how to find the file(s) if any which as using a particular sector on the hard drive (ext2/3). There is a similar question here regarding Windows, however I need a Linux command line solution (this is a headless system).
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