I am trying to replace the first number in a string at the end of the line with the word that matches that number. for example i want to replace 546215 to be five-46215. The command that I have tried is
sed -r 's/5[0-9]{5}$/five-[0-9]{5}/'
Say I have a file as
[code]....
It would be great, if i could issue a command (Vi/Bash/awk, ...) in order to obtain
[Code]...
So, the "replace string" should be replaced by another string containing the counter of replacement.
Can the Replace function replace more than one word with the same character(s)?
Also, do you know how to access the plugins provided by the gedit-plugins package?
I want to replace a string of directory path in a string to empty:
Code:
But this doesnt seem to give me the desired thing:
Code:
This gives the desired outcome, but its specific, i need a variable in the sed not a string. And if I replace STRING="/mnt/sda1/record/$dd/" then I cant use it for something else, cause its has all the weird backslashes now.
I need a bash script that can read a file, say example.txt search for the string "This is my example string" and save whatever word/number comes immediately after it to a variable, var.
Example:
blah blah
blah This is my example string extracthere is a very nice word.
blah blah
There are two constraints:1. This needs to assume as little as possible about the nature of the known string "This is my example string" and the word that follows it. I am trying to keep my code adaptable.2. Speed is valuable. This shell will be executed dozens if not hundreds of times so speed is very desirable. I thought I read that some commands are faster than others.
i use this script to get the time and date of back and fourth transactions for a particular execution id. I use a substr command on the 5th column to to cut the milli seconds off the time value. - otherwise the times would look like 08:30:04.235
grep <executionID> <auditfile> | awk '{ print $1, $2, $3, $4, substr($5,1,8}
FIX -> Mon 3/1/2010 08:30:04
FIX <- Mon 3/1/2010 08:32:36
FIX <- Mon 3/1/2010 08:35:08
[code].....
anyhow - i append two sed commands to further clarify the direction of the message.
awk '{ print $1, $2, $3, $4, substr($5,1,8} | sed -e 's/->/ ->IN/g' | sed -e 's/<-/<-OUT/g'
FIX -> IN Mon 3/1/2010 08:30:04
FIX <- OUT Mon 3/1/2010 08:32:36
[code]....
I tried using an awk gsub () command within the string instead of the two seds, but it did not work:
awk '{ print gsub(/<regex>/, <replace with>,$1), $2, $3, $4, substr($5,1,8}
the sed works ok, but it would be cooler to make the replacement within the awk command:
gsub(/->/,-> IN, $1)
Is there a way where i could replace the value of the $1 column in the awk print string?
Moving right along, I have a folder of MP3 files containing various Movie sound tracks and scores. I'm using Audio Tag Tool to tag all the files at once with an "Artist" of "Soundtrack", and to inherit the "Title" tag from the file name. After that, I will rename all the files (Using Audio Tag Tool -- awesome program, btw) with the format "<Artist> - <Title>.mp3"
The problem, is many of my files already contain the string "Soundtrack", which would be redundant. I happen to be a perfectionist, so I'm unable to ignore it and move on. Hence my question to you fine folk: I want to delete all instances of "soundtrack" (-i case irrelevant) in the filenames before I go through the above steps. But, its not quite that simple. This is a sample of some of the file names:
[Code]....
Almost by mistake, I figured out you could do something like:
$ cp foo.data bar1.data
$ ^bar1^bar2
And that runs the same command with bar2.data instead of bar1.data. Now, how about if I have multiple occurrences of the target word? For example:
$ cp foo.data bar.data
$ ^data^index
It only replaces the first data extension. How do I get it to replace both?
I have a line in a text file that has 40 random characters within a tag and i want to change the characters to a new set of 40 random characters (alphanumeric a-z 0-9 etc)
The line in the text file looks like this:
Quote:
How would i go about doing that?
Also second question same as the above but how would i remove them instead of replacing them?
I need to change all number 10 in a text file to word form, or in short from 10->ten. the thing is number 10 including in dates such as 10/22/1997 or 03-10-2011 should not be changed. im having some trouble because the file contains numbers like "price range from 10-50k".
this is just a sample.
name: john smith
birthday: 10-11-1995
date hired: 05/10/2010
expected salary: 10-50k
typing speed: 10 wpm
[Code].....
Using sed command is it possible to change like this..
If I have a word in a text file and I need to replace it by another word (for example, i need to replace abc by fff) so what is the command I can type it?
I am using vi editor.
I have a set of lines as ahown below:
Leon went to school
Leon came back from school..
Leon had dinner...
I have to replace the line containing "dinner" by a single string LUNCH...
I'd like a sed command to replace all decimal values greater than 0.5 with nothing in a tab delimited text file.
EX:
There would be one tab before 0.301 and two tabs after it. This way when you paste the text into an excel spreadsheet, there are empty cells where you deleted values.
I thought the sed command would be something like:
But this will delete everything.
What I need is something that will start deleting when it sees 0.[5-9] and stop when it reaches a tab. I know you can use [^character]+ to do this, but it doesn't seem to work with a TAB as the character.
Another idea I had would be to have sed replace from 0.[5-9] to 0. and replace with a tab + 0. But I also cant get [^0.]+ to work as it only works with single characters.
I have a file in the form below, and wish to replace each start line with an increasing number. So instead of:
Code:
start
content content
start
content content
start
[Code]....
After several searches and a bit of messing around, it's clear I'm missing something, so was wondering if anyone could offer any insight?
