Programming :: Combine CGI Script With A Bash Script ?
Feb 9, 2010
I have a fallowing CGI script, which does nothing more than prints out the values user inserted:
Code:
If I insert Martin to the name box and 192.168.1.1 to the IP box I get fallowing output:
Quote:
Name is Martin
IP address is 192.168.1.1
As you can see, script above works fine(I host this script in Apache server and use Firefox as a web-client). Now I made a fallowing bash script:
Code:
Which is started like this: ./script.sh Martin 192.168.1.1. Output is user name plus port numbers and descriptions. This bash script works fine as well
How can I combine those two scripts? I would like to insert name and IP to according boxes in Firefox and after clicking Generate button, user name plus list of port numbers and descriptions will appear in Firefox window instead of terminal emulator window
How to link/combine those two scripts to work together as one?
In my code printf seems to have a problem with elements that have the same letters but a space inbetween. For instance "new foo", "newfoo" are the same for printf
Code: #!/bin/bash f1=apple f2=banana f3=grape echo "Enter number 1,2 or 3:" # 3 is entered read x choice=${f+$x} # yielding choice=$f3 echo "$choice" # so $choice is, essentially, read as f3, which = grape
grape I am, essentially, trying to combine "f" and the number entered (3, for example) to create "f3", which when echoed as "$choice" will lead to grape!
I am working on a script that allows me to convert an IP address to a country name. I have 2 files. One that has text like: PORT.80 TCP SRC=x.x.x.x and the other is x.x.x.x United States. How can I combine these files so that the file output is PORT.80 TCP SRC=x.x.x.x United States?
My backup script generates 2 lengthy log file. They have the same name, but the date is appended. I want to select the oldest one, condense it with "head" and "tail" and then append the condensed version of the newer one. They seem to get tangled up.Code:
ls `find . -iname "bak-log_*"` -1t | tail -1 and ls `find . -iname "bak-log_*"` -rt | tail -1
We have a program that catalogs to 40 different mount points. The program is fine as long as thier is free space on at least one of the 40 mount points. My boss wants me to come up with a script that will email us daily to know how much overall free space is left. I know I can do a df but I don't know how to combine the 40 mount points into a single disk used/disk free report.
The 40 mount points are /dev/mapper/areaxx, xx being 01 to 40.
I would like to know how do I print the line # in a script. My requirement is, I have a script which is about ~5000 lines long. If there are any errors happen I just exit. And I would like to add the line # of the script where the error happened.
Code: #!/bin/bash trap "echo 'you got me'" SIGINT SIGTERM # to trap ctrl+c echo "Press ctrl+c during 5 sec loop" for ((i=0;i<5;i++)); do
[Code]...
How come code behaves normally and stops when ctrl+c signal is caught and resumes, but after I use at least one timeout read in the code it looks like, if signal is caught again it doesn't pause the execution but skips the loop. If you remove -t (timeout) option from the read, both loops look the same!
Now in my bash script, I want to get the output /home/user instead of $HOME once read. So far, I have managed to get the $HOME variable but I can't get it to echo the variable. All I get is the output $HOME.
I have written quite a few separate bash & scripts and php scripts that up to now I have run from cron jobs. However I have to estimate how long each takes to run, before running the next and so it probably takes much longer than necessary to run them all. They have to run in order.
Now there are so many I am thinking it would be better to have a master bash script that would run one after the other, but I am not sure how to get the master script to wait before starting to run the next script. Is this possible and is there a command that will make the script wait between bash and php scripts , for them to finish, before running the next?
I think it would be better to count the len and remove 3 chars to right to get the extension, but it can be macintosh filenames with have 4 chars for extensions.
I need to rename the resulted searched files from a loopI have the following code:
find . -name DOC* | while read i do find $i -type f -name '*.txt' done
basically, I am searching for all txt files inside any folder starting with DOC name.this code is working fine with me.I need to rename those .txt files to .txtOLDOS: Ubuntu 10.4Bash shell
I am trying to write a bash script that sources another bash script. Essentially, I need a few lines to check to see if a certain variable is set. If not, I set it manually, and then source a scripts with that variable in the path. I wrote a test script to try it, but for some reason the last line does not work. Here is what I wrote:
#!/bin/sh source ~setupdir/setup.shrc #just a test, this line works echo ${#SETUP} # prints 0 if setup is not set, which it isn't if [ ${#SETUP} -eq 0 ] then SETUP="~setupdir" fi echo $SETUP # prints ~setupdir
i'm in the process of learing C++. currently i'm creating shell scripts to get things done. i'm just curious how, as a programmer using C++ you would get a similar job done.as an example i have a script that takes the contents of files, pipes it to some sed and awk commands, which is piped to create a new file. that file is then imported into a mysql database.if you were going to do this in C++, would you call the sed/awk programs to modify the file, or can it be done within the program itself? i'm probably jumping the gun here because i've just started learing about pointers so this is above my ability
Creating script that converts hex to dec. But without using bc calculator or other methods that could convert it in one line. I need to make something like this script that converts dec to hex.
I have a basic awk script that can read a file named 'server_info' and output to the screen which fax lines are not working. Now I want to make the script execute commands instead of printing to the screen but I am having trouble... This is better explained by my code below:
test.sh Code: #!/usr/bin/awk -f # #The name of this script is test.sh
Code: #!/bin/sh #System commands and other configurable. IPT=/sbin/iptables IP6T=/sbin/ip6tables IPST=/usr/sbin/ipset MODP=/sbin/modprobe GET=/usr/bin/wget INT_NET=192.168.1.0/24 .....
I can find lots of tutorials in how to use if, then, else. However, how do I define a variable inside the function? SEE>> Code: for c in $ISO Also, am I using the 'test' command correctly( -/+ week as valid test)?
I'm somewhere between Novice and I have no idea what I'm doing with bash scripts. I'm writing a script to deploy images using partimage on my company's desktops, and while I have just about everything else figured out I have one issue left.Each of our 4 sites that will be using this disc will have a deployment server due to the fact that our sites have dedicated point to point links that our business traffic is conducted on. I need to be able to determine what site I'm at based onubnet and set a variable based on this determination. What I don't know is how to get the IP address in to an if statement, and properly determine subnet. For example:
192.168.1.0/16 - 192.168.7.0/16 need to use DEPLSERV01 192.168.8.0/16 - 192.168.16.0/16 use DEPLSERV02 192.168.17.0/16 - 192.168.24.0/16 use DEPLSERV03
I know it's a very silly question but could someone please explain the difference between "/bin/bash" & "/bin/sh" I was under the impression that both are same but following output on my Ubuntu 8.10 is making me raise my eyebrows.
i want to run bash script on website.i still have to choose between unix hosting and windows hosting. my web hosting service offer Own Cgi - Bin PHP,ASP,MYSQL,MSSQL, and script schedule(cronejob). This is script
#!/bin/bash #Store arguments from bash command line fight=$1 support=$2 msg=rmsg
Having a problem with an unwanted redirection in in a function call. Although this isn't the function it does illustrate the problem:
Code: #!/bin/bash doat () { ALL="sys1 sys2" for Sys in $ALL;do echo "---> $Sys <---"; echo $(eval echo $1);
[Code]...
figure out how to get the variable into the command without outputting to the file in the eval statement? So that ssh line that gets executed would look like the following to each iteration of the for loop:
Code: ssh root@$Sys rpm -qa|sort > /trans/${Sys}-rpm-list.txt; doat works when the incoming argument doesn't have any redirection in the command.
