I am trying to create scripts to move files over from one directory to an ftp server and there is this one file with spaces that bash is see each word as being a file, here is the variable i am trying to use:
Code: Select allLOCL = '/mnt/cifs/"File name with spaces"/'
cd $LOCL
ls -l
I have over 50 files names with spaces in them.
I'm trying to use a for loop as such:
However, when I print the $filename in the script, the script prints out parts of the filename because of the spaces in the file name.
For example, say the file name was Star Quest.php
When the script executes one $filename would be Star and another Quest.php.
How could I account for this? Something like $'filename'
Are there numerical variables (like type int in C) in the shell script language of bash? Say I want a counter to increment each time a loop is traversed.
View 1 Replies View RelatedHow do you add strings to the front and end of variables in bash scripting? for example, if I have
Code:
in as the contents of my variable, I want to add "l" to the front and "k" to the back of the contents.
Ok, so I find myself ripping audio CDs frequently, which I then lame to mp3's to put on my media player. I usually define the --ta and --tl (artist and album) ID3 tags and batch encode each album, but don't bother with the track tags as I'd have to do each one seperately.
So, I'm working on a script to do all this for me, extracting info from 'pwd' etc. to fill in the blanks for --ta, --tl and --tt (track name). All is working well, except that I can't get sed to pass on the "" character to lame to escape spaces.
Here's what I've got so far: (trouble spot is bolded - no need to pay attention to the rest of it)
Code:
All this does is pass a 'space' on to lame, which it takes as an invalid argument.
I'm writing something which takes user input (which may or may not contain spaces...) and then runs a command on a remote system via ssh. However the remote command does not work. I can't print the exact code so I'll just provide an equivelenat problem. This needs to work with filenames which do and do not contain spaces.
Code:
FILES=`ls`
echo "Specify a file"
echo "$FILES"
echo -n "File name: "
read $FILES
ssh root@127.0.0.1 "ls $FILES"
You are probably using systemd (check it with ps --pid 1) and therefore /etc/init.d isn't considered for autostart. Here can you find some information about systemd and autostart [1]. As far as I know systemd isn't intended to start applications with systemd. I recommend you to use the autostart feature of your window manager or desktop environment or at least the .xinitrc.
[URL] ....
mkvmerge -o <filename without extension>_TV.mkv -S <filename> && mkvextract tracks <filename> 3:<filename without extension>.*** && perl /home/brian/Desktop/ass2srt.pl <filename without extension>.*** && rm <filename without extension>.***
Doing these commands for multiple command line file inputs is the goal. So I can just type ./script.sh *.mkv in my terminal.This is what I have so far, but it doesn't work whatsoever.
I am trying to modify a script for research purposes and am having difficulty here as I have little prior experience with C-shell scripting.
The script looks as follows (it includes tcl commands like runFEP that you can ignore)
#!/bin/bash
for ((old=1, new=2; old<=4; old++,new++))
a1=${old}%50
a2=${new}%50
do
cat > input${new}.conf <<EOF
${a1}
code....
My question: I keep getting a syntax error when defining my two variables a1 and a2. I essentially need these variables to be
a1 = value of variable old divided by 50
a2 = value of variable new divided by 50
I would like to get the filename (without extension) and the extension separately. The best solution I found so far is:
Let FILE="thefilenameofsomefilesfor_instance.txt"
Code:
NAME=`echo "$FILE" | cut -d'.' -f1`
EXTENSION=`echo "$FILE" | cut -d'.' -f2`
I think it would be better to count the len and remove 3 chars to right to get the extension, but it can be macintosh filenames with have 4 chars for extensions.
I have a config file that contains:
my.config:
Code:
Now in my bash script, I want to get the output /home/user instead of $HOME once read. So far, I have managed to get the $HOME variable but I can't get it to echo the variable. All I get is the output $HOME.
