Programming :: Sed In A Bash Loop With Ascending Output?
Jan 1, 2011
I have a file like below:
PU12829,24869;PD15733,24869;PD15733,19785;PD12829,19785;PD12829,24869;
PU4599,20915;PD9924,20915;PD9924,18898;PD4599,18898;PD4599,20915;
PU12829,24869;PD15733,24869;PD15733,19785;PD12829,19785;PD12829,24869;
PU4599,20915;PD9924,20915;PD9924,18898;PD4599,18898;PD4599,20915;
PU1723,3423; #this line is ignored to short
[Code]...
What I'm trying to do is while true, cut each line from file that begins with PU and thats longer than 12 characters and write to a increasing numbered file for each line. Stating with object1 etc.
How would I list 4 users ID numbered 10, 11, 12 and 13 from my users list and output them to a file busers where their names are numbered by ascending order? How would I accomplish that on a one line command?
I need to rename the resulted searched files from a loopI have the following code:
find . -name DOC* | while read i do find $i -type f -name '*.txt' done
basically, I am searching for all txt files inside any folder starting with DOC name.this code is working fine with me.I need to rename those .txt files to .txtOLDOS: Ubuntu 10.4Bash shell
I work in a simulations environment. I'm trying to write a bash script that will read fields from a .csv file into an array, the first field being an identifiyng number and the second field being a corresponding url. There are about 1600 of these number/url combinations in the .csv file that i'm reading from. Once that is done i want it to parse a text file and match the number, when it has a match i want it to enter the corresponding url into a particular line in the text file. The script I have written (with the help of the people on this forum a while back) does this well, but now I have a lot more data to parse. I think the script itself is explanatory enough to see what i'm doing. What i would like to do is cut it down to one while loop nested inside another loop so that I don't have 1600 or so elif statements. I can't figure out how to increment the output of the array. for instance, the first cycle would find the number that matches ${record1[2]} and input the url stored in ${record1[3]}. the next cycle would match ${record1[4]} and input the url in ${record1[5]}, and so on, does that make sense? The code is below and a sample .csv and text file are attached.
I'm writing a mass snmp toner check which polls any toners available to be snmp polled, however when using a loop statement I get the results on different lines; which sounds good, however the tool I use to check with (nagios) ignores the new lines.
Is there any way I can get the output on one line? Also, I need to raise a fault if any of the toners are below a specific level (with nagios you raise faults with the exit code) - any way I can do this without exiting the loop. Code below with bits and bobs commented out.
The script that Iam trying to write is running a for loop and reading line by line from a text file. inside this for loop i would like to execute update SQL statement .
a pesudo code is Quote: `$ISQL -U $username -P $Password -D $Dbname -I $INTERFACE <<QRY for id in $idlist #idlist iam reading from a file
2. for I in 1 2 3 4 5 6 7 8 9 10; do echo $I; done|
3. for I in $(seq 1 10); do echo $I; done|
4. for ((I=1; I <= 10 ; I++)); do echo $I; done
I have a script which uses the 1st form of for loop. I'm trying to modify it to use a variable instead of a static hard-coded value in the section that controls the looping.of the for loop.
I've tried all different ways of quoting and escaping the variable, and the problem is that the quoting chars and escape char are being translated and passed into the loop along with the value stored in the variable.
For example, to change the start value of 1 to whatever value I want passed in through a variable:
Change:
I have tried: {{$a}..10} and {`$a`..10}, to have the variable evaluated first.
I have tried using the eval() function.
I have tried single and double quotes and the backslash escape character.
Nothing I've tried works. It's probably a syntax error.
So I need to write a bash script that can read lines and column 3 from a file. It needs to start on line 16 and read every 20th line starting from there. But the value that it reads needs to be checked, should it be too great I need it to shut the program down.I'm pretty new to bash, but my ultimate goal is being able to safely run a program on a GPU for an extended period of time with out worrying about it overheating. I have a command that outputs information from the GPU every second, and I can save this to a file. So all I really need is something to read and check that file, I played around a bit with the awk command and can't get it to work within my for loop with dynamic variable.
I need to know how to assign a result from a select. I am clueless on the sytax. I am trying this in bash. Maybe I am not assigning the array right. It gives me the whole row in the echo instead of just field a. How do I get fieldA = a in the select. Note script was stripped for security on database info but the syntax is same.
Code:
#!/bin/sh results="$(mysql --user ${DB_USER} -p${DB_PWD} ${DB_NAME} -Bse 'select a,b,c,d from tblMytable')" for rows in "${results[@]}" do fieldA=${rows[0]}; echo ${fieldA}; done
How do I get this loop to stop on each increment? This script does work but I would like it to stop at each increment, remember what the value of $n is, then continue until it gets to 7. I have worked so hard on this. My brain is hurting now.
I have a bash variable where the content looks like this where ;f1; and ;f2; are delimiters: ;f1;field1value1;f2;field2 value1 ;f1;field1value2;f2;field2 value2 ;f1;field1value3;f2;field2 value3
So what I need is to extract and put into variables each combination of f1 and f2 in a loop to something like that:
#first pass of the loop I need: f1=field1value1 f2=field2 value1
#second pass of the loop I need: f1=field1value2 f2=field2 value2
# third pass of the loop I need: f1=field1value3 f2=field2 value3
I have a script that generates a bunch of output, including the expansions details provided by: set -v -xI am trying to pipe everything that is displayed to a file, in addition to displaying it on the screen. I've managed to get stderr and stdout into the file, but the expansions are only printed to the screen. Here is what I have so far:sudo -u <user> source my_job.sh |tee my_log.txt 2>&1
So that when I grep on the local file again later, it can be printed out with original log lines. Otherwise, the log lines will be dropped and lines becomes concatenated into a single line, e.g., if I rewrite the script in this way, echoing the $result is not a good idea..
is there some workaround that I can save it to a variable rather than file but still keep the eol? That will simplify my script and don't need to do all those I/Os!
