I am having trouble with the code below, I'm trying to check if a variable holding a character is a hyphen.
Code:
#!/bin/bash
$char="-"
if (( "$char" == "-" )); then
[code]....
i have the following:
Quote:
echo %host%|sed "$s/.$//"
this would remove the Last character of the value assigned to the %host%. for example if my value is: abcd i get abc. but i am not able to assign the output. for example when i do
Quote:
set k=`echo %host%|sed "$s/.$//"`
after doing echo %k i get no output at the command prompt...!! whereas when i just type:
Quote:
echo abcd|sed "$s/.$//"
at the command prompt i get abc. maybe some other ways to Remove the Last character...?
I have a file with one line. I want to check whether the first character is TAB or space, how can i do this.? using "cut" wont as it "bypasses the tab and space characters"
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Code: #!/bin/sh
echo "Veuillez saisir un nombre"; read nmbr
nmbrf=$nmbr
while [ $nmbrf -gt 0 ]
do mkdir -p "foo$nmbrf"
nmbrf=`expr $nmbrf - 1`
echo "$nmbrf"
how do I check that nmbr is a number or something else?
I am in need of a way to check that the same file exists within two different directories using a filename as a variable. Here is the process which requires it: The script is reaches out (via ftp) and pulls down a file(s) and delete it afterwards. This is halfhazard because in the instance it doesnt pull down the file, yet still deletes it, we are up a creek. I am looking to pull it down to a temp location and then verify that file exists in the location in which it needs to be present to process before deleting it, adding a little extra layer for security. The script itself is finished.If I put a file name in manually it works perfect. I just need a way to pump the filename into the variable.
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set -A allArgs
set +A allArgs ${allArgs[@]} -all
set +A allArgs ${allArgs[@]} -date
[code]...
I want to remove single quote from a variable. eg: Suppose I have a variable VAR='TEST' (including single quotes) How can I remove single quotes and make it TEST.
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View 4 Replies View Related1.What character instructd the shell to interpret a special character as an ordinary character?
2.What directory contains some of the utilities available on the system in the form of binary files?
3. What command is used to search the location of a utility?
4. What command is used to instruct the editor to write the file and quit the editor?
5. What key quits the more utility and displays the shell prompt?
6. What command starts a child shell as the super user, taking on root's identity and environment?
7. Which wildcard characters can be used for searching all the files in the system that start with "A"?
8. The user name or login name of the super user is????
[Code]....
I'm trying to read content of file to variable and use this variable in for loop. The problem is, when I have c++ comment style in file - /*. Spaces in line are also interpreted as separated lines.
For example:
Code:
Changing $files to "$files" eliminate these problems but causes that whole content of variable is treated as one string (one execution of loop).
I have a CSV file with 8 columns. I want to check the 5th column, which will contain a single capitalised letter. If that letter is say "B" I would then like to replace the 2nd column in the csv with an incremental number starting at 0 (basically a count) with a prefix of B (B0000001) Sample row would be:
Code:
C, 0109390,sfs,sfsf,B,blah,blah
Amended row would be:
Code:
C, B000001,sfs,sfsf,B,blah,blah
my script has a variable which comes in the form +00.00 +0.00 -00.00 or -0.00 (the numbers can be any in that form) for any that have a + symbol I need to remove the +, but if it has a - symbol it needs to stay.
i need to make a new variable with the string from the old variable btut without any plus sign. I have tried a lot of different ways with no success, each thing I tried either left the + or removed the entire string. I think this should work but doesn't
foo=+12.40
bar=${foo#+}
how I can search within a variable and assign the results to a new variable. I'll use the following as an example -
cars="Audi BMW Cadillac Chevy Dodge Ferrari Ford Mercedes"
list=`echo ${cars} | egrep -o '<A?+|<C+'`
with the echo command I get the following output assigned to list -
A
C
C
What I'd like to get for output is -
Audi
Cadillac
Chevy
how I could do this regardless of upper/lower case letters?
included shell script inside c program, and i wanted to assign the value of c variable to shell variable..Can any one please suggest me how to do it?
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Code:
for ((i=1;i<=$number;++i)) ; do
offset=$(($i+5))
[code]...
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Code:
char aname[][15] = { "Illegal month", "Jan", "Feb", "Mar" };
char amessage[] = "now is the time";
[code]...
i am compiling the following program in linux. it's in c language. after the compilation with gcc when i run the executable file. it asks for input. but when i enter a name. i prints "Segmentation fault" and then terminate the program. can you please help me.
#include <stdio.h>
#include <ctype.h>
#include <stdlib.h>
#include <unistd.h>
[code]....
which is the simplest way to have first and last character cropped out from a string? Something simpler than
Code:
echo $STRING | cut -b 2- | rev | cut -b 2- | rev
I have the following file:
Code:
1 line
...
49 test test=AA:AA:AA:AA:AA=0
I need to substitute on the line number 49, all text until =. I have used the following, but with no actual result.
sed -re '49s/^.+=//' file
and
sed -e '49s/.*[=]//' file
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egrep '^s' file | nawk '{virtual=substr($0,9,1); if ($virtual=="v") {printf "%s", $1}}'
nawk: illegal field $(e)
input record number 1
source line number 1
I believe I have unwanted ' characters left in a 9 element character array that are causing subsequent operations with it to fail. I see wildly differing views on the web on the proper way to flush 'em. It's clearly not as simple as it would appear at first sight. What's currently the best (or else "least deprecated") method?
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I can then take that information and use it with the following string to strip off the lead characters so as to make the 3 in $substr either a variable or redirect to multiple occurrences of raw based on the count returned.
sub raw {
$substr = substr ($_, 3);
$raw1 = substr ($substr, 0, -4);
$raw = lc($raw1);
}
how to count from the c to the t inclusive so I get 3, 4, 5, etc ...
how to replace last character string. For example
$>export T1=abcde
$>export T2=xyz
how to get result abcdxyz?
I have a string as below
LogFormat "%h %l %u %t "%r" %>s %b "%{Referer}i" "%{User-Agent}i"" combined
Want the above string to be modified as
LogFormat "%h %l %u %D %t "%r" %>s %b "%{Referer}i" "%{User-Agent}i"" combined
inserting %D after %u in the string