Here is my parse_cmd script:
Code:
I am reading the output of /proc/acpi/thermal_zone/ATF0/temperature in a program to read my CPU temp. I am using cat like the following:
Code:
#cat /proc/acpi/thermal_zone/ATF0/temperature
temperature: 49 C
I basically want to get rid of the spaces in between temperature and the actual temperature. Is there a command I can pipe the cat output to, to remove the spaces. I have seen suggestions for sed, or tr, but for some reason I cannot get them to work properly.
I have a laptop that I am in through SSH. The laptop does not have an Xwindow system so I am using the program fbi to open an image on my laptop screen from my SSH connection:
fbi -T 8 picture.jpg #this opens the image on the laptops tty8 terminal
I've found that making a for loop does not work with files that contain a space in the name. Something to due with a bug that they call a "feature" that stops the first variable at the first whitespace.
Using a "while" loop is not exactly what i require either seeing as I want to be able to view each image in the directory on screen and tag it accordingly, before it jumps off to the next image, and I'm not sure how to add a pause to a while loop.
How do I make a Bash script and loop Variables handle files like "files that contain spaces.jpg"
What I have done wrong with my escaping here:
Code:
The original filename is:
Code:
I have a BASH shell script with embedded SQL script. The SQL script fetches the data from oracle server and the data contains more than 8 spaces in the value (eg, 28051630 A) and the data is written to flat file using the below syntax:
$ORACLE_HOME/bin/sqlplus -s ${CONNECT_STRING} >${out_file} <<!!
.. sql query..
!!
The problem is that whenever the data is written to ${out_file} spaces are getting converted to TAB character
eg, 10 spaces (in Oracle) converted to 1 TAB and 2 spaces 7 spaces (in Oracle) converted to 1 TAB and 1 space Also, from above example you can see the width of TAB char is not constant (8 in first example and 6 in second example) Is there any way that I can stop shell script to convert spaces into TAB character as I want the data as it is from Oracle DB (i.e. only spaces not TABs)
*I'm using Ubuntu 10.10
My issue is I can't handle the files with spaces in their name, I've donde the below script to print each file found inside folder and subbfolders with "find".
I would like to "ls" to each file found with its complete path and with its basename too.
Code:
files=$(find . -type f)
for each in "$files"
do
ls -l "$each" # 1rst option I've tried to list with full path
ls -l "$(/bin/echo "$each")" # 2nd option I've tried to list with full path
ls -l "$(/bin/echo $(basename "$each"))" # 1nd option I've tried to list with it basename
[Code].....
How can I list "ls -l" in both cases (with full path and with basename) when there are files with spaces in their name?
I was wondering if anyone knows how to do this in Bash:
I have quite a few music files which have names like this:
All my music is named "ARTIST - SONGNAME.EXTENTION"
I have been looking for a program or bash script that would fix this automatically, but I can't find anything that will do this. a script laying around?
Tried pyRenamer, and it does a lot of things, except this...
I have a directory with files like this:
Code:
And what I'd like is to have the files renamed like this:
Code:
How could I code it so that it removes the numerical part of the filename (at the beginning), even with different patterns (like the 01 - artist vs the 01-artist)?
I named a number of files with spaces in them, and I want to replace the space with "_". However, every time I write a command in the shell with the file name (eg "Spring 2011"), the shell doesn't recognize the file or directory. What can I do about this? Is there any way to use the unicode character for a space?
View 5 Replies View Relatedhaving bit of a trouble with path expansion of strings that contain some whitespace and wildcards First my script sources a configuration file that contains array assignments
Code:
...
BACKUP_TARGET_FILES[2]=/boot/config-* # no problems
BACKUP_TARGET_FILES[3]="/root/random dir with space/file*" # this is the problem
...
then later in the script I want to expand BACKUP_TARGET_FILES elements as below
Code:
IFS_DEFAULT="$IFS"
shopt -s nullglob
shopt -s dotglob
IFS=
[code]....
this code seems to work but I'm not quite satisfied with it. I'd like to get rid those IFS changes, but haven't found out a solution as of yet. Problem with default IFS seems to be that with it neither $pattern or "$pattern" work; it either interprets pattern as multiple words (because of spaces) and so expands to wrong paths or it ignores * because it's within quotes.