I have a bash script that calls a java class method. The method returns a string to the linux console when run independently. how can I assign the value from the java method to a variable in a bash script?running the script: java -cp /opt/my_dir/class.method [parameter]
I am trying to process a column separated data file, with a few bash command. For example, I have
Code:
file1 aaaa yes file2 aaaa no file3 bbbb yes
Let say I want to create new file with the output of first column and do something else with the output of 3rd column. Of course there are many ways to process this data file, but I wish to know by using awk, how could I do it. I'm trying:
Code:
awk '{system("touch $1")}' datafile
but the shell command will not able to get the awk '$1' output. How do I get this done ? And for another question, if the data file contains the variable name of a shell variable, how could I make use of it during a awk output ? For example I have a datafile1:
Code:
server1 yes server2 no
And in another server declaration data file, I got this datafile2:
Code:
server1=xxx1 server2=yyy1
And in my awk script, I want to achieve something like (the syntax is definitely wrong, just to demonstrate what I assume it will like):
I'm trying to read content of file to variable and use this variable in for loop. The problem is, when I have c++ comment style in file - /*. Spaces in line are also interpreted as separated lines.
For example:
Code:
Changing $files to "$files" eliminate these problems but causes that whole content of variable is treated as one string (one execution of loop).
I have got a script with an outer and inner loop. The inner loop issues loads of echo's which need to be redirected to a log file determined by the outer loop. The obvious solution is to redirect every echo to >$LOG and set LOG in the outer loop.
Code:
for f in $FILES ; do LOG=<logfile> for l in $LINES ; do
[code]....
it is possible to map stdout to $LOG in the outer loop without having to redirect every subsequent individual command output?
I am not sure if that Subject really explains it, basically I have a script that executes a CLI java-applet that requires a passphrase from the user. I can easily execute this by issuing the -p argument followed by the passphrase however that shows up on possible logs or at least on the results of the ' ps ' command. If you do not supply this -p argument it provides a new line with the echo " Enter Passphrase: " and asks for input.
how can I provide a result/input for the Passphrase request and is it still possible to throw this application in the background with the ' & ' following the command? I have seen a few examples that show a /bin/expect that expects a result and sends a command however I would like to refrain from any extra dependencies. Example of Regular Execution of application:
I have wrote a 1 line command that parses a file, locates the IP Address in the file and then trims the output the way I want it, and then sorts numerically and by uniqueness and then >> appends to output.txt
I can get all the IP's into 1 file "output.txt", but what I am really looking for is some type of way to create a text file, for each IP it finds labeled xxx.xxx.xxx.xxx.txt and also put that ip address into that file..
I am writing a bash script that utilizes the output of another script (which I will refer to as script#2.) Script#2 is not owned by me, I cannot modify it. All of the output from script#2 is blue, which makes it difficult for me to read.
I would like to have the output of it changed to grey. Is there a way I can do that in my script? A command I can pipe the output to?
Edit: One other question related to this. I put a trap function in my script that works well. Script#2 essentially runs a tail -f. When I ctrl+c to stop it, it stops script#2 and never calls the trap in my script. Is there any way I can work around that?
I have a problem with snmp answers being empty or having spaces.
What I already have:
#get all interface indexes (if you wonder - I'm working for a cable company and different cablemodems have different number and types of interfaces):
The problem is the physical address which is sometimes empty and the description which has spaces. So I'm doing 2 snmpgets which is slower than 1 snmpget (sometimes I have up to 18 interfaces).
I'm trying to explain it a bit simpler.
Interface 5 gives me back the following lines:
Ethernet CPE Interface
Now the first line should go into variable ifadm, 2nd line should go into variable ifoper, 3rd line should go into variable ifspeed, 4th line should go into variable iftype, 5th line (which is empty) should go into variable ifphys and finally 6th line (which has spaces) should go into variable ifdescr
I have a set of bash scripts that I'm running that automatically build a set of packages for me and redirect their output into logs. Basically, I have a bunch of lines that are something like this: ${CONFIGURE_DIR}/configure &> ${LOG_DIR}/log or cd ${CONFIGURE_DIR} && make &> ${LOG_DIR}/log, etc.
This is supposed to make the entire process silent. However, sometimes with some packages some output leaks to my console (either stdout or stderr). I'm thinking that maybe the configure scripts/make are executing commands within new shell instances that don't inherit my redirect, or something to that effect.
Another reason for thinking this is that in another part of my script I detect errors when running make by testing with "if [ $? -ne 0 ]", and if the redirect leaks to my console and also the leaked output indicates that the build failed ("make: Error" and so on), then my $? test fails (i.e., it thinks that $? == 0, whereas a failed make should return a non-zero value). It's as if my original script can't "see" the results from child commands executed from later scripts.
I am posting this just for the sake of curiosity. I am trying to feed a while loop structure with a command output, but using the bash built-in I get the error "ambiguous redirect":
Code: My First Line My Second Line ::::While Loop::: Program:
Code: while read line do echo "$line" done < Filename.txt output:
Code: My First Line My Second Line
Is it possible to use for loop to get the same output. I have tried executing below code but I get every word of my file being displayed one below above.Is there any way I can modify the for loop code to get the output returned by while loop?
:::For Loop::: Program:
Code: for line in $(cat Filename.txt) do echo $line done output:
