how to use a variable in a sed command, but I can't get the output into a variable.
FILE=readme.txt
now i want to remove the extension of filename
so file woud be:
FILE=readme
my script:
NFILE=`echo $FILE | sed 's/.txt//'`
mv ../out/$FILE ../out/$NFILE
FILE=$NFILE
now when i run my script. i get this unknown character extensions in my new file(NFILE).
I am trying to rename a lot of files but need to keep the extension :
the files are films names :
a.b.c.d.***.iso
the result should be replacing "." by spaces " "
this command :
for files in *.iso ; do mv "$files" `echo "$files" | tr '.' ' '`; done
put a space also before the extension iso ??
How can I rename files from
"a.b.c.d.iso" to "a b c d.iso"
I have a jar, and I need to replace a class in it, at this moment, I can only open it with "archive manager" and then drag and drop the new compiled class into the jar, but I think this is really boring, if I can do with with just a command ?
View 1 Replies View RelatedI have an SQL dump, file.sql that has many references to a particular domain, d1.com. I would like to run a command that can replace every occurrence of d1.com with d2.com. I've tried looking into sed before but the man pages are quite daunting.
View 14 Replies View RelatedI'm having problems with Tomboy. I have a few hundred note files and I need to go through all of them and replace all instances of "<link:broken>a</link:broken>" with "a". Is there a bash command I can use to do this?
View 2 Replies View Relatedhow to run a command on all files with the same extension in a directory like this:
Code:
tex breqn.dtx; tex empheq.dtx; tex flexisym.dtx; tex mathstyle.dtx; tex mathtools.dtx; tex mhsetup.dtx; tex xfrac.dtx;
but in a simpler manner? I found this: Code: find . -type f -name *.dtx -exec tex {} ; but isn't there something simpler?
I wanted to find and replace a string from a perl file. I have written a script in bash which runs the following command.
perl -pi -e "s/$findstring/$replacestring/" testfile
where as $findstring = print F_WC_TMP"$line
";
and $replaceString = $line = join ' ', split ' ', $line; print F_WC_TMP"$line
";
But when I am running the above command, i think it is replacing the $findstring with the above mentioned string and hence it contains a $line, it is looking for the variable $line and not finding the exact string. I am confused about how to search for a string that contains $ in it and replace it with another $string.
I have a considerable number of files in a subdirectory (some fascinating old military clips from archive.org - search on Big Picture if interested). Anyhow, I am downloading them using Internet Download Manager running in an XP virtual machine in VMWare on my Ubuntu 10.04 PC (due to the queuing, restart and speed capabilities of IDM). But I digress - the files are being saved on the host (Samba share) without a file extension. So I have a collection of files with names like
Quote:
The Douglas MacArthur Story
THEY WERE THERE (1960)
I wish to add the extension ".mp4" In Windows this is simply done with the command
Quote:
rename *. *.mp4
This of course does not work in Linux. I have researched the Linux rename command and reviewed a lot of examples. However, I have not found a way to add an extension to a batch of files which are named with no extension to start with. The spaces in the file names also seem to present an issue. At the moment I am renaming them from the Windows VM while they are sitting on the Samba share using the ancient File Manager program from Windows NT which works great on XP. I have experimented with the file rename facility in Gnome Commander however, it does not seem to want to do something so simple.
I am trying to access a .dd file extension. Do I have to mount it?
VMware-VMvisor-big-3.5.0_Update_2-110271.i386.dd
# fdisk -ul VMware-VMvisor-big-3.5.0_Update_2-110271.i386.dd
Blocks Id System
VMware-VMvisor-big-3.5.0_Update_2-110271.i386.dd1 8192 1535999 763904 5 Extended
VMware-VMvisor-big-3.5.0_Update_2-110271.i386.dd4 * 32 8191 4080 4 FAT16 <32M
VMware-VMvisor-big-3.5.0_Update_2-110271.i386.dd5 8224 106495 49136 6 FAT16
[Code].....
I am trying to grab some files off this file to create a PXE vmware boot.
#!/bin/csh -f
source /xxxx/
set $spicedir = `sim_${1%.*}`
printf "Output folder is %s
" $spicedir
toolcommand -i $1 -o $spicedir
(-o output directory, -i =input)
I got spicedir: Undefined variable in my xterm
How could I match a file name without extension in csh
How will I open a file with extension .pmd in linux ?
View 7 Replies View RelatedIs there any command in Linux which will find a particular word in all the files in a given directory and the folders below and replace it with a new word?
View 4 Replies View RelatedTrying to get the basename of a file without the extension, I found this snippet but it just returns command not found twice:
[Code]....
Also tried (with and without the quotes on input and file_ext):
input=$1
file_ext=.${input##*.}
base=`basename "$input" $file_ext`
executed: convert.sh /path/music.wav But it echoes base as music.wav
I am playing with my LAMP server1. why can i access a php file on the server only by typing http://serverip/file with no .php extension on?2. later i tryed to play with .htaccess, but when i uploaded it to the server it just disappeared, why is that
View 4 Replies View RelatedFor example, I always go to this path:
/user/something/somefolders/somewhere
but I don't want to type
cd
/user/something/somefolders/somewhere
in the terminal all the time, can I have some short hand to do so? for example, can I do something like
cd commandPlace
to replace the path?
Almost by mistake, I figured out you could do something like:
$ cp foo.data bar1.data
$ ^bar1^bar2
And that runs the same command with bar2.data instead of bar1.data. Now, how about if I have multiple occurrences of the target word? For example:
$ cp foo.data bar.data
$ ^data^index
It only replaces the first data extension. How do I get it to replace both?