Have worked with Linux at home for some time and have wrote the below script.
This script is run when a .torrent file finishes downloading and extracts any .rar files into an extracted directory.
However there are 2 thing that i cannot for the life of me get working.
These are:
1. I need the script to check a txt file to see if the file has been extracted previously.
2. The script does not work with any paths that contain spaces.
Code:
i have lots of files with dots insde file name for example:
document.1.is.bigger.doc
resume.version12.doc
10.photo.www.cnn.com.jpg
i want to rename all files in that directory to be the same (with same extention) but convert dots to underscore "_"
how can i do that on bash script / php.
I'm trying to get the substring of a string in bash. Here is the code:
Code:
#! /bin/bash
LOCAL_HOSTNAME=$(hostname)
echo $LOCAL_HOSTNAME
INDEX_OF=`expr index "$LOCAL_HOSTNAME" 1`
echo $INDEX_OF
SERVER_HOSTNAME=${LOCAL_HOSTNAME:0:INDEX_OF}
echo $SERVER_HOSTNAME
It's supposed to get the current hostname, assign it to variable LOCAL_HOSTNAME, get the first occurrence of "1" from hostname and assign value to INDEX_OF, the get the substring from variable LOCAL_HOSTNAME (starting at index 0 through INDEX_OF) and asign it to SERVER_HOSTNAME. No matter how much I've tried it keeps throwing Bad substitution error at the substring. I've searched and it says it has to be bash... but it is bash, both the sh script and the running shell. The LOCAL_HOSTNAME and INDEX_OF variables are ok.
Here is the output:
I've also tried to get the substring without the INDEX_OF but it gives the same error: SERVER_HOSTNAME=${LOCAL_HOSTNAME:0}
Code:
host1
5
test.sh: 7: Bad substitution
What is the purpose of bash scripting? Is it just for file manipulation?
View 4 Replies View RelatedI need to find a way to download the attachment from a daily report e-mail to me. The kicker is it will need to be down with a cron tabbed bash script.For example, which linux based CLI client is best suited to be scripted?
View 2 Replies View RelatedI have a question;
Is it possible to set incrontab in bash script? I tried to set normal crontab and it works like a charm but unfortunately not "incrontab"
I have two bash files; test-incrontab.sh and addlinetocrontab.sh and here are the contents of these files respectively;
Code:
Code:
As you can see there are two enteries in each file. One for normal crontab and other one for incrontab. When i run "test-incrontab.sh" like following;
Code:
crontab works perfectly and i can see cron job set but for incrontab it just does not work. No error either!
I am only getting this back "table unchanged"
I'm trying to put together a script that will quickly run through an archive directory of log files that are named by day of the month 01.gz, 02.gz, 03.gz.... 31.gz. The script uses gunzip -c | grep | wc to count up the total number of hourly occurrences of a filename and outputs the results to stdout.
The only snag I have left is the octal limit when it gets to 08 and 09. I've seen examples using perl and awk, but this script uses a number of nested for loops and if statements that I don't want to have to rewrite in a different syntax. I found that I can use num=10#08 to set that variable to a base 10 instead of a base 8, but then I lose the leading 0 again when it passes the number to the next filename variable.
Is there a difference when variables are referred to as $variableName and ${variableName} in bash?
View 1 Replies View RelatedWhat is the difference between For and While when creating loops in bash scripting?
View 1 Replies View RelatedI have a bash script that inserts some text onto every image at a certain place within a directory.
Heres what I have (from a German friend who appears online once in a blue moon), this is the line that resizes to a maximum of 800 either width or height and puts in the text 'text goes here'.
convert ${bild} -resize "800x800>" -strip -family Arial -pointsize 16 -draw "gravity southeast fill rgba(255,0,0, 1.0) text 10,10 'text goes here'" ${dstdir}/${bild}
Now, I would like to know how to place a PNG image (a watermark, so to speak) over all images within a directory in a certain place, so how would I go about modifying this line to place an image instead of the text?