I need to find this "TYPE=MyISAM;" and replace with "ENGINE=MyISAM;" in all .sql files in a directory. How can I do this with sed?
View 2 Replies View RelatedI am having difficulty getting sed to replace a string of text in an XML file, despite the fact that I have no trouble using grep to find that same string. Since the new string and old string to be replaced contain a lot of special characters, I thought it best to store them in variables as opposed to using a slew of backslashes:
OLD_STRING='<property name="webServiceHost">${jboss.bind.address}</property>'
NEW_STRING='<!--<property name="webServiceHost">${jboss.bind.address}</property>-->'
[Code]....
After hours (literally) of searching the web and reading man pages, I think I've come up with the following:Code:find . -exec grep 'path/to/file' -print | xargs -0 -I new_path mv {this is where I get confused}So my code above is incomplete, obviously. In order to finish replacing the string, I need to mv the new file into the old file's spot. How do I do this, by incorporating it into my line of code?
View 14 Replies View RelatedNeed to replace the following string :
By
In multiple .exp files and in sub directories.
How do I find a string in files in a directory. And these file names begin with letter a. I also want to get the number of occurrences of this string from the grep I run.
I tried this:
cat * | grep -c string but it searches all files. I just want to search files that begin with letter a
I want to convert strings like 002, 049, 050, 100 to numbers: 2, 49, 50, 100.
I tried to use:
Code:
`printf "%5d" $i`
, but it doesnt work , it convert:
002=>2
014=>12
049=>0
I have large text files with space delimited strings (2-5). The strings can contain "'" or "-". I'd like to replace say the second space with a pipe. What's the best way to go?
Using sed I was thinking of this:
sed -r 's/(^[a-z'-]+ [a-z'-]+) /1|/' filename.txt
I want to know the Perl command to replace a string by pointing the line number. I know how to replace a string without pointing a line number but I am in need to replace only the two matching string in a file
View 6 Replies View RelatedI need to replace a string in a file(startup.sh) using a script(parser.sh). After running parser.sh startup.sh should be filled with nfs path like /home/vimal etc but im getting error since path contains /. how to remove this.
View 3 Replies View RelatedBelow is extract of my file:
What I need is to replace "--destination-path=" with "--destination-path=/home/dest"
i.e. desired output is ----destination-path=/home/dest
I could achieve it with below command
$cat outgoing-xfer|grep destination-path|perl -pi -e "s/destination-path=/destination-path=/home/dest/g"
But the problem is that in this case i just wanted to append "/home/dest" for which I could easily escape "/" with just two "", but I wonder if i have a long path like "/a/b/c/d/e/f/g/h/i/j" I will have to escape so many /. Is there any other way by which I can avoid escaping forward slash.
I tried following:
But receiving follo error
Bareword found where operator expected at -e line 1, near "s/destination-path=/'destination-path=/home"
syntax error at -e line 1, near "s/destination-path=/'destination-path=/home"
Bad name after dest' at -e line 1. tried with enclosing in double quotes as well but in vain
I'm trying to use sed to search for a certain 'primary' pattern that may exist on several lines, with each primary pattern followed by an --unknown-- number of 'secondary' patterns.The lines containing the pattern start with: test(header_name)On that same line is an arbitrary number of strings that come after it.I want to move those strings over to their own lines so that they each are preceded by their own test(header_name).e.g. Original file (mytest.txt):
apples
test("Type1", "hat", "cat", "dog", "house");
bananas
[code]....
I have a large number of log files, on a linux box, I need to cleanse sensitive data from before sending to a third party. I have used the below script on previous occasions to perform this task, and it has worked brilliantly (script was built with some help from here :-)
#!/bin/bash
help_text () {
cat <<EOF
Usage: $0 [log_directory] [client_name(s)]
EOF
[Code]...
However, now one of our departments has sent me a CLIENT_FILE.txt with 425000+ variables! I think I may have hit some internal limit. I have tried splitting the client file into 4 with around 100000 variables in each, this still doesn't work. I'm loathe to keep splitting though as I have 20 directories with up to 190 files in each directory to run through. The more client files I make, the more passes I have to do.
on creating a new perl script which replace IP address from the text file. eg. If in a file, we found any word like 11.222.333.44 then it has to be replaced to XX.XXX.333.44
View 8 Replies View RelatedI need to search a text file for a string of numbers which are different lengths, and always are between number=" and " like:
number="1234567890"
number="22390"
I need to grab those numbers and pipe each one to a line in a file. I've already tried something with awk and that didn't seem to work.
I want to write a small script to rename a bunch of files. Their name is of the form 'long number'|'name'|'extension', for example:
52354Football_part2.flv
2353452Nice_weather_4_ducks.flv
I would like to rename these to:
Football_part2.flv
Nice_weather_4_ducks.flv
If in my script I use something like
Code:
sed s/[0-9]//g
on each file, I will get
Football_part.flv, instead of Football_part2.flv,
and
Nice_weather__ducks.flv, instead of Nice_weather_4_ducks.flv.
how to instruct sed to only remove numbers that are in the beginning of the name in a simple way?
After running the following command, I get:
[root@yukiko /]# find / -iname .bashrc
/home/clamav/.bashrc
/home/vpopmail/.bashrc
/etc/skel/.bashrc
/root/.bashrc
But I would like to have a command that prints a specific line by supplying the command with the line number, for example:
[root@yukiko /]# find / -iname .bashrc | getline(2)
/home/vpopmail/.bashrc
Is there such a command on CentOS?