I have been trying to compile a pascal file using fpc. I succeeded using the command fpc pas1.pas, but this gave me a new object file pas1.o. How do i compile this file to get my output. gcc -o pas1.o does not work.
View 2 Replies View RelatedI want to know the Perl command to replace a string by pointing the line number. I know how to replace a string without pointing a line number but I am in need to replace only the two matching string in a file
View 6 Replies View RelatedI know this is possible in GUI gnome. But is it possible to do it too in shell command? Let say if i type this in shell:
#file.txt
then it will open gnome-editor in nautilus which open file.txt. gnome is the desktop manager. nautilus is the explorer windows in gnome. gnome-editor is one like notepad in MS windows.
How do you rename:
abc123.txt
abc124.txt
abc125.txt
to
abc.txt.123
abc.txt.124
abc.txt.125
Basically, I want to move the digits from the filename to after the extension.
It works for one file if I type:
rename 123.txt .txt.123 abc.txt.123
but I have thousands of files like these.
Many years ago, I converted a portion of my files to an arbitrary format with a specific extension. i no longer desire to have them in this format and i would like begin the process of replacing them because conversion is not an appropriate solution. unfortunately, they are mixed in separate folders of the same root folder with files in my current format of a different extension. I feel it would make this process easier if I were to move every folder that contained a file with the undesired format to a separate root folder. The files are stored on a Linux server and shared via samba. How can I do this with a couple of commands or a script? I am open to other suggestions as well. I want to avoid time spent editing text files. Ultimately, I'd like a command that produced a list of full paths for folders, sorted by the number of levels would be a nice touch. A list of all of the files is clearly not what I'm looking for.
View 2 Replies View Relatedhave a gzip file ABC_000023232.gzipBCD_023232032.gzipI want to split these files into smaller files but keep the extension same because I am using this as a variable in a script
Code:
for i in `ls *.gzip`
split -b 500K $i $i
[code]...
I trying to change a file with hundreds of entries, replacing line with "IP Address Number" for "Host Name", one for another.
this is the original: [IP Address Configuration : "172_17_27_161.SUBNET_U"] IP Address Number = 172.17.27.161Assignment Type = 8Host Name = CAST124Last Used = 1290499294000MAC Address = 1 00 16 35 74 4C 59Client Identifier = 01 00 16 35 74 4C 59and the result desired is: [IP Address Configuration : "172_17_27_161.SUBNET_U"]Host Name = CAST124Assignment Type = 8IP Address Number = 172.17.27.161Last Used = 1290499294000MAC Address = 1 00 16 35 74 4C 59Client Identifier = 01 00 16 35 74 4C 59I know how to change one character by another with sed, but not to change a line for another, because I don't know in which line number it is.
I want to replace a pattern in a file.The file format is given below.
111111
path=/home/fun/
222222
path=/home/fun/
[Code]....
I want to replace "path=/home/fun" with another pattern, but only under "111111", all the others should be the same.
I have txt file with list of ID's and I need to insert comma in every line and then remove new line character so it'll become one long string. So to clarify, I have txt file content that looks like this.
234
5466
2356
... and so on.
but I would like this to change to 234,5466,2356,... I looked at sed and tried to wrap my head around the commands but I guess my brain isn't smart enough. its really confusing for me. I've managed to add commas to end of line (sed "s/$/,/g" filename) but somehow I can't seem to remove new line character from each line.
sed 's/[
]*$//' doesn't seem to work.
I have the following values in my log file:
...
2010-05-13 11:00:00 k_TRANSFER OK (11)
2010-05-13 11:30:01 m_TRANSFER OK (21)
2010-05-13 12:00:00 k_TRANSFER OK (12)
2010-05-13 12:30:00 m_TRANSFER OK (32)
2010-05-13 13:00:00 m_TRANSFER OK (13)
...
I want to replace every number with it's decrement. For example, the above values should be:
...
2010-05-13 11:00:00 k_TRANSFER OK (10)
2010-05-13 11:30:01 m_TRANSFER OK (20)
2010-05-13 12:00:00 k_TRANSFER OK (11)
2010-05-13 12:30:00 m_TRANSFER OK (31)
2010-05-13 13:00:00 m_TRANSFER OK (12)
i got the slackware folder with my builds of my favorites packages, in /tmp i create the new versions of that packages. theres is a way in bash to replace the new ones in /tmp with the old ones in /home/user/slackware??
something like..... in /tmp: mv -i package1.tgz /home/user/slackware | and somethin to replace the old version of the app with the new one
I am having difficulty getting sed to replace a string of text in an XML file, despite the fact that I have no trouble using grep to find that same string. Since the new string and old string to be replaced contain a lot of special characters, I thought it best to store them in variables as opposed to using a slew of backslashes:
OLD_STRING='<property name="webServiceHost">${jboss.bind.address}</property>'
NEW_STRING='<!--<property name="webServiceHost">${jboss.bind.address}</property>-->'
[Code]....
I have a large number of log files, on a linux box, I need to cleanse sensitive data from before sending to a third party. I have used the below script on previous occasions to perform this task, and it has worked brilliantly (script was built with some help from here :-)
#!/bin/bash
help_text () {
cat <<EOF
Usage: $0 [log_directory] [client_name(s)]
EOF
[Code]...
However, now one of our departments has sent me a CLIENT_FILE.txt with 425000+ variables! I think I may have hit some internal limit. I have tried splitting the client file into 4 with around 100000 variables in each, this still doesn't work. I'm loathe to keep splitting though as I have 20 directories with up to 190 files in each directory to run through. The more client files I make, the more passes I have to do.
Need to replace the following string :
By
In multiple .exp files and in sub directories.
