General :: Sed Append Word At End Of Line If Word Is Missing
Feb 19, 2010
I have to modify formsweb.cfg file in Oracle IAS.
In formsweb.cfg file are two lines with labels archive_jini= and archive= at the beginning of line. After equal sign (=) is row of filenames of java archives delimited by coma(,). When I insert a new jar file in java directory, I have to append the very same name of jar file to both lines if that name is not yet present.
Want to search for ~ and delete it as well as to append the entire line to the above line. For Ex:
1111xxxx date Sandy area is ~around this area.3222xxx date There seems to ~left side of map, the colours are accurate (showing green areas)Even if I ~zoom in, the green parks, xxx3258 date The dammed up ~away, the "other" body of water varies ~blackNatural gas leaching.
IT MUST LOOK LIKE:
1111xxxx date Sandy area is around this area. 3222xxx date There seems to left side of map, the colours are accurate (showing green areas)Even if I zoom in, the green parks, xxx3258 date The dammed up away, the "other" body of water varies blackNatural gas leaching.
I am pretty new to bash scripting...I am trying to write a script that will take an input and read it word for word and then DO something with it like echo. I have been able to find how to read word for word from a file but I don't know how to do it with input.
I was looking for something like
exit 0 The input would be A-Z a-z 0-9 and have a single space between each word.
sed -i ''$line_number',/port/s/port/portMARKED/' file
to substitute the word "port" by the word "portMARKED" at the specific line that is saved in "line_number". The substitution happens, but it is copying my line twice... and I have no idea why... I need to make a single substitution of one word for another at a certain line in my text file. Would somebody know how I could do that?
I have a file which a number at the end of each line. I need to change this number in the file to be correct, i.e. each time the number is 9 it needs to be 1, each time it is 233 it needs to be 2, etc... There is no pattern to the numbers currently in the list other than the same number appears only in a single line/group of lines, not throughout the file, but the replacements need to be sequential (but can be repeated an arbitrary number of times).
In linux is there a way to find the next word of a particular word of a file. grep displays entire line of the particular word. But i want only the exact next word of that particular word.is there any command for that.
I'm building a script for my place of employment. The next step in it is checking what the user input was. Determining if they added a part in there or not. The script prompts for a hostname. Hostnames are localhost.localdomain. Now, I want the script to check to see if they put localdomain and if they did, not to add the domain to the /etc/sysconfig/network, but just what they entered. So say the user inputs:
Using the latest version of Ubuntu desktop on an emachine t5062 if it matters. I have a text file of keywords that is one-three words line after line for like 5000 lines. How would I go about adding a word to each line.Aside from typing it in or copying and pasting.If it can`t be done with Gedit I am all for using another program.
I have grepped a log file to obtain every line that contains a word (let's call it 'blah'). I now want to only display a list of entries within that search result that feature the word 'host' anywhere in the line, and I also want to display the single word *after* 'host' (up until the next space). So, the end result will look like this:
How can I make the less utility in Linux not wrap lines?
Long version: Often I need to view huge CSV files using less with hundreds of columns. I frequently only care about the first couple columns. However, word wrap causes one line to become several lines even on wide-screen monitors.
I need a bash script that can read a file, say example.txt search for the string "This is my example string" and save whatever word/number comes immediately after it to a variable, var.
Example: blah blah blah This is my example string extracthere is a very nice word. blah blah
There are two constraints:1. This needs to assume as little as possible about the nature of the known string "This is my example string" and the word that follows it. I am trying to keep my code adaptable.2. Speed is valuable. This shell will be executed dozens if not hundreds of times so speed is very desirable. I thought I read that some commands are faster than others.
In a wide family of "ancient" text editors, by pressing ^T you erased from the cursor up to the beginning of the following word. If we use '_' to represent the cursor, the thing was like this:
Code: want to feel _ at home with vim. If I now hold <CNTL> down and press <T>, the result will be Code: want to feel at home with vim. Many times I have consulted and even tried to systematically study vim's man page. Sometimes I consulted it with profit, sometimes not. This is one of the latter.
I have a large file in which each line has three or more blank-delimited words. I'd like to code a grep to keep only those lines which have the letter M in the last word. the M (if present) will be the first character in the last word